Answer:
d = 4 d₀o
Explanation:
We can solve this exercise using the relationship between work and the variation of kinetic energy
W = ΔK
In that case as the car stops v_f = 0
the work is
W = -fr d
we substitute
- fr d₀ = 0 - ½ m v₀²
d₀ = ½ m v₀² / fr
now they indicate that the vehicle is coming at twice the speed
v = 2 v₀
using the same expressions we find
d = ½ m (2v₀)² / fr
d = 4 (½ m v₀² / fr)
d = 4 d₀o
Suppose a proton is moving with a speed of 10 m/s in a direction parallel to a uniform magnetic field of 3.0 T. What is the magnitude and direction of the magnetic force on the proton
Answer:
the magnetic force on the proton is zero.
Explanation:
Given;
speed of the proton, v = 10 m/s
magnitude of the magnetic field, B = 3 T
The magnitude of the magnetic force on the particle is calculated as;
F = qvBsinθ
where;
θ is the angle between the velocity of the particle and the magnetic field
Since the particle is moving parallel to the magnetic field, θ = 0
F = qvBsin(0)
F = 0
Therefore, the magnetic force on the proton is zero.
Answer:
This is a trick question, in that the numbers do not matter.
Study the dependence of the magnetic force on the direction of the magnetic field and the direction of motion of the particle. When is it a maximum? When is it a minimum?
Hint: In vector notation, this is often expressed as q v x B, where q is the electric charge of the particle, v is its velocity (a vector), and B is the magnetic field vector.
A proton moves across a magnetic field and feels a force. If an electron were to
move at the same speed in the same direction across the same magnetic field, the
force
O 1) would be smaller in the opposite direction
O2) would be the same magnitude in the same direction
3) would be the same magnitude in the opposite direction
4) would be larger in the opposite direction
5) would be smaller in the same direction
potang ina mooooooo bubu hayop kaaaaapestrng yawa
Explanation:
peste kakkkkaaaaaaaa bubu pesteng yawaaaayaka kaayu kaaaaaaa
give you point but please i need help in physcis
Explanation:
Hi
Hi
Hi
Hi
BRAINILIEST PLEASE
What is 4+4+2+2
.The answer is 12
Hope this helps
Ftension = 120 N
10 kg
Fg
What is the weight (not mass) of the box?
O 10 kg
0 19 N
Ô 98 N
O 98 kg
Answer:
98Kg
Explanation:
true or False? PLEASE HELP ME
Answer:
a. True - Joules is the unit measure for energy.
b. False - Potential energy is associated with position
c. False - Kinetic energy is associated with movement.
d. False - It's climbing, which means it also has kinetic energy.
What is the voltage drop across the 10.0 alpha resistor
Answer:
wow so cool the answer is vr 10
You are on a train that is traveling at 3.0 m/s along a level straight track. Very near and parallel to the track is a wall that slopes upward at a 12 angle with the horizontal. As you face the window (0.90 m high, 2.0 m wide) in your compartment, the train is moving to the left, as the drawing indicates. The top edge of the wall first appears at window corner A and eventually disappears at window corner B. How much time passes between appearance and disappearance of the upper edge of the wall
Questions Diagram is attached below
Answer:
[tex]T=2.08s[/tex]
Explanation:
From the question we are told that:
Speed of Train [tex]V=3.0m.s[/tex]
Angle [tex]\theta=12\textdegree[/tex]
Height of window [tex]h_w=0.90m[/tex]
Width of window [tex]w_w=2.0m[/tex]
The Horizontal distance between B and A from Trigonometric Laws is mathematically given by
[tex]b=\frac{0.9}{tan12}[/tex]
[tex]b=4.23[/tex]
Therefore
Distance from A-A
[tex]d_a=2.0+4.23[/tex]
[tex]d_a=6.23[/tex]
Therefore
Time Required to travel trough d is mathematically given as
[tex]T=\frac{d_a}{v}[/tex]
[tex]T=\frac{6.23}{3}[/tex]
[tex]T=2.08s[/tex]
14. Name the 3 primary causes for the expected mass migration due to Climate
Change.
Answer: sea-level rise, extreme weather events, and drought, and water scarcity.
Explanation:
A solid sphere a solid cylinder, and a hoop each have the same mass and radius. If they are spinning at the same angular velocity, which one has the greatest rotational kinetic energy
Answer:
KE = 1/2 I * w^2 where I = moment of inertia and w the angular velocity
The hoop has all of it mass at a distance of R from the axis of rotation,
I = M R^2 for the hoop, the others have values of I that are less that of the hoop.
