1. ¿Qué expresiones a continuación se pueden usar para encontrar el área del prisma rectangular de abajo? ¡ELIJA TODOS LOS QUE SE APLIQUEN! Nota: Puede probarlos todos para asegurarse de que sean iguales. * 15 (5x2x3) + (2x3x3) (5x2) + (5x2) + (5x2) + (5x2) 5x2x2 2 (5x2) + 2 (5x2) + 2 (2x2)
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We need to find the area of the prism given in the following image:
You need to add the surfaces of ALL rectangles in the image (recall that the area of a rectangle is : Base x Height)
So for this prism we have:
FOUR rectangles that measure 5 x 2
and also TWO small squares of area 2 x 2
So we need to select all the formulas they give you that read like the addition of the two above:
(5x2) + (5x2) + (5x2) + (5x2) + (2x2) + (2x2)
It can also be written as:
2 (5x2) + 2 (5x2) + 2 (2x2)
Related Questions
2x - 6(x-3) ≥ 5
solve for x.
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Answer:
It’s siu
Step-by-step explanation:
Answer:x≤4.6
Step-by-step explanation: 2x-6(x-3)≥5. 1).combine the like terms. 2x+x=3x & -6+-3=-9. 2). isolate the "x". 3x-9≥5. 3x≥14. 3). divide both sides by your coefficient. 3x≥14/ 3
x≥4.6
4) flip your sign. x≤4.6
Hi. Been out due to medical issues trying to catch-up and learn my work. Thank you in advance
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The break even point is where cost is equal to revenue
cost : y = 25.96x + 22752
Revenue : y = 57.56x
Set the two equations equal to determine x
25.96x + 22752 = 57.56x
Subtract 25.96x from each side
25.96x-25.96x + 22752 = 57.56x-25.96x
22752 = 31.6x
Divide each side by 31.6
22752/31.6 = 31.6x/31.6
720 =x
Now find the value of y
y = 57.56x
y = 57.56 (720)
y = 41443.20
( 720, 41443.20)
Answer: ( 720, 41443.20)
Find the formula for an exponential function that passes through the 2 points given
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The form of the exponential function is
[tex]f(x)=a(b)^x[/tex]a is the initial value (value f(x) at x = 0)
b is the growth/decay factor
Since the function has points (0, 6) and (3, 48), then
Substitute x by 0 and f(x) by 6 to find the value of a
[tex]\begin{gathered} x=0,f(x)=6 \\ 6=a(b)^0 \\ (b)^0=1 \\ 6=a(1) \\ 6=a \end{gathered}[/tex]Substitute the value of a in the equation above
[tex]f(x)=6(b)^x[/tex]Now, we will use the 2nd point
Substitute x by 3 and f(x) by 48
[tex]\begin{gathered} x=3,f(x)=48 \\ 48=6(b)^3 \end{gathered}[/tex]Divide both sides by 6
[tex]\begin{gathered} \frac{48}{6}=\frac{6(b)^3}{6} \\ 8=b^3 \end{gathered}[/tex]Since 8 = 2 x 2 x 2, then
[tex]8=2^3[/tex]Change 8 to 2^3
[tex]2^3=b^3[/tex]Since the powers are equal then the bases must be equal
[tex]2=b[/tex]Substitute the value of b in the function
[tex]f(x)=6(2)^x[/tex]The answer is:
The formula of the exponential function is
[tex]f(x)=6(2)^x[/tex]What is the first step for finding the quotient of 3x^3 z^5/5y * x^2 z^6/20y^3
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The initial expression is:
[tex]\frac{3x^3z^5}{5y}\text{ / }\frac{x^2z^6}{20y^3}[/tex]So the first step is to multiply the numerator of the second fraction with the denominator of the first franction and the denominator of the second fraction by the numerator of the first fraction so:
[tex]\frac{3x^3z^6}{5y}(\frac{20y^3}{x^2z^6})[/tex]So is option C)
The graph of f(x) is shown in black.Write an equation in terms of f(x) to match the redgraph.For example, try something like this:f(x)+3, f (x - 2), or 4f(x).
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Notice that the red function is similar to the black function, which means the transformation applied was a translation.
The transformation is 5 units to the right, exactly.
