The Solution:
Given the data below in dollars:
15 10 30 25 30 40 20 50 20
30 40 20 10 10 20 10 15 40
20 25 10 15 30 30 20 15 10
10 20 20 10 50 20 10 30 30
We are asked to find the frequency of $10.00.
Note:
The frequency of $10.00 is the number of times $10 appears in the given data.
So, the frequency of $10.00 is 9.
Therefore, the correct answer is 9.
Please help me help help me please help help me out to
Step 1:
Write the expression
[tex]undefined[/tex]6. Select ALL of the correct ways of factor the following: -5x - 15A 5 (x-3)B-5 (x-3)C. 5(x-3)D. 5 (x + 3)E-5 (X + 3)7. Consider the expression: 10x + •15y.Part A: Factor the expression using the GCF.Part B: What is the value of the expression when x = -2 and y=-1?8. Consider the expression: -3a + 6 + 9 - 6a - 3b + 3.Part A: Simply the expressionPart B: Factor the expression using the GCF.Part C: What is the value of the expression when a = 2 and b = -2?
Part A
To factorie 10x + 15y
The GCF is 5
Hence, 10x + 5y = 5(2x + 3y)
Part B
The value of the expression when x = -2 and y = -1
5(2x +3y) = 5( 2(-2) + 3(-1) )
= 5(-4 - 3)
=5( -7)
= -35
For this question it is asking for the mean, standard deviation, Q1, Q3, lower fence, and upper fence
Step 1
Given;
[tex]10,\:15,\:19,\:52,\:34,\:44,\:47,\:20,\:60,\:25[/tex]Step 2
Find the mean
[tex]\begin{gathered} The\:arithemtic\:mean\:\left(average\right)\:is\:the\:sum\:of\:the\:values\:in\:the\:set\: \\ \begin{equation*} divided\:by\:the\:number\:of\:elements\:in\:that\:set. \end{equation*} \\ \mathrm{If\:our\:data\:set\:contains\:the\:values\:}a_1,\:\ldots \:,\:a_n\mathrm{\:\left(n\:elements\right)\:then\:the\:average}= \\ \frac{\sum x}{n}=\frac{326}{10}=32.6 \end{gathered}[/tex]Step 3
Find the standard deviation
[tex]S\mathrm{tandard\:deviation,\:}\sigma\left(X\right)\mathrm{,\:is\:the\:square\:root\:of\:the\:variance:}\sigma\left(X\right)=\sqrt{\frac{\sum(x_i-\mu)^2}{N}}[/tex][tex]Standard\text{ deviation=}17.28326[/tex]Step 4
Find Q1
[tex]\begin{gathered} The\:first\:quartile\:is\:computed\:by\:taking\:the\:median\:of\:the\:lower\:half\:of\:a\:sorted\:set \\ Arrange\text{ in ascending order} \\ 10,\:15,\:19,\:20,\:25,\:34,\:44,\:47,\:52,\:60 \\ Take\text{ the lower half of the ascending set} \\ 10,15,19,20,25 \\ Q_1=19 \end{gathered}[/tex]Step 5
Find Q3
[tex]\begin{gathered} \mathrm{The\:third\:quartile\:is\:computed\:by\:taking\:the\:median\:of\:the\:higher\:half\:of\:a\:sorted\:set.} \\ Arrange\text{ the terms in ascending order} \\ 10,\:15,\:19,\:20,\:25,\:34,\:44,\:47,\:52,\:60 \\ Take\text{ the upper half of the ascending term} \\ 34,44,47,52,60 \\ Q_3=47 \end{gathered}[/tex]Step 6
Find the lower fence
[tex]\begin{gathered} =Q_1-1.5(IQR) \\ IQR=Q_3-Q_1=47-19=28 \\ =19-1.5(28)=-23 \end{gathered}[/tex]Step 7
Find the upper fence
[tex]\begin{gathered} =Q_3+1.5(IQR) \\ =47+1.5(28)=89 \end{gathered}[/tex]sofia makes pies for sale the materials for each pie cost $4.00 and she sells the pies for $7.00. to find her profits, she writes the equation p=7.50X-4.00X explain what the variable x represents
Andrew, this is the solution:
Price of the pie materials = $ 4
Sale price of each pie = $ 7
Sofia writes this equation:
p= 7.50X - 4.00X
X represents the number of pies Sofia makes and sells
Andrew, the equation Sofia wrote is wrong.
