102 is what percent more than 50

Answer:

81

Step-by-step explanation:

Evaluating v • w

Recall: Given vectors a and B in Cartesian plane, x, y and z

vector a = [ax ay az] and b = [bx by bz]

The dot product is :

a•b = axbx + ayby + azbz

Using the relation above,

v • w = (5*9) + (-4*-2) + (4*7)

v • w = 45 + 8 + 28

v • w = 81

Hence, v • w = 81

Answer:

1.cube

6faces

2.i can't understand it what is it but I think rectangle

3.i think it's pyramid if it is it has

5 faces

3. cone

1 face

Answer:

you but question you don't understand and some one will help you with it can take a bit though

Step-by-step explanation:

Answer:

45x³

Step-by-step explanation:

Given

3x × 15x²

= 3 × 15 × x × x²

= 45 × x³

= 45x³

Answer:

45x^3

Step-by-step explanation:

Multiply the digits that is 15 x 3

Then multiply the Variable x^2 and x

variables are added when multiplied keep this rule in mind always

Answer:

142

Step-by-step explanation:

Answer:

8.4 feet

I would appreciate Brainliest, but no worries.

Answer:

0.3594 = 35.94% probability that a truck will weigh less than 14.3 tons

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean is 15.8 tons, with a standard deviation of the sample of 4.2 tons.

This means that [tex]\mu = 15.8, \sigma = 4.2[/tex]

What is probability that a truck will weigh less than 14.3 tons?

This is the pvalue of Z when X = 14.3. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{14.3 - 15.8}{4.2}[/tex]

[tex]Z = -0.36[/tex]

[tex]Z = -0.36[/tex] has a pvalue of 0.3594

0.3594 = 35.94% probability that a truck will weigh less than 14.3 tons

[tex]it \: is \: simple \\ between \: 8 \: \: \: 10[/tex]

Answer:

A

Step-by-step explanation:

the between of two bumber of 9 is 8 & 10 8<9<10

Answer:

the value is 36

Step-by-step explanation: so you add

The value of q is 36 in the equation  q+9=45

Two or more expressions with an Equal sign is called as Equation.

The given equation is q+9=45

q plus nine equal to forty five

We have to find the value of q

Plus is the operator

q is the variable

Subtract 9 from both sides

q=45-9

q=36

Hence, the value of q is 36 in the equation  q+9=45

To learn more on Equation:

https://brainly.com/question/10413253

#SPJ7

Find the value of q in equation q+9=45

Answer:

299792 km in one second

Step-by-step explanation:

I think it's helps you

Answer:

You gave us the same numbers... so the range is the exact same...

Step-by-step explanation:

Answer:

(E) square

Step-by-step explanation:

because it's all side's are equal

A, B, C, D, E, F

A square is all of them :D

Answer:

2,4,6

3,6,9

Step-by-step explanation:

hope this helps

Answer:

B. 128 in³

Step-by-step explanation:

the volume of a rectangle prism: width × length × height

=> 4.1 × 8.2 × 3.9 = 131.118 => closest to 128

Answer:

8

Step-by-step explanation:

where the 2 lines cross would be the point at which they are the same. It appears as if their point of intersection is at 8 rentals for $14

Answer:

for finding a 2 it would be 2/12 then for finding a number greater than 1 it would be 10/12. 16.6666...%=2/12  10/12=83.33333333...%

Step-by-step explanation:

Answer:

[tex] \displaystyle x = 3.97[/tex]

Step-by-step explanation:

we are given a exponential equation

[tex] \displaystyle {3}^{x} = 78[/tex]

we want to figure out x

remember that,

[tex] \displaystyle \log_{a}( {a}^{c} ) = c[/tex]

thus

take [tex]\log_3[/tex] both sides:

[tex] \displaystyle \log_{3}( {3}^{x} ) = \log_{3}(78) [/tex]

use the formula:

[tex] \displaystyle x = \log_{3}(78) [/tex]

by using calculator

[tex] \displaystyle x = 3.97[/tex]

Answer:

The height for the original part is  10 cm

Never mind that the solid is standing at the angle of 60 degrees.

If you cut the bottom of the solid at the angle of 30 degrees, and put that part on the top of the solid,  

the height is going to be exactly 10 cm.

So, we have...      V = (10 * 4 * 3) / 8  

                     or     V = 5 * 2 * 1.5  

Step-by-step explanation:

Answer:c

Step-by-step explanation:

Answer:

Volume=11.25

Step-by-step explanation:

Answer:

C maybe

Step-by-step explanation:

Answer:

56

Step-by-step explanation:

Answer:

45.5

Step-by-step explanation:

5x7=35

3/2x3/2 = 4.5

7-3=4

4/2x3/2=6

35+4.5+6= 45.5

Answer:

answer is +4...

Step-by-step explanation:

when x=6, the expression becomes

2(6)^2+ 4-5

2(36)+(-1)

72-1=71

therefore 71+4 gives 75

Answer:

 a > -24

Step-by-step explanation:

3/4*a-(-18)>0

           3

Simplify   —

           4

  3        

 (— • a) -  -18  > 0

  4        

3a + 72  =   3 • (a + 24)

3 • (a + 24)

 ————————————  > 0

      4      

 a > -24

9514 1404 393

Answer:

  50.3 square units

Step-by-step explanation:

The circle has a diameter of 8 units, so a radius of 4 units. The area formula is ...

  A = πr²

  A ≈ 3.14159(4²) ≈ 50.265

The area of the circle is about 50.3 square units.

Answer:

Raul needs 42 yards of fence.

Step-by-step explanation:

Perimeter of a rectangle:

The perimeter of a rectangle of length l and width w is given by:

P = 2(l + w)

In this question:

The fence is rectangular.

12 yards long means that l = 12.

9 yards wide means that w = 9.

Perimeter:

P = 2(12 + 9) = 2(21) = 42

Raul needs 42 yards of fence.

Answer:

Step-by-step explanation:

From the given diagram,

i. ACBD - circle

ii. AB = secant

ii. CD = diameter

iii. EC, EB, ED, GF and GH - radii

iv. D, C, H and F - points of tangency

v. ACB - segment

vi. CBD - semicircle

vii. CBE, BDE and FHG - sectors

vii. E and G - centers of the given circles

viii. BH and DF - tangents

ix. DAB and HF - major segments

x. EDF, EBH, GHB - right angles

xi. DA, AC, CB, BD and FH - minor arcs