Therefore, the function that represents the red figure is
[tex]f(x-5)[/tex]you bought a car for $5000. each year it depreciates by 8.5%. Which equation can be used to find the value, v, of the car, x years after it was purchased?
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We have the following:
In this case, we have the following formula:
[tex]v=C\cdot(1-r)^x[/tex]Where C is the original value of the car, r is the depreciation rate and x is the time in years
What the answer to this to solve the problem
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Answer:
25
Step-by-step explanation:
180-88=92
92+61=123
123+30+x=180
153+x=180
x=25
A window washer drops a tool from their platform 155ft high. The polynomial -16t^2+155 tells us the height, in feet, of the tool t seconds after it was dropped. Find the height, in feet, after t= 1.5 seconds.
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Write 3.25% as a fraction in simplest form. Can you explain step by step please?
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From the problem, we have 3.25% to convert into fraction.
Note that percentage a% can be written as a/100
So 3.25% will be :
[tex]3.25\%=\frac{3.25}{100}[/tex]From here, we can multiply the numerator and the denominator by 100 to make 3.25 a whole number.
[tex]\frac{3.25\times100}{100\times100}=\frac{325}{10000}[/tex]Next step is to simplify the fraction by getting the factors of the numerator and the denominator.
325 = 25 x 13
10000 = 25 x 400
Rewriting it again :
[tex]\frac{325}{10000}=\frac{25\times13}{25\times400}[/tex]Cancel the common factor (25)
[tex]\frac{\cancel{25}\times13}{\cancel{25}\times400}=\frac{13}{400}[/tex]The answer is 13/400
Perform a DuPont analysis on Healthy Body Nursing Home, Inc. Assume that the industry average ratios are as follows: Total margin: 3.9%
Total asset turnover: 0.5
Equity multiplier: 2.8
Return on equity: %
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Using the DuPont analysis the return on equity is 5.46%.
What is the return on equity?
Return on equity is the ratio of net income to average total equity. Return on equity is an example of a profitability ratio. Profitability ratios measure the ability of a firm to generate profits using available resources.
Return on equity = net income / average total equity
Using the Dupont formula, return on equity can be determined using:
Return on equity = total margin x asset turnover x equity multiplier
Return on equity = (Net income / Sales) x (Sales/Total Assets) x (total asset / common equity)
3.9% x 0.5 x 2.8 = 5.46%
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the length of a rectangle is 13 centimeters less then four times it’s width it’s area is 35 centimeters find the dimensions of the rectangle
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Solution:
The area of a recatngle is expressed as
[tex]\begin{gathered} \text{Area of rectangle = L}\times W \\ \text{where} \\ L\Rightarrow\text{length of the rectangle} \\ W\Rightarrow\text{ width of the rectangle } \end{gathered}[/tex]Given that the length of the rectangle is 13 centimeters less than four times its width, this implies that
[tex]L=4W-13\text{ ---- equation 1}[/tex]Tha area of the rectangle is 35 square centimeters. This implies that
[tex]36=L\times W\text{ --- equation 2}[/tex]Substitute equation 1 into equation 2. Thus,
[tex]\begin{gathered} 36=L\times W \\ \text{where} \\ L=4W-13 \\ \text{thus,} \\ 36=W(4W-13) \\ open\text{ parentheses} \\ 36=4W^2-13W \\ \Rightarrow4W^2-13W-36=0\text{ ---- equation 3} \\ \end{gathered}[/tex]Solve equation 3 by using the quadratic formula expressed as
[tex]\begin{gathered} W=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}_{} \\ \text{where} \\ a=4 \\ b=-13 \\ c=-36 \end{gathered}[/tex]thus, we have
[tex]\begin{gathered} W=\frac{-(-13)\pm\sqrt[]{(-13)^2-(4\times4\times-36)}}{2\times4}_{} \\ =\frac{13\pm\sqrt[]{169+576}}{8} \\ =\frac{13\pm\sqrt[]{745}}{8} \\ =\frac{13}{8}\pm\frac{\sqrt[]{745}}{8} \\ =1.625\pm3.411836016 \\ \text{thus,} \\ W=5.036836016\text{ or W=}-1.786836016 \end{gathered}[/tex]but the width cannot be negative. thus, the width of the recangle is
[tex]W=5.036836016[/tex]From equation 1,
[tex]\begin{gathered} L=4W-13 \\ \end{gathered}[/tex]substitute the obtained value of W into equation 1.
