This is defined as a propagation of disturbances from place to place in a regular and organized way.
The answers provided above are therefore the most appropriate choices in this scenario.
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Answer: Light waves do not require a medium to propagate and As a wave's frequency increases, more energy is carried by the wave in a given time period.
Explanation:
how far does a 1.2g bullet with kinetic energy of 1.2 j go in 2 seconds ?
Answer:
To calculate the energy in joules, simply enter the mass of ammunition (in grams) that you use, and the fps that you've read from your Chrono unit.
Lightning always follows
(a) a thunder
(b) rain pour
(c) the easiest path
(d) a straight path
Answer:
a thunder
Explanation:
It's because the difference in speed of light and sound
Light has speed about 3×10^8m/sSound has speed 344m/sSo we hear thunder later
Answer:
C
Explanation:
Lightning is a giant spark. A single stroke of lightning can heat the air around it to 30,000 degrees Celsius This extreme heating causes the air to expand at an explosive rate. The expansion creates a shock wave that turns to a booming sound wave, better known as thunder. Thunder & lightning occur at roughly the same time, although u see the flash of lightning before u hear the thunder. This is because light travels much faster than sound.Lightning always follows the easiest path. Lightning strikes buildings or projecting objects such as trees, poles, wires or building than larger, flatter surfaces because the material in them provide easier paths to the ground than the other. The primary target of lightning are lone buildings.Therefore, Thunder Follows The Easiest Part. And it is not (A) because Thunder Follows A Lightening Not Vice Versa.
Use F = 1/T as your basis:
9. Find the frequency of a tuning fork that takes 2.50×10−3s to complete one oscillation.
The answer is 400 Hz but please show your work.
Now
Frequency:-
[tex]\\ \rm\rightarrowtail \nu=\dfrac{1}{T}[/tex]
[tex]\\ \rm\rightarrowtail \nu=\dfrac{1}{2.5\times 10^{-3}}[/tex]
[tex]\\ \rm\rightarrowtail \nu=0.4\times 10^{3}[/tex]
[tex]\\ \rm\rightarrowtail \nu=400Hz[/tex]
The frequency for this time will be 400 Hz.
What is the frequency?Frequency is defined as the ratio of the number of waves to time. It is denoted by f.
f=[tex]\frac{1}{T}[/tex] where,
f is the frequency and,
T is the time period.
SI unit of frequency is Hz.
There are different types of frequency in sound :
Infrasonic-The frequency is less than 20 Hz.Audible-The frequency is between 20Hz to 20,000 Hz.Ultrasonic-The frequency is greater than 20,000 Hz.According to the question :
Given :
T= 2.50×[tex]10^{-3}[/tex]
f=[tex]\frac{1}{T}[/tex]
⇒f=1/(2.50×[tex]10^{-3}[/tex])
⇒400 Hz
Hence, the frequency for this time will be 400 Hz.
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The particles that make up matter are ______, ions or molecules.
Answer:
Atoms.
Explanation:
Atoms are purely one bit of an element. Ions are positive or negative atoms. Molecules are not pure, they have other stuff with it.
How can gravitational tugs from orbiting planets affect the motion of a star?.
Answer:
Gravitational tugs from orbiting planets don't affect the motion of a star. The star, being much larger than the planet, has a much smaller orbit. But it does move slightly. Explain how alien astronomers could deduce the existence of planets in our solar system by observing the Sun's motion.
A proton is moving south with a speed of 4500 m/s in a magnetic field of 5500 T directed into the page. Determine the magnitude and direction of the magnetic force on the charge.
a.3.96 x 10-12 N west
b.1.55 x 1026 west
c.1.55 x 1026 east
d.3.96 x 10-12 N east
Answer:
F = q V X B
V is south and B is into the page
The resultant vector is directed to the East
F = 1.6E-19 * 4.5E3 * 5.5E3 N = 3.96 N East
(Note q is negative for an electron producing a force in the opposite direction)
Tuning a piano to tune middle c on a piano, a tuner hits the key and at the same time sounds a 261 hz tuning fork. if the turner hears 3 beats per second, what are the possible frequencies of the piano key?
This question deals with the physics of resonance and sound. The possible frequency of the pano key is 258hz.
How to compute the variation in frequencyThe beat of a frequency is the difference (an absolute value) in the frequencies produced by the two waves.
