Answer:
6.80×10¯²⁶ J
Explanation:
From the question given above, the following data were obtained:
Frequency (f) = 102.5 MHz
Energy (E) =?
Next, we shall convert 102.5 MHz to Hz. This can be obtained as follow:
1 MHz = 10⁶ Hz
Therefore,
102.5 MHz = 102.5 MHz × 10⁶ Hz / 1 MHz
102.5 MHz = 1.025×10⁸ Hz
Finally, we shall determine the energy. This can be obtained as follow:
Frequency (f) = 1.025×10⁸ Hz
Planck's constant (h) = 6.63×10¯³⁴ Js
Energy (E) =?
E = hf
E = 1.025×10⁸ × 6.63×10¯³⁴
E = 6.80×10¯²⁶ J
2). H2S and SO2 as follows,(8pt)
H2S + SO2 ------>S + H2O
In a particular experiment, 7.95 g of sulfur is produced by the reaction of 7.5 g of H2S with 12.75 g of SO2.
What is the % yield of sulfur?
Answer: 75.7 % yield
Explanation:
The balanced chemical equation is:
[tex]2H_2S+SO_2\rightarrow 3S+2H_2O[/tex]
According to stoichiometry :
68.2 g of [tex]H_2S[/tex] will require = 64 g of [tex]SO_2[/tex]
Thus 7.5 g of [tex]H_2S[/tex] will require = [tex]\frac{64}{68.2}\times 7.5=7.0g[/tex] of [tex]SO_2[/tex]
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
As 68.2 g of give = 96 g of
Thus 7.5 g of [tex]H_2S[/tex] give =[tex]\frac{96}{68.2}\times 7.5=10.5g[/tex] of [tex]S[/tex]
% yield=[tex]\frac{\text{Actual yield}}{\text {Theoretical yield}}\times 100=\frac{7.95g}{10.5g}\times 100=75.7\%[/tex]
Thus 75.7 % yield is there.
Most cooking utensils are made up of aluminum because aluminum is _____
Explanation:
Cooking utensils, such as pots, pans and menu trays, are often made from aluminium because it is lightweight and conducts heat well, making it energy-efficient for heating and cooling. These properties also make it a preferred material for packaging.
A 9.56 sample of CuS is found to contain 6.35 g of copper what is the percent by mass of the copy and sulfur in this compound? (show your work)
Answer:
%Cu = 66.4%
%S = 33.6%
Explanation:
Step 1: Given data
Mass of CuS: 9.56 gMass of Cu: 6.35 gStep 2: Calculate the mass of S
The mass of CuS is equal to the sum of the masses of Cu and S.
mCuS = mCu + mS
mS = mCuS - mCu
mS = 9.56 g - 6.35 g = 3.21 g
Step 3: Calculate the percent by mass of each element
We will use the following expression.
%Element = mElement / mCompound × 100%
%Cu = mCu / mCuS × 100% = 6.35 g / 9.56 g × 100% = 66.4%
%S = mS / mCuS × 100% = 3.21 g / 9.56 g × 100% = 33.6%
What cell tissue helps carry messages? :
options:
muscular
nervous
connective
Answer:
Nervous
Explanation:
Nervous tissue is composed of two main cell types: neurons and glial cells. Neurons transmit nerve messages.
A student is given an antacid tablet that weighs 5.4630 g. The tablet is crushed and 4.3620 g of the antacid is added to 200. mL of simulated stomach acid. It is allowed to react and then filtered. It is found that 25.00 mL of this partially neutralized stomach acid required 13.6 mL of a NaOH solution to titrate it to a methyl red end point. It takes 27.7 mL of this NaOH solution to neutralize 25.00 mL of the original stomach acid. How much of the stomach acid (in mL) has been neutralized in the 25.00 mL sample that was titrated
Solution :
It is given that :
Weight of the antacid tablet = 5.4630 g
4.3620 gram of antacid is crushed and is added to the stomach acid of 200 mL and is reacted.
25 mL of the stomach acid that is partially neutralized required 13.6 mL of NaOH to be titrated for a red end point.
