Answer:
Answer: (0.4356,0.4844)
Step-by-step explanation:
Use Ti 84
use function "1-PropZInt".
Enter x = 736
n = 1600
c= 0.95
Answer: (0.4356,0.4844)
a city grid of Anytown, USA is shown on the grid below the fire department is represented by the quadrilateral RSTU. Another fire department is opening in a different part of the city to maximize fire protection. The size of the new department's property must be congruent to the older department. Vertices A and B are plotted on the grid below to represent two vertices of the new?fire Department quadrilateral ABCD:
What could be the ordered pairs of representing vertices C and D of quadrilateral ABCD so that the new fire department to congruent to the old fire department?
Answer:
C(1, 1)D(4, 1)Step-by-step explanation:
The fire department property is 2 units in height. 2 units from the line y=3 can be on the line y=5, or on the line y=1.
There are no answer choices with y=5, so the appropriate choices are those with C and D having the x-coordinates of B and A, respectively, and y=1.
C(1, 1), D(4, 1)
A respiratory therapist predicts that the proportion of U.S. college students who smoke hookah is greater than 30%. To test this prediction, she surveys 300 random U.S. college, and it is determined that 80 of them smoke hookah. The following is the setup for this hypothesis test: H0:p=0.30 H0:p>0.30 The p-value for this hypothesis test is 0.10. At the 5% significance level, should she reject or fail to reject the null hypothesis? Select the correct answer below: Reject the null hypothesis because 0.30>0.05. Fail to reject the null hypothesis because 0.30>0.05. Reject the null hypothesis because the p-value =0.10 is less than the significance level α=0.05. Fail to reject the null hypothesis because the p-value =0.10 is more than the significance level α=0.05.
Answer:
Fail to reject the null hypothesis because the p-value =0.10 is more than the significance level α=0.05.
Step-by-step explanation:
The significant level for this case study is 5% - 0.05. If the results gotten is less than the significance level, we reject the null hypothesis, but if greater, we fail to reject the null hypothesis.
In this case study, the p-value is 0.10 which is a lot higher than 0.05, thus we will fail to reject the null hypothesis because the p-value =0.10 is more than the significance level α=0.05.
A new fertilizer was applied to the soil of 146 bean plants. 23% showed increased growth. Find the margin of error and 95% confidence interval for the percentage of all bean plants which show increased growth after application of the fertilizer. Round all answers to 2 decimal places.
Answer:
The significance level for this case would be [tex]\alpha=1-0.95=0.05[/tex] and the critical value for this case would be:
[tex] z_{\alpha/2}=1.96[/tex]
The margin of error is given by:
[tex] ME = z_{\alpha/2} \sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]
And replacing we got:
[tex] ME = 1.96 \sqrt{\frac{0.23*(1-0.23)}{146}} =0.0683[/tex]
And the margin of error for this case would be [tex] ME = 0.07[/tex]
Step-by-step explanation:
For this case we have the following dataset given:
[tex] n= 146[/tex] represent the sample size
[tex] \hat p =0.23[/tex] represent the estimated proportion of interest
[tex] Conf=0.95[/tex] represent the confidence level
The significance level for this case would be [tex]\alpha=1-0.95=0.05[/tex] and the critical value for this case would be:
[tex] z_{\alpha/2}=1.96[/tex]
The margin of error is given by:
[tex] ME = z_{\alpha/2} \sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]
And replacing we got:
[tex] ME = 1.96 \sqrt{\frac{0.23*(1-0.23)}{146}} =0.0683[/tex]
And the margin of error for this case would be [tex] ME = 0.07[/tex]
Suppose that vehicles taking a particular freeway exit can turn right (R), turn left (L), or go straight (S). Consider observing the direction for each of three successive vehicles.
A) List all outcomes in the event A that all three vehicles go in the same direction.
B) List all outcomes in the event B that all three vehicles take different directions.C) List all outcomes in the event C that exactly two of the three vehicles turn right.D) List all outcomes in the event D that exactly two vehicles go in the same direction.E) List outcomes in D'.F) List outcomes in C ∪ D.G) List outcomes in C ∩ D.
