Answer:
The correct answer is option C.
Explanation:
The pH of the solution with weak acid and its conjugate base is given by the Henderson-Hasselbalch equation:
[tex]pH=pK_a+\log[\frac{[A^-]}{[HA]}][/tex]
Where:
[tex]pK_a[/tex]= The negative logarithm of the dissociation constant of a weak acid
[tex][A^-][/tex]= Concentration of conjugate base of a weak acid
[tex][HA][/tex]= Concentration of weak acid
We are given a solution with acetic acid and acetate ion.
[tex]HAc(aq)\rightleftharpoons H^+(aq)+Ac^-(aq)[/tex]
The concentration of acetic acid in a solution= [tex][HAc]=0.2M[/tex]
The concentration of acetate ion in a solution = [tex][Ac^-]=0.35M[/tex]
The pK_A of the acetic acid = [tex]pK_a=4.8[/tex]
The pH of the solution:
[tex]pH=4.8+\log[\frac{0.35 M}{0.2M}]=5.04[/tex]
5.04 the pH of a solution of 0.2M acetic acid and 0.35M acetate ion.
Hence, the correct answer is option C.
What is an example of a Low Energy-created depositional environment?
Answer:
River flood plains, swamps, lakes, lagoons, marshes, and offshore.
Explanation:
Slow-moving currents prevent coarse-grained sediment from migrating into low-energy depositional environments. Fine materials can be carried long distances before they can settle out in the absence of waves and currents.
Which of the following limits a population's growth?
Answer: Limitations to population growth are either density-dependant or density-independent. Density-dependent factors include disease, competition, and predation. Density-dependant factors can have either a positive or a negative correlation to population size.
Explanation:
How many grams of the bromide salt of the conjugate acid must be combined with how many grams of the weak base, to produce 1.00 L of a buffer that is
Answer:
79.1g of weak base must be combined with 56.0g of conjugate acid
Explanation:
that is 1.00 M in the weak base?
The weak base is C5H5N with a pKa of 5.17 (Ka=6.7×10-6)and a desire pH of 5.63
The equilibrium of the weak base is with the bromide salt of the conjugate acid is:
C5H5N(aq) + H2O(l) + Br- ⇄ C5H5NHBr(aq) + OH-(aq)
Where Kb = Kw / Ka = 1x10⁻¹⁴ / 6.7x10⁻⁶
Kb = 1.49x10⁻⁹ is defined as:
Kb = 1.49x10⁻⁹ = [C5H5NHBr] [OH-] / [C5H5N]
Where [OH-] = 10^-(14- pH) = 10^-(14- 5.63) = 4.255x10⁻⁹M
[C5H5N] = 1.00M
Replacing:
1.49x10⁻⁹ = [C5H5NHBr] [OH-] / [C5H5N]
1.49x10⁻⁹ = [C5H5NHBr] [4.255x10⁻⁹M] / [1.00M]
[C5H5NHBr] = 0.35M
In 1L the moles of C5H5NHBr are 0.35 moles
Mass C5H5NHBr: 160.0118g/mol
0.35 moles * (160.0118g / mol) =
56.0g of C5H5NHBr are necessaries
The mass of C5H5N is -79.1g/mol-:
1.00moles * (79.1g/mol) =
79.1g of C5H5N are necessariesWhat is the molar mass of 4.23 g of an elemental gas in a 2.5L container at 282K and 1.4 atm?
Answer:
27.98g/mol
Explanation:
Using ideal gas law equation;
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
T = temperature (K)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
According to the information given:
V = 2.5L
P = 1.4 atm
T = 282K
n = ?
Using PV = nRT
n = PV/RT
n = 1.4 × 2.5/0.0821 × 282
n = 3.5/23.1522
n = 0.151mol
Using the formula to calculate molar mass of the elemental gas:
mole = mass/molar mass
Molar mass = mass/mole
Molar mass = 4.23g ÷ 0.151mol
Molar mass = 27.98g/mol
HELP HELP HELP
NH3 + NO + N2 + H2O
5. Given 8.25 x 1025molecules of ammonia, determine the number of grams of
nitrogen produced.
Answer:
4NH3+6NO+5N2+6H20
Explanation:
Please someone solve this and tell me how you solve it
Answer:
Supersaturated.
Explanation:
Hello there!