This is the correct equation:
p= 7.00X - 4.00X
If you don’t need any further explanation, I’ll go ahead and end our session. Feel free to let me know how I did by rating our session - all feedback is welcome and appreciated. Thanks for coming today!
Remember that the solutions from tutors are always available in your profile!
Look at this graph: 5 3 2 0 1 2 3 4 5 6 7 8 9 10 What is the slope?
Here, we want to find the value of the slope
To do this, we will need to select two points on the graph
Any two points selected will sufice as far as they are reasonably apart to draw the slope triangle
The points we are seecting are (6,3) and (9,4)
Mathematically, the slope formula is as follows;
[tex]\begin{gathered} m\text{ = }\frac{y_2-y_1}{x_2-x_1} \\ m\text{ = }\frac{4-3}{9-6} \\ \\ m\text{ = }\frac{1}{3} \end{gathered}[/tex]find the measure of angle R to the tenth of a degree, if tan R=9.4618.
Explanation:
tan R = 9.4618
To get angle R, we would find the inverse of the trigonometry function
[tex]\text{Inverse of tan = tan}^{-1}[/tex]We take the inverse of of tan 9.4618
There are calculators which helpin this aspect
[tex]undefined[/tex]Define a variable and write an equation to model the situation
Answer:
D.
We were given that:
Perimeter (square) = 4 times the length of a side
For a square, all its sides are congruent
[tex]\begin{gathered} Perimeter_{square}=4\times length \\ \text{Let the length be represented by ''s'', the expression becomes:} \\ length=s \\ Perimeter_{square}=4\times s \\ Perimeter_{square}=4s \\ \\ \therefore p=4s \end{gathered}[/tex]Therefore, the correct option is D.
a bus route takes about 45 minutes. the company's goal is mad of less than 0.5 minute. one drivers times for 9 runs of the route. did the driver meet the goal?44.2 , 44.9 , 46.1, 45.8 , 44.7 , 45.2 , 45.1 , 45.3, 44.6
Answer:
The driver meet the goal
Explanation:
We are given that a bus route takes about 45 minutes
If companys goal is made less than 0.5minute, then, the company's goal is 45 - 0.5 = 44.5minutes
If one drivers times for 9 runs of the route, as ahown;
44.2 , 44.9 , 46.1, 45.8 , 44.7 , 45.2 , 45.1 , 45.3, 44.6
We will have to calculate the mean data first as shown;
Mean time = 44.2 +44.9+46.1 +45.8+ 44.7+ 45.2+45.1+45.3+44.6/9
Mean time = 405.9/9
Mean time = 45.1minutes
Since the mean time(45.1minutes) is greater than the company's goal (44.5minutes), hence the driver meet the goal
If mZDEF = (7x + 4)", mZDEG = (5x + 1)', and mZGEF = 23", find eachmeasure.EFDAngle DEF -What is x?Number 4
m∠FEH is 49 degrees greater than m∠HEG (option 1)
Explanation:4) ∠FEH = 90 degrees
m∠HEG = 41 degrees
∠FEH = m∠HEG + m∠FEG
90 = 41 + m∠FEG
m∠FEG = 90 - 41
m∠FEG = 49 degrees
Since m∠FEH = 90 degree and m∠HEG = 41 degree, their difference is 49 degrees
It means m∠FEH is 49 degrees greater than m∠HEG (option 1)
The above statement is true
Caitlin travels from 1 1/3 hours to visit a friend who lives 4 and 1/2 miles away Martin travels 4 1/4 miles to visit a friend it takes in 1 1/5 hours to get there who travels at a greater rate of 4 miles per hour
Caitlin travels 4.5 miles at 11/3 hours.
So his rate of travel will be
[tex]\frac{4.5}{\frac{11}{3}}=1.23[/tex]His rate is 1.23 mile/hour
Again Martin travels 4.25 miles at 11/5 hours
So his rate will be
[tex]\frac{4.25}{\frac{11}{5}}=1.93[/tex]Hence martins rate is 1.93 miles/hour.
SO Martin travels at a greater rate than Caitlin.
Answer:
Step-by-step explanation:
Please help me with this problem:Which properties justify the steps taken to solve the system?{2x−4y=183x+3y=0Drag and drop the answers into the boxes to match each step. Image is attached
First step.
If we multiply by 3 the first equation and by 2 the second equation we get the first step:
[tex]\begin{gathered} 6x-12y=54 \\ 6x+6y=0 \end{gathered}[/tex]therefore, the answer for the first box is: Multiplication property of equality.
Second step.
If we subtract both equations, we have
[tex]-18y=54[/tex]then, the answer for the second box is: Subtraction property of equality
Third step.
By dividing both sides of our last result by -18, we get
[tex]y=\frac{54}{-18}=-3[/tex]then, the answer for the third step is: Division property of equality.
Fourth step.
Once we have obtained the result for variable y (which is -3), we need to find the result for variable x. So, by substituting our result for y into the first equation, we have
[tex]2x-4(-3)=18[/tex]Therefore, the answer for the fourth box is: Substitution property of equality.
Fifth step.
Then, by simplifying our last result, in which there is a product of -4 and -3, we get
[tex]2x+12=18[/tex]Thefore, the answer for the fifth box is: Simplify.
Sixth step.
Now, by subtracting 12 to both sides, we have
[tex]2x=6[/tex]then, the answer for the sixth box is: Subtraction property of equality.
Seventh step.
Finally, by dividing both sides by 2, we obtain
[tex]x=3[/tex]Then, the answer for the seventh box is: Division property of equality.
A point P(x,y) is shown on the unit circle corresponding to a real number t. Find the values of the trigonometric functions at t. The point P is (√10/10 , -3√10/10) sin t=cos t= tan t=csc t=sec t=cot t=
Given
Graph
Procedure
Point P
[tex]P=(\frac{\sqrt[]{10}}{10},-\frac{3\sqrt[]{10}}{10})[/tex]Let's calculate the swept angle
[tex]\begin{gathered} \sin \theta=\frac{\frac{3\sqrt[]{10}}{10}}{1} \\ \sin \theta=\frac{3\sqrt[]{10}}{10} \\ \theta=\sin ^{-1}(\frac{3\sqrt[]{10}}{10}) \\ \theta=71.56\text{ \degree} \end{gathered}[/tex]Now the angle swept by t is
[tex]\begin{gathered} t=360-\theta \\ t=288.44\text{ \degree} \end{gathered}[/tex][tex]\begin{gathered} \sin (288.44)=-0.948 \\ \cos (288.44)=0.3163 \\ \tan (288.44)=-2.999 \\ \end{gathered}[/tex][tex]\begin{gathered} \csc (288.44)=-1.054 \\ \sec (288.44)=3.1614 \\ \cot (288.44)=-0.333 \end{gathered}[/tex]Round to the nearest hundredth please in the final answer
see the attached figure below to better understand the problem
In this problem, we have an isosceles triangle
the measure of the other two interior angles are
2A+64 10'=180
2A=115 50'
115 50'------> convert to degrees
115+50/60=115.83 degrees
2A=115.83
A=57.92 degrees
Now we have the right triangle
tan(57.92)=x/2.100
x=2.100*tan(57.92)
x=3.35 inO How many times greater is:the value of the digit 2 in234,567 than the value ofthe digit 2 in 765,432?
Given:
The given numbers are 234,567 and 765,432.
Required:
We need to find the number of times the value of the digit 2 in 234,567 is greater than the value of digit 2 in 765,432.
Explanation:
The value of digit 2 in 234,567 is 200,000.
The value of digit 2 in 765,432 is 2.
Divide 200,000 by 2.
[tex]\frac{200,000}{2}=100,000[/tex]200,000 is 100,000 times greater than 2.
The value of digit 2 in 234,567 is 100,000 times greater than the value of digit 2 in 765,432 is 2.
Final answer:
The value of digit 2 in 234,567 is 100,000 times greater than the value of digit 2 in 765,432 is 2.
[tex]100,000[/tex]Write in standard form: 3.6 x 10^5*
Standard form is the process of writing down very large or very small numbers easily. The mathematical expression for standard form is shown below.