When a person sits erect, increasing the vertical position of their brain by 38.6 cm, the heart must continue to pump blood to the brain at the same rate. (a) What is the gain in gravitational potential energy (in J) for 110 mL of blood raised 38.6 cm
Answer:
the gain in gravitational potential energy is 0.4369 J
Explanation:
Given the data in the question;
from the definition of density, we know that;
ρ = m / V
where ρ is density, m is the mass and V is the volume.
Now, lets make mass the subject of the formula
m = ρV ------ let this be equation 1
Now, we know that potential energy PE = mgh ------- let this be equation 2
where m is mass, g is acceleration due gravity, and h is the height.
substitute equation 1 into 2
PE = ρVgh
given that; V = 110 mL = 110 × 10⁻⁶ m³, h = 38.6 cm = 38.6 × 10⁻² m, g = 9.8 m/s², ρ = 1.05 × 10³ kg/m³
we substitute
PE = (1.05 × 10³ kg/m³) × (110 × 10⁻⁶ m³) × 9.8 m/s² × 38.6 × 10⁻² m
PE = 0.4369 J
Therefore, the gain in gravitational potential energy is 0.4369 J
What is the voltage drop across an alarm clock that is connected to a circuit with a current of 1.10A and a resistance of 90Ω?
Answer:
,hgfghjhytreftgyhujijjuhygtfrderftgyh
Explanation:
what is hydrofluorocarbon
Answer:
Hydrofluorocarbons (HFCs) are man-made organic compounds that contain fluorine and hydrogen atoms, and are the most common type of organofluorine compounds. Most are gases at room temperature and pressure.
Answer:
Hydrofluorocarbons (HFC) are man-made organic compounds that contain fluorine and hydrogen atoms and are the most common type of organofluorine compounds. Most are gases at room temperature and pressure. HFCs are produced synthetically and are used primarily as refrigerants. In general, they are relatively non-flammable, chemically stable, and nonreactive.
A _____ is used to make magnifying glasses.
convex mirror
concave lens
plane mirror
convex lens
concave mirror
At an amusement park, a 7.00 kg swimmer uses a water slide to enter the main pool. The swimmer starts at rest, slides without friction, and descends through a vertical height of 0.40 m. Find the total energy present when the swimmer is at the top of the slide.
Answer:
27.44 J
Explanation:
We can find the energy at the top of the slide by using the potential energy equation:
PE = mghAt the top of the slide, the swimmer has 0 kinetic energy and maximum potential energy.
The swimmer's mass is given as 7.00 kg.
The acceleration due to gravity is 9.8 m/s².
The (vertical) height of the water slide is 0.40 m.
Substitute these values into the potential energy equation:
PE = (7.00)(9.8)(0.40) PE = 27.44Since there is 0 kinetic energy at the top of the slide, the total energy present is the swimmer's potential energy.
Therefore, the answer is 27.44 J of energy when the swimmer is at the top of the slide.
physics
i really need help with this physics question
this was due last week but i had no idea what to do
pls help
Answer: Water fills the bucket until its force/weight is greater than the block’s. The lever tilts over, causing the bucket to water the plant.
what is the length of x of the side of the triangle below?
what mass of water will release 60000 J of energy while cooling from 40.0 degrees celsius to 20.0 degrees celsius?
Answer:
714.286g
Explanation:
Q=mcT
60000=m×4.2×(40-20)
m=714.285....g
What do the planets Saturn, Neptune, and Uranus have in common?
A. They are all smaller than Earth.
B. They are the closest to the Sun.
C. They are all outer planets.
D. They are all inner planets.
Answer:
they are all outer planets
A 0.2-kg stone is attached to a string and swung in a circle of radius 0.6 m on a horizontal and frictionless surface. If the stone makes 150 revolutions per minute, the tension force of the string on the stone is:____.
a. 0.75 N.
b. 1.96 N.
c. 0.03 N.
d. 30 N.
e. 0.2 N.
Answer:
the tension force of the string on the stone is 30 N
Option d) 30 N is the correct answer.
Explanation:
Given the data in the question;
mass m = 0.2 kg
radius r = 0.6 m
θ = 150 revolutions = 300π rad
time t = 60 seconds
we know that; Angular speed ω = θ / t
we substitute
ω = 300π / 60
ω = 5π rad
Linear speed of stone u = ω × r
we substitute
u = 5π × 0.6
u = 3π m/s
The tension force of the string on the stone is equal to centripetal force, which aid it move in circle;
so
T = mv² / r
we substitute
T = [ 0.2 × (3π)² ] / 0.6
T = 17.7652879 / 0.6
T = 29.6 ≈ 30 N
Therefore, the tension force of the string on the stone is 30 N
Option d) 30 N is the correct answer.