Answer:
A) A = {RRR, LLL, SSS}
B) B = {LRS. LSR, RLS, RSL, SLR, SRL}
C) C = {RRL, RRS, RSR, RLR, LRR, SRR}
D) D = {RRL, RRS, RSR, RLR, LRR, SRR. LLR, LLS, LSL, LRL, RLL, SLL, SSL, SSR, SLS, SRS, LSS, RSS}
E) D' ={RRR, LLL, SSS, LRS. LSR, RLS, RSL, SLR, SRL}
F) C ∪ D = {RRL, RRS, RSR, RLR, LRR, SRR. LLR, LLS, LSL, LRL, RLL, SLL, SSL, SSR, SLS, SRS, LSS, RSS}
G) C ∩ D = {RRL, RRS, RSR, RLR, LRR, SRR}
Step-by-step explanation:
A) All vehicles must go right, left or straight ahead (three possibilities):
A = {RRR, LLL, SSS}
B) One vehicle must go right, one must go left, and the remaining one must go straight ahead (six possibilities):
B = {LRS. LSR, RLS, RSL, SLR, SRL}
C) There are three ways that exactly two vehicles go right (1 and 3, 2 and 3, 1 and 2), there are then two options for the remaining vehicle (left and straight) for a total of six possibilities:
C = {RRL, RRS, RSR, RLR, LRR, SRR}
D) Follow the same reasoning from the previous item, but multiply the number of possibilities by 3 (for each direction in which both cars can go: right, left or straight):
D = {RRL, RRS, RSR, RLR, LRR, SRR. LLR, LLS, LSL, LRL, RLL, SLL, SSL, SSR, SLS, SRS, LSS, RSS}
E) D' is the set containing all possibilities not present in set D. D' is comprised by the possibilities of all vehicles going in the same direction, or each vehicle in a different direction:
D' ={RRR, LLL, SSS, LRS. LSR, RLS, RSL, SLR, SRL}
F) The outcomes in C ∪ D is the union of elements from set C and D (neglecting repeated values), which happens to be all values in set D.
C ∪ D = {RRL, RRS, RSR, RLR, LRR, SRR. LLR, LLS, LSL, LRL, RLL, SLL, SSL, SSR, SLS, SRS, LSS, RSS}
G) The outcomes in C ∩ D is the list of values present in both sets C and D, which happens to be all values in set C:
C ∩ D = {RRL, RRS, RSR, RLR, LRR, SRR}
Solve the following system by substitution.
y = - 3x + 11
5x + y = 21
Answer:
x = 5 and y = -4
Step-by-step explanation:
y = - 3x + 11 ______(1)
5x + y = 21______(2)
Substitute (1) into (2).
5x + (-3x + 11) = 21
5x - 3x + 11 = 21
2x = 21-11
2x = 10
x = 10/2
x = 5
Now substitute x = 5 into (1).
y = -3(5) + 11
y = -15 + 11
y = -4
Hence, x = 5 and y = -4
What is the horizontal asymptote of the function f (x) = StartFraction (x minus 2) Over (x minus 3) squared EndFraction?
The horizontal asymptote of the function f(x) = (x-2)/(x-3)² is at y = 0 which is the x-axis.
What is an asymptote?An asymptote is a line that is approached by a curve but never touches it. In other words, an asymptote is a line where the graph of a function converges.
What is the horizontal asymptote?Because a horizontal asymptote is a horizontal line, its equation is of the form y = k. The horizontal asymptote of a rational function is at y = 0, which is the x-axis if the degree of the numerator is smaller than the degree of the denominator.
How to solve this problem?Here, the function is f(x) = (x-2)/(x-3)². Here the degree of the numerator of this rational function is 1 and the degree of the denominator is 2. Since 1<2, the horizontal asymptote is at y = 0 which is the x-axis.
The horizontal asymptote of the function f(x) = (x-2)/(x-3)² is at y = 0 which is the x-axis.
Learn more about horizontal asymptotes here -
https://brainly.com/question/14357352
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Answer:
c
Step-by-step explanation:
Applying the Segment Addition Postulate
Point B lies between points A and C on AC. Let x
represent the length of segment AB in inches.
A
B
3x
Use the segment to complete the statements.
The value of x is v.
The length of AR in inches is
✓x
C
The length of BC in inches is
20 inches
Intro
Answer:
x = 5, AB=5, BC = 15
Step-by-step explanation:
AC = AB + BC (Segment Addition)
AC= 20, AB =x Bc = 3x,
20= x+3x 20=4x
x=5
AB=x, AB =5
BC=3x BC= 15
The segment addition postulate states gives the value of x as 5, given
that the sum of x and 3·x is 20.
Responses:
The value of x is 5The length of [tex]\overline{AB}[/tex] is 5 inchesThe length of [tex]\overline{BC}[/tex] is 15 inchesHow does segment addition postulate give the value of x?From the given diagram, we have;
[tex]\overline{AB}[/tex] = x
[tex]\overline{BC}[/tex] = 3·x
According to segment addition postulate we have;
[tex]\overline{AB}[/tex] + [tex]\overline{BC}[/tex] = [tex]\overline{AC}[/tex] = 20 inches
Which gives;
x + 3·x = 20
Therefore;
4·x = 20
[tex]x = \dfrac{20}{4} = 5[/tex]
The value of x is 5The length of [tex]\overline{AB}[/tex] is 5 inches[tex]\mathbf{\overline{BC}}[/tex] = 3·x
[tex]\mathbf{\overline{BC}}[/tex] = 3 × 5 = 15
The length of [tex]\overline{BC}[/tex] is 15 inchesLearn more about segment addition postulate here:
https://brainly.com/question/1397818
find the local and/or absolute extrema for the function over the specified domain. (Order your answers from smallest to largest x.) f(x)
Answer:
Minimum 8 at x=0, Maximum value: 24 at x=4
Step-by-step explanation:
Retrieving data from the original question:
[tex]f(x)=x^{2}+8\:over\:[-1,4][/tex]
1) Calculating the first derivative
[tex]f'(x)=2x[/tex]
2) Now, let's work to find the critical points
Set this
[tex]2x=0\\x=0[/tex]
0, belongs to the interval. Plug it in the original function
[tex]f(0)=(0)^2+8\\f(0)=8[/tex]
3) Making a table x, f(x) then compare
x| f(x)
-1 | f(-1)=9
0 | f(0)=8 Minimum
4 | f(4)=24 Maximum
4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.
A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 290 babies were born, and 261 of them were girls. Use the sample data to construct a 99% confidence interval estimate of the percentage of girls born. Based on the result, does the method appear to be effective?
Answer:
The 99% confidence interval estimate of the percentage of girls born is between 85.46% and 94.54%.
Usually, babies are equally as likely to be boys or girls. Here, it is desired to increase the probability of conceiving a girl, which is achieved, considering the lower bound of the confidence interval is considerably above 50%.
Step-by-step explanation:
Confidence interval for the proportion:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].
For this problem, we have that:
[tex]n = 290, \pi = \frac{261}{290} = 0.9[/tex]
99% confidence level
So [tex]\alpha = 0.01[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.01}{2} = 0.995[/tex], so [tex]Z = 2.575[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.9 - 2.575\sqrt{\frac{0.9*0.1}{290}} = 0.8546[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.9 + 2.575\sqrt{\frac{0.9*0.1}{290}} = 0.9454[/tex]
Percentage:
Proportion multplied by 100.
0.8546*100 = 85.46%
0.9454*100 = 94.54%
The 99% confidence interval estimate of the percentage of girls born is between 85.46% and 94.54%.
Based on the result, does the method appear to be effective?
Usually, babies are equally as likely to be boys or girls. Here, it is desired to increase the probability of conceiving a girl, which is achieved, considering the lower bound of the confidence interval is considerably above 50%.
