1 If electromagnetic radiation acted like particles in the double-slit experiment, what would be observed?

a The screen would remain dark because no radiation would reach the screen.
b One bright band would appear in the center of the screen.
c A series of light and dark bands would appear on the screen.
d Two bright bands would appear on the screen in line with the slits.

2 Which statement about the interference behavior of electromagnetic radiation seen in the double-slit test experiment is true?

a Waves that make up the radiation collide with each other so that they add together or cancel each other out.
b Particles that make up the radiation collide with each other and scatter randomly.
c Particles that make up the radiation collide with each other so that they add together or cancel each other out.
d Waves that make up the radiation do not interact with each other.

3 Which statement about the observed results of the double-slit experiment is true?

a Waves that are out of phase constructively interfere to create bright bands.
b Waves that are in phase destructively interfere to create bright bands.
c Waves that are out of phase constructively interfere to create bright bands.
d Waves that are in phase constructively interfere to create bright bands.

4 Which statement about the observed results of the double-slit experiment is true?

a Waves that are in phase constructively interfere to form dark bands.
b Waves that are out of phase constructively interfere to form dark bands.
c Waves that are in phase destructively interfere to form dark bands.
d Waves that are out of phase destructively interfere to form dark bands.

5 A scientist decreases the wavelength of the light used in a double-slit experiment and keeps every other aspect the same. What will be true about the new interference pattern seen on the screen compared to the original interference pattern?

a The spacing between the dark fringes will increase.
b The spacing between the bright fringes will increase.
c The spacing between the bright fringes will decrease.
d The spacing between the dark fringes will remain the same.

6 Consider the two-slit interference experiment. Electromagnetic radiation passes through the two slits that are a distance of 0.0170 nm apart. A fourth-order bright fringe forms at an angle of 8.0 degrees relative to the incident beam. What is the wavelength of the light?

a 789 nm
b 420 nm
c 581 nm
d 591 nm

Answer:

So where's the problem now?

A kitten is just sitting

Answer:

the distance between two consecutive crests or troughs

Answer:

44°

Explanation:

Look for the longest distance under the 'Distance ' column....look to the left to find the corresponding angle

  Table clearly shows that the longest distance (133 ft) occurs at angle of 44°

Answer:

a parachute falling to the ground is uniform

Hi there!

We can use the angular equivalent of the following kinematic equation:

[tex]\omega_f^2 = \omega_i^2 + 2\alpha \theta[/tex]

ωf = final angular velocity (1.9 rad/s)

ωi = initial angular velocity (11.3 rad/s)

α = angular acceleration (? rad/s²)

θ = angular displacement (17.95 rad)

We can rearrange the equation to solve for angular acceleration.

[tex]\omega_f^2 - \omega_i^2 = 2\alpha \theta\\\\\alpha = \frac{\omega_f^2 - \omega_i^2}{2\theta}[/tex]

Plug in the given values and solve.

[tex]\alpha = \frac{1.9^2 - 11.3^2}{2(17.95)} = \boxed{3.456 \frac{rad}{s}}[/tex]

Answer:

22583.5J

Explanation:

KE=1/2 mv^2

=1/2*47Kg*(31m/s^2)

=23.5Kg * 961m/s^2

=22583.5J

A likely source of bias in the survey is undercoverage bias because some parts of the community may not be represented in the survey results.

The bias present in the survey may lead to error in the result obtained from the random sampling survey.

One of the likely source of bias in the survey is undercoverage.

It is not possible to ascertain the accurate opinion of the entire community from the 50 residents chosen for the survey.

Thus, a likely source of bias present in survey is undercoverage bias because some parts of the community may not be represented in the survey results.

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Answer:

B. Question wording bias may be present because the question leads those responding toward a certain response.

Explanation:

Answer:

42

Explanation:

P = M × V

so

P = 35 × 1.2

P = 42

Answer:

42kg•m/s

Explanation:

p=m*v

Answer:

i think its 100

Explanation:

For a rock is suspended from the lower end of a light string,  the weight of the rock is mathematically given as

W = 3.10 N

Generally, the equation for the W = Fh1+  is mathematically given as

W = Fh+T1

Where

PiVg+T1 = P2V9+T

(1000) V(9.8) + 1.2 = (790) V(9.8) + 1.6

V = 1.944* 10^-4 m3

In conclusion

W = Fh+T1

W = (1000) (1.944 * 10-4) (9.8) + 1.2

W = 3.10 N

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Answer:

0.73kg

Explanation:

Potential gravitational energy is equal to [tex]Pe=mgh[/tex], where Pe is potential gravitational energy, m is mass in kilograms, g is gravity in m/s^2 and h is height in meters.