[tex]\begin{gathered} x\text{ }\times10^m \\ x\text{ is a positive real number betwe}en1\text{ and 10} \\ m\text{ is real number( both positive and negative)} \end{gathered}[/tex][tex]undefined[/tex]Erika has a baking company and needs to purchase 17 pounds of flour for her cakes. The Baking Goods Store sells two different-sized bags of flour. The table shows the amounts of flour in the bag, the number of bags at the store, and the cost per bag of flour. Size Pounds 1 Bags for Sale 75 Cost per Bag Small $0.84 5 Large 4 4 $16.80 If Erika buys all of the large bags, how many small bags will she need? A. 7 small bags B. 12 small bags C. 28 small bags D. 71 small bags
There are 4 large bags, and each one has 4 pounds. Then, since she buys all of the large bags, she already has
[tex]4\times4=16[/tex]16 pounds. So, she only needs
[tex]17\text{ }\frac{2}{5}-16=1\text{ }\frac{2}{5}=\frac{5}{5}+\frac{2}{5}=\frac{7}{5}[/tex]1 2/5 pounds more, this fraction is equals to 7/5 pounds. Since the small bags only contains 1/5 pounds of flour, then, she needs
[tex]\frac{\frac{7}{5}}{\frac{1}{5}}=\frac{7}{5}\times\frac{5}{1}=\frac{7\times5}{5\times1}=7[/tex]7 small bags
The amount of time needed to Stuff and address envelopes for the local high schools followers in campaign varies inversely with the number of parent and student volunteers that attend the envelope stuffing event last year It took 20 people 3 hours to stuff in the dress the envelopes select the equation that could be used to estimate the amount of time Y, it will take the X number of volunteers to stuff and address the same number of envelopes.
This is a proportion question. In this case, it states that the time, y, and the number of volunteers, x, are inversely proportion. So:
20 -- 3
x -- y
Because the proportion is inverse, we inverse one of them to write the equation:
[tex]\begin{gathered} \frac{20}{x}=\frac{y}{3} \\ y=\frac{60}{x} \end{gathered}[/tex]The equation asked is:
[tex]y=\frac{60}{x}[/tex]What fraction is considered zero? when zero is on top o depends on the numerator when zero is on bottom no fraction is undefined
When the numerator of the fraction = 0 then the fraction is consider to be zero
Justin has 16 new magazines to readi.Let M be the number of magazines the would have left to read after reading R of them.Write an equation relating Mr. R. Then use this equation to find the number of magazines he would have left to read after reading9 of them.Equation:금Х$?Number left to read after reading of them: magazines
Let M be the number of magazines Justin would have left to read after reading R of them, then we can set the following equation:
[tex]M+R=16.[/tex]If R=9, then:
[tex]M+9=16.[/tex]Solving the above equation for M we get:
[tex]M=16-9=7.[/tex]Answer: After reading 9 magazines, Justin has 7 left to read.
Describe how the formula is a transformation of a toolkit function. Then sketch a graph of the transformation.. Be sure to include labels for the increments on your x and y axis. Take a picture of that written work and upload it when submitting your answer. You may want to create a table of values to help you graph the function.p(x)=(\frac {1}{3}x)^3-3
Given the function:
[tex]p(x)=(\frac{1}{3}x)^3-3[/tex]The parent function to the given function is f(x) = x³
To get the function p(x) from f(x), we will perform the following translations:
1) Horizontal stretch with a factor of 1/3
2) Shift downward 3 units
The graph of f(x) and p(x) will be as shown in the following picture:
Hiromi goal is to collect 40 dollars for a school fundraiser he has already collected 26.50 dollars Hiromi wants to know how much more money he needs to collect
he needs to collect 40-26.50=13.50 dollars more
graph the line that has a slope of 2/3 and includes the point (6,4)
First of all, remember what the equation of a line is:
y = mx+b
Where:
m is the slope, and
b is the y-intercept
m = 2/3
[tex]\begin{gathered} b=y-mx \\ b=4-2/3\cdot6 \\ b=4-4 \\ b=0 \end{gathered}[/tex]The equation of the line that passes through the point (6,4) with a slope of 2/3
[tex]y=\frac{2}{3}x[/tex]7f+15-29 True or false the expression contains 2 terms
1) Examining the expression 7f +15 -29
7f +15 -29 is equivalent to 7f -14
2) So, false the expression 7f +15-29 contains 3 terms but it is equivalent to another expression of 2 terms.
I need to find area of them composite shape please
Answer:
[tex]A=1,026\imaginaryI n^2[/tex]Explanation: We have to find the total area of the figure shown, the total area would be the area of the triangle and the square:
[tex]\begin{gathered} A=A_T+A_S\rightarrow(1) \\ \\ A_T=\frac{1}{2}(B\times H) \\ \\ A_S=S^2 \end{gathered}[/tex]plugging in the unknowns in the equation (1) gives the answer as follows:
[tex]\begin{gathered} H=35in \\ \\ \\ B=\sqrt{37in^2-35in^2} \\ \\ \\ A_T=2\times\frac{1}{2}(BH)=(35in\times\sqrt{37\imaginaryI n^2-35\imaginaryI n^2}) \\ \\ \\ A_T=(35in\times\sqrt{37\mathrm{i}n^2-35\mathrm{i}n^2})=35in\times\sqrt{144}=35in\times12in^2 \\ \\ \\ A_T=420in^2 \\ \\ \\ A_S=S^2 \\ \\ \\ S=2\times B=2\times12in=24in \\ \\ \\ A_S=24in^2=576in^2 \\ \\ \\ A=A_T+A_S\Rightarrow A=420in^2+576in^2 \\ \\ \\ A=1,026in^2 \end{gathered}[/tex]find the volume of pyramid. the base is a rectangle.
