12. A rocket, initially at rest on the ground, accelerates vertically. It accelerates uniformly until it
reaches a speed of 900 m/s after 30 s. After this period of uniform acceleration, the rocket
engine cuts out. During the next 90 s, the upward speed of the rocket decreases uniformly to
zero.
speed
m/s
times
plot a speed-time graph for the rocket for the first 120 s of it's flight ​

Answer:

Solids expand when they are heated.

Explanation:

It is possible to loosen caps on the screw  top bottles by dipping the cap briefly in hot water due to the fact that whenever a solid is heated, it expands. This means that the size of the solid Screw cap (in this our case) increases as the temperature does.

This increase in size causes it to slide off easily from the mouth of the bottle when a little twisting effort is applied.

Answer:

[tex]m1v1 + m2v2 = m1v3 + m2v4[/tex]

[tex](0.2 x 5) + (0.3 x 2) = (0.2 x 0) + (0.3 x v4)[/tex]

[tex]1.0 + 0.6 = 0 + 0.3v4,  0.3v4 = 1.6[/tex]

[tex]v4 = 1.6/0.3 = 5.3 m/s (2 sf)[/tex]

Hello!

[tex]\large\boxed{KE = 360 J}[/tex]

Use the equation KE = 1/2mv² to solve for the kinetic energy of the man.

We are given the mass and velocity, so plug these values into the equation:

KE = 1/2(80)(3²)

KE = 1/2(720)

KE = 360 J

Explanation:

The velocity of an object can be found by using the formula

[tex]v = \frac{d}{t} \\ [/tex]

d is the distance

t is the time taken

From the question we have

[tex] v = \frac{10}{5} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

W = 1526.43 J

Explanation:

Given that,

Force acting on a heavy crate, F = 325 N

The rope will make 29.0° angle with the horizontal

The distance covered by the crate, d = 5.37 m

We need to find the work done by the crate. The work done by an object is given by :

[tex]W=Fd\cos\theta\\\\=325 \times 5.37\times \cos29\\\\=1526.43\ J[/tex]

So, the required work done is 1526.43 J.

Answer:

Difference is given below.

Explanation:

The main difference between beneficial and harmful friction is that beneficial friction is necessary for performing different activities while on the other hand, harmful effect of friction is destroy different parts of products and machines. examples of beneficial friction are walking, holding things, rubbing hands to produce heat, running etc whereas examples of harmful friction are destruction of sole, slipping, tearing of machine's part, Wet roads and Mudslides etc.

Answer:

When a body is in uniform circular motion, its speed remains constant but its velocity, angular acceleration, angular velocity changes due to change in its direction.

Positive Work.

Negative Work.

Case of zero work done.

Displacement at an angle to the force.

Energy.

Kinetic Energy.

work is the energy transferred to or from an object via the application of force along a displacement. In its simplest form, it is often represented as the product of force and displacement.

Answer :

556.59 m/s.

Explanation:

Given that,

An airplane is traveling at an altitude of 15,490 meters.

A  box of supplies is dropped from its cargo hold. We need to find the velocity of cargo when it hits the ground.

The initial velocity of the box is 0 as it as at rest. Let v is the velocity of cargo when it hits the ground. We can find it using third equation of motion as follows :

[tex]v^2-u^2=2as[/tex]

Put u = 0 and a = g

[tex]v^2=2gs\\\\v=\sqrt{2gs} \\\\v=\sqrt{2\times 10\times 15490 } \\\\v=556.59\ m/s[/tex]

So, when it hits the ground its velocity is 556.59 m/s.

Answer:

v₀ = 16.55 m/s

Explanation:

This motion of the ball can be modeled as a projectile motion with following data:

R = Range of Projectile = 27.5 m

θ = Launch Angle = 50°

g = acceleration due to gravity = 9.81 m/s²

v₀ = Initial Speed of Ball = ?

Therefore, using formula for range of projectile, we have:

[tex]R = \frac{v_{0}^2\ Sin2\theta}{g}\\\\v_{0}^2 = \frac{Rg}{Sin2\theta}\\\\v_{0}^2 = \frac{(27.5\ m)(9.81\ m/s^2)}{Sin100^o}\\\\v_{0} = \sqrt{273.93\ m^2/s^2}[/tex]

v₀ = 16.55 m/s

Answer:

v = 14.7m/s

Explanation:

When the rock was at the top of cliff it had only Potential Energy and no Kinetic Energy but soon as the rock hit the ground all the Potential Energy converted into Kinetic Energy so by the Law of Conservation of Energy

[tex]Potential\ Energy = Kinetic\ Energy\\mgh=\frac{1}{2}mv^2\\\\v^2=\frac{2mgh}{m} \\\\v^2=2gh[/tex]

because all of that potential energy got converted into kinetic energy so we use the following formula as we need to calculate the velocity (v)

[tex]Potential\ Energy = Kinetic\ Energy\\mgh=\frac{1}{2}mv^2\\\\v^2=\frac{2mgh}{m} \\\\v^2=2gh[/tex]

here we know  [tex]g = 9.8m/s^2[/tex] because the rock was under free fall motion so it had acceleration of 9.8 but we do not the height which is h but we do know the formula:

