EXPLANATION
Let's see the facts:
Initial Amount = $1,030
Interest rate = 4% = 0.04 (in decimal form)
Compounding rate = Semiannually = 2 times by year
Time= 2 years
As we already know, the Formula to calculate the Principal is as follows:
[tex]P=I(1+\frac{r}{n})^{nt}[/tex]Substituting terms:
[tex]P=1030(1+\frac{0.04}{2})^{2\cdot2}[/tex]Adding numbers:
[tex]P=1,030(1.02)^4[/tex]Simplifying the power:
[tex]P=1,030\cdot1.0824=1,114.87[/tex]The Amount obtained is $1,114.87
Supposed a sample of 1453 tankers is drawn. Of these ships 989 did not have spills. Using the data construct the 99% confidence interval for the population proportion of all tankers that have spills each month. Ranch your answers to three decimal places
Sample: 1453
989= Without spills
99% Confidenece interval is given by:
[tex]ConfidenceInterval=Z_c*\sqrt[\placeholder{⬚}]{\frac{p(1-p)}{n}}[/tex]For 99% confidence, the Z_c is:
[tex]Z_c=2.576[/tex]And p is given by:
[tex]\begin{gathered} p=\frac{989}{1453}=0.68 \\ 1-p=0.319 \end{gathered}[/tex]Substituing:
[tex]ConfidenceInterval=2.576*\sqrt[\placeholder{⬚}]{\frac{0.68*(0.319)}{1453}}=0.0315[/tex]Finally, the way to find the intervals is given by:
[tex]p\pm ConfidenceInterval[/tex]ANSWER:
Upper endpoint:
[tex]0.68+0.0315=0.7115\approx0.712[/tex]Lower endpoint:
[tex]0.68-0.0315=0.6485\approx0.648[/tex]A bottle is 6.5 cm long. How far will 110 bottles reach if laid end to end? Give your answer in meters.
Solutions
We are given that
• each bottle is 6.5cm long
,• we have to lay 110 bottles next to each other
(i)Total length = lenght of a bottle * number of bottles
= 6.5 cm * 110
=715 cm
(ii) Convert 715 cm to meters :
• 100 cm = 1 meter
∴715 /100 = 7.15 meters
• This means that the bottles will reach 7.15 meters in length.
I need help with all A B C, I’m going to type the C QUESTION BECAUSE IT DIDNT APPER ON THE PIC
1. Class width:
The class width is given by the following expression:
[tex]Width=\frac{Range}{#intervals}[/tex]The number of intervals are: 4
And the range is:
[tex]Range=maximumV-MinimuV=509-210=299[/tex]Replacing:
[tex]Width=\frac{299}{4}=74.75\approx74[/tex]A) The class width is 74 (rounding to the smallest value).
2. Number of team attempted from 360 to 434:
B) The number of teams are: 4
3. According to the histogram, what is the total number of teams?
The total number of teams is given by:
[tex]Total=8+3+4+8=23[/tex]C) 23.
In which of the number line does the plotted point represent a number greater than -1 1/2 ?
Answer:
• The second number line
,• The fourth number line
,• The fifth number line.
Explanation:
In the number lines plotted:
0. In option A, the number plotted is -1½.
,1. In option B, the number plotted is -½.
,2. In option C, the number plotted is -2½.
,3. In option D, the number plotted is 2.
,4. In option E, the number plotted is 0.
,5. In option F, the number plotted is -2¾.
The numbers greater than -1½ in the options are -½, 2, and 0.
Therefore, the number lines that represent a number greater than -1 1/2 are:
• The second number line
,• The fourth number line
,• The fifth number line.
,•
An angle measures 12° less than the measure of its supplementary angleWhat is the measure of each angle?
Supplementary angles add up to 180°.
Assuming the angles are x and y, we have that
[tex]x+y=180\text{ ----------(1)}[/tex]If one angle is 12° less than the other, we have the equation to represent the statement to be
[tex]x-12=y\text{ ----------(2)}[/tex]We can solve both equations 1 and 2 simultaneously.
Let us substitute for y in equation 2 into equation 1:
[tex]\begin{gathered} x+x-12=180 \\ 2x=180+12 \\ 2x=192 \\ x=\frac{192}{2} \\ x=96 \end{gathered}[/tex]To find y, we can put the value of x into equation 2:
[tex]\begin{gathered} y=x-12 \\ y=96-12 \\ y=84 \end{gathered}[/tex]Therefore, the values for each angle are 84° and 96°
translate the sentence into an equation seven times the sum of a number and 8 equals 6use the variable c for the unknown number
c = unknown number
seven times the sum of a number and 8 equals 6
Seven times: multiply by 7
the sum of a number and 8:c+8
7 (c+8) = 6
A 25 foot ladder leans aganist the side of the house. The base of the ladder is 12 ft. from the house level ground. Find, the nearest degeee the measure of an angle that the ladder makes with the ground.
