1). what is the area of the rectangle whose length is (x+5) and width (x-5)?​

1). What Is The Area Of The Rectangle Whose Length Is (x+5) And Width (x-5)?

Answers

Answer 1

Answer:

[tex]x^{2}[/tex]-25

Step-by-step explanation:

formula for areas of rectangles= width x height

width=x-5

height=x+5

(x-5)(x+5)= [tex]x^{2}[/tex]-5x+5x-25

since the 5x's cancel out each other

              =[tex]x^{2}[/tex]-25 will be the answer

Answer 2

The area of rectangle is [tex](x^{2} -25)[/tex] unit square.

The area of rectangle is product of length and width.

         [tex]Area = length*width[/tex]

Given that length is [tex](x+5)[/tex] and width is [tex](x-5)[/tex].

    [tex]Area=(x+5)*(x-5)\\\\Area=x^{2} -5x+5x-25=x^{2} -25[/tex]

Hence, the  area of rectangle is [tex](x^{2} -25)[/tex] unit square.

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