Find the surface area of this composite solid.
Answer:
B
Step-by-step explanation:
area of top on triangle=1/2×4×3=6m²
area of four top triangles=6×4=24 m²
area of bottom square=4×4=16 m²
area of four side rectangles=4×(4×5)=80 m²
Total area= 24+16+80=120m²
Please help me the venn diagram is wrong too im confused on how to do this :(((
Answer:
probability of chosing a student that has a cat and a dog is 9/25
Step-by-step explanation:
And yes the Venn diagram is wrong because you forgot to subtract 9 from 15 and 16
This makes it
[ 3 ( 6 ( 9 ) 7 ) ]
3 + 6 + 9 + 7 = 25
If a varies inversely with b, and a=12 when b=1/3, find the equation that relates a and b
Answer:
a = 4 /b
or ab = 4
Step-by-step explanation:
An inverse relation is given by
a = k/b where k is the constant
Rewriting
ab = k
12 * 1/3 = k
4 = k
a = 4 /b
or ab = 4
Find a formula for the general term an of the sequence, assuming that the pattern of the first few terms continues. (Assume that n begins with 1.) −3, 2, − 4 3 , 8 9 , − 16 27 , ...
Answer:
The general term is
Sn = -(-2)ⁿ.3¹⁻ⁿ
step by step Explanation:
we were told to find a general term of the above sequence, what should come to mind is that the terms will follow an order....
CHECK THE ATTACHMENT FOR DETAILED EXPLANATION
Suppose that the function g is defined, for all real numbers, as follows.
Pls help me help me
Answer:
C.
Step-by-step explanation:
When two lines are parallel, their slopes are the same.
Since the slope of line l is 2/7, the slope of its parallel line m must also be 2/7.
The answer is C.
Answer:
C. 2/7
Step-by-step explanation:
Parallel lines are lines that have the same slopes.
We know that line l is parallel to line m.
Therefore, the slope of line l is equal to the slope of line m.
[tex]m_{l} =m_{m}[/tex]
We know that line l has a slope of 2/7.
[tex]\frac{2}{7} =m_{m}[/tex]
So, line m also has a slope of 2/7. The answer is C. 2/7
Compute the critical value z Subscript alpha divided by 2 that corresponds to a 86% level of confidence.
Answer:
z = 1.476
Step-by-step explanation:
We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1-0.86}{2} = 0.07[/tex]
Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].
So it is z with a pvalue of [tex]1-0.07 = 0.93[/tex], so [tex]z = 1.476[/tex]
The answer is z = 1.476
Is 47 a prime number or composite?
Answer:
Prime number
Step-by-step explanation:
A prime number has 2 factors.
A composite number has more than 2 factors.
47 has the factors 1 and 47.
47 is a prime number.
Answer:
47 is prime.
Step-by-step explanation:
Its factors are 1 and 47.
If a number has only 2 factors, then it's prime.
15 3/4 is what decimal
━━━━━━━☆☆━━━━━━━
▹ Answer
15.75
▹ Step-by-Step Explanation
3 ÷ 4 = .75
15 + .75 = 15.75
Hope this helps!
- CloutAnswers ❁
Brainliest is greatly appreciated!
━━━━━━━☆☆━━━━━━━
A school is 16km due west of a school q.
What is the bearing of q from p?
Answer:
16 km due west
Step-by-step explanation:
The bearing of the school p from school q is 16 km due west.
To find the bearing of school q from school p, we have to find the direction that the school q is with respect to school p.
Since p is directly west of q, then it implies that q must be directly east of p.
We now know the direction.
Since the distance from q to p is exactly the same as the distance from p to q, then, the distance from p to q is 16 km.
Hence, the bearing of q from p is 16 km due west.
What is the equation of the line that is parallel to the given line and passes through the point (12, -2)? A) y = -6/5x + 10 B) y= -6/5x + 12 C) y = -5/6x -10 D) y = 5/6x - 12
Answer:
D
Step-by-step explanation:
Parallel lines are those that have the same slope, or coefficient of x.