A hovering mosquito is hit by a raindrop that is 45 times as massive and falling at 8.2 m/s , a typical raindrop speed. How fast is the raindrop, with the attached mosquito, falling immediately afterward if the collision is perfectly inelastic
Answer:
The speed of the raindrop and the mosquito is 8.02 m/s.
Explanation:
mass of mosquito = m
mass of drop = 45 m
initial velocity of mosquito, u = 0 m/s
initial velocity of drop, u' = 8.2 m/s
During the inelastic collision, the momentum of the system is conserved.
Let the speed of rain drop and the mosquito is v.
Use the conservation of momentum
m x u + 45 m x u' = (m + 45 m) v
m x 0 + 45 m x 8.2 = 46 m x v
v = 8.02 m/s
If a 50 W light bulb and a 90 W light bulb operate from 120 V, which bulb has a greater current in it?
50 W
90 W
3. A small statue is recovered in an archaeological dig. Its weight is measured to be 96 lb, and its volume 0.08 ft3. a. What is the statue’s weight density?
Answer:
[tex]d=1200\ lb/ft^3[/tex]
Explanation:
Given that,
The weight of the statue, m = 96 lb
The volume of the statue = 0.08 ft³
We need to find the statue’s weight density. We know that the density of an object is the mass of an object divided by its volume. So,
[tex]d=\dfrac{m}{V}\\\\d=\dfrac{96\ lb}{0.08\ ft^3}\\\\d=1200\ lb/ft^3[/tex]
So, the density of the statue is equal to [tex]1200\ lb/ft^3[/tex].
Consider the cylindrical weir of diameter 3 m and length 6m. If the fluid on the left has a specific gravity of 0.8, find the magnitude and direction of the resultant force
This question is incomplete, the complete question is;
Consider the cylindrical weir of diameter 3m and length 6m. If the fluid on the left has a specific gravity of 1.6 and on the right has a specific gravity of 0.8, Find the magnitude and direction of the resultant force.
Answer:
- the magnitude of the resultant force is 557.32 kN
- the direction of resultant force is 48.29°
Explanation:
Given the data in the question and the diagram below,
First we work on the force on the left hand side.
Left Horizontal
[tex]F_{LH[/tex] = βgAr
here, h = 3/2 = 1.5 m, β = 1.6, g = 9.81 m/s², A = 3 m × 6 m = 18 m²
we substitute
[tex]F_{LH[/tex] = βgAh = ( 1.6 × 1000 ) × 9.81 × 18 × 1.5 = 423792 N
Left Vertical
[tex]F_{LV[/tex] = ( βgπh² / 2 ) × W
we substitute
[tex]F_{LV[/tex] = [ ( ( 1.6 × 1000 ) × 9.81 × π(1.5)² ) / 2 ] × 6 = 332845.458 N
Now we go to the right hand side
Right Horizontal
[tex]F_{RH[/tex] = βgAh
here, h' = 1.5/2 = 0.75 m, β = 0.8, g = 9.81 m/s², A = 1.5 m × 6 m = 9 m²
we substitute
[tex]F_{RH[/tex] = ( 0.8 × 1000 ) × 9.81 × 9 × 0.75 ) = 52974 N
Right Vertical
[tex]F_{RV[/tex] = ( βgπh² / 4 ) × W
we substitute
[tex]F_{RV[/tex] = [ ( ( 0.8 × 1000 ) × 9.81 × π(1.5)² ) / 4 ] × 6 = 83211.36 N
Hence
Fx = [tex]F_{LH[/tex] - [tex]F_{RH[/tex] = 52974 N - 423792 N = 370818 N
Fy = [tex]F_{LV[/tex] + [tex]F_{RV[/tex] = 332845.458 N + 83211.36 N = 416056.818 N
R = √( Fx² + Fy² ) = √[ (370818 N)² + (416056.818 N)² ] = 557323.3 N
R = 557.32 kN
Therefore, the magnitude of the resultant force is 557.32 kN
Direction of resultant force;
tanθ = Fy / Fx
we substitute
tanθ = 416056.818 N / 370818 N
tanθ = 1.121997
θ = tan⁻¹( 1.121997 )
θ = 48.29°
Therefore, the direction of resultant force is 48.29°
What was the earliest energy source for humans?