[tex]Velocity=\frac{Displacement}{Time}[/tex]

the height h is the displacement so we replace height with the following:

[tex]Velocity=\frac{Displacement}{Time}\\\\Displacement=Velocity*Time\\h=vt[/tex]

now, insert h = vt in the above equation

[tex]v^2=2gh\\\\v^2=2g(vt)\\v^2=2vgt\\\\\frac{v^2}{v} =2gt\\\\v=2gt\\v=2(9.8)(0.75)\\v=14.7m/s[/tex]

Answer:

1mph

Explanation:

During the "U" part of the turn, the car would follow an approximately circular path, and if it's moving at a constant speed, it would have to accelerate toward the center of the circle in order to change its direction.

Answer:

I'll try and find the answer for you:)

Explanation:

I can't promise you I will though

Answer:

[sə′plī ‚vōl·tij] (electricity) The voltage obtained from a power source for operation of a circuit or device.

Explanation:

hope this helps :)

Answer: The pressure exerted on a surface by an object increases as the surface area of contact decreases.

Explanation:

Pressure measures the amount of force exerted per a given area of an object. From this definition, the surface area of the object and force applied, affects the pressure applied.

As Benny presses his finger against a map, nothing happens to the map because the force applied is affected by the increased surface area of his finger. However as he presses a thumbtack into the map using the same force the tack will probably poke a hole in the map because the small( decreased) surface area of the sharp point of the thumbtack produces a much larger pressure on the map than the area of Benny finger. I hope this helps, thanks!

Answer:

yo so if nobody helps ill gladly take the brainliest

Explanation:

Answer: 5N

Explanation:

Horizontal component is the force that is applied as a result of the diagonal application of force.

here in this case,

given diagonal force =10N.

angle= 30°

horizontal component is found using trigonometry..

so,

A vector of magnitude 10 N is provided.

It is at an angle of 30° to the + x axis.

To find:

The components along the x and y axis.

Calculation:

Along x axis:

F(x) = F cos(θ)

=> F(x) = 10 × cos(30)

=> F(x) = 10 (√3/2) = 5√3N

Along y axis:

F(y) = F sin(θ)

=> F(y) = 10 sin(30°)

=> F(y) = 10 × ½

=> F(y) = 5 N.

Additional information:

1. A vector is a quantity that can be defined with both magnitude and direction.

2. Since force is a vector, we are able to break it down into components along chosen axis.

Answer:

3N

Explanation:

Answer:

Mass

Explanation:

The mass of an object expresses the amount of matter it comprises. Which implies that objects with higher mass contains higher matter compared to objects with lesser masses. Thereby it determines the measure of inertia experienced by an object when a force is applied to change its direction of motion, or to set it in motion when at rest, or bring it to rest when in motion.

The mass of an object the same no matter its location, and it is measured in kilograms.

Answer:

credits to the real owner of the answer I just found it here

Answer:

a) The centripetal acceleration of the car is 0.68 m/s²

b) The force that maintains circular motion is 940.03 N.

c) The minimum coefficient of static friction between the tires and the road is 0.069.

Explanation:

a) The centripetal acceleration of the car can be found using the following equation:

[tex] a_{c} = \frac{v^{2}}{r} [/tex]

Where:

v: is the velocity of the car = 51.1 km/h

r: is the radius = 2.95x10² m

[tex] a_{c} = \frac{(51.1 \frac{km}{h}*\frac{1000 m}{1 km}*\frac{1 h}{3600 s})^{2}}{2.95 \cdot 10^{2} m} = 0.68 m/s^{2} [/tex]

Hence, the centripetal acceleration of the car is 0.68 m/s².

b) The force that maintains circular motion is the centripetal force:

[tex] F_{c} = ma_{c} [/tex]

Where:

m: is the mass of the car

The mass is given by:

[tex] P = m*g [/tex]

Where P is the weight of the car = 13561 N

[tex] m = \frac{P}{g} = \frac{13561 N}{9.81 m/s^{2}} = 1382.4 kg [/tex]

Now, the centripetal force is:

[tex] F_{c} = ma_{c} = 1382.4 kg*0.68 m/s^{2} = 940.03 N [/tex]

Then, the force that maintains circular motion is 940.03 N.

c) Since the centripetal force is equal to the coefficient of static friction, this can be calculated as follows:

[tex] F_{c} = F_{\mu} [/tex]

[tex] F_{c} = \mu N = \mu P [/tex]

[tex] \mu = \frac{F_{c}}{P} = \frac{940.03 N}{13561 N} = 0.069 [/tex]

Therefore, the minimum coefficient of static friction between the tires and the road is 0.069.

I hope it helps you!                

sorry

Explanation:

Sorry

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 3.2 × 3.1

We have the final answer as

Hope this helps you

Answer:

9.92

Hope I helped

Explanation:

Its organism are one cell I think

Sulfur trioxide/Formula

SO3

this is what i looked up and got

Answer:

5400

Explanation:

i calculated it

Big  brain