12. The distance an object has traveled when starting at an initial velocity is given by the equation:
d = vit +at². In the equation, vi represents the initial velocity, t represents the time traveled, and
a represents the acceleration. Solve the equation for a.

The equivalent resistance between points A and B is 0.837Ω.

Resistors in series are connected end-to-end so that the current flows through them in sequence. The equivalent resistance of resistors in series is the sum of their individual resistances.

The formula for equivalent resistance of resistors in series: R_eq = R_1 + R_2 + ... + R_n

Resistors in parallel are connected across each other so that the voltage is the same across each resistor. The equivalent resistance of resistors in parallel is the reciprocal of the sum of the reciprocals of their individual resistances.

The formula for equivalent resistance of resistors in parallel: 1/R_eq = 1/R_1 + 1/R_2 + ... + 1/R_n

Here in the Fig.

we can simplify the second set of resistors in parallel (4.8 Ω, 3.3 Ω, and 8.1 Ω) using the same formula:

1/Req1 = 1/4.8 + 1/3.3 + 1/8.1

Req1=1.575Ω

This Req1 connected series with 6.3Ω, then Req of this two resistance given by:

Req2= 1.575Ω+ 6.3Ω

Req2=7.875Ω

Once again this req2 makes the parallel with the other two resistance i. e 1.5Ω and 2.5Ω

Their equivalent resistance  is given by,

1/Req3=1/1.5 + 1/2.5 + 1/7.875

Req3=0.837Ω

Hence, The equivalent resistance between points A and B is 0.837Ω

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The gravitational potential energy of the object will be two times greater than the elastic potential energy of the spring after the distances are doubled. The correct option is A.

The gravitational potential energy of an object is given by the formula:

PE = mgh

Where m is the mass of the object, g is the acceleration due to gravity and h is the height of the object above the reference point.

In this case, the height of the object is doubled, so the potential energy will also be doubled. Therefore, when the distance is doubled, the gravitational potential energy of the object will be two times greater than before.

The elastic potential energy of a spring is given by the formula:

PE = 1/2 kx^2

Where k is the spring constant and x is the displacement of the spring from its equilibrium position.

In this case, the displacement of the spring is doubled, so the potential energy will be four times greater than before. Therefore, option B is not correct.

Option C is also not correct because the potential energy of the spring will be four times greater than the gravitational potential energy of the object.

Option D is not correct because the potential energies of the object and the spring are not equal to one another when the distances are doubled.

Therefore, The correct answer is option A.

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The speed at the top of the loop is √gR.

Let the starting point be A, the lower point of loop be B and the top of loop be C.

So, at A the car is having only potential energy.

PE = mgh

At B, the kinetic energy,

KE = 1/2 mv²

a) At point C,

mv²/R = mg

The velocity at the top point, v(C)

v(top) = √gR

b) According to Conservation of energy, at B and C,

1/2 mv(B)² = 1/2 mv(C)² + mg(2R)

v(B)² = gR + 4gR

Therefore, v(B) = √5gR

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The frequency of Az string is 0.818Hz.

Recall the formula:

f = (1/L) * sqrt(T/μ)

where

L = the length of the string,

T = the tension in the string,

μ = the linear mass density of the string,

f = the frequency.

Given

L = 0.65m, μ = 0.0085kg/m, and we want to find the frequency f.

To find the tension T, we can use the frequency of C₂, which is given as 65.4 Hz. The frequency of C₂ is related to the frequency of Az by the formula:

f(Az) = f(C₂) * 2^(n/12)

where n is the number of semitones between C₂ and Az. We can count the number of semitones using a piano keyboard or a frequency chart.

Az is two octaves lower than C₂, so n = -24.

Substituting the values, we get:

f(Az) = 65.4 Hz * 2^(-24/12) = 0.818 Hz

b) The wave speed of the second harmonic wave on the string can be found using the formula:

v = fλ

where

f = the frequency of the wave

λ = the wavelength

For the second harmonic wave, the wavelength is twice the length of the string, i.e:

λ = 2L = 1.3 m.

Substituting the values, we get:

v = (2f) * L = 2 * 0.818 Hz * 0.65 m ≈ 1.063 m/s

c) The tension in the string is given by the formula:

T = μ * f^2 * L^2

Substituting the values, we get:

T = 0.0085 kg/m * (0.818 Hz)^2 * (0.65 m)^2 ≈ 0.034 N

Therefore, the tension in the string is approximately 0.034 N.

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Answer:Calculate the work done using:

work done (in joules) = force (in newtons) x distance moved (in metres)

To practice calculations involving force, distance and work done.

Explanation: I hope this helps srry if I'm wrong

Answer: Carbon is the chemical backbone of life on Earth. Carbon compounds regulate the Earth’s temperature, make up the food that sustains us, and provide energy that fuels our global economy.

A diagram of the carbon cycle with arrows showing the movement of carbon through a landscape with plants and animals, mountains and a volcano, a river leading to the ocean, and an industrial area. Carbon moves in and out of our atmosphere, ocean, waterways, and soil through burning fossil fuels, precipitation, fires, vegetation, volcanoes, and organic processes.

The carbon cycle. (Image credit: NOAA)

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Most of Earth’s carbon is stored in rocks and sediments. The rest is located in the ocean, atmosphere, and in living organisms. These are the reservoirs through which carbon cycles.

This graph shows the monthly mean carbon dioxide measured at Mauna Loa Observatory, Hawaii, the longest record of direct measurements of CO2 in the atmosphere.

Climate change: Atmospheric carbon dioxide

Carbon dioxide concentrations are rising mostly because of the fossil fuels that people are burning for energy.

Carbon storage and exchange

Carbon moves from one storage reservoir to another through a variety of mechanisms. For example, in the food chain, plants move carbon from the atmosphere into the biosphere through photosynthesis. They use energy from the sun to chemically combine carbon dioxide with hydrogen and oxygen from water to create sugar molecules. Animals that eat plants digest the sugar molecules to get energy for their bodies. Respiration, excretion, and decomposition release the carbon back into the atmosphere or soil, continuing the cycle.

The ocean plays a critical role in carbon storage, as it holds about 50 times more carbon than the atmosphere. Two-way carbon exchange can occur quickly between the ocean’s surface waters and the atmosphere, but carbon may be stored for centuries at the deepest ocean depths.

Rocks like limestone and fossil fuels like coal and oil are storage reservoirs that contain carbon from plants and animals that lived millions of years ago. When these organisms died, slow geologic processes trapped their carbon and transformed it into these natural resources. Processes such as erosion release this carbon back into the atmosphere very slowly, while volcanic activity can release it very quickly. Burning fossil fuels in cars or power plants is another way this carbon can be released into the atmospheric reservoir quickly.

A research vessel ploughs through the waves, braving the strong westerly winds of the Roaring Forties in the Southern Ocean, in order to measure levels of dissolved carbon dioxide in the surface of the ocean.

Southern Ocean confirmed as strong carbon dioxide sink

New research utilizes airborne measurements of carbon dioxide to estimate ocean uptake.

Changes to the carbon cycle

Human activities have a tremendous impact on the carbon cycle. Burning fossil fuels, changing land use, and using limestone to make concrete all transfer significant quantities of carbon into the atmosphere. As a result, the amount of carbon dioxide in the atmosphere is rapidