1. Animals that eat only plants are called ________.

1. carnivores
2. decomposers
3. herbivores
4. omnivores

Answers

Answer 1

Answer:

3

Explanation:

they are called herbivores

Answer 2

Answer:

Herbivores

Explanation:


Related Questions

modern scientific explanations of evolution
a. have replaced darwin’s thinking
b. combine the principles of natural selection and genetic inheritance
c. rely on genetics instead of natural selection
d. fail to explain how traits are inherited

Answers

C is the answer hope it’s right

Consider a plant with the following characteristics. Round leaves (R) are dominant to pointed leaves (r). White flowers (W) are dominant to pink flowers (w). Plants heterozygous for both traits are crossed. What is the probability of obtaining a plant with pointed leaves and pink flowers

Answers

Answer:

.0625 or 6.25%

Explanation:

Find the probability for the plant to have pointed leaves. If the two parent plants are heterzygous, then the likelihood the plant has a recessive characteristic is 25%, 1/4, or .25 for our calculations.Find the probability for the plant to be pink. If the two parent plants are heterzygous, the likelihood the plant has another recessive characterisitc is again 25%, 1/4, or .25 for our calculations.Multiply them together. (1/4)*(1/4)=(1/16) or .0625, or 6.25%

In the laboratory, a genetics student crossed flies with normal, long wings to flies with mutant, dumpy wings, which she believed was a recessive trait. In the F1, all flies had long wings. In the F2, the following results were obtained: 672 long-winged flies 218 dumpy-winged flies The student tested the hypothesis that the dumpy wing is inherited as a recessive trait by performing chi-square analysis of the F2 data.

Determine:
a. Chi-Square Value.
b. Degrees of freedom.
c. Reject or fail to reject the hypothesis.

Answers

Answer:

a. Chi-Square Value = 0.12

b. Degrees of freedom = 1

c. Reject or fail to reject the hypothesis = fail to reject the hypothesis

Explanation:

Available data:

Cross: long wings to flies with mutant, dumpy wingsF1) 100% long-winged fliesF2)  672 long-winged flies 218 dumpy-winged flies Hypothesis: the dumpy wing is inherited as a recessive trait

Let us name the allele for Long L and the allele for dumpy l

The number of observed individuals:

Total number: 890 flies (672 + 218) Long-winged = 672 Dump-winged = 218

In the F2 generation, if l was a recessive allele and L a dominant allele, exhibiting complete dominance, we would expect a 3:1 phenotypic ratio.

Cross:          Ll   x   Ll

Gametes)   L   l    L  l

Punnett square)   L     l

                     L    LL    Ll

                      l     lL     ll

F2) 3/4 LL + Ll long-winged individuals

      1/4 ll dump-winged individuals

From this ratio and the total number of individuals in the F2 generation, we can get the expected number of individuals:

4 possible genotypes ------- 890 individuals

3 LL + Ll genotype ------------X = 667.5 long-winged individuals

1 ll genotype ---------------------X = 222.5 dump-winged individuals

 

Chi square = ∑ (O-E)²/E

LL + Ll = (O-E)² /E

LL+ Ll = (672 - 667.5) ² / 667.5

LL + Ll = 0.03

ll= (O-E)²/E        

ll= (218 - 222.5)² / 222.5

ll= 0.09  

Chi square= ∑ ((O-E)²/E) = 0.03 + 0.09 = 0.12 Freedom Degrees = genotypes - alleles = 3 - 2 = 1 Significance level = 0.05     Table value/Critical value = 3.84

0.12 < 3.84 meaning that there is enough evidence to reject the null hypothesis.

Fail to reject the hypothesis.  The genotypes in the population might be in equilibrium H-W. L is the dominant allele, and l is the recessive allele. The dumpy wing is inherited as a recessive trait.

Which of the following is an example of a learned response? OA A child figures out how to ride a bicycle. O B. An adult salmon is able to return to the river where it hatched. OC. A plant turns to follow the sun during the day. OD. A man blinks when an object is tossed toward his face.​

Answers

Answer:

Explanation:

I would say A. Learning to ride a bicycle is a process of getting on and falling off. You have no idea how to do it properly without practice. That's learned.

But look out for D. I'm not sure that that isn't instinctive. Somewhere along the line I think even a baby knows not to let his/her eyes be touched. Is it learned? It's close but A is a much better answer.

The salmon is instinctive. The plant doesn't learn to turn towards the sun. It does so because more food is produced.

Yes, it's A.

A is the only option that is not instinctual. Riding a bicycle is something that has to be taught (and even if you weren't taught to ride a bike, you had to figure it out by trial and error.)

The other options are instinctual and reflexive responses. The salmon returning to the river is a behavior that is pretty much hard-wired into the salmon's brain. The plant turns to follow the sun because it is a source of light and energy.

The other user expressed uncertainty as to option D, but in fact, option D is very much a reflexive, instinctual response as well. To flinch or blink when something abruptly moves towards you is not a choice or something you have to be taught — it's a reflex, something you can't control.

Distinguish between herbaceous and woody stems​

Answers

Answer: herbaceous plants are plants with very flexible stems. Their leaves and stems die down to soil level at the end of every growing season amd woody plants are plants with very strong and not easily bendable stems such as trees. Woody plants produce wood as a structural tissue

How to be a grown up

Answers

Answer:

yOu nEeD ThE mOnEy DuDe

Explanation:

Job

The kingdom Eubacteria is so called as they have a "True" nucleus.
True
False

Answers

I believe false. It should be

what is a selectable marker?????​

Answers

a selectable marker is a gene introduced into a cell, especially a bacterium or to cells in culture, that confers a trait suitable for artificial selection
ectable marker is a gene introduced into a cell, especially a bacterium or to cells in culture, that confers a trait suitable for artificial selection.

This is the answer that i know !

Hope it helps , stay home stay safe dear !!

How many amino acids are there in A peptide, B peptide and C peptide in human insulin???​

Answers

Answer:

Insulin is composed of an A chain of 21 amino acids and a B chain of 30 amino acids. C-peptide is a peptide composed of 31 amino acids

Explanation:

Insulin is composed of an A chain of 21 amino acids and a B chain of 30 amino acids, the chains being held together by two disulfide bonds. A third disulfide bond is present within the A chain. Human insulin differs from porcine insulin by a single amino acid and from beef insulin by three amino acids.

Explanation:

Dashed circles around either an R or K indicate sites of peptidase cleavage that result in generation of the mature insulin that is comprised by two separate peptides: the A chain with 21 and the B chain with 30 amino acids. A third C peptide with 21 amino acids served as a linker between the A and B chains.

Write a scientific explanation to explain how natural selection and adaptation increase or decreases the chances of survival for the mice if they entered one another’s environment.

Answers

Answer:

Natural selection is a factor of biological evolution, by means of which individuals who possess a certain characteristic tend to prevail over those who lack such characteristic. Thus, by reproducing, individuals with favorable characteristics end up imposing their own set of characteristics, taking control of the environment in which they develop and relegating other individuals or condemning them to their extinction or displacement.

Thus, in the case, if some mice entered the environment of others, most likely they would not be able to adapt to the conditions to which the original group of that environment had previously adapted. In this way, natural selection itself would make the new mice end up disappearing from it, in favor of the mice that already lived there and that, therefore, had adapted their characteristics to those of the environment.

Consider a cross between a plant with two flower colors, yellow and red. Yellow (Y) exhibits complete dominance over red (y). It also has either single blossoms or double blossoms, single blossoms (S) exhibit complete dominance over double blossoms (s). A dihybrid yellow, single blossomed flower is crossed with a red flowered and double blossomed plant. You observe the following phenotype frequencies among the 1545 offspring plants:
500 yellow flowers and single blossom plants
515 red flowers and double blossom plants
260 yellow flowers and double blossom plants 270 red flower and single blossom plants.
What is the recombination frequency between these two genes?
a. (260+270) 1545
b. 270/1545
c. 1545/ (260+270)
d. 260/1545
e. (500+515)/1545
f. 1545/260
g. 1545/270
From these results one can conclude that:_______.
a. the two genes are linked
b. the two genes are not linked
c. if the genes are linked, they are separated far enough apart to appear to assort independently

Answers

Answer:

1) option a is correct. (260+270)/1545

(Note about this option: In the statement, it is written as (260+270) 1545. Lacks the division symbol, / )

2) From these results one can conclude that the two genes are linked (option a)

Explanation:

To know if two genes are linked, we must observe the progeny distribution. If heterozygous individuals, whose genes assort independently, are test crossed, they produce a progeny with equal phenotypic frequencies 1:1:1:1. If we observe a different distribution, phenotypes appearing in different proportions, we can assume linked genes in the double heterozygote parent.  

We might verify which are the recombinant gametes produced by the di-hybrid, and we will be able to recognize them by looking at the phenotypes with lower frequencies in the progeny. Phenotypes with the highest frequencies represent the parental gametes.

To calculate the recombination frequency, we will use the following formula: P = Recombinant number / Total of individuals.  

In the present example:

Parental)        YySs                        x                 yyss

Gametes)  YS parental type                        ys, ys, ys, ys

                 ys parental type

                 Ys recombinant type

                 yS recombinante type

The total number of individuals in the offspring: 1545

Phenotypic class Number of offspring  

500 Y-S- (parental)515 yyss (parental)260 Y-ss (recombinant)270 yyS- (recombinant)

According to this information, the phenotypic frequencies of the progeny differ from the phenotypic ratio 1:1:1:1. We can assume then, that these genes are linked.

The recombination frequency is:

P = Recombinant number / Total of individuals

P = 260 + 270 / 1545

P = 530/1545

P = 0.343

The genetic distance between genes is 0.343 x 100= 34.4 MU.

What are the Necessary conditions to form a natural lake

Answers

Answer:

What conditions are necessary for a natural lake? Lakes form in a variety of ways when a natural depresion fills with water. The lake must have a source of water that is greater than the outflow and evaporation. It must be on earth that does not allow too much water to infiltrate.

Explanation:

Answer:

Lakes form in a variety of ways when a natural depression fills with water. The lake must have a source of water that is greater than the outflow and evaporation. It must be on earth that does not allow too much water to infiltrate.

Yeast is a: rhizobium, legume, bacteria or fungi?

Answers

Answer:

legume mark me brainy plz!

Explanation:

Answer:

I think its a legume?

Explanation:

2. Write a word equation for the process of photosynthesis.
3. Why do plants test positive for starch?​

Answers

Carbon dioxide + water ————> Glucose + oxygen


Glucose is stored by plants as starch, which plants use as food, the presence of starch in a leaf is evidence of photosynthesis, because starch formation requires photosynthesis.

ESP: actuan las hormonas solo sobre celulas o pueden actuar sobre otras estructuras?

ENG: do hormones act only on cells or can they act on other structures?

Answers

Answer:

Hormones act only on cells not structures.

Explanation:

Hormones act only on cells and they  do not act on other structures because there are specific cells have receptors for that particular hormone. Some hormones bind itself to the receptors on the surface of target cells whereas other hormones enter the cells and bind itself to the receptors present in the cytoplasm or nucleus of the cell.

What can you tell about bacteria that have been Gram stained?
A) Microscopic morphology
B) Macroscopic morphology
C) Gram reaction
D) A and C

Answers

Answer:

D) A and C

Explanation:

Gram staining is a laboratory technique used for bacterial species. It is used to differentiate between two groups of bacteria based on the components of their cell wall. Gram staining was developed by a scientist called Christian Gram in the year 1884. In the gram stain procedure, the following occurs:

- Due to the thick peptidoglycan component of their cell wall, GRAM POSITIVE bacteria retains the crystal violet due and stain VIOLET.

- On the contrary, due to the thin peptidoglycan component of their cell wall, GRAM NEGATIVE bacteria do not retain the crystal violet dye and hence stain, RED.

Based on this, a bacteria that has been gram stained has been tested for its GRAM REACTION and microscopic morphological characteristics, since it is a microbe.

If you throw a rock into the air, its instantaneous speed is probably highest
A) at the top of its flight
B) halfway to the top of its flight
C) when you throw it and right before it hits the ground
D) when you throw it
E) right before it hits the ground​

Answers

Answer:

B halfway to the top of it's flight

D or B

Explanation:

I don’t know how to explain it.. sorry

A group of students were asked to study and record the movement of amoeba to try and determine how they move. The group knew that they must plan this descriptive investigation carefully, including the selection of the appropriate technology needed to observed these single-celled organisms. Which type of microscope would be most appropriate for this investigation? A) Compound Light Microscope B) Scanning Electron Microscope (SEM) Stereo Microscope (Dissecting Scope) D Transmission Electron Microscope (TEM)​

Answers

Answer:

A. Compound Light Microscope

Explanation:

USA TestPrep

Answer:

coumpound light microscope

Explanation:

Select ALL the correct answers.

A pitcher for a professional baseball team allows runs in the first nine games he starts this season. Let A be the set of the number of

runs allowed by the pitcher in his first nine starts.

A = {1, 4, 2, 2, 3, 1, 1, 2, 1}

In the tenth game he starts, he allows 9 runs. Let B represent the set of the number of runs allowed in all ten games he has started.

Select the true statements.

The median of B is 1 run more than the median of A.

The interquartile range of B is greater than the interquartile range of A.

The interquartile range of A is 1 less than the interquartile range of B.

The median of A is the same as the median of B.

Including the runs allowed in the tenth game does not cause the spread of the data to

change.

Answers

Answer:

(b) The interquartile range of B is greater than the interquartile range of A.

(d) The median of A is the same as the median of B.

Explanation:

Given

[tex]A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}[/tex]

[tex]10th\ run = 9[/tex]

So:

[tex]B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}[/tex]

Required

Select all true statements

(a) & (d) Median Comparisons

[tex]A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}[/tex]                         [tex]B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}[/tex]

[tex]n = 9[/tex]                                                         [tex]n = 10[/tex]

Arrange the data:

[tex]A = \{1, 1, 1, 1, 2, 2, 2,3, 4\}[/tex]               [tex]B = \{1,1,1,1,2,2,2,3,4,9\}[/tex]

                               [tex]Median = \frac{n + 1}{2}th[/tex]

[tex]Median = \frac{9 + 1}{2}th[/tex]                            [tex]Median = \frac{10 + 1}{2}th[/tex]

[tex]Median = \frac{10}{2}th[/tex]                              [tex]Median = \frac{11}{2}th[/tex]

[tex]Median = 5th[/tex]                                 [tex]Median = 5.5}th[/tex] --- average of 5th and 6th

[tex]Median = 2[/tex]                                    [tex]Median = \frac{2+2}{2} = 2[/tex]

Option (d) is correct because both have a median of: 2

(b) & (c) Interquartile Range Comparisons

[tex]A = \{1, 1, 1, 1, 2, 2, 2,3, 4\}[/tex]               [tex]B = \{1,1,1,1,2,2,2,3,4,9\}[/tex]

[tex]n = 9[/tex]                                                         [tex]n = 10[/tex]

First, calculate the lower quartile (Q1)

[tex]Q_1 = \frac{n + 1}{4}th[/tex][Odd n]             [tex]Q_1 = \frac{n}{4}th[/tex] [Even n]

[tex]Q_1 = \frac{9 + 1}{4}th[/tex]                            [tex]Q_1 = \frac{10}{4}th[/tex]

[tex]Q_1 = \frac{10}{4}th[/tex]                              [tex]Q_1 = 2.5[/tex]

[tex]Q_1 = 2.5th[/tex]                              

This means that:

[tex]Q_1 = 2nd + 0.5(3rd - 2nd)[/tex]              [tex]Q_1 = 2nd + 0.5(3rd - 2nd)[/tex]

[tex]Q_1 = 1 + 0.5(1- 1)[/tex]                   [tex]Q_1 = 1+ 0.5(1 - 1)[/tex]                      

[tex]Q_1 = 1[/tex]                                       [tex]Q_1 = 1[/tex]

Next, calculate the upper quartile (Q3)

[tex]Q_3 = \frac{3}{4}(n + 1)th[/tex] [Odd n]             [tex]Q_3 = \frac{3}{4}(n)th[/tex] [Even n]

[tex]Q_3 = \frac{3}{4}(9 + 1)th[/tex]                            [tex]Q_3 = \frac{30}{4}th[/tex]

[tex]Q_3 = \frac{30}{4}th[/tex]                                     [tex]Q_3 = 7.5th[/tex]  

[tex]Q_3 = 7.5th[/tex]                                    

This means that:

[tex]Q_3 = 7th + 0.5(8th- 7th)[/tex]           [tex]Q_3 = 7th + 0.5(8th- 7th)[/tex]

[tex]Q_3 = 2 + 0.5(3- 2)[/tex]                       [tex]Q_3 = 2+ 0.5(4 - 2)[/tex]                      

[tex]Q_3 = 2.5[/tex]                                       [tex]Q_3 = 3[/tex]

The interquartile range is  [tex]IQR = Q_3 - Q_1[/tex]

So, we have:

[tex]IQR = 2.5 - 1[/tex]                  [tex]IQR = 3 - 1[/tex]

[tex]IQR = 1.5[/tex]                       [tex]IQR =2[/tex]

(b) is true because B has a greater IQR than A

(e) This is false because some spread measures (which include quartiles and the interquartile range) changed when the 10th data is included.

The upper quartile and the interquartile range of A and B are not equal

define unplanned urbanization?​

Answers

here's your answer dude

hope it helps you

One of the following is not a function of proteins:

Select one:
a. Catalysis as Enzymes
b. Transport of proteins
c. Protection as antibodies
d. Regulation of hormones

Answers

d... i took science last year

helppppppppppp meeeeeeee​

Answers

The answer is flow of energy

Please answer the three questions. ☺️
d) Out of the 16 possible outcomes, how many have to yellow leaves?
e) Out of the 16 possible outcomes, how many have green leaves?
f)Out of the 16 possible outcomes, how many have green leaves and rough
seeds?

Answers

Answer:

12 out of 16 have yellow leaves

4 out of 16 have green leaves

1 out of 16 has green leaves and rough seeds

Explanation:

<3

The answer to the three questions is as follows:

Out of the 16 possible outcomes, 12 of them have to possess yellow leaves. Out of the 16 possible outcomes, 4 of them have to possess green leaves. Out of the 16 possible outcomes, only one has green leaves and rough seeds.

What is a Dihybrid cross?

A dihybrid cross may be characterized as a type of cross that significantly takes place between two individuals with two observed traits that are controlled by two distinct genes. It is a breeding experiment between two organisms that are identical hybrids for two traits.

According to the context of this question, the allele Y encodes for yellow color leaves, and y codes for green color leave. Yellow is dominant over the green. Similarly, S encodes for smooth leaves while s codes for rough seeds. Smooth is dominant over rough.

yyss is the only genotype that has a green and rough phenotype. While the possibilities that have yy in their genotypes must possess a green phenotype.

To learn more about Dihybrid cross, refer to the link:

https://brainly.com/question/12540319

#SPJ2

Ask a question about your assignment Explain what are shared characteristics of transcription to translation and what are their differences. Explain what their function is in each cell and their importance to the body.​

Answers

Explanation:

perform the following the rhythm patterns using the given legend use any kind of membranophones pearl shoes us

why do we commonly see isotherms on local weather broadcasts?

Answers

Explanation:

Isotherms are lines of constant or equal temperature. They are often used on weather maps by meteorologists to give a large scale view of temperatures across the U.S. If you have ever looked at a weather map in a newspaper, the isotherms are used to divide the color-filled temperatures.

they are lines of the equator so when it shows a map on the news of the weather it shows you because it is ok every map

WILL GIVE BRAINLIEST


mutualism relates to which of the following relationships?

A. Both organisms benefit
B. One organism benefits; the other is harmed
C. Both organisms are harmed
D. Neither organisms benefit or is harmed

Answers

Answer:

A. Both organisms benefit

Explanation:

0.3 kilogram golf ball moving at 45 meters/second equals

Answers

Answer:

F = 13.5 N

Explanation:

help l m a o ........​

Answers

Answer:

D

Explanation:

LKM iF i AM CORRECT

explain why it is an advantage for plants to store carbohydrates as starch rather than as sugars​

Answers

Answer:

More energy are packed into less space by starch molecules far more than glucose or sucrose yet they are able to release this energy easily, hence maximizing both storage and mobilization.

Explanation:

When plants have a period of dormancy to survive, they store their food as starch. They store enough of this energy so as to be able to restart with and to be able to maintain metabolism for the entire period of dormancy.

In addition, we know that starch is not water soluble, hence, lacks the ability to pull water into storage cells or cause irregularity in water balance. More energy are packed into less space by starch molecules far more than glucose or sucrose yet they are able to release this energy easily, hence maximizing both storage and mobilization.

Glucose is not directly transported by plants to storage. Rather, in a plant stem, the form of carbohydrate being transported is sucrose and this is because it is a non-reducing and does not react with oxygen during transport in the stem to specialized storage plastids.

It is advantageous for plants to store carbohydrates as starch rather than as sugars because:

sugars such as sucrose, fructose, and glucose are soluble and cannot be stored in the body of plant.as such, plants have to find a way to store their food reservesone way to store the food would be to store them in less soluble form that cannot be washed away easily and can also be converted to usable forms when needed.Hence, starch provides for that option. Cellulose could also have been a choice, but its structure makes it such that it becomes a permanent part of the plant and cannot be converted to usable food anymore.

Hence, it is advantageous to store carbohydrates as starch by plant rather than sugars because starch cannot be washed away easily and can also be converted to usable foods when needed.

More on starch can be found here: https://brainly.com/question/14278135

Answer for 10 points!

Answers

Answer:

I think the answer is D

Explanation:

Hope that helps!

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