Here, let's calculate the slope of the given line. Slope is the difference in the y-coordinates divided by the difference in the x-coordinates, so given the two coordinates (12, 6) and (0, -4):
slope = m = (-4 - 6) / (0 - 12) = -10 / (-12) = 10/12 = 5/6
So the slope is 5/6. That means the equation we want should also have a slope of 5/6. Already, we can eliminate A, B, and C, leaving D as our answer. But, let's check.
The equation of a line can be written as [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1,y_1)[/tex] is the coordinates of a given point.
Here, our slope is 5/6 and our given point is (12, -2). So plug these in:
[tex]y-y_1=m(x-x_1)[/tex]
[tex]y-(-2)=(5/6)(x-12)[/tex]
[tex]y+2=\frac{5}{6} x-10[/tex]
[tex]y=\frac{5}{6} x-12[/tex]
This matches D, so we know that it's the correct answer.
~ an aesthetics lover
The answer is D I just took the test
Average rate of change from G from x=1 to x=4 is
Answer:
3
Step-by-step explanation:
minus the variable, 4-1 is 3.
I NEED HELP PLEASE, THANKS! :)
Write 18(cos169° + isin169°) in rectangular form. Round numerical entries in the answer to two decimal places. (Show work)
Answer:
z = -17.67 + i3.43
Step-by-step explanation:
Let us apply the formula z = r(cos Ф + i sin Ф), given 18(cos169° + isin169°) -
z = 18( cos169 + isin169 ),
z = r(cos Ф + i sin Ф)
Now we can solve this question in the form z = a + bi, in this case where a = 18 cos169, and b = 18 sin169. This is as a = r cos Ф and b = r sin Ф -
sin169 is positive, while cos169 is negative, thus -
a = -17.6692893021...,
b = 3.43456191678...
Rectangular Form, z = -17.67 + i3.43
Hope that helps!
06:Pretest 06:Quadrilaterals
27. Which statement is true?
O All squares are quadrilaterals,
O All quadrilaterals are parallelograms,
All rectangles are squares,
O All quadrilaterals are squares,
Answer:
all squares are quadrilaterals
Someone pls help me
The slope greater than one would be the last image, because for every step in x, you get more than one y step.
The slope between 1 and 0 would be the second image
And the slope less than 0 would be the third image
g Steel used for water pipelines is often coated on the inside with cement mortar to prevent corrosion. In a study of the mortar coatings of the pipeline used in a water transmission project in California, researchers noted that the mortar thickness was specified to be 7/16 inch. A very large sample of thickness measurements produced a mean equal to 0.635 inch and astandard deviation equal to 0.082 inch. If the thickness measurements were normally distributed, approximately what proportion were less than 7/16 inch?
Answer:
[tex]P(X<0.4375)=P(\frac{X-\mu}{\sigma}<\frac{0.4375-\mu}{\sigma})=P(Z<\frac{0.4375-0.635}{0.082})=P(z<-2.41)[/tex]
And we can find this probability using the z table and we got:
[tex]P(z<-2.41)=0.0080[/tex]
Step-by-step explanation:
Let X the random variable that represent the thickness of a population, and for this case we know the distribution for X is given by:
[tex]X \sim N(0.635,0.082)[/tex]
Where [tex]\mu=0.635[/tex] and [tex]\sigma=0.032[/tex]
We are interested on this probability
[tex]P(X<0.4375)[/tex]
And the best way to solve this problem is using the normal standard distribution and the z score given by:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
If we apply this formula to our probability we got this:
[tex]P(X<0.4375)=P(\frac{X-\mu}{\sigma}<\frac{0.4375-\mu}{\sigma})=P(Z<\frac{0.4375-0.635}{0.082})=P(z<-2.41)[/tex]
And we can find this probability using the z table and we got:
[tex]P(z<-2.41)=0.0080[/tex]
the bus fare in a city is $2.00. people who use the bus have the option of purchashing a monthly coupoun book is $20.00. with the copoun bok, the fare is reduced to $1.00 Determine the number of times in a month the bus be used so that the total monthly cost without the coupon book is the same as the total monthly cost with the coupon book
Answer:
but I can do it if you want but I don't you too too y u your help and you have time can you
Step-by-step explanation:
guy who was it that you are not going to be able to make it to the meeting tonight but I can tomorrow if you have time can you come to my house
Lisa is in charge of planning a reception for 3600 people. She is trying to decide which snacks to buy. She has asked a random sample of people who are coming to the reception what their favorite snack is. Here are the results.