Beat per second equals |f1 - f2| Where
ft = Frequency of the Tunning fork and
fp= Frequency of the Piano Key
Hence
3 = 261 - fp
Solving for fp,
fp = 261-3
= 258hz
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The free-body diagram below represents all the forces acting on an object. What is the net force acting on this object?
300 N right
100 N down
0 N up
200 N right
Answer:
200 N to the right
Explanation:
The 50 N forces cancel each other since they are opposing each other.Why was the light peppered moth able to flourish prior to the Industrial Revolution?
O by blending in with the trees
o the ability to fly
O an abundance of food
O fewer predators
Answer:
B. by blending in with the trees
Answer:
B. by blending in with the trees
Explanation:
Derive an expression for the block's centripetal acceleration ac in terms of m , θ , and physical constants, as appropriate
The expression for the block's centripetal acceleration is derived as ω²r or v²/r.
What is centripetal acceleration?The centripetal acceleration of an object is the inward or radial acceleration of an object moving in a circular path.
The expression for the block's centripetal acceleration is derived as follows;
ω = dθ/dt
where;
ω is the angular speed θ is the angular displacementt is the time of motionac = ω²r
where;
r is the radius of the circular pathAlso, ω = v/r
ac = (v/r)²r
ac = v²/r
Thus, the expression for the block's centripetal acceleration is derived as ω²r or v²/r.
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4. An archer pulls a bowstring back 0.440 m, and the spring constant of the bow is 545 N/m.
a.) Find the amount of work the archer did to draw the bow.
b.) Find the speed an arrow of mass 0.060 kg will have when it is shot from the bow.
Assume no losses from friction
Answer: (a)part:545nm multiply by 0.440m=239.8JEWELS(J)
(B):1/2MULTIPLY BY MVSQUARE(APPLY THE FORMULA OF KINETIC ENERGY)REARANGE THE FORMULA,V=2.13MS
Explanation:
SO FOR PART A, IN ORDER TO CALCULATE THE WORK DONE YOUR SUPPOSE TO APPLY THE FORMULA FORCE MULTIPLY BY DISTANCE WHICH IS THE FORMULA FOR WORK DONE,IN THIS SCENARIO YOU HAD A FORCE OF 545NM AND A DISANCE OF 0.440,SO I ORDER TO FIND THE WORK DONE WE MULTIPLIED THEM BOTHE ACCORDING TO THE FORMULA AND GOT THE ANSWER.
FOR PARTB,I JUST SIMPLY APPLIED THE FORMULA FOR KINETIC ENERGY AND SIMPLY REARRANGED IT IN ORDER TO FIND THE VELOCITY.I MADE V THE SUBJECT OF THE FORMULA.
what is the medium for an ocean wave? Provide evidence that the medium is not transferred when a water wave moves on a lake
The medium for an ocean wave is the ocean water which involves movement on the water body.
What is a Medium?This is defined as a substance or material that carries the wave. In the case of ocean waves, the medium is referred to the ocean water.
The medium is not transferred when a water wave moves on a lake as energy is transported but the water molecules aren't which is why lakes have water present in them.
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Hello people ~
last one I've got for y'all
Which of the following phenomenon is not explained by Huygen’s wave theory?
⇢Diffraction
⇢Interference
⇢Polarisation
⇢Photoelectric effect
Answer:
Photoelectric effect
Explanation:
Photo electric effect was a great invention of Albert EinsteinEinstein got nobel prize for discovering photoelectric effect.Option D is correct
How does energy affecf a wave?
One source error is __________, and one of its solutions is having a lie scale inserted into the assessment. a. social desirability bias b. deliberate deception c. response bias d. response set please select the best answer from the choices provided a b c d
One source error is deliberate deception and one of its solutions is having a lie scale inserted into the assessment.]
What is the error?An error is a mistaken or erroneous action. In some contexts, an error is interchangeable with a mistake.
The discrepancy between the calculated value and the correct value is referred to as an "error" in statistics.
When a person is completely aware of what they are doing, they are engaging in deception. They are concealing the truth and making a deliberate decision to tell someone something that is false.
When describing a magic trick, such as a sleight of hand, the term deception can also be used.
When there are repetitive questions that ask the same questions over and over with different formats to check if the responses are constant over time, lie scales are utilized.
Hence one source error is deliberate deception and one of its solutions is having a lie scale inserted into the assessment.
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The Earth's biosphere is consists of
A(only the water on Earth that is in its solid form.
B(all of the Earth's water, including surface water, groundwater, snowcover, ice, and water in the atmosphere.
C(the part of the earth and its atmosphere in which living organisms exist or that is capable of supporting life.
D(the solid part of the earth consisting of the crust and outer mantle.
Answer:
The part of the earth and its atmosphere in which living organisms exist or that is capable of supporting life.
Explanation:
It’s in the definition of biosphere. “Bio” means “life,” so “biosphere” is that portion of the Earth capable of supporting life.
A metal spoon was placed in a dish of ice cream and became cool. Which correctly describes the heat transfer process that resulted in the cooling of the spoon?.
Answer:
The heat went from the i cream to the spoon making it cool.
Explanation:
i just know.
HELP MEEEE, question number 5
Explanation:
The gravitational potential energy of an object is given by GPE=mgh
where m is the mass of the object, g is the gravitational field strength (9.81 m/s² on earth) and h the height it is lifted at above the GPE reference ground.
Mass 1 has a GPE=m¹gh=(2)(9.81)(10)=196.2 Joule
Mass 2 has a GPE=m²gh=(4)(9.81)(10)=392.4 Joule
Object 2 has more potential energy and it makes sense since it's heavier
Hope this helps :))
Which is NOT a part of transverse waves?
A. wavelength
B. trough
C. compression
D. crest
Answer:
C. Compression
Explanation:
✧✧✧EMOTIONAL DAMAGE✧✧✧
kleann
In most cultures, the difference between the majority viewpoint and the minority viewpoint is that the majority group is made to feel __________ and the minority group is made to feel __________. A. Divergent. . . Normal B. Equal. . . Superior C. Superior. . . Equal D. Normal. . . Divergent Please select the best answer from the choices provided A B C D.
The difference between the majority viewpoint and the minority view is that the majority group is made to feel normal and the minority group is made to feel divergent.
What is the viewpoint?A vantage point or point of view from which something is viewed or assessed is known as the viewpoint The story is narrated from a variety of perspectives, including two major ones and several smaller ones.
Most studies comparing majority versus minority influence argue the author, places a premium on influence in the sense of prevailing. In this context.
There is evidence that majorities have greater public influence than minorities, and that minority impact when it happens, is mostly latent. In the current version,
Hence the difference between the majority viewpoint and the minority view is that the majority group is made to feel normal and the minority group is made to feel divergent.
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Answer: D
Explanation:
Simplified for you.
What are the postulates of the KMT of gases?
Two planets are orbiting a star in a distant galaxy the first has a semimajor axis of 150 x 10^6 km an eccentricity of 0. 20 and a period of 1. 0 earth years
For two planets orbiting a star in a distant galaxy, having the first semimajor axis of 150 x 10^6 km, the period of the second plane is mathematically given as
T=2.2earth year
What is the period of the second planet?Generally, the equation for the time period is mathematically given as
[tex]T^{2} \appox a^{3}[/tex]
Therefore, for planet one
[tex]1^2\approx (150 x 10^6)^3[/tex]
In conclusion, For planet 2
T^2=(250/150)^3
T=√4.632
T=2.2earth year
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The period of the second planet for two planets circling a star in a faraway galaxy with a first semimajor axis of 150× 10⁶ km. The time period of the planet will be 2.2 earth years.
What is the time period of the revolution?The time period of the revolution is the time required to complete one revolution. It is guven by T. It is measured in seconds.
The equation of the time period is found as;
[tex]\rm T = \frac{250}{150} ^3 \\\\ T= \sqrt{4.632} \\\\ T=2.2 \ earth \ year[/tex]
Hence the time period of the planet will be 2.2 earth years.
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If you have 10 ounces of meat, what percentage of the calories comes from fat if the meat is 90% lean?
Answer:
There are 602 calories in 10 ounces of Ground Beef (85% Lean / 15% Fat). serving sizes of Ground Beef
Explanation:
hope this helps if not please let me now
Which is NOT a characteristic of
the temperate region?
A. a lot of organic matter
B. moderate temperatures
C. moderate rainfall
D. under-developed soil horizons
Answer:
under developed soil horizons
The change in momentum that occurs when a 1. 0 kg ball traveling at 4. 0 m/s strikes a wall and bounces back at 2. 0 m/s is.