27.7 mL of [tex]$NaOH$[/tex] solution is equivalent to [tex]$25 \ mL$[/tex] of the original stomach acid. Therefore, 13.6 mL of NaOH will take x [tex]$\frac{25\text{ mL of original stomach acid}}{\text{27.7 mL of NaOH}}$[/tex]
= 12.27 ml of the original stomach acid.
How many mL of 0.25 M NaOH would have 0.18 moles of NaOH?
Answer:
720 mL
Explanation:
To answer this problem we'll use the definition of molarity:
Molarity = moles / litersWith that in mind we can calculate the volume in liters:
0.25 M = 0.18 moles / litersliters = 0.72 LFinally we convert liters to mL:
0.72 L * 1000 = 720 mLThus 720 mL of 0.25 M NaOH would have 0.18 moles of NaOH.
The total pressure in a container is 37.9 psi. There are two gases in the container. Gas A exerts a pressure of 18.4 psi. What is the pressure of gas B?
Answer:
19.5
Explanation: using dalton law pt=p1+p2+p3...
the total pressure is 37.9 so to get pressure of gas b subtract pressure of gas a from total pressure.37.9-18.4 gas b equals 19.5
3) How many grams of calcium hydroxide are necessary to create 49.5 mL of a 1.55 M solution?
Answer:
5.68g
Explanation:
6. The drawing shows Samir riding his mountain bike.
i) Draw a circle around the places on the drawing where there
should be a lot of friction.
ii) Explain why there should be a lot of friction in these places.
Answer:
You Need To Upload The Photo Then I Will Help You :)
Explanation:
the lens of the eye is clear so that light can go through.
A. True
B. False
Answer:
true
Explanation:
the clear lens over the eye is called the cornea
how many lone pairs are on the central atom in GeH4?
How will an increase in the average yearly ocean temperature most
likely affect Earth's weather?
Answer:
I'd Say B
Explanation:
Suppose you are provided with a 30.86 g sample of potassium chlorate to perform this experiment. What is the mass of oxygen you expect
to release upon heating?
Answer:
The mass of oxygen is 12.10 g.
Explanation:
The decomposition reaction of potassium chlorate is the following:
2KClO₃(s) → 2KCl(s) + 3O₂(g)
We need to find the number of moles of KClO₃:
[tex] \eta_{KClO_{3}} = \frac{m}{M} [/tex]
Where:
m: is the mass = 30.86 g
M: is the molar mass = 122.55 g/mol
[tex] \eta_{KClO_{3}} = \frac{30.86 g}{122.55 g/mol} = 0.252 moles [/tex]
Now, we can find the number of moles of O₂ knowing that the ratio between KClO₃ and O₂ is 2:3
[tex] \eta_{O_{2}} = \frac{3}{2}*0.252 moles = 0.378 moles [/tex]
Finally, the mass of O₂ is:
[tex] m = 0.378 moles*32 g/mol = 12.10 g [/tex]
Therefore, the mass of oxygen is 12.10 g.
I hope it helps you!
What pair of properties do all solids have?
Answer:
Has definite shape and volume
Solids have high melting point
Explanation:
Is the bond length in HCl the same as that in DCl? The wavenumbers of the J = 0 1 rotational transitions for H35Cl and 2H35Cl are 20.8784 and 10.7840 cm–1, respectively. Accurate atomic masses are H = 1.007825 amu, 2H = 2.0140 amu, and 35Cl = 34.96885 amu. Based on this information alone, can you conclude that the bond lengths are the same or different in the two molecules?
The lithosphere ______ part of the earth’s crust.
A. Gaseous
B. Solid
C. Water
D. Liquid
Answer:
The lithosphere solid part of the earth's crust
If a ball rolling down a hill is half way between the top and bottom, how much potential energy does the ball have compared to kinetic energy?
Answer:
The gravitational potential energy and kinetic energy of this ball should be equal (assuming that there is no energy loss due to friction.)
Explanation:
The ball loses gravitational potential energy as it rolls down the hill. At the same time, the speed of the ball increases, such that the ball gains kinetic energy.
If there is no friction on this ball (and that the ball did not deshape,) all the gravitational potential energy that this ball lost would be converted to kinetic energy.
If the gravitational field strength [tex]g[/tex] is constant throughout, the gravitational potential energy of an object in that gravitational field would be proportional to its height.
If [tex]m[/tex] denote the mass of this ball, the gravitational potential energy ([tex]\rm GPE[/tex]) of this ball at height [tex]h[/tex] would be [tex]{\rm GPE} = (m \cdot g) \cdot h[/tex], which is proportional to [tex]h\![/tex].
The value of [tex]g[/tex] near the surface of the earth is indeed approximately constant (typically [tex]g \approx 9.8\; \rm m \cdot s^{-2}[/tex].)
At halfway between the top and bottom of this hill, the height of this ball would be [tex](1/2)[/tex] of its initial value (the value when the ball was at the top of the hill.) Because the [tex]\rm GPE[/tex] of this ball is proportional to its height, at halfway down the hill, the [tex]\rm GPE\![/tex] of this ball would also be [tex](1/2)\![/tex] its initial value.
However, if there was no friction on this ball (and that the ball did not deshape,) that [tex](1/2)[/tex] of the initial [tex]\rm GPE\![/tex] of this ball was not lost. Rather, these [tex](1/2)\![/tex] of the initial [tex]\rm GPE[/tex] would have been converted to the kinetic energy ([tex]\rm KE[/tex]) of this ball.
Hence, when the ball is halfway down the hill:
[tex]\displaystyle \text{GPE halfway down the hill} = \frac{1}{2}\, \text{Initial GPE}[/tex].
[tex]\begin{aligned}& \text{KE halfway down the hill}\\ &= \text{Initial GPE} - \text{GPE halfway down the hill}\\ &= \text{Initial GPE} - \frac{1}{2}\, \text{initial GPE}\\ &= \frac{1}{2}\, \text{Initial GPE}\end{aligned}[/tex].
Therefore:
[tex]\begin{aligned}& \text{GPE halfway down the hill} \\ &= \frac{1}{2}\, \text{Initial GPE} \\ &= \text{KE halfway down the hill}\end{aligned}[/tex].
In other words, under these assumptions, when this ball is halfway down the hill, the gravitational potential energy and the kinetic energy of this ball would be equal.
The volume of water in a graduated cylinder is 88 mL. After a small object is placed in the cylinder, the volume increases to 100 mL. What is the volume of the object? First give your answer in milliliters, then in cubic centimeters.
Answer:
12mL or 12 cubic centimeters.
Explanation:
The displacement of water is equal to the volume of the object.
100 mL - 88 mL = 12 mL
One milliliter is equal to one cubic centimeter.
3.
Question
Many chemical warfare reagents readily convert into reactive 3-membered ring intermediates (although
maybe not the Joker's venom from the Batman comics). In turn, these intermediates can damage DNA by
what type of chemical reaction?
Your answer
O a. Elimination
O b. Sn1
OC. SN2
O d. None of the above
Answer:
I think it's letter B
Explanation:
Hope it helps correct if I'm wrong
Which combination will make a buffer?
A. NaOH and NaCl
B. KOH and KC1
C. HC1 and NaCl
D. CH3COOH and CH3COONa
Answer:
D
Explanation:
A buffer solution contains (1)a weak base and its salt, or (2) a weak acid and its salt.
So, the combination of the weak acid CH3COOH and its salt CH3COONa will make a buffer.
Answer:
D. CH3COOH and CH3COONa
Explanation:
A buffer is made of:
- a weak acid + its conjugate base
- a weak base + its conjugate acid
A. NaOH is a strong base
B. KOH is a strong base
C. HCl is a strong acid
Chlorine gas and solid phosphorus combine to produce phosphorus trichloride gas.
Write a balanced chemical equation for this reaction.
How many moles are contained in 325 gram sample of ammonium dichromate (NH4)2Cr2O7
Answer:
Hyba odpowiedzi c. Hyba
Mole can be defined as the number of molar mass units of the compound in the sample. The moles of ammonium dichromate in 325 grams sample is 1.29 mol.