In this case, according to this solubility chart, we infer that for NH3, the solubility starts at 90 grams of NH3 that are soluble in 100 g of water at 0 °C and ends in about 8 g in 100 g of water at 100 °C for a saturated solution.
However, since we are asked for the solubility of NH3 at 20 °C, we can see that, according to the table and the curve for NH3, about 52 g of NH3 are soluble in 100 g of water; thus, for the given 60 g of NH3, we will say that 8 grams will remain undissolved, and therefore, this solution will be supersaturated.
Regards!
When two colorless solutions of ionic compounds are mixed, and the final mixture remains colorless. What type of a change does this represent
The question is incomplete, the complete question is;
when two colorless solutions of ionic compounds are mixed, and the final mixture remains colorless. What type of a change does this represent? Select from the options below The information provided is insufficient for determining the type of change Physical change because the absence of color change indicates that there is no change in chemical composition of the mixture B Chemical change because the absence of color change indicates that there is a change in chemical composition of the mixture
Answer:
The information provided is insufficient for determining the type of change
Explanation:
A chemical change is one in which new substances are formed. Chemical changes are not easily reversible and they are often accompanied by evolution or absorption of heat.
A physical change does not lead to the formation of new substances. It is easily reversible.
Change in colour alone can not tell us whether a physical or chemical change has taken place. This is because colourless, miscible substances may have been formed in the process hence the final mixture remains colorless.
It is also possible that the two solutions were merely physically mixed. This is a physical change,
Therefore, the information provided is insufficient for determining the type of change.
What is the net ionic equation Pb(NO3)2(aq)+NaS(aq)=PbS(s)+2NaNO3(aq)
From the molecular equation, we can se that the net ionic equation is; Pb^2+(aq) + S^2-(aq) -----> PbS(s)
What is a net ionic equation?The net ionic equation is the equation that involves only the ions that underwent a change in the reaction.
The molecular equation is;
Pb(NO3)2(aq)+Na2S(aq)------->PbS(s)+2NaNO3(aq)
The complete ionic equation is;
Pb^2+(aq) + NO3^-(aq) + 2Na^+(aq) + S^2-(aq) -----> PbS(s)+ 2Na^+(aq) + NO3^-(aq)
The net ionic equation is;
Pb^2+(aq) + S^2-(aq) -----> PbS(s)
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In the titration, 15 mL of CsOH solution is neutralized by 38.2 mL of 0.250 M HBr solution. What is the molarity of the CsOH solution?
Answer: 0.637M
10.2M
1.36M
0.0982M
Explanation: the answer is 1.36M
The molarity of the CsOH solution is 0.636 M.
What is molarity?Molarity is the concentration of any substance in a place.
The reaction is
HBr + CsOH —> CsBr + H₂O
The formula of molarity
[tex]M = \dfrac{n}{V}[/tex]
[tex]\dfrac{0.25 \times 38.2 }{15} = 0.6366[/tex]
Thus, the molarity of the CsOH solution is 0.636 M.
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When the pressure and number of particles of a gas are constant, which of the following is also constant
Determine whether each substance listed is a strong acid, weak acid, strong base, weak base, acid salt, basic salt, or neutral salt. a) sodium hydroxide, NaOH b) ammonium chloride, NH4Cl c) perchloric acid, HClO4 g
Answer:
a) Strong Base
b) Acid Salt
c) Strong Acid
Explanation:
a) sodium hydroxide, NaOHAs is the case with most hydroxides, NaOH is a strong base. It dissociates completely into Na⁺ and OH⁻ species when in water.
b) ammonium chloride, NH₄ClNH₄Cl is a acid salt, as it produces H⁺ species when dissolved in water:
NH₄Cl → NH₄⁺ + Cl⁻NH₄⁺ → NH₃ + H⁺c) perchloric acid, HClO₄HClO₄ is a strong acid, as it completely dissociates into H⁺ and ClO₄⁻ species when in water.
What are the coefficients that will balance the skeleton equation below?
N2 + H2 -> NH3
Which of the following statements about the pH of 0.010 M HClO4 is correct?
pH=2.00, because [H+]=1.0×10−2M.
A: p H equals 2.00 , because the molar concentration of H with a positive 1 charge equals 1.0 times 10 to the negative 2 power molar .
pH=2.00, because [H+]=2.0×10−2M.
B: p H equals 2.00 , because the molar concentration of H with a positive 1 charge equals 1.0 times 10 to the negative 2 power molar .
pH>2.00, because HClO4 is a strong acid.