Let's begin by listing out the information given to us:
Hypotenuse = 25 ft
Base = 12 ft
We have two known sides & we are to find the angle the ladder makes with the ground. We will use Trigonometric Ratio (SOHCAHTOA). In this case, CAH
Cos C = 12/25⇒ Cos C = 0.48
C = 61.3 = 61
C = 61° (to the nearest degree)
5. When you calculate f(g(x)) and/or g(f(x)) to determine if they are inverses, whatshould your answer be in order to conclude that f(x) and g(x) are inverses?A. OB. 1C. 10D. x
If function f(x) and g(x) are inverse of each other, then value of function f(g(x)) and g(f(x)) must be equal to x.
So, the value of f(g(x)) and g(f(x)) must be equal to x, in order that f(x) and g(x) are inverses.
Answer: Option D
Which of the following is resistant (not affected by outliers)?A. SlopeB. LSRLC. Correlation coefficientD. Coefficient of determinationE. None of these are resistant measures
E. None of these are resistant measures
Explanation:Outliers of a given distribution are values that are very far apart from other values of the distribution. When outliers are used in a calculation, they strongly affect the accuracy of the results.
Note that the slope, LSRL, correlation coefficient, and correlation of determination always give relationship between two connected variables in different ways. They always take the form of a line.
Therefore, the inclusion of outliers in their calculations always affect the result gotten. Hence, all of them are affected by outliers. That is, none of them is outlier resistant.
Mr. Civitello is building a wall in the building with bricks. He has 1 bag of mortar which costs $6 and a briek costs $2 each. The school gave hima budget of $200. How many bricks can he use to build the wall?
We will model the situation with an equation, first lets stablish the value that we need to find: We need to find the quantity of bricks that Mr. Civitello can buy with $200, lets call this value B, but the say to us that he will not only need the bricks, he also need a bag of mortar which costs $6, then we put this information in a equation
[tex]2B+6=200\Rightarrow2B=194\Rightarrow B=\frac{194}{2}=97[/tex]so he can use 97 bricks to build the wall.
What exponent is assumed is we just have the number ? For example what is the exponent for the following:80 1 0 0 0 1000 8
Answer: 1
[tex]\begin{gathered} \text{According to the law of indices} \\ x^1\text{ = x} \\ \text{Therefore,} \\ 8^1\text{ = 8} \\ \text{Where the exponent is 1} \end{gathered}[/tex]can u please help me before it gives me a error on my screen and kicks me from the session
Given the following System of equations:
[tex]\begin{cases}x-5y=5 \\ 4x-11y=29\end{cases}[/tex]You can solve it using the Elimination method. Follow the steps shown below:
1. Multiply the first eqeuation by -4,
2. Add the equations.
3. Solve for the variable "y".
Then:
[tex]\begin{gathered} \begin{cases}-4x+20y=-20 \\ 4x-11y=29\end{cases} \\ ----------- \\ 9y=9 \\ y=\frac{9}{9} \\ \\ y=1 \end{gathered}[/tex]4. Now you must substitute the value of the variable "y" into any original equation.
5. Solve for the variable "x".
Then, you get:
[tex]\begin{gathered} x-5y=5 \\ x-5(1)=5 \\ x-5=5 \\ x=5+5 \\ x=10 \end{gathered}[/tex]The solution is:
[tex]\begin{gathered} x=10 \\ y=1 \end{gathered}[/tex]Is the expression x^3 X x^3 X x^3 equivalent to x^3X3X3 ? Why or why not?
The given expressions are
[tex]x^3\times x^3\times x^3\text{ and }x^{3\times3\times3}[/tex]Consider the first expression
[tex]x^3\times x^3\times x^3[/tex][tex]\text{Use the formula a}^n\times a^m\times a^p=a^{n+m+p},\text{ here a=x and n=3,m=3 and p=3}[/tex][tex]x^3\times x^3\times x^3=x^{3+3+3}[/tex]Adding 3,3 and 3, we get 9
[tex]x^3\times x^3\times x^3=x^9[/tex]Consider the second expression
[tex]x^{3\times3\times3}[/tex]Multiplying 3,3 and 3, we get 27
[tex]x^{3\times3\times3}=x^{27}[/tex]Equating both expressions as follows:
[tex]x^3\times x^3\times x^3=x^{3\times3\times3}[/tex]Substitute values, we get
[tex]x^9=x^{27}[/tex][tex]\text{Use the conditions if a}^n=a^mimplies^{}_{}\text{ n=m, here a=x and n=9, m=27.}[/tex][tex]9=27[/tex]It is not true.
Hence the given two expressions are not equivalent.
The reason is it doesn't satisfy the following condition
[tex]x^n\times x^m_{}=x^{n+m}[/tex]Functions defined by integrals, graphing calculator required. Please let me know if you have any questions regarding the materials, I'd be more than happy to help. Thanks!
The important detail here is to remember the fundamental theorem:
[tex]\int_a^bf\mleft(x\mright)dx=F\lparen b)-F\left(a\right)[/tex]There F is the primitive of f, but what happens when we take the derivative of F? We get f, then
[tex]\frac{d}{dx}F\left(x\right)=f\mleft(x\mright)[/tex]It's very important!
Let's say that know we have a function by integral, like
[tex]\int_0^xf\mleft(t\mright)dt[/tex]Using our theorem and the derivative
[tex]\frac{d}{dx}\int_0^xf\lparen t)dt=\frac{d}{dx}F\lparen x)-\frac{d}{dx}F\left(0\right)[/tex]Therefore!
[tex]\frac{d}{dx}\int_0^xf\mleft(t\mright)dt=f\mleft(x\mright)[/tex]That's the important property here!
After this quick introduction let's solve our problem, in fact, let's do it step by step because we can do small errors.
[tex]F\left(x\right)=\int_0^{2x}\tan\mleft(t^2\mright)dt[/tex]The problem asks for the value of the second derivative at 1! but first, let's find the first derivative, remember that
[tex]F\left(x\right)=\int_0^{2x}\tan\mleft(t^2\mright)dt=G\left(2x\right)-G\lparen0)[/tex]Then if we do the derivative we get
[tex]F^{\prime}\left(x\right)=\frac{d}{dx}G\left(2x\right)-\frac{d}{dx}G\left(0\right)[/tex]Where G is the primitive of tan(t²). Look at the right side, see that we must apply the chain rule on one term and the other term is constant, G(0) is a number then its derivative is zero! Hence
[tex]F^{\prime}\left(x\right)=\frac{d}{dx}G\left(2x\right)[/tex]Apply the chain rule
[tex]F^{\prime}\left(x\right)=2G^{\prime}\left(2x\right)[/tex]Now let's just use the fact that
[tex]G^{\prime}\left(t\right)=\tan\mleft(t^2\mright)[/tex]Then we can already solve the derivative! Where we have t we will input 2x
[tex]F^{\prime}\left(x\right)=2G^{\prime}\left(2x\right)=2\tan\mleft(4x^2\mright)[/tex]Now we already know the first derivative!
[tex]F^{\prime}\left(x\right)=2\tan\mleft(4x^2\mright)[/tex]Now we have the first derivative, we will do the derivative again, then
[tex]F^{^{\prime}^{\prime}}\left(x\right)=\frac{d}{dx}\lparen2\tan(4x^2))[/tex]Apply the chain rule again and remember that d/dx of tan(x) is sec²(x)
[tex]F^{^{\prime}^{\prime}}\left(x\right)=16x\cdot\sec^2\mleft(4x^2\mright)[/tex]Therefore the second derivative is
[tex]F^{^{\prime}^{\prime}}(x)=16x\sec^2(4x^2)[/tex]We want to evaluate it at x = 1, which means F''(1), then
[tex]F^{\prime}^{\prime}\lparen1)=16\sec^2\left(4\right)[/tex]Now we must use the calculator to evaluate sec²(4), if we use our calculator to do it we find
[tex]\begin{gathered} F"\left(1\right)=16*2.340550 \\ \\ F"\left(1\right)=37.4488 \end{gathered}[/tex]Then the final result is
[tex]F"\left(1\right)=37.449[/tex]4(6)+3(6)-x(8+9) -(2)
Simplify
4(6)+3(6)-x(8+9) -(2)
Multiplying and adding:
4(6)+3(6)-x(8+9) -(2) = 24 + 18 - x(17) - (2)
Operating the parentheses:
4(6)+3(6)-x(8+9) -(2) = 24 + 18 - 17x - 2
Simplifying:
4(6)+3(6)-x(8+9) -(2) = 40 - 17x
Please im studying and I need help with this question
To answer this question, we will use the following formula for simple interest:
[tex]F=A(1+rt),[/tex]and the following formula for annually compounded interest:
[tex]F=A(1+r)^t,[/tex]where t is the time in years, A is the initial amount, and r is the rate of interest as a decimal.