Thus, we have
[tex]\begin{gathered} L=4W-13 \\ =4(5.036836016)-13 \\ =20.14734-13 \\ \Rightarrow L=7.14734 \end{gathered}[/tex]Hence:
The width is
[tex]5.036836016cm[/tex]The length is
[tex]7.14734cm[/tex]Can someone help with this question?✨
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The equation of the line that is perpendicular with y = 4 · x - 3 and passes through the point (- 12, 7) is y = - (1 / 4) · x + 4.
How to derive the equation of a line
In this problem we find the case of a line that is perpendicular to another line and that passes through a given point. The equation of the line in slope-intercept form is described below:
y = m · x + b
Where:
m - Slopeb - Interceptx - Independent variable.y - Dependent variable.In accordance with analytical geometry, the relationship between the two slopes of the lines are:
m · m' = - 1
Where:
m - Slope of the first line.m' - Slope of the perpendicular line.If we know that m = 4 and (x, y) = (- 12, 7), then the equation of the perpendicular line is:
m' = - 1 / 4
b = 7 - (- 1 / 4) · (- 12)
b = 7 + (1 / 4) · (- 12)
b = 7 - 3
b = 4
And the equation of the line is y = - (1 / 4) · x + 4.
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#8 iOrder the figures described below according to their volumes from least (on top) to greatest (on bottom).= a cylinder with 2-inch radius and 6-inch height= a cube with side length 4 inches= a rectangular prism with a length of 2 inches, a width of 3 inches, and a height of 6 inches
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step 1
Find out the volume of each figure
Cylinder
The volume of a cylinder is given by
[tex]\begin{gathered} V=\pi r^2h \\ V=(3.14)(2)^2(6) \\ V=75.36\text{ in}^3 \end{gathered}[/tex]Cube
The volume of the cube is given by
[tex]\begin{gathered} V=b^3 \\ V=4^3 \\ V=64\text{ in}^3 \end{gathered}[/tex]Rectangular prism
The volume of the prism is given by the formula
[tex]\begin{gathered} V=L*W*H \\ V=(2)(3)(6) \\ V=36\text{ in}^3 \end{gathered}[/tex]therefore
The answer is
rectangular prismcubecylinderNeed help !! Geometry unit 3 parallel and perpendicular lines
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ANSWER;
Converse; Exterior alternate angles are equal
[tex]x\text{ = 3}[/tex]EXPLANATION;
Here, we want to get the value of x given that the lines l and m are parallel
From the diagram given, we can see that;
[tex]15x\text{ +29 = 26x-4}[/tex]The reason for this is that they are a pair of exterior alternate angles
Mathematically, exterior alternate angles are equal
From here, we can proceed to solve for the value of x;
[tex]\begin{gathered} 26x-15x\text{ = 29+4} \\ 11x=33 \\ x\text{ = }\frac{33}{11} \\ x\text{ = 3} \end{gathered}[/tex]find the LCD of the list of fractions 7/20, 5/15
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Explanation:
First we have to find multiples of each of the denominators:
[tex]\begin{cases}20\rightarrow20,40,60,80,100\ldots \\ 15\rightarrow15,30,45,60,75,90\ldots\end{cases}[/tex]From those multiples we have to find which one is the least that is in both lists. In this case, the least number that's in both lists is 60
Answer:
LCD = 60
Need help with this question
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Given: a quadratic function with vertex (2,3) opening upward .
Find: the given statement is true or false.
Explanation: if parabola has a vertex at (2,3) and opens upward, it has one real solution., (2,3) will be a lowest point. The vertex will be at lowest point, it will be minimum.
that means graph has no one real solution. hence it will never going to intersect. so this statement is false.
Final answer: the given statement is FALSE.
helppppppppppppppppppp
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you own a pet store that sells fish tank you brought a fish tank for $35 and are going to mark it up 20% what is the selling price going to be on the fish tank
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If you're marking the fish tank up by 20%, it means you're looking to sell it at 120% of its original value.
Now, let's use a rule of three to calculate such percentage:
Thereby,
[tex]x=\frac{120\cdot35}{100}\rightarrow x=42[/tex]The selling price would be $42
Angle RQT is a straight angle. What are m angle RQS and m angle TQS? Show your work.