Answer:
The change is momentum is given by ∆p=p(inital) - p(final) =4-2=2 kg.m/s
Explanation:
momentum is the product of mass and velocity (speed)
So it's initial momentum would be:
p=mv=(1)(4)=4 kg.m/s
It's final momentum is given by:
p=mv=(1)(2)=2 kg.m/s
A 20 Ohm resistance is connected
across the secondary winding of a
single-phase power transformer
whose secondary voltage is 150 V.
Calculate the primary voltage if the
supply current is 5 A, neglecting
losses.
Answer: 225 V
Explanation:
Given:
Secondary voltage,V2 = 150v
Resistance is connected across secondary winding,∴R2 = 20Ω
Supply current, ie, I1 = 5A
[tex]\text{Now, secondary current,} \ $I_{2}=\frac{V_{2}}{R_{2}}=\frac{150}{20}=7.5$$$\therefore I_{2}=7.5 \mathrm{~A}$$For Transformers, we have $\frac{N_{2}}{N_{1}}=\frac{V_{2}}{V_{1}}=\frac{I_{1}}{I_{2}}$ so, Taking $\frac{N_{2}}{N_{1}}=\frac{l_{1}}{l_{2}}$ inserting all given \& obtained values, we get $\frac{N_{2}}{N_{1}}=\frac{5}{7.5}$$$\therefore \text { Turns ratio }=\frac{N_{1}}{N_{2}}=\frac{7.5}{5}=\frac{3}{2}=3: 2$$[/tex]
[tex]\text{Again taking,}\frac{N_{1}}{N_{2}}=\frac{V_{2}}{V_{1}}$ \\So, \\$V_{1}=\frac{N_{1}}{N_{2}} V_{2}\\$ inserting all values, we get, $V_{1}=\frac{7.5}{5} * 150=225$\\Therefore, \fbox{Primary voltage, {$V_{1}=225 \mathrm{~V}$}}[/tex]
An aircraft is in a steady climb, at an airspeed of 100 knots, and the flight path makes a positive 10 degree angle with the horizontal. Find the Rate of Climb.
The rate of climb of the aircraft in a steady climb making a 10 degree angle with the horizontal is : 17.36 knots
Given data
Airspeed = 100 knots
Angle with the horizontal ( ∅ ) = 10°
Determine the rate of climb of the aircraftwe will apply the formula below
Vy ( rate of climb ) = Airspeed * sin ∅
= 100 * sin ( 10 )
= 17.36 Knots
Hence we can conclude that rate of climb of the aircraft in a steady climb is : 17.36 knots.
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A thundercloud has an electric charge of 48.8 C near the top of the cloud and –41.7 C near the bottom of the cloud. The magnitude of the electric force between these two charges is 7980000 N. What is the average separation between these charges
a/ 1.51 km
b/ 2.53 Km
c/ 1.51 m
d/ 1001 m
Answer: 1.51 km
Explanation:
Coulomb's Law: The electrostatic force between two charge particles Q: and Q2 is directly proportional to product of magnitude of charges and inversely proportional to square of separation distance between them.
Or, [tex]\vec{F}=k \frac{Q_{1} Q_{2}}{r^{2}}[/tex]
Where Q1 and Q2 are magnitude of two charges and r is distance between them:
Given:
Q1 = Charge near top of cloud = 48.8 C
Q2 = Charge near the bottom of cloud = -41.7 C
Force between charge at top and bottom of cloud (i.e. between Q: and Q2) (F) = 7.98 x 10^6N
k = 8.99 x 109Nm^2/C^2
So,
[tex]\begin{aligned}&7.98 \times 10^{6}=\left(8.99 \times 10^{9} \mathrm{Nm}^{2} / \mathrm{C}^{2}\right) \frac{48.8 \mathrm{C} \times 41.7 \mathrm{C}}{\mathrm{r}^{2}} \\&r=\sqrt{\frac{1.8294 \times 10^{13}}{7.98 \times 10^{6}}}=1.514 \times 10^{3} \mathrm{~m}=1.51 \mathrm{~km}\end{aligned}[/tex]
Therefore, the separation between the two charges (r) = 1.51 km
When charging objects by induction which of the following must be true
A. A path to ground is not needed when using a positive source
B. The objects being charged must be conductors
C. The objects takes on the same charge as it's source
D. The source loses some of its charge
Answer:
C
Explanation:
because that's how science works
0. 85 kg of lead, specific heat 128 J/kgC, is heated from 50 C to 95 C. How much heat energy did the sample absorb?