A. coal
B. oil
C. natural gas
D. wood
Answer:
i think its oil
Explanation:
It was made & used as early as the fourth century BC.
Part
A block of mass 2 kg is acted upon by two forces: 3 N (directed to the left) and 4 N (directed to the right). What can you say about the blocks motion?
Answer:
Explanation:
the block will move to the right side with small velocity because the force from the left side greater than force from right side. Velocity will be less because of friction and gravitational attraction.
If a block of mass 2 kg is acted upon by two forces: 3 N (directed to the left) and 4 N (directed to the right), then the block would move towards the right side.
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
As given in the problem statement If a block of mass 2 kg is acted upon by two forces: 3 N (directed to the left) and 4 N (directed to the right),
The net force acting on the block = 4 Newtons - 3 newtons
= 1 Newton
Thus, we can say that the block would move to the right side.
To learn more about Newton's second law here, refer to the link given below;
brainly.com/question/13447525
#SPJ2
What is the electric field at a point 0.450 m to the left of a -5.77*10^-9 C charge?
Include a + or - sign to indicate the direction the field.
The answer is -0.13
256.2 is the answer.
Here, we are asked to calulate the electric field.
Using the following formula:
E=k*lql/r^2
Yeah! Something that can easily bamboozle you.
So:
E=electric field
k=constant (8.99x10^9)
q=charge
ll= absolute value marks ( I still remember from my Algebra Course))
r=distance
Now, let's plug in the numbers.
E=8.99x10^9*l-5.77x10^-9l/(0.450)^2
And yes! That's a LOT!
But I solved the same problem on paper 2 minutes ago:)
If you perform the calculations, you will get 256.2
Well. THIS one was correct or Acellus.
So our answer is:
256.2 N/CNewtons per CoulombHope this helps:)
g A circular swimming pool has a diameter of 10 m, the sides are 4 m high, and the depth of the water is 3 m. How much work (in Joules) is required to pump all of the water over the side
Answer:
[tex]W=2.69*10^{6}J[/tex]
Explanation:
Generally the equation for momentum is mathematically given by
Diameter [tex]d=10m[/tex]
Radius [tex]r =\frac{d}{2}=>5m[/tex]
Height [tex]h=4m[/tex]
Depth [tex]d=3m[/tex]
Generally the equation for Area of the circle is mathematically given by
[tex]A=\pi r^2[/tex]
[tex]A=\pi 5^2[/tex]
[tex]A=78.5m^2[/tex]
Generally the equation for Work done is mathematically given by
[tex]d_w=d_f*x[/tex]
Where
[tex]d_f=(\rho*d_v)*g[/tex]
Therefore
[tex]d_w=((\rho*d_v)*g)*x[/tex]
[tex]d_w=((1000*78.5)*9.8)*x dx[/tex]
[tex]d_w=769300x dx[/tex]
[tex]W=\int dw[/tex]
[tex]\int dw=769300 \int^4_{3}x dx[/tex]
[tex]W=(769300\2)*7[/tex]
[tex]W=2.69*10^{6}J[/tex]
When the bell in a clock tower rings with a sound of 474 Hz, a pigeon roosting in the belfry flies directly away from the bell.
If the pigeon hears a frequency of 453Hz, what is its speed?
Answer:
15.44 m/s
Explanation:
Below is the given values:
The bell in rings with a sound = 474 Hz
If the frequency of pigeon hears = 453 Hz
Speed = ?
Use below formula:
Frequency = [(Vs - Vo) / Vs ] x fo
Vs = Speed of sound
Vo = Speed of observer
fo = Sound frequency
Frequency = [(Vs - Vo) / Vs ] x fo
453 = [(343 - Vo) / 343 ] x 474
453 / 474 = [(343 - Vo) / 343 ]
0.955 = (343 - Vo) / 343
0.955 x 343 = 343 - Vo
327.56 = 343 - Vo
Vo = 343 - 327.56
Vo = 15.44 m/s
Question 23 of 33 Which phrase best describes when kinetic friction occurs? A. When two surfaces are moving relative to each other B. When one object is resting on another C. When two surfaces are in contact but not moving relative to eatn other D. When balanced forces are acting on an object
Answer:
A. When two surfaces are moving relative to each other.
Explanation:
It is also know as dynamic friction
A 0.160 kg hockey puck is moving on an icy, frictionless,horizontal surface. At t = 0 the puck is moving to theright at 2.40 m/s.
(a) Calculate the magnitude of the velocity of the puck after a force of 37.0 N directed to the right has been applied for 0.050 s.
a. +x direction.
b. +y direction.
c. -x direction.
d. -y direction.