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11x + 5 + 8x + 4 = 180
Simplifying like terms
11x + 8x = 180 - 5 - 4
19x = 171
x = 171/19
x = 9
RQS = 11(9) + 5
= 99 + 5
= 104°
TQS = 8(9) + 4
= 72 + 4
= 76°
12 = - 2/5 yI got -30 I want to see if I did the correct steps
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Solution
[tex]12=-\frac{2}{5}y[/tex]Step 1: Simplify the expression
[tex]\begin{gathered} 12=-\frac{2}{5}y \\ \text{cross multiply} \\ 12(5)=-2y \\ 60=-2y \end{gathered}[/tex]Step 2: Divide the both side by -2
[tex]\begin{gathered} 60=-2y \\ \frac{60}{-2}=-\frac{2y}{-2} \\ y=-30 \end{gathered}[/tex]Therefore the correct value of y = - 30
If you select one card at random from a standard deck of 52 cards, what is the probability of that card being a 5, 6 OR 7?
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To solve this question we will use the following expression to compute the theoretical probability:
[tex]\frac{\text{favorable cases}}{total\text{ cases}}.[/tex]1) We know that there are 4 fives, 4 sixes, and 4 sevens in a standard deck of 52 cards, then, the probability of selecting a 5, 6, or 7 is:
[tex]\frac{4+4+4}{52}\text{.}[/tex]2) Simplifying the above expression we get:
[tex]\frac{12}{52}=\frac{3}{13}\text{.}[/tex]Answer:
[tex]\frac{3}{13}\text{.}[/tex]ur answer as a polynomial in standard form.=f(x) = 5x + 1g(x) = x2 – 3x + 12=Find: (fog)(x)
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(fog)(x) = 5x² - 15x + 61
Explanation:The given functions are:
f(x) = 5x + 1
g(x) = x² - 3x + 12
(fog)(x) = f(g(x))
This means that we are substituting g(x) into f(x)
(fog)(x) = 5(x² - 3x + 12) + 1
(fog)(x) = 5x² - 15x + 60 + 1
This can be further simplified as:
(fog)(x) = 5x² - 15x + 61
For p(2) = 7 + 10x - 12x^2 - 10x^3 + 2x^4 + 3x^5, use synthetic substitution to evaluate
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Answer:
p(-3) = -428
Explanations:Given the polynomial function expressed as:
[tex]p(x)=7+10x-12x^2-10x^3+2x^4+3x^5[/tex]Determine the value of p(-3)
[tex]\begin{gathered} p(-3)=7+10(-3)-12(-3)_^2-10(-3)^3+2(-3)^4+3(-3)^5 \\ p(-3)=7-30-12(9)-10(-27)+2(81)+3(-243) \\ p(-3)=-23-108+270+162-729 \\ p(-3)=-428 \end{gathered}[/tex]Hence the value of p(-3) is -428
Don’t get part b of the question. Very confusing any chance you may help me with this please.
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To solve this problem, first, we will solve the given equation for y:
[tex]\begin{gathered} x=3\tan 2y, \\ \tan 2y=\frac{x}{3}, \\ 2y=\arctan (\frac{x}{3}), \\ y=\frac{\arctan(\frac{x}{3})}{2}=\frac{1}{2}\arctan (\frac{x}{3})\text{.} \end{gathered}[/tex]Once we have the above equation, now we compute the derivative. To compute the derivative we will use the following properties of derivatives:
[tex]\begin{gathered} \frac{d}{dx}\arctan (x)=\frac{1}{x^2+1}, \\ \frac{dkf(x)}{dx}=k\frac{df(x)}{dx}. \end{gathered}[/tex]Where k is a constant.
First, we use the second property above, and get that:
[tex]\frac{d\frac{\arctan(\frac{x}{3})}{2}}{dx}=\frac{d\arctan (\frac{x}{3})\times\frac{1}{2}}{dx}=\frac{1}{2}\frac{d\arctan (\frac{x}{3})}{dx}\text{.}[/tex]Now, from the chain rule, we get:
[tex]\frac{dy}{dx}=\frac{1}{2}\frac{d\text{ arctan(}\frac{x}{3})}{dx}=\frac{1}{2}\frac{d\arctan (\frac{x}{3})}{dx}|_{\frac{x}{3}}\frac{d\frac{x}{3}}{dx}\text{.}[/tex]Finally, computing the above derivatives (using the rule for the arctan), we get:
[tex]\frac{dy}{dx}=\frac{1}{2}\frac{\frac{1}{3}}{\frac{x^2}{9}+1}=\frac{1}{6}(\frac{1}{\frac{x^2}{9}+1})=\frac{3}{2(x^2+9)}.[/tex]Answer:
[tex]\frac{3}{2(x^2+9)}.[/tex]Which number is greater in each set?