C: p H is greater than 2.00 , because H C l O 4 is a strong acid.
pH<2.00, because HClO4 is a weak acid.
Answer:
Option B: p H equals 2.00 , because the molar concentration of H with a positive 1 charge equals 1.0 times 10 to the negative 2 power molar .
pH = 2 because [H⁺] = 1×10¯² M
Explanation:
To know which option is correct, we shall determine the pH of the 0.010 M HClO₄ solution. This can be obtained as follow:
We'll begin by calculating the concentration of the hydrogen ion [H⁺] in the solution. This is illustrated below:
HClO₄ is a strong acid and will dessociates as follow:
HClO₄ (aq) —> H⁺ (aq) + ClO₄¯ (aq)
From the balanced equation above,
1 mole of HClO₄ produced 1 mole H⁺.
Therefore, 0.010 M HClO₄ will also produce 0.010 M H⁺.
Finally we shall determine the pH of the solution. This can be obtained as follow:
Concentration of the hydrogen ion [H⁺] = 0.010 = 1×10¯² M
pH =?
pH = –Log [H⁺]
pH = –Log 1×10¯²
pH = 2
Thus,
The pH = 2
because,
[H⁺] = 1×10¯² M
Thus, option B gives the correct answer to the question.
Based on the definition of pH, pH of 0.010 M solution of HClO4 equals 2.00, because the molar concentration of H with a positive 1 charge equals 1.0 times 10 to the negative 2 power molar.
What is pH?The pH of a solution is the negative logarithm of the hydrogen ion concentration of a solution.
pH of a solution is a measure of the acidity of the solution.
pH = - log[H+]where
[H+] is hydrogen ion concentrationFor the 0.010 M solution of HClO4, [H+} = 0.01 M
pH = -log(0.01)
pH = 2.00
Therefore, pH of 0.010 M solution of HClO4 equals 2.00, because the molar concentration of H with a positive 1 charge equals 1.0 times 10 to the negative 2 power molar.
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Which would make the greenhouse effect stronger?
O A. Adding oxygen gas to the atmosphere
O B. Decreasing greenhouse gas levels in the atmosphere
O C. Removing CO2 from the atmosphere
O D. Increasing the CO2 concentration in the atmosphere
Answer: D
Explanation:
Earth's ozone depleting substances trap heat in the air and warm the planet. The fundamental gases answerable for the nursery impact incorporate carbon dioxide, methane, nitrous oxide, and water fume (which all happen normally), and fluorinated gases (which are manufactured). The most mainstream ozone depleting substance is Water Vapor. The appropriate response is D.
The correct option for the given question about Green House Effect is Option D) Increasing the CO₂ concentration in the atmosphere.
What is Green House Effect?The greenhouse effect is the mechanism through which solar energy is absorbed by greenhouse gases rather than being reflected back into space. This keeps the earth's surface warm and keeps it from freezing.Fossil fuel combustion, deforestation, industrial waste disposal, global warming, pollution, and other factors are the main contributors to the greenhouse effect.What are the various Green House Gasses?Carbon dioxide, nitrous oxide, methane, water vapour, and fluorinated gases are the major Green House Gasses.Thus we can conclude that as CO₂ is a green house gas, the increase in concentration of CO₂ in the atmosphere will make the green house effect stronger.
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How many grams of KNO3, are needed to create 675.0 mL with a concentration of 1.71 M
Answer:
Бардык белгилүү авиация мыйзамдарына ылайык, аары учуу мүмкүнчүлүгү жок. Канаттары өтө эле кичинекей, семиз денесин чече албайт. Албетте, аары баары бир учат. Себеби аарылар адам мүмкүн эмес деп эсептеген нерсеге маани бербейт.
Explanation:
Канаттары өтө эле кичинекей, семиз денесин чече албайт. Албетте, аары баары бир учат. Себеби аарылар адам мүмкүн эмес деп эсептеген нерсеге маани бербейт.
If 5.0 liters of hydrogen react with excess oxygen, what mass of water would be produced?
Answer:
our equation specifies that
32
⋅
g
of dioxygen and
4
⋅
g
of dihydrogen give
36
⋅
g
of water upon reaction, so..........
Explanation:
2
H
2
(
g
)
+
O
2
(
g
)
→
2
H
2
O
(
g
)
We started with
5.0
⋅
g
32.00
⋅
g
⋅
m
o
l
−
1
=
0.156
⋅
m
o
l
dioxygen
.
