Answer:
Labor = $49.95
Hourly Charge = $33.3
Step-by-step explanation:
166.50 x .3 = $49.95
$49.95 x 2/3 = $33.3
$3000 is invested for a period of 3 years at a rate of 6% compound monthly. What will the balance in the account be at the end of 3 years?
Answer:
Hence, the total amount of money that the investor would have after 6 years will be $ 536.04 .
Step-by-step explanation
Answer:
Interest = $3573.048
Step-by-step explanation:
Given: $3000 is invested for a period of 3 years at a rate of 6% compound monthly. What will the balance in the account be at the end of 3 years?
The formula to compound interest is:
I = P(1 + R)^T
First, put in the terms:
I = $3000(1 + 6%)^3
Then calculate:
I = $3000(1 + [tex]\frac{6}{100}[/tex])^3
I = $3000(1 + 0.06)^3
I = $3000(1.06)^3, 1.06^3 = 1.191016
I = $3000 x 1.191016
I = $3573.048
The first term in a sequence is 13. The term to term rule is "take away 5" write an expression in terms of n , for the nth term of the sequence
9514 1404 393
Answer:
an = 13 -5(n -1)
Step-by-step explanation:
The "take away 5" rule means the common difference between terms is d=-5. For first term a1=13, the n-th term is ...
an = a1 +d(n -1)
an = 13 -5(n -1)
ill mark brainlist plss help
Answer:
18.5
Step-by-step explanation:
1.02 sinusoidal graph
WHAT IS THE AMPLITUDE OF THE SINUSOIDAL FUNCTION?
Enter your answer in the box.
___
Answer:
[tex]\displaystyle 5[/tex]
Step-by-step explanation:
[tex]\displaystyle \boxed{y = -5cos\:(\frac{39}{64}\pi{x} + \frac{\pi}{2}) + 1} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{32}{39}} \hookrightarrow \frac{-\frac{\pi}{2}}{\frac{39}{64}\pi} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{3\frac{11}{39}} \hookrightarrow \frac{2}{\frac{39}{64}\pi}\pi \\ Amplitude \hookrightarrow 5[/tex]
OR
[tex]\displaystyle \boxed{y = -5sin\:(\frac{39}{64}\pi{x} + \pi) + 1} \\ \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-1\frac{25}{39}} \hookrightarrow \frac{-\pi}{\frac{39}{64}\pi} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{3\frac{11}{39}} \hookrightarrow \frac{2}{\frac{39}{64}\pi}\pi \\ Amplitude \hookrightarrow 5[/tex]
As you can see, the right-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -5cos\:\frac{39}{64}\pi{x} + 1,[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph farthest to the left], accourding to the horisontal shift formula above. Also keep in mind that −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so be very careful with your calculations. So, between both photographs, we can tell that the cosine graph [centre right photograph] is shifted [tex]\displaystyle \frac{32}{39}\:unit[/tex]to the right, which means that in order to match the sine graph [photograph farthest to the left], we need to shift the graph BACKWARD [tex]\displaystyle \frac{32}{39}\:unit,[/tex]which means the C-term will be negative, and by perfourming your calculations, you get [tex]\displaystyle \boxed{-\frac{32}{39}} = \frac{-\frac{\pi}{2}}{\frac{39}{64}\pi}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = -5cos\:(\frac{39}{64}\pi{x} + \frac{\pi}{2}) + 1.[/tex]Intermediate, we have two sine graphs [centre left photograph and the photograph farthest to the left]. The left-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -5sin\:\frac{39}{64}\pi{x} + 1.[/tex]So, just like before, we need to figure out the appropriate C-term that will horisontally shift the graph back into position ["position", meaning shifting this sine graph back in plase (matching the sine graph in the photograph on the left)]. So, between the two photographs, we can tell that the left-centred sine graph is shifted [tex]\displaystyle 1\frac{25}{39}\:unit[/tex]to the right, which means that in order to match the leftward sine graph, we need to shift the graph BACKWARD [tex]\displaystyle 1\frac{25}{39}\:unit,[/tex]which means the C-term will be negative, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-1\frac{25}{39}} = \frac{-\pi}{\frac{39}{64}\pi}.[/tex]So, when shifted back into original position, the sine graph is [tex]\displaystyle y = -5sin\:(\frac{39}{64}\pi{x} + \pi) + 1.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-6\frac{22}{39}, 1],[/tex]from there to [tex]\displaystyle [-3\frac{11}{39}, 1],[/tex]they are obviously [tex]\displaystyle 3\frac{11}{39}\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle 3\frac{11}{39}.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, and in case you want to be certain, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 1,[/tex]in which each crest is extended five units beyond the midline, hence, your amplitude. Now... the sine graph in the photograph farthest to the right is the OPPOCITE of the sine graph in the photograph farthest to the left, and the reason for this is because of the negative inserted in front of the amplitude value. Whenever you insert a negative in front of the amplitude value of any trigonometric equation, the whole graph reflects over the midline. Keep this in mind moving forward. So, overall, no matter how far the graph shifts vertically, the midline will ALWAYS follow.