(b) If instead, a force of 13.3 Ndirected to the left is applied from t = 0 to t =0.050 s, what is the final velocity of the puck?
a. +x direction.
b. +y direction.
c. -x direction.
d. -y direction.
Answer:
a. 13.96 m/s in the +x direction
b. -1.76 m/s that is 1.76 m/s in the -x direction
Explanation:
(a) Calculate the magnitude of the velocity of the puck after a force of 37.0 N directed to the right has been applied for 0.050 s.
Since Impulse, I = Ft = m(v₂ - v₁) where F = force applied = + 37.0 N(positive since it is applied to the right), t = duration of applied force = 0.050 s, m = mass of hockey puck = 0.160 kg, v₁ = initial velocity of hockey puck = + 2,40 m/s (positive since it is moving to the right) and v₂ = final velocity of hockey puck
So, making v₂ subject of the formula, we have
v₂ = v₁ + Ft/m
substituting the values of the variables into the equation, we have
v₂ = v₁ + Ft/m
v₂ = 2.40 m/s + 37.0 N × 0.050 s/0.160 kg
v₂ = 2.40 m/s + 1.85 Ns/0.160 kg
v₂ = 2.40 m/s + 11.56 m/s
v₂ = 13.96 m/s
(b) If instead, a force of 13.3 N directed to the left is applied from t = 0 to t =0.050 s, what is the final velocity of the puck?
Since Impulse, I = Ft = m(v₂ - v₁) where F = force applied = - 13.3 N(positive since it is applied to the right), t = duration of applied force = 0.050 s, m = mass of hockey puck = 0.160 kg, v₁ = initial velocity of hockey puck = + 2,40 m/s (positive since it is moving to the right) and v₂ = final velocity of hockey puck
So, making v₂ subject of the formula, we have
v₂ = v₁ + Ft/m
substituting the values of the variables into the equation, we have
v₂ = v₁ + Ft/m
v₂ = 2.40 m/s + (-13.3 N) × 0.050 s/0.160 kg
v₂ = 2.40 m/s - 0.665 Ns/0.160 kg
v₂ = 2.40 m/s - 4.156 m/s
v₂ = -1.756 m/s
v₂ ≅ -1.76 m/s
(a). The velocity of the puck is 13.96 m/s in the +x direction
(b). The final velocity of the puck is -1.76 m/s which is 1.76 m/s in the -x direction
What is velocity?The velocity of the object is defined as the movement of the object in a particular direction with respect to time.
(a) Calculate the magnitude of the velocity of the puck after a force of 37.0 N directed to the right has been applied for 0.050 s.
It is given that
Impulse, I = Ft = m(v₂ - v₁)
where F = force applied = + 37.0 N(positive since it is applied to the right),
t = duration of applied force = 0.050 s,
m = mass of hockey puck = 0.160 kg,
v₁ = initial velocity of hockey puck = + 2,40 m/s (positive since it is moving to the right)
v₂ = final velocity of a hockey puck
So, making v₂ subject of the formula, we have
[tex]V_2=v_1+\dfrac{Ft}{m}[/tex]
substituting the values of the variables into the equation, we have
[tex]v_2=2.40+\dfrac{37\times 0.050}{0.160}[/tex]
[tex]v_2=2.40+11.56[/tex]
[tex]v_2=13.96\ \dfrac{m}{s}[/tex]
(b) If instead, a force of 13.3 N directed to the left is applied from t = 0 to t =0.050 s, what is the final velocity of the puck?
Since Impulse, I = Ft = m(v₂ - v₁)
where F = force applied = - 13.3 N(positive since it is applied to the right),
t = duration of applied force = 0.050 s,
m = mass of hockey puck = 0.160 kg,
v₁ = initial velocity of hockey puck = + 2,40 m/s (positive since it is moving to the right)
v₂ = final velocity of a hockey puck
So, making v₂ subject of the formula, we have
[tex]v_2=v_1+\dfrac{Ft}{m}[/tex]
substituting the values of the variables into the equation, we have
[tex]v_2=2.40+\dfrac{-13.3\times 0.050}{0.160}[/tex]
[tex]v_2=2.40-4.156[/tex]
[tex]v+2=-1.76\ \frac{m}{s}[/tex]
Thus
(a). The velocity of the puck is 13.96 m/s in the +x direction
(b). The final velocity of the puck is -1.76 m/s which is 1.76 m/s in the -x direction
To know more about velocity follow
https://brainly.com/question/4931057