Given excess dihydrogen, this molar quantity thus gives
2
×
0.156
⋅
m
o
l
water.
And thus,
2
×
0.156
⋅
m
o
l
×
18.01
⋅
g
⋅
m
o
l
−
1
≅
6
⋅
g
water are evolved. Is this reaction exothermic or endothermic?
g a 144 g metal bar requires 2500 J to change its temperature from 23.5 to 100 degree C what is the specific heat of the metal
Answer:
226.9 J·kg⁻¹·°C⁻¹
Explanation:
The specific heat of a substance can be defined as the amount is heat that has to be added in order for a given mass of the substance to increase its temperature:
c = ΔQ/(m*ΔT)In this case:
ΔQ = 2500 Jm = 144 g ⇒ 144 g / 1000 = 0.144 kgΔT = 100 - 23.5 = 76.5 °CWe input the data:
c = 2500 J / (0.144 kg * 76.5 °C)And calculate c:
c = 226.9 J·kg⁻¹·°C⁻¹Assume a substance X has a body centered cubic lattice. The edge length is 379.0 pm. The atomic mass of X is 195.0 amu What is the density of Xin g/cc
Answer:
[tex]\rho=12g/cm^3[/tex]
Explanation:
From the question we are told that:
Length[tex]l=379.0pm=>379*10^{-10}cm[/tex]
Atomic mass of X [tex]M= 195.0 amu=>gmol^{-1}[/tex]
Where
[tex]Avogadro\ constant = 6.023 * 10^{23} mol-1[/tex]
Let
The Number of units in BCC unit cell [tex]n= 2[/tex]
Generally the equation for Density is mathematically given by
[tex]\rho= \frac{M x n}{l^3*Avogadro constant}[/tex]
[tex]\rho=\frac{197 x 2}{(379*10^{-10})^3*6.023 x 10^{23}}[/tex]
[tex]\rho=12g/cm^3[/tex]
Therefore he density of Xin g/cc
[tex]\rho=12g/cm^3[/tex]
A student dissolves 9.6g of styrene in of a solvent with a density of . The student notices that the volume of the solvent does not change when the styrene dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to significant digits.
Answer:
Molarity = 0.06 mol/L
Molality = 0.063
Explanation:
Complete question
A student dissolves 1.5g of styrene C8H8 in 225.mL of a solvent with a density of 1.02/gmL . The student notices that the volume of the solvent does not change when the styrene dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to 2 significant digits
Solution
We must to know:
Molarity is equal to no. of moles divided by volume of solution
No. of moles = Mass/Molecular Mass
No. of moles of C8H8 = 1.5/104 = 0.0144
Molarity = 0.0144/225 = 0.06 mol/L
Molality = no. of moles / mass of solvent
Substituting the given values, we get -
Density = mass / V
Mass = density x V
1.02 * 225
= 229.5 g
Molality = 0.0144 / 229.5
0.063
How many moles are in 150g of Li2O?
Answer:
moles= w/mm
moles=150/30
moles=5
Which of the following has the greatest mass for one mole of the compound?
A. SIHA
B. CO
C. CH3OH
D. C2H6
The concept molar mass is used here to determine the compound which has the greatest mass for its one mole. The correct option is C.
What is molar mass?The molar mass also defined as the molecular weight of a compound is generally the sum of the atomic masses of each atoms present in the given compound. Its unit is g mol⁻¹.
The mass of 1 mole of any substance is also called the molar mass. Evidently molar mass is equal to the atomic mass or the molecular mass denoted in grams depending upon whether the substance contains atoms or molecules.
Here (SiHA) is known as the most important bioceramic which is used in the field of bioactive bone implants. The compound CO is carbon monoxide, CH₃OH is methanol and C₂H₆ is ethane.
The molar mass of the given compounds are obtained by adding their atomic masses :
CO = (12.011 g/mol+ 15.999 g/mol) = 28.01 g/mol
CH₃OH = (12.011 g/mol + 3 × 1.007 g/mol + 15.999 g/mol + 1.007 g/mol) = 32.04 g/mol
C₂H₆ = (2 × 12.011 g/mol + 6 × 1.007 g/mol) = 30.07 g/mol
Here among the given compounds CH₃OH has the greatest mass for one mole of the compound.
Thus the correct option is C - CH₃OH.