Substituting A=1600/2=800, r= 0.06, and t=5 in the formula for simple interest, we get:
[tex]F=800(1+0.06\times5)\text{.}[/tex]Simplifying the above result, we get.
[tex]F=1040.[/tex]Therefore, after 5 years, she earned:
[tex]1040-800=240.[/tex]Substituting A=1600/2=800, r= 0.05, and t=5 in the formula for compounded interest, we get:
[tex]F=800(1+0.05)^5.[/tex]Simplifying the above result, we get:
[tex]F=1021.03.[/tex]Therefore, after 5 years she will have earned:
[tex]1021.03-800=221.03.[/tex]Therefore, after 5 years she will have a total of:
[tex]461.03.[/tex]dollars.
Answer: $461.03.
based on this graph what is the rate that co2 increses per year
The graph is given where x -axis denotes year and y-axis denotes carbon-dioxide in ppm.
ExplanationTo determine the rate that co2 increases per year .
[tex]R=\frac{\Delta CO_2}{\Delta t}[/tex]Substitute the values from the graph.
[tex](1980,340),(2000,380)[/tex][tex]\begin{gathered} R=\frac{380-340}{2000-1980} \\ R=\frac{40}{20} \\ R=2 \end{gathered}[/tex]AnswerHence the rate that co2 increases per year is 2.
A four-sided figure is resized to create a scaled copy. The proportional relationship between any given side length in the original figure f, and the corresponding side length in the scaled copy, s, can be represented by the equations s=1/7f. What is the constant of proportionality from side lengths in the original figure to side lengths in the scaled copy?
Answer:
Given that,
A four-sided figure is resized to create a scaled copy.
The proportional relationship between any given side length in the original figure f, and the corresponding side length in the scaled copy, s, can be represented by the equations s=1/7f.
To find the constant of proportionality from side lengths in the original figure to side lengths in the scaled copy
The equation we get as,
[tex]f=7s[/tex]The constant of proportionality is 7.
An object is thrown upward from the top of an 80 -foot building with an initial velocity of 64 feet per second. The height h of the object after t seconds is given by the quadratic equation H= -16T^2+64T +80. When will the object hit the ground?
Answer:
The object will hit the ground 5 seconds after it is thrown.
Step-by-step explanation:
Given equation:
[tex]h(t)=-16t^2+64t+80[/tex]
where:
h is the height of the object from the ground (in feet).t is time (in seconds).The object will hit the ground when the height of the object is zero.
Therefore, to find the time when the object hits to ground, set the equation to zero and solve for t.
[tex]\begin{aligned}\implies -16t^2+64t+80&=0\\-16(t^2-4t-5)&=0\\t^2-4t-5&=0\\t^2-5t+t-5&=0\\t(t-5)+1(t-5)&=0\\(t+1)(t-5)&=0\\\\t+1&=0\implies t=-1\\t-5&=0\implies t=5\end{aligned}[/tex]
As t ≥ 0, t = 5 only.
Therefore, the object will hit the ground 5 seconds after it is thrown.
Amy, Corey, and John go to Central Park to throw a flying disk among themselves They stand at the positions as shown on the coordinate grid below. CENTRAL PARK Oy Amy Legend: 2 It Corey John Heach square on the grid represents an area of 2 feet by 2 feet how far apart are Corey and Amy? Round your answer to the nearest hundredth of a foot 22 67 feet 32 00 feet 45 34 feet 64.00 feet
Answer:
45.34 feet.
Explanation:
The location of Corey and Amy on the grid are:
Corey(-6,-9) and Amy(9,8).
We use the distance formula to find how far apart Corey and Amy are.
[tex]Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]Substituting the points:
[tex]\begin{gathered} Distance=\sqrt[]{(9-(-6)_{})^2+(8-(-9))^2} \\ =\sqrt[]{(9+6_{})^2+(8+9)^2} \\ =\sqrt[]{(15)^2+(17)^2} \\ =\sqrt[]{514} \\ =22.67 \end{gathered}[/tex]Since each square on the grid represents an area of 2 feet by 2 feet, we multiply the result by 2:
[tex]\begin{gathered} 2\times22.67 \\ =45.34\text{ feet} \end{gathered}[/tex]Corey and Amy are 45.34 feet apart.