I am delighted to assist you at any time.
The bar graph shows the recommended number of hours of sleep for each age group.
How many hours of sleep are recommended for elementary-age children?
A. exactly 9 hours
B. exactly 10 hours
C. about 10 hours
D. about 12 hours
Answer:
Step-by-step explanation:
c
At his new job, Jeremiah can choose an hourly rate of $9 plus a $50 weekly bonus for opening the store, or an hourly rate of $10 per hour with no opening bonus. The equations model his salary options.
y = 9x + 50
y = 10x
What does x represent?
the number of times he opened the store
the number of hours worked per week
the total amount he earns each week
the amount of money earned per day
Answer:
The correct option is B
Step-by-step explanation:
just did the test on Ed.
find the solution of given expression
[tex] \sqrt{2545 \times 2545} [/tex]
Answer:
√{2545×2545}=√2545²=±2545
PLZ PLZ HELP!! BRAINLIEST IF RIGHT!!
Which point is located on the line represented by y = -3x + 4? A) (4,8) B) (4-8) C) (-4, 8) D) (-4,-8)
Answer:
B
Step-by-step explanation:
To determine which point lies on the line, substitute the x- coordinate of the point into the equation and if the value equals the y- coordinate of the point then it lies on the line.
A (4, 8)
y = - 3(4) + 4 = - 12 + 4 = - 8 ≠ 8 ← not on line
B (4, - 8 )
y = - 3(4) + 4 = - 12 + 4 = - 8 ← lies on line
C (- 4, 8 )
y = - 3(- 4) + 4 = 12 + 4 = 16 ≠ 8 ← not on line
D (- 4, - 8 )
y = - 3(- 4) + 4 = 12 + 4 = 16 ≠ - 8 ← not on line
The point lying on the line is (4, - 8 ) → B
Slove the system
Linear equations
by substation
Y+11=6x
2x+3y=7
Step-by-step explanation:
y = 6x-11
substitute y into 2x+3y=7
2x+3(6x-11)=7
2x + 18x-33 = 7
20 x = 7+33
x = 2
y?
y= 6(2)-11
y = 12-11 = 1
so, x = 2 and y = 1
Express 90 as the product of its prime factors.
Write the prime factors in ascending order.
|
I
Answer:
fafafasda
Step-by-step explanation:
wdwasdsa wr 1+11123121
I need help!
The foot of a ladder is placed 77 meters from a wall. If the top of the ladder rests 99 meters up on the wall, how long is the ladder?
Pretty pretty please if ur good at geometry!! Help a girl out!!
Answer:
Yes, They are similar by SSS PMK similar to LMQ.
Step-by-step explanation:
Similar triangles corresponding side lengths are in a proportion.
KM corresponds with MQ
PM corresponds with LM.
Set up this proportion.
[tex] \frac{km}{pm} = \frac{lm}{mq} [/tex]
[tex] \frac{15}{28} = \frac{21}{39.2} [/tex]
Cross multiply
[tex]588 = 588[/tex]
So the triangles ARE Similar.