Favorite Snack Number of People
Brownies 32
Cookies 22
chips 56
other 65
Based on the above sample, predict the number of the people at the reception whose favorite snack will be chips. Round your answer to the nearest whole number. Do not round any intermediate calculations.
Answer:
The expected number of the people at the reception whose favorite snack will be chips is 1152
Step-by-step explanation:
Given
The data in the above table and
Reception = 3600
Required
Predict the number of the people at the reception whose favorite snack will be chips.
The first step is to determine the total number of samples;
[tex]Total = Brownies + Cookies + Chips + Other[/tex]
[tex]Total = 32 + 22 + 56 + 65[/tex]
[tex]Total = 175[/tex]
The next step is to determine the fraction of people whose favorite is chips
[tex]Fraction = \frac{Chips}{Total}[/tex]
[tex]Fraction = \frac{56}{175}[/tex]
The product of the above fraction and the expected number of people in the reception is the solution to this question;
[tex]Expected\ Number = \frac{56}{175} * 3600[/tex]
[tex]Expected\ Number = \frac{56* 3600}{175}[/tex]
[tex]Expected\ Number = \frac{201600}{175}[/tex]
[tex]Expected\ Number = 1152[/tex]
Hence, the expected number of the people at the reception whose favorite snack will be chips is 1152
A chemist wishes to test the effect of four chemical agents on the strength of a particular type of cloth. Because there might be variability from one bolt to another, the chemist decides to use a randomized block design, with the bolts of cloth considered as blocks. She selects five bolts and applies all four chemicals in random order to each bolt. The resulting tensile strengths follow. Analyze the data from this experiment (use α = 0.05) and draw appropriate conclusions.
Bolt
Chemical 1 2 3 4 5
1 73 68 73 71 67
2 73 67 75 72 70
3 75 68 78 73 68
4 73 71 75 75 69
Answer:
p > α
0.7038 > 0.05
Also since F < F critical
0.475 < 3.238
We failed to reject H₀
We do not have significant evidence at the given significance level to show that there is a difference among the four chemical agents on the strength of a particular type of cloth.
Step-by-step explanation:
We are given that a chemist wishes to test the effect of four chemical agents on the strength of a particular type of cloth.
Since we are given data for four independent chemical agents to determine the effect on the strength of a particular type of cloth, therefore, a one-way analysis of variance may be used for the given problem.
ANOVA:
The one-way analysis of variance (ANOVA) may be used to find out whether there is any significant difference between the means of two or more independent categories of data.
Set up hypotheses:
Null hypotheses = H₀: μ₁ = μ₂ = μ₃ = μ₄
Alternate hypotheses = H₁: μ₁ ≠ μ₂ ≠ μ₃ ≠ μ₄
Set up decision rule:
We Reject H₀ if p ≤ α
OR
We Reject H₀ if F > F critical
ANOVA in Excel:
Step 1:
In the data tab, select data analysis
Step 2:
Select "Anova single factor" from the analysis tools
Step 3:
Select the destination of input data in the "input range"
Step 4:
Select "rows" for the option "Group By"
Step 5:
Tick the option "labels in first row"
Step 6:
Set alpha = 0.05
Step 7:
Select the destination of output data in the "output options"
Conclusion:
Please refer to the attached results.
The p-value is found to be
p = 0.7038
The F value is found to be
F = 0.475
The F critical value is found to be
F critical = 3.238
Since p > α
0.7038 > 0.05
We failed to reject H₀
Also since F < F critical
0.475 < 3.238
We failed to reject H₀
We do not have significant evidence at the given significance level to show that there is a difference among the four chemical agents on the strength of a particular type of cloth.
Please help ?!!! Solve the three equations in the table using any method of your choice. List the method you used.
Equation
x^2-4=-12
-9x^2+4x-10=0
x^2+8x=-17
With solutions and method
Step-by-step explanation:
[tex]x = \frac{ - b \frac{ + }{ - } \sqrt{ {b}^{2} - 4ac } }{2a} [/tex]
The quadratic formula is honestly the most straightforward way of solving here.
Your other options are completing the square (which is the same thing as the quadratic formula but it's good to know that method if you have to take Integral Calculus at some point) or maybe factoring by grouping if it's appropriate. But the quadratic formula will work for you in all three equations:
1) a=1, b=0, c=8
This reduces pretty quickly into x=8i,-8i due to the negative under the radical. (Actually we didn't even really need the formula here.)
2) a=-9, b=4, c=-10
This reduces into x=(-4+i√(344))/-18, (-4-i√(344))/-18 and doesn't go any further because 344 isn't a perfect square.
3) a=1, b=8, c=17
This reduces to x=(-4+i), (-4-i)
So those are the answers for each.
Please Refer to the screenshot. Hope this helps!
g red bell pepper seeds germinates 85% of the time. planted 25 seeds. What is the probability that 20 or more germinate
Answer:
[tex] P(X\geq 20)= P(X=20)+P(X=21)+P(X=22)+P(X=23)+P(X=24)+P(X=25)[/tex]
And replacing using the mass function we got:
[tex]P(X=20)=(25C20)(0.85)^{20} (1-0.85)^{25-20}=0.156[/tex]
[tex]P(X=21)=(25C21)(0.85)^{21} (1-0.85)^{25-21}=0.211[/tex]
[tex]P(X=22)=(25C22)(0.85)^{22} (1-0.85)^{25-22}=0.217[/tex]
[tex]P(X=23)=(25C23)(0.85)^{23} (1-0.85)^{25-23}=0.161[/tex]
[tex]P(X=24)=(25C24)(0.85)^{24} (1-0.85)^{25-24}=0.0759[/tex]
[tex]P(X=25)=(25C25)(0.85)^{25} (1-0.85)^{25-25}=0.0172[/tex]
And adding the values we got:
[tex] P(X\geq 20) = 0.8381[/tex]
Step-by-step explanation:
Let X the random variable of interest, on this case we now that:
[tex]X \sim Binom(n=25, p=0.85)[/tex]
The probability mass function for the Binomial distribution is given as:
[tex]P(X)=(nCx)(p)^x (1-p)^{n-x}[/tex]
Where (nCx) means combinatory and it's given by this formula:
[tex]nCx=\frac{n!}{(n-x)! x!}[/tex]
We want to find the following probability:
[tex] P(X\geq 20)= P(X=20)+P(X=21)+P(X=22)+P(X=23)+P(X=24)+P(X=25)[/tex]
And replacing using the mass function we got:
[tex]P(X=20)=(25C20)(0.85)^{20} (1-0.85)^{25-20}=0.156[/tex]
[tex]P(X=21)=(25C21)(0.85)^{21} (1-0.85)^{25-21}=0.211[/tex]
[tex]P(X=22)=(25C22)(0.85)^{22} (1-0.85)^{25-22}=0.217[/tex]
[tex]P(X=23)=(25C23)(0.85)^{23} (1-0.85)^{25-23}=0.161[/tex]
[tex]P(X=24)=(25C24)(0.85)^{24} (1-0.85)^{25-24}=0.0759[/tex]
[tex]P(X=25)=(25C25)(0.85)^{25} (1-0.85)^{25-25}=0.0172[/tex]
And adding the values we got:
[tex] P(X\geq 20) = 0.8381[/tex]