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What is the present Ba in Ba(NO3)2?
Answer:
Percentage of Ba = 52.5%
Explanation:
We'll begin by calculating the molar mass of Ba(NO3)₂. This can be obtained as follow:
Molar mass of Ba(NO3)₂ = 137 + 2[14 +(16×3)]
= 137 + 2[14 + 48]
= 137 + 2[62]
= 137 + 124
= 261 g/mol
Next, we shall determine the mass of Ba in Ba(NO3)₂. This can be obtained as follow:
Mass of Ba in Ba(NO3)₂ = 137 g/mol
Finally, we shall determine the percentage of Ba in Ba(NO3)₂. This can be obtained as follow:
Percentage of Ba = mass of Ba / mass of Ba(NO3)₂ × 100
Percentage of Ba = 137 / 261 × 100
Percentage of Ba = 13700 / 261
Percentage of Ba = 52.5%
Thus, the percentage of Ba in Ba(NO3)₂ is 52.5%
The gases in a hair spray can are at a temperature of 26.0 °C and a pressure of 25.0 lbs/in2. If the gases in the can reach a pressure of
90.0 Ibs/in?, the can will explode. To what temperature in Celsius must the gases be raised in order for the can to explode?
Answer:
The gases in a hair spray can are at a temperature of 26.0 °C and a pressure of 25.0 lbs/in2.
If the pressure becomes [tex]90.0lbs/in^{2}[/tex], what is the temperature of the gases?
Explanation:
According to Gay lussac's law:
the pressure of a gas is directly proportional to its absolute temperature.
[tex]P\alpha T[/tex]
[tex]\frac{P{1} }{T{1} }=\frac{P{2} }{T{2} }[/tex]
Given,
[tex]P1=25.0lbs/in^{2} \\P2=90.0lbs/in^{2} \\T1=26^{o} C=(26+273)K=299K\\T2=?[/tex]
Substitute these values in the above formula:
[tex]\frac{P{1} }{T{1} }=\frac{P{2} }{T{2} }\\\\\frac{25lbs/in^{2} }{299K} }=\frac{90.0lbs/in^{2} }{T{2} }\\\\\\On simplification \\T2=1076.4K\\T2=(1076.4-273)^{o} C=803.4^{o} C[/tex]
Answer:
The gases will be raised to a temperature of 803.4[tex]^{o} C[/tex].
In the reaction below does water acts as the acid or as the base?
H2S + H20 - HS1- + H30+ *
O a. Neither, water is neutral
O b. Acid
O C. Base
Answer:
C. Base.
Explanation:
Hello there!
In this case, according to the given information, it turns out convenient for us to realize that the concept acid and base we should use here is based off the Bronsted-Lowry one, which says that an acid is a hydrogen donor. In such a way, since water accepts one H ion as it goes to H3O⁺, we infer it is C. Base and the H2S the acid.
Also, we can tell HS⁻ is the conjugate base and H3O⁺ the conjugate acid.
Regards!
D‑Glucose and L‑glucose are
a. epimers.
b. enantiomers.
c. anomers.
d. diastereoisomers.
1. Which on these elements has chemical properties most similar to
those of oxygen (O)?
O Nitrogen
O carbon
O Magnesium
O Sulphur
Answer:
A
Explanation:
nitrogen has the similar properties because carbon is the opposite of oxygen
An industrial process of producing ammonia gas runs with a 74.0% yield. How many kilograms of ammonia gas will be produced in this process if theoretically 50.1 Kg can be made
Answer:
37.1 kilograms of ammonia gas will be produced in this process
Explanation:
The percentage yield of the reaction is given by:
[tex](Yield)\%=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100[/tex]
According to question
The percentage yield of the given industrial process = 74.0%
The given theoretical yield of ammonia gas = 50.1 kg
The experimental yield of ammonia gas = x
The percentage yield of the reaction is calculated a:
[tex]74.0\%=\frac{x}{50.1 kg}\times 100[/tex]
Solving for x, we get:
[tex]x = 37.074 kg\approx 37.1 kg[/tex]
37.1 kilograms of ammonia gas will be produced in this process
1.00 x 10-7 moles to grams
hetrocyclic reactions
Answer:
I am really sorry but i really don't no
How many of the planets have an orbital period of less than one Earth year?
Since orbital period depends on how far you are from the sun, planets closer to the sun have a orbital period less than one earth year.
These planets are Mercury and Venus