PM corresponds with LMKM corresponds with MQPK corresponds with LQSo PMK is similar to LMQcan someone pls help i will mark u brainliest!? :)
Answer:
28.5
Step-by-step explanation:
Plzz mark brainlies thanks!!
in slope intercept form slope=2/7 y-intercept=0
Answer:
y=2/7x
Step-by-step explanation:
y=mx+b where m=slope and b=y-intercept
y=2/7x+0
y=2/7x
Poppy has one bag of beads. She is going to make three difference necklaces.
For the first necklace, she needs 3/8 of a bag of beads. For the second, she
needs 1/8 of a bag of beads. For the third, she needs 5/8 of a bag. What
fraction of a bag of beads does she need? Does she have enough? Explain.
Answer:
9/8 of a bag
she doesn't have enough beads.
Step-by-step explanation:
Bag of bead poppy has = 1
Bag of bead needed for necklace 1 = 3/8 of a bag
Bag of bead needed for necklace 2 = 1/8 of a bag
Bag of bead needed for necklace 3 = 5/8 of a bag
Total bag of beads needed = 3/8 + 1/8 + 5/8
= (3+1+5)/8
= 9/8
She needs 9/8 of a bag of bead
9/8 = 1 1/8
Therefore, she doesn't have enough beads.
4x2-24x+34=0 answer rounded to the nearest hundredth ASAP PLEASEEE ILL GIVE 20 POINTS AND A BRAINLIEST
Answer:
x=[tex]-3+\frac{1}{2}\sqrt{2}[/tex]
x=[tex]-3+\frac{-1}{2} \sqrt{2}[/tex]
Step-by-step explanation:
Someone help me with the last question please! Free brainliest
Answer: 6
Step-by-step explanation: [tex]log_{2} 64 = 6[/tex]
Here are two squares, A and B. A B The length of each side of square B is 4cm greater than the length of each side of square A. The area of square B is 70cm2 greater than the area of square A. Find the area of square B. Give your answer correct to 3 significant fi
Answer:
La²+8La+16 = La²+70
Step-by-step explanation:
8La+16 = 70
8La=70-16
La=54/8
La= 6.75
Area b = (6.75+4)*(6.75+4)
Area b = 10.75*10.75
Area b =115.563
The area of a square is the square of its side lengths
The area of square B is 116 centimeter square
Let the side length of square A be (a), and the side length of square B be (b)
So, we have:
[tex]\mathbf{A_a = a^2}[/tex]
[tex]\mathbf{A_b = b^2}[/tex]
From the question, we have:
[tex]\mathbf{A_b = 70 + a^2}[/tex]
[tex]\mathbf{b = 4 + a}[/tex]
Take square of both sides
[tex]\mathbf{b^2 = (4 + a)^2}[/tex]
[tex]\mathbf{b^2 = 16 + 8a+ a^2}[/tex]
Substitute [tex]\mathbf{b^2 = 16 + 8a+ a^2}[/tex] in [tex]\mathbf{A_b = b^2}[/tex]
[tex]\mathbf{A_b = 16 + 8a+ a^2}[/tex]
So, we have:
[tex]\mathbf{16 + 8a+ a^2 = 70 + a^2}[/tex]
Subtract a^2 from both sides
[tex]\mathbf{16 + 8a = 70}\\[/tex]
Subtract 16 from both sides
[tex]\mathbf{8a = 54}[/tex]
Divide both sides by 8
[tex]\mathbf{a = 6.75}[/tex]
Recall that:
[tex]\mathbf{A_b = 70 + a^2}[/tex]
So, we have:
[tex]\mathbf{A_b = 70 + 6.75^2}[/tex]
[tex]\mathbf{A_b = 115.5625}[/tex]
Approximate
[tex]\mathbf{A_b = 116}[/tex]
Hence, the area of square B is 116 centimeter square
Read more about areas at:
https://brainly.com/question/1658516
1. A coin is tossed and a single die is rolled. What is the theoretical
probability that the coin shows tails and the die shows an even number?