Substitute:

[tex]Pe=mgh\\23=m*9.8*3.2\\23=31.36m\\0.73=m[/tex]

Hi there!

Recall the following relationship between the electric field and electrical potential:
[tex]E = -\frac{dV}{dx}[/tex]

Begin by taking the derivative of the electric potential function using basic power and constant rules.

Remember:
[tex]\frac{dy}{dx}x^n = nx^{n - 1}[/tex]

[tex]\frac{dy}{dx}(C) = 0[/tex]

Differentiate the function, and take its negative.

[tex]-\frac{dV}{dx} = -(2(1)(x^{1-1}) + 0 )\\\\-\frac{dV}{dx} = -2[/tex]

The magnitude is the absolute value, so:
[tex]|\frac{dV}{dx} = |-2| = \boxed{2 \frac{V}{m}}[/tex]

First normal transportation is the light energy of sun is transmitted to our earth .

Next for transportation inside sun they are

Fusion means when two hydrogen atoms reacts to form helium nucleus .

Fission means when one nucleus is broken into two or more nucleus

Explanation:

#Make_the smartest_answer

#sorry_if_wrong

#I hope this helps

#follow_and_like_me

#No copas

#Thank_you_for_watching

么•ᴮᴬᴰʙᵒʏツ

ॐhน໓ค • ๓นhค๓๓ค໓ঔৣ

ॐŞiŞ¢ค • วนคriคঔৣ

Answer:

1/8 = (1/2)^3

This implies the sample has decayed for 3 half lives

3 * 5730 yrs = 17,200 years

Answer:

P = VI

Explanation:

the power is equal to the current × voltage

Answer:

P = V • I

Explanation:

Power = Voltage • Current

Condense x₁ to get

sin(2πt) + cos(2πt) = √2 • (sin(2πt) + cos(2πt))/√2

… = √2 (cos(2πt) cos(π/4) + sin(2πt) sin(π/4))

… = √2 cos(2πt - π/4)

So the amplitude of x₁ is (5/2) • √2 = 5/√2, while the amplitude of x₂ is 5. The ratio between them is then 5/√2 : 5, or equivalently 1/√2 : 1 or 1 : √2.

Answer:

Breaststroke can be divided up into 4 distinct phases, which consists of the out sweep, in sweep, breathing phase, and lunge, extension, or recovery phase.

Explanation:

pa follow po

Answer:

Explanation:

When the balls meets, the time should be the same, let say t.

For the first ball (released from a loom):

[tex]\bar{h}=\frac{1}{2}gt^{2}[/tex] (Free fall motion) ([tex]\bar{h}[/tex] = the distance travelled by the first ball, measured from the loom)

So, we can find that [tex]\bar{h}=\frac{1}{2}(10t^{2})=5t^{2}[/tex]

For the second ball (which is thrown directly upwards):

[tex]y=v_{o}t-\frac{1}{2}gt^{2} = 25t-5t^{2}[/tex]

Because the height of the loom is h :

[tex]h=\bar{h}+y[/tex]

[tex]h=25t[/tex]

So, the time when two balls meets is : [tex]t=\frac{h}{5}[/tex] (In this question, the height of the loom h is not declared). When the height of the loom is known, you can calculate the time and the value of [tex]\bar{h}[/tex] or y

For a total charge of Q coulomb is uniformly distributed along a rod 40cm in length,  the electric field intensity 20cm away from the rod is mathematically given as

E1=1.598*10^11v/m

Generally, the equation for the  initial electric field intensity   is mathematically given as

[tex]dEp=\int{kd/r}cosd\theta[/tex]

Therefore

[tex]e1=kd/r{sin\theta2+sinR1}[/tex]

Hence

[tex]E1=(9*10^9/20*10^{-2})({sin45+sin45})*B/40*10^-2[/tex]

E1=B*9*10^{13})/(10*110)*[tex]\sqrt{2}[/tex]

E1=1.598*10^11v/m

In conclusion, the electric field intensity

E1=1.598*10^11v/m

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Answer:

I think that CL IS THE ONLY BEST ANSWER

Explanation:

PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT PLEASE

Answer:

Explanation:

weather pattern

A pattern of weather over three months is called a climate.

Climate is the long-term pattern of weather in a particular area. Weather can change from hour-to-hour, day-to-day, month-to-month or even year-to-year. A region's weather patterns, usually tracked for at least 30 years, are considered its climate.

Weather refers to short-term changes in the atmosphere, climate describes what the weather is like over a long period of time in a specific area.

A pattern of weather over three months is called a climate.

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coefficient of static friction is 1.7329

Explanation:

given data

velocity = 60 mph

acceleration  = 17 m/s²

to find out

coefficient of static friction

solution

we will apply here centripetal force equation

that is

m×v²/r  =  µ × m × g      ..................1

here v²/r is centripetal acceleration and m is mass and  µ  is coefficient static friction so

µ = a / g

µ = 17 / 9.81

µ  = 1.7329

so coefficient of static friction is 1.7329

The power delivered to the truck of mass 1000 kg that was lifted by a garage hoist, 2 m high above the ground in 15 seconds is 1308 W.

Power can be deifned as the rate at which work is done.

To calculate the power delivered to the truck, we use the formula below.

Formula:

Where:

From the question,

Given:

Subsitute these values into equation 1

Hence, The power delivered to the truck of mass 1000 kg that was lifted by a garage hoist, 2 m high above the ground in 15 seconds is 1308 W.

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Hi ! I will help you to discuss about Proportionally Changes in Circular Motion. The analogy of proportionally changes in circular motion is same as the analogy of proportionally changes in direct motion. Here you will hear again the terms acceleration and change in speed, only expressed in the form of a certain angle coverage. Before that, in circular motion, it is necessary to know the following conditions:

The following equations apply to proportionally changes circular motion:

[tex] \boxed{\sf{\bold{\omega_t = \omega_0 + \alpha \times t}}}[/tex]

With the following conditions:

[tex] \boxed{\sf{\bold{\theta = \omega_0 \times t + \frac{1}{2} \times \alpha \times t^2}}}[/tex]

Or

[tex] \boxed{\sf{\bold{(\omega_t)^2= (\omega_0)^2 + 2 \times \alpha \times \theta}}}[/tex]

With the following condition :

We know that :

What was asked :

Step by step :

[tex] \sf{(\omega_t)^2= (\omega_0)^2 + 2 \times \alpha \times \theta} [/tex]

[tex] \sf{0^2= (11)^2 + 2 \times \alpha \times 80} [/tex]

[tex] \sf{0 = 121 + 160 \alpha} [/tex]

[tex] \sf{-160 \alpha = 121} [/tex]

[tex] \sf{\alpha = \frac{121}{-160}}[/tex]

[tex] \sf{\alpha = -0.75625 \: rad/s^2 \approx \boxed{-0.76 \: rad/s^2}}[/tex]

[tex] \sf{\alpha = \frac{\omega_0 - \omega_t}{t}}[/tex]

[tex] \sf{-0.76 = \frac{0 - 11}{t}}[/tex]

[tex] \sf{-0.76t = -11}[/tex]

[tex] \sf{t = \frac{- 11}{-0.76}}[/tex]

[tex] \boxed{\sf{t \approx 14.474 \: s}}[/tex]

So :

Answer:

180 m amp

Explanation:

V = IR

v/r = i     mutiply both sides by

3

3v / r = 3 i     so the current will triple to 180 mAmp

Based on Hooke's law, the spring constant of the the body's muscle mechanism is the ratio of force to extension, the effective mass is m/3 and the potential energy that can be stored is ke^2 / 2.

The spring constant or stiffness constant of an elastic spring is constant which describes the extent a bit forceapplied to an elastic spring will extend it.

Assuming, a body's muscle mechanism is a spring obeying Hooke's law, the effective mass of the spring with mass m is 1/3 of the mass of the spring = m/3

The potential energy that can be stored = ke^2 / 2

where K is spring constant and e is the extension produced.

Therefore, the spring constant of the the body's muscle mechanism is the ratio of force to extension, the effective mass is m/3 and the potential energy that can be stored is ke^2 / 2.

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Answer:

Energy = mcΔt

where m the mass ,  c specific heat capacity

Δt is the change in temperature

1200x10^3=75x4184xΔt

Δt=3.82°

Explanation:

Answer:

legal guardians, the four types: personal guardians, financial guardians, conservators, and pet “guardians”