1-D catch-up: Two cars move with constant velocities. At t = 0, a blue car is at xBo = 20 m. After t = 4s in the blue car time frame of reference, a red car located then at xRo = 0m, within 3 seconds catches up with the blue car at xB = XR = 60 m.
Find the velocities of blue and red cars.

Answer:

For example, a wave with a time period of 2 seconds has a frequency of

1 ÷ 2 = 0.5 Hz.

Explanation:

Answer:

Process 1

Explanation:

Bees help move the pollen from flower to flower

Answer:

A

Explanation:

Sudden change in climate means there is no time to change and adapt to the new temperatures/weather conditions.

Answer:

A

Explanation: Correct on A P E X

Answer:

13kg

Explanation:

Force = Mass x Acceleration

26 = Mass x 2

divide both sides by 2

26/2 = Mass

13 = Mass

Mass is 13kg

Answer:

We conclude that the kinetic energy of a 1.75 kg ball traveling at a speed of 54 m/s is 2551.5 J.

Explanation:

Given

To determine

Kinetic Energy (K.E) = ?

We know that a body can possess energy due to its movement — Kinetic Energy.

Kinetic Energy (K.E) can be determined using the formula

[tex]K.E=\frac{1}{2}mv^2[/tex]

where

now substituting m = 1.75, and v = 54 in the formula

[tex]K.E=\frac{1}{2}mv^2[/tex]

[tex]K.E=\frac{1}{2}\left(1.75\right)\left(54\right)^2[/tex]

[tex]K.E=1458\times 1.75[/tex]

[tex]K.E=2551.5[/tex] J

Therefore, the kinetic energy of a 1.75 kg ball traveling at a speed of 54 m/s is 2551.5 J.

Answer:

See the explanation below.

Explanation:

Attached is a picture of a chocolate bar that can be easily found on the market. In this picture, we see the table of contents with the amount of energy that depends on the mass in grams of the chocolate bar.

We see that for the bar size of 100G, the energy value is 483 [kcal].

We can see that the energy depends on the size of the chocolate bar.

Answer:

403.63

Explanation:

I'm assuming you were asking for the last question on the Calorimetry gizmo.

Answer:

True

Explanation:

Answer:

dab is the answerjdjdjnejee

Answer:

the answer is b temperature

Answer:

a = 30 [m/s²]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration. In this way, we have the following equation.

∑F = m*a

where:

m = mass = 2.5 [kg]

a = acceleration [m/s²]

F = force = 75 [N]

Now replacing:

[tex]75=2.5*a\\a=75/2.5\\a=30[m/s^{2} ][/tex]

Answer:

222.2N/m

Explanation:

Given parameters:

Elastic potential energy = 4000J

Extension  = 6m

Unknown:

Spring coefficient  = ?

Solution:

The elastic potential energy is the energy stored within a string.

It is expressed as;

           EPE = [tex]\frac{1}{2}[/tex] k e²  

k is the spring constant

e is the extension

         4000  =  [tex]\frac{1}{2}[/tex] x k x 6²  

        8000  =  36k

          k  = 222.2N/m

Answer:

[tex]\boxed {\boxed {\sf v \approx 33.088 \ mL}}[/tex]

Explanation:

The formula for density is:

[tex]d= \frac{m}{v}[/tex]

where m is the mass and v is the volume.

The mass is 0.45 kilograms and the density is 13.6 grams per milliliter. The density is given in grams, so we must convert the mass.

There are 1000 grams in 1 kilogram or [tex]\frac{1000 \ g} {1 \ kg}[/tex]. We can multiply the mass by this ratio.

[tex]0.45 \ kg * \frac{1000 \ g} {1 \ kg} = 0.45 * 1000 \ g = 450 \ g[/tex]

Now we have values for the mass and density:

[tex]13.6 \ g/mL =\frac{450 \ g}{ v}[/tex]

Cross multiply.

[tex]\frac {13.6 \ g/mL}{1} =\frac{450 \ g}{ v}[/tex]

[tex]13.6 \ g/mL * v=450 \ g * 1 \\13.6 \ g/mL * v=450 \ g[/tex]

We are trying to find the volume, so we must isolate that variable.

13.6 and v are being multiplied. The inverse of multiplication is division. Divide both sides by 13.6

[tex]\frac {13.6 \ g/mL*v } { 13.6 \ g/mL} = \frac{ 450 \ g} {13.6 \ g/mL}[/tex]

[tex]v= \frac{ 450 \ g} {13.6 \ g/mL}[/tex]

The grams will cancel.

[tex]v= 33.0882353 \ mL\\v \approx 33.088 \ mL[/tex]

The volume is about 33.088 milliliters.

Answer:

0.9s

2592km/hr

Explanation:

Given parameters:

Final velocity of the bullet  = 720m/s

Distance covered  = 324m

Unknown:

Time for the bullet to strike a target = ?

Velocity in km/h

Solution:

To solve this problem, we use the kinematics equation shown below:

     S  =( [tex]\frac{v + u}{2}[/tex]) t

So;

        324  = [tex]\frac{720 + 0}{2}[/tex]  t

        324  = 360t

           t  = 0.9s

B. to convert this velocity to km/hr

       1000m  = 1km

       3600s  = 1hr

  720 x m x [tex]\frac{1}{s}[/tex]  x [tex]\frac{1km}{1000m}[/tex]  x [tex]\frac{3600s}{1hr}[/tex]    = 2592km/hr

Answer:

2.41m/s

Explanation:

Given parameters:

Initial velocity  = 1.5m/s

Acceleration  = 0.275m/s²

Distance  = 6.45m

Unknown:

Final velocity  = ?

Solution:

To solve this problem, we apply the kinematics equation below:

           v²  = u²  + 2aS

v is the final velocity

u is the initial velocity

a is the acceleration

S is the distance

         v²  = 1.5²  +  (2 x 0.275 x 6.45)  

          v  = 2.41m/s

Answer: 5km per hour

If the train is going 25km in 5 hours, you can figure out how many kilometers per hour it is traveling by dividing 25km by the 5 hours.

25/5 = 5km per hour

Explanation:

Answer:

its 60

Explanation:

it just is man

Answer: D=pg

Explanation:

?????

15 mm Hg is the guage pressure of an object with a mass of 30 kg and 5ft height.

The measurement of pressure in relation to atmospheric pressure is known as gauge pressure. The zero point for this pressure measurement is set at 1 atm. With relation to atmospheric pressure, pressure is measured.

When a car climbs a mountain, the gauge pressure rises as the air pressure falls, but the tire's absolute pressure stays the same, assuming no tire leaks.

guage pressure = mass×height

                          = 30×5

                         =15 mm Hg

Therefore, 15 mm Hg is the guage pressure of an object with a mass of 30 kg and 5ft height.

To know more about gauge pressure, here:

https://brainly.com/question/29341536

#SPJ2

Answer: 21 kg x m/s

Momentum can be found using the equation p = mv, or momentum = mass times velocity.

Therefore, to find the momentum of the bowling bowl, you can plug the mass and velocity values into the equation to get p = (7kg)(3m/s)

Solve the equation to get a momentum of 21kg x m/s

I hope I could help :)

Answer:

A sea star that has the ability to regenerate amputated limbs must first undergo a repair phase to heal the exposed wound. Once the wound is healed, the sea star can begin to generate new cells, which in turn, sparks new growth. Regeneration can take anywhere from several months to years. Reproduction: Sea stars are broadcast spawners. Males release sperm into the water and females release eggs. The fertilized eggs hatch into a larval form that lives as plankton, sometimes for months, before settling on the sea floor in its adult form..

Answer:

Second Option

Explanation:

The "hard drive" or the second option is one of the main components of storing information on a computer. You already have a hard drive built into your computer, or laptop when you buy it, and you can buy additional hard drives in the form of plugins that can store even more data if your original hard drive becomes full of data.

Hope this helps.

Answer:

B

Explanation:

Whereas memory refers to the location of short-term data, storage is the component of your computer that allows you to store and access data on a long-term basis. Usually, storage comes in the form of a solid-state drive or a hard drive.

Answer:

Hertzsprung-Russell Diagram

The Hertzsprung-Russell diagram (HR diagram) is one of the most important tools in the study of stellar evolution. Developed independently in the early 1900s by Ejnar Hertzsprung and Henry Norris Russell, it plots the temperature of stars against their luminosity (the theoretical HR diagram), or the colour of stars (or spectral type) against their absolute magnitude (the observational HR diagram, also known as a colour-magnitude diagram).

Depending on its initial mass, every star goes through specific evolutionary stages dictated by its internal structure and how it produces energy. Each of these stages corresponds to a change in the temperature and luminosity of the star, which can be seen to move to different regions on the HR diagram as it evolves. This reveals the true power of the HR diagram – astronomers can know a star’s internal structure and evolutionary stage simply by determining its position in the diagram.

Explanation:

Hence the answer is C : Super Giants

Answer/Explanation:

A timeline of atomic models

Technically, ALL of the planets do.

The effect is greatest inside Mercury, because Mercury is the one closest to the Sun.

Answer:

60kgm/s

Explanation:

Given parameters:

Mass of frisbee  = 5kg

Final speed  = 12m/s

Unknown:

Impulse of the frisbee  = ?

Solution:

The impulse of the frisbee is the same as the change in momentum.

It is given as:

 Impulse  = mass (Final velocity  -  Initial velocity)

 Impulse  = 5(12  - 0)  = 60kgm/s

Answer:

the relative density of the gravel in the field is 0.7365 or 73.65%

Explanation:

Given that;

wet density of gravel [tex]r_{b}[/tex] = 2.3 Mg/m³

field water content w = 16%

density of solids in lab [tex]r_{s}[/tex] = 2.70 Mg/m³

Maximum void ratio [tex]e_{max}[/tex] = 0.59

Minimum void ratio [tex]e_{mini}[/tex] = 0.28

first we determine the dry density of gravel  [tex]r_{d}[/tex] =  [tex]r_{b}[/tex] / 1+ w

 [tex]r_{d}[/tex] = 2.3 Mg/m³ / 1 + 0.16 = 2.3/1.16 = 1.9827 Mg/m³

we know that;  [tex]r_{w}[/tex] = 1000 kg/m³ = 1 g/cm³

Specific Gravity of soil G = [tex]r_{s}[/tex]  / [tex]r_{w}[/tex]  = 2.70 Mg/m³ / 1 = 2.70 Mg/m³  

eo = ((G×[tex]r_{w}[/tex])/[tex]r_{d}[/tex]) - 1

eo = (( 2.70 × 1) / 1.9827 ) - 1

eo = 1.3617 - 1

Co = 0.3617

so Relative density [tex]I_{D}[/tex] will be;

[tex]I_{D}[/tex] = [tex]e_{max}[/tex]  - eo  / [tex]e_{max}[/tex] - [tex]e_{mini}[/tex]

we substitute

[tex]I_{D}[/tex] = 0.59  - 0.3617 / 0.59 - 0.28

[tex]I_{D}[/tex] = 0.2283 / 0.31

[tex]I_{D}[/tex] = 0.7365 or 73.65%

Therefore;  the relative density of the gravel in the field is 0.7365 or 73.65%

[tex] \huge \boxed { \red{\bold{Aɴsᴡᴇʀ}}}[/tex]

False

perimeter is used to measure length of an object

Answer:

vs

Explanation:

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