1/4
1/2
3/6
1/3
Answer:
A
Step-by-step explanation:
The chance the coin will show 'tails' is 1/2, since there are only 2 sides to a coin. The chance that the die will show an even number is also 1/2, since half of the numbers on a die are even, and half are odd. But, since both of these events depend on each other, or in other words, are dependent, we have to multiply both numbers. 1/2 x 1/2 = 1/4, therefore your answer is A.
Evaluate the expression 1/4y + 10 + y2
Answer:
9/4y+10
Step-by-step explanation:
1/4y+10+2y
9/4y+10
unless u meant y^2 then the answer would be
0.25(y+40+4y^2)
help!!!!? pleaseeeeee
Answer:
19.47
Step-by-step explanation:
I plugged it into a right triangle trig calculator
Answer:
HERE ARE SOME NOTES ON HOW TO DO these types of geo- problems and some more ! SORRY .
See attachment below!
Step-by-step explanation:
If your in High school Geometry, I could help with that and more!
If your someone who likes to have Notes.. I could send you some PDF's and more for Geometry!! I took Geometry and have good notes!
Please contact me for any concerns or questions!How does the graph of the
function g(x) = 3x + 4 differ from
the graph of f(x) = 3X?
It is moved (a). unit(s) (b)
Answer:
Math (way) is good if you wanna try that.
ee
Step-by-step explanation:
Answer:
the graph of f(x) = 7x. 3x + 4 = 7x
Which function best models the data?
Time, t (s) 0 0.5 1.0 1.5 2.0
Height, h (m) 3.0 6.8 8.2 7.0 3.3
A. h(t) = −15.9t2 + 2.99t + 10.22
B. h(t) = −16.1t2 + 10.22t + 2.99
C. h(t) = −5.03t2 + 10.22t + 2.99
D. h(t) = −5.03t2 + 2.99t + 10.22
Answer:
Step-by-step explanation:
Option c
Write a polynomial with 5 terms in standard form.
Identify the leading coefficient and the degree of the polynomial and name the polynomial.?
Answer:
Step-by-step explanation:
5x⁴ - 2x³ + 12x² + 24x - 26
Degree = 4
Leading term = 5x⁴
Leading coefficient = 5
Pleaseeeeee helpppppp fasttttttt 11 pointssss
Answer:
x = 9
m∠1 = m∠2 = 54°
Step-by-step explanation:
Two lines r and s are the parallel lines and a transversal line is intersecting these lines at two distinct points.
a). ∠1 ≅ ∠2 [Corresponding angles]
Therefore, m∠1 = m∠2
(63 - x)° = (72 - 2x)°
2x - x = 72 - 63
x = 9
b). m∠1 = (63 - x)°
= 63 - 9
= 54°
m∠2 = (72 - 2x)°
= 72 - 18
= 54°
Describe the transformation of the graph of f into the graph of g as either a vertical stretch or compression. (Be sure to include the stretching/compression factor as well f(x) = √x and g(x) =5√x
Is anyone able to help me with this question rq pls
Answer:
B. 196πx² + 392πx + 196π
Step-by-step explanation:
Total surface area of a sphere = 4πr²
Radius, r = 7x + 7
Total surface area of a sphere = 4πr²
= 4 * π * (7x + 7)²
= 4π * (7x + 7) * (7x + 7)
= 4π * 49x² + 49x + 49x + 49
= 4π * (49x² + 98x + 49)
= 196πx² + 392πx + 196π
B. 196πx² + 392πx + 196π
Choose the correct simplification of (8x + 3y)(2x - 4y). (5 points)
16x2 + 26xy + 12y2
16x2 + 26xy - 12y2
16x2 - 26xy + 12y2
16x2 - 26xy - 12y2
Answer: [tex]16x^{2} - 26xy - 12y^{2}[/tex]
Find the slope that passes. through the two points (5-8 and (4,6)
Answer:
-14
Step-by-step explanation:
Line is passing through the points (5, -8) and (4, 6).
Therefore,
[tex]slope = \frac{ - 8 - 6}{5 - 4} \\ \\ = \frac{ - 14}{1} \\ \\ = - 14[/tex]