3x degrees and 8x =70
We have a supplementary angle that means the sum of these angles will have as a result 180°
so we have the next equation in order to find x
3x+10+2x=180
we sum similar terms
5x+10=180
5x=180-10
5x=170
x= 170/5
x=34
At a football game, a vender sold a combined total of 172 sodas and hot dogs. The number of sodas sold was three times the number of hot dogs sold. Find the number of sodas and the number of hot dogs sold.Number of sodas sold:Number of hot dogs sold:
Let the number of sodas be s and the number of hotdogs be h
Since there are 172 sodas and hot dogs, then
Add s and h, then equate the sum by 172
[tex]s+h=172\rightarrow(1)[/tex]Since the number of sodas is three times the number of hot dogs
That means s is equal to 3h
[tex]s=3h\rightarrow(2)[/tex]Now, substitute s in equation (1) by equation (2)
[tex]\begin{gathered} 3h+h=172 \\ 4h=172 \end{gathered}[/tex]Divide both sides by 4
[tex]\begin{gathered} \frac{4h}{4}=\frac{172}{4} \\ h=43 \end{gathered}[/tex]Substitute h in equation 2 by 43
[tex]\begin{gathered} s=3(43) \\ s=129 \end{gathered}[/tex]The answer is
The number of sodas sold: 129
The number of hot dogs sold: 43
The monthly rents (in dollars) paid by 9 people are given below.(Note that these are already ordered from least to greatest.)940, 945, 975, 990, 1000, 1030, 1055, 1095, 1150Suppose that one of the people moves. Her rent changes from $940 to $985.Answer the following.
Solution
The question tells us the rent of 9 people is given as:
940, 945, 975, 990, 1000, 1030, 1055, 1095, 1150.
- We are told that the rent of 940 changes to 985 and we are asked by how much the mean and median rent change.
- In order to know how much the mean and median rents changed, we need to know the initial mean and median rent values.
- The mean of the data can be calculated using the formula below:
[tex]\begin{gathered} \mu=\frac{\sum ^n_{k=1}x_k}{n} \\ \text{where,} \\ k\text{ is the position of an individual data point.} \\ n\text{ is the number of people or total number of data points} \end{gathered}[/tex]- The median is the middle number of the data points when arranged in ascending or descending order.
- With these two definitions, we can proceed to find the initial mean and median.
Initial Mean:
[tex]\begin{gathered} \mu_1=\frac{940+945+975+990+1000+1030+1055+1095+1150}{9} \\ \\ \mu_1=\frac{9180}{9} \\ \\ \mu_1=1020 \end{gathered}[/tex]Initial Median:
The middle number is the 5th number. The 5th number is 1000. Thus, 1000 is the initial median.
Final Mean:
- We are told that the rent of 940 was replaced with 985. This change would definitely change the mean. Thus, we can calculate the new mean by simply replacing 940 with 985 in our mean calculation. This is done below:
[tex]\begin{gathered} \mu_2=\frac{985+945+975+990+1000+1030+1055+1095+1150}{9} \\ \mu_2=\frac{9225}{9} \\ \\ \mu_2=1025 \end{gathered}[/tex]Final Median
- We know that 940 has been replaced with 985. This means that we should rearrange the dataset to get the new Median.
- Arranging the dataset in ascending order, we have:
945, 975, 985, 990, 1000, 1030, 1055, 1095, 1150
- The new median is the number in the 5th position and the new median is 1000
- Thus, we can answer the questions asked of us.