What is molar mass?The molar mass can be given as the mass of each atom in the formula unit. The molar mass of ammonium chromate is given as:
[tex]\rm (NH_4)_2Cr_2O_7=2(N)+4\;\times\;2(H)+2(Cr)+7(O)[/tex]
Substituting the mass of each atom to identify the molar mass of ammonium chromate:
[tex]\rm (NH_4)_2Cr_2O_7=2(14)+4\;\times\;2(1)+2(52)+7(16)\\ (NH_4)_2Cr_2O_7=28+8+104+112\\ (NH_4)_2Cr_2O_7=252 \;g/mol[/tex]
The molar mass of ammonium dichromate s 252 g/mol. The moles of the compound in 325 g is given as:
[tex]\rm Moles=\dfrac{mass}{molar\;mass} \\\\Moles=\dfrac{325\;g}{252\;g/mol}\\\\ Moles=1.29\;mol[/tex]
The moles of ammonium dichromate in the sample are 1.29 mol. Thus, option c is correct.
Learn more about moles, here:
https://brainly.com/question/15209553
Which carbohydrate strengthens plant cells?
A. glucose
B. glycogen
C. cellulose
D. lactose
Answer:
a
Explanation:
Answer:
c
Explanation:
edge
Is this statement true or false?
All gymnosperms lose their leaves in the winter.
Answer:
they do fall off of themselves
Answer:
True!
Explanation:
They usually fall off in the winter
Cells are made of cells true or false
false
cells are made up of nucleus and cytoplasm and it's contained within the cell membrane
a'Zorria Ward
An elevator traveled 15 floors (150 ft) at a speed of 4.5 m/s. What additional information is needed to determine the velocity of the elevator?
the direction the elevator traveled
how long the elevator was stationary
O how many times the elevator stopped
O the total mass of the elevator plus anything in it
Answer:
Velocity includes Direction
So you need to know if it was going up or down
Explanation:
Which carbohydrate strengthens plant cells?
A. glucose
B. glycogen
C. cellulose
D. lactose
Answer: Its C
Explanation:
A solution is prepared by dissolving 27.7 g of CaCl2 in 375 g of water. The density of the resulting solution is 1.05 g/mL. The concentration of CaCl2 is ________% by mass. A solution is prepared by dissolving 27.7 g of CaCl2 in 375 g of water. The density of the resulting solution is 1.05 g/mL. The concentration of CaCl2 is ________% by mass. 6.24 6.88 7.22 0.0722 0.0688
Answer:
6.88%
Explanation:
Step 1: Given data
Mass of CaCl₂ (solute): 27.7 gMass of water (solvent): 375 gStep 2: Calculate the mass of the solution
The mass of the solution is equal to the sum of the masses of the solute and the solvent.
mSolution = mSolute + mSolvent
mSolution = 27.7 g + 375 g = 402.7 g
Step 3: Calculate the percentage by mass of CaCl₂
We will use the following expression.
%m/m = mass CaCl₂/mass Solution × 100%
%m/m = 27.7 g/402.7 g × 100% = 6.88%
Calculate the molarity of each of the following
solutions.
Part A
4.35 mol of LiCl in 3.60 L solution
Part B
29.43g of C6H12O6 in 1.37 L solution
Part C
34.5mg of NaCl in 119.1 mL of solution
Answer:
a. 1.21M
b. 0.119M
c. 0.00496M
Explanation:
Molarity, M, is an unit of concentration defined as the ratio between moles of solute and liters of solution:
a. 4.35 mol LiCl / 3.60L = 1.21M
b. 29.43gC6H12O6 * (1mol / 180.16g) = 0.1634moles / 1.37L = 0.119M
Molar mass C6H12O6: 180.16g/mol
c. 34.5mg NaCl = 0.0345g * (1mol / 58.44g) = 5.9x10⁻⁴moles / 0.1191L = 0.00496M
2 NaOH + H2SO4 → 2 H2O + Na2SO4
How many grams of water are produced from 203.50 grams of H2S04?
Answer:
[tex]m_{H_2O}=74.8gH_2O[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction, it is possible to realize there is a 1:2 mole ratio of sulfuric acid to water; thus, given the mass of the former and its molar mass (98.07 g/mol), it is possible to determine the mass of produced water as shown below:
[tex]m_{H_2O}=203.50gH_2SO_4*\frac{1molH_2SO_4}{98.07gH_2SO_4}*\frac{2molH_2O}{1molH_2SO_4} *\frac{18.02gH_2O}{1molH_2O}\\\\m_{H_2O}=74.8gH_2O[/tex]
Regards!