Given the volume of a rectangular based pyramid as;
[tex]V=\frac{1}{3}lbh\Rightarrow\begin{cases}l=\text{length} \\ b=\text{breadth} \\ h=\text{height}\end{cases}[/tex]Given the following parameters
[tex]\begin{gathered} l=9in \\ b=8in \\ h=7in \end{gathered}[/tex]Substitute the above values in the volume formula
[tex]\begin{gathered} V=\frac{1}{3}\times9\times8\times7 \\ V=\frac{504}{3} \\ V=168in^3 \end{gathered}[/tex]Hence, the volume of the pyramid with the rectangle base is 168 in³
the diameter of a circle is 14 feet. what is the area?give the exact answer in simplest form.
The area of a circle can be found multiplying pi by the radius of the circle raised to the square.
Given that the diameter equals 14feet, the area is:
[tex]\pi(7)^2=49\pi[/tex]Therefore, the area equals 49pi square feet.
Find the indicated probability for a randomly selected x value from the distribution
We need to find:
[tex]P(x\ge\mu-\sigma)[/tex]For the graph we get
here we know that the probability that we want is all the values from the mu-sigma line onwards
find three consecutive intergers whose sum is 276
If we need to find three consecutive integers, we have that they can be written as follows:
[tex]x,x+1,x+2[/tex]Since the sum of all of them is equal to 276, we can write the following equation:
[tex]x+(x+1)+(x+2)=276[/tex]Now, adding like terms, we have:
[tex]\begin{gathered} (x+x+x)+(1+2)=276 \\ 3x+3=276 \\ \end{gathered}[/tex]Now, we can subtract 3 from both sides of the equation, and then divide by 3 as follows:
[tex]\begin{gathered} 3x+3-3=276-3 \\ 3x=273 \\ \frac{3x}{3}=\frac{273}{3} \\ x=91 \end{gathered}[/tex]Then, we have that:
[tex]\begin{gathered} x=91 \\ x+1=92 \\ x+2=93 \end{gathered}[/tex]If we add these three consecutive integers, we will have:
[tex]\begin{gathered} 91+92+93=276 \\ 276=276\Rightarrow This\text{ is True.} \end{gathered}[/tex]In summary, the three consecutive integers whose sum is 276 are 91, 92, and 93.
What is the weight of the piece of aluminum shown below at 0.0974 lbs/in.^3 (hint:subtract the volume of the cylindrical hole.) Round to the nearest tenth as needed.
We will have the following:
First, we will determine the volume of the side plate:
[tex]V_1=0.5\cdot4\cdot5\Rightarrow V_1=10[/tex]Now, we find the volume of the front plate:
[tex]V_2=0.5\cdot4\cdot4-\pi(2)^2(0.5)\Rightarrow V_2=8-2\pi[/tex]Now, we calculate the total volume:
[tex]V_t=2V_1+V_2\Rightarrow V_t=2(10)+(8-2\pi)[/tex][tex]\Rightarrow V_t=28-2\pi[/tex]Now, we calculate its weight:
[tex]w=0.0974\cdot\frac{b}{in^3}\cdot(28-2\pi)\cdot in^3\Rightarrow w=2.115217751\ldots[/tex][tex]\Rightarrow w\approx2.1[/tex]So, it's weight is approximately 2.1 Lb.
If the diameter of a circle is changed from 5 cm to 10 cm, how will the circumference change?
Solution
Step 1
Write out an expression for the circumference of a circle
[tex]\begin{gathered} C\text{ =}\pi d \\ C\text{ is the circumference} \\ d\text{ is the diameter} \end{gathered}[/tex][tex]\begin{gathered} \text{when d = 5}cm \\ C=5\pi cm \end{gathered}[/tex][tex]\begin{gathered} \text{when d=10cm} \\ C=10\pi cm \end{gathered}[/tex]Thus, when the diameter changed from 5cm to 10cm, the circumference is twice the previous size
That is, the circumference when the diameter is 10cm is 2 times the circumference when the diameter is 5cm