Question 1:
[tex]\begin{gathered} Old\text{ Mean - New Mean} \\ \mu_1-\mu_2=1020-1025=-5 \\ \\ \text{Thus, the Mean increased by 5} \end{gathered}[/tex]Question 2:
[tex]\begin{gathered} \text{Old median - New Median} \\ 1000-1000=0 \\ \\ \text{Thus, the Median does not change} \end{gathered}[/tex]Final Answer
The Mean increased by 5
The Median does not change
Awaitress sold 18 ribeye steak dinners and 27 grilled salmon dinners, totaling $587.93 on a particular day. Another day she sold 26 ribeye steak dinners and 9 grilled salmondinners, totaling $584.62. How much did each tipe or dinner cost?The cost of ribeye steak dinners is and the cost of salmon dinners is $(Simplify your answer. Round to the nearest hundredth as needed)o
Explanation
Step 1
Let x represents the price of ribeye steak dinner
Let y represents the price of salon dinner
then,
Awaitress sold 18 ribeye steak dinners and 27 grilled salmon dinners, totaling $587.93 on a particular day, traslate
[tex]18x+27y=587.93\rightarrow Equation\text{ (1)}[/tex]Another day she sold 26 ribeye steak dinners and 9 grilled salmon
dinners, totaling $584.62, traslate
[tex]26x+9y=584.62\rightarrow Equation(2)[/tex]Step 2
solve the equations
a)isolate x in equation (1) and replace in equation (2) to get y
[tex]undefined[/tex]2 10 12 This graph represents the system of equations below: 3x + 4y = 22 2x + 6y= 22 What is the solution (the values of x and y that are true for both equations)? 8 ). Fill in the coordinates of the ordered pair: (
The solution (the values of x and y that are true for both solutions):
x = 4.4 and y = 2.2
The coordinates of the ordered pair = (4.4, 2.2)
Explanation:system of equations below: 3x + 4y = 22
2x + 6y= 22
From the graph, there is an intersection, a point where both graphs meet.
The point is x = 5, y = 2
3(5) + 4(2) = 15 + 8 = 23
2(5) + 6(2) = 10 + 12 = 22
The value of both sloution is different.
This could be due to the compressed form of the graph.
Plotting the graph using a graphing calculator, the point the x and y of both solutions are the same is at x = 4.4 and y = 2.2
3(4.4) + 4(2.2) = 22
2(4.4) + 6(2.2) = 22
Hence, the solution (the values of x and y that are true for both solutions ):
(x, y)= (4.4, 2.2)
x = 4.4 and y = 2.2
The coordinates of the ordered pair = (4.4, 2.2)
What is the value of relationship between x and y shown in the table may be expressed where k is the constant of proportionality, A A A / у 3 2.25 B) 1 0.75 2 1.5 5 3.75 D
The constant of proportionality can be obtained by:
[tex]k=\frac{y_2-y_1}{x_2-x_1}[/tex]Using the first two rows of the table we have:
[tex]\begin{gathered} k=\frac{0.75-2.25}{-1-(-3)} \\ =\frac{-1.5}{2} \\ =-0.75 \end{gathered}[/tex]Therefore, k=-0.75, this is equal to -3/4, hence the answer is B.
Find the 10th term of the sequence-9,2,13,24...
10th term = 90
Explanations:-9, 2, 13, 24, ....................
This is an Arithmetic Progression because it has a common difference
Let the common difference be represented as d
d = 2 - (-9)
d = 2 + 9
d = 11
The nth term of an Arithmetic Progression is given by the equation
[tex]\begin{gathered} T_n=\text{ a + (n-1)d} \\ \end{gathered}[/tex]where a is the first term
n is the number of terms
d is the common difference
To find the 10th term, substitute n=10, d = 11, and a = -9 into the equation for nth term given above
[tex]\begin{gathered} T_{10}=\text{ -9 + (10-1)11 } \\ T_{10}=\text{ -9 + 9(11)} \\ T_{10}=\text{ -9 + 99} \\ T_{10}=\text{ 90} \end{gathered}[/tex]The 10th term of the sequence is 90
Let X and Y be the following sets: X = {3,8,9,12} Y = {8,9} What is the set X\Y?
Answer:
X\Y={3,12}
Explanation:
Given the sets X and Y below:
[tex]\begin{gathered} X=\mleft\{3,8,9,12\mright\} \\ Y=\mleft\{8,9\mright\} \end{gathered}[/tex]The set X\Y is the set of elements in X but not in Y.
Therefore:
[tex]X\Y=\mleft\{3,12\mright\}[/tex]May I please get help with this For I am confused on where u should draw it in the other graph and I have tried multiple time but still couldn’t get the correct answer or draw it correctly
Solution
[tex]1\text{ unit = 6cm}[/tex]Now the new
[tex]1\text{ unit =2}cm[/tex]Further explanation
Current scale 1 unit represent 6cm
New scale 1 unit represent 2cm
The accompanying graph shows the heart rate, in beats per minute, of a jogger during a 4-minute interval. 3110 100 90 Heart Rate boats per minute) 80 70- 60 2 3 Time (minutes) What is the range of the jogger's heart rate during this interval? 14
The range is the values that the function takes in a certain interval (it could be all of the domain or, like in this case, a part of it).
The range goes from the minimum value (60 bpm) to the maximum value (110 bpm).
The range of the jogger is [60, 110] in this interval.