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We have three set of numbers and we must choose the greater value in each set
1.
[tex]\frac{1}{3}or\frac{1}{4}or\frac{1}{5}[/tex]When the numerator is 1, the greater fraction is the one that has the small denominator.
So, in this case the greater number is
[tex]\frac{1}{3}[/tex]2.
[tex]\frac{1}{4}or\frac{4}{3}or\frac{5}{6}[/tex]In this case we can rewrite the fractions as fractions with the same denominator
[tex]\frac{1}{4}=\frac{3}{12}[/tex][tex]\frac{4}{3}=\frac{16}{12}[/tex][tex]\frac{5}{6}=\frac{10}{12}[/tex]Then, the greater number is the one that has the greater numarator
So, it is
[tex]\frac{16}{12}=\frac{4}{3}[/tex]in this case the greater number is
[tex]\frac{4}{3}[/tex]3.
[tex]\frac{16}{5}or3\frac{2}{5}or3.25[/tex]In this case we can rewrite the numbers as decimal numbers
[tex]\frac{16}{5}=3.2[/tex][tex]3\frac{2}{5}=3.4[/tex][tex]3.25=3.25[/tex]In this case the greater number is
[tex]3\frac{2}{5}[/tex]A pound of rice crackers cost 42.88 Jacob purchased a 1/4 pound how much did he pay for the crackers?
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Answer:
10.72
Step-by-step explanation:
The price per pound is 42.88
We are getting 1/4 pound.
Multiply 42.88 by 1/4
42.88 * 1/4 =10.72
Answer:
So you know that a pound of rice crackers cost $42.88. You also know that Matthew bought 1/4 or 25% or 0.25 of a pound. This means that by 42.88 divided 4 will equal the answer.
42.88 ÷ 4 = 10.72
Therefore, Matthew paid or $10.72 for 1/4 pound of rice crackers.
a janitor had 2/3 of a cleaning solution. he used 1/4 of the solution in an day. how much of the bottle did he use?
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Answer:
5/12 of the cleaning solution.
Step-by-step explanation:
2/3 – 1/4
------------------------------------------
2 × 4
= 8/12
3 × 4
------------------------------------------
1 x 3
= 3/12
4 x 3
------------------------------------------
8 – 3
12
= 5/12
------------------------------------------
Hopefully this makes sense!
Find a polynomial f (x) of degree 3 that has the following zeros.6 (multiplicity 2), -7Leave your answer in factored form.
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If a polynomial has a zero of "a" with multilicity b, the factor would be:
[tex](x-a)^b[/tex]So, accordingly the factors would be:
[tex]\begin{gathered} (x-6)^2 \\ (x-(-7))^1 \end{gathered}[/tex]They are
[tex]\begin{gathered} (x-6)^2 \\ (x+7) \end{gathered}[/tex]We can write out the polynomial, f(x), as:
[tex]f(x)=(x-6)^2(x+7)[/tex]Which of the following statements must be true based on the diagram below!(Diagram is not to scale)O JL is a segment bisector.JL is a perpendicular bisector.OJT is an angle bisectora Lis the vertex of a right angle,Jis the midpoint of a segment in the diagramNone of the above.
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From the diagram, we notice that the line JL bisects the angle J into two equal angles. Hence, we can conclude that the correct statement is this:
JL is an angle bisector
An angle bisector are
If each machine produces nails at the same rate, how many nails can 1 machine produce in 1 hour
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Divide the number of nails by the number of minutes:
16 1/5 ÷ 15 = 1 2/25 per minute
48 3/5 ÷ 45 = 1 2/25 per min
59 2/5 ÷ 55 = 1 2/25 per min
We have the number of nails produced per minute, to calculate the number of nails in an hour multiply it by 60, because 60 minutes= 1 hour:
1 2/25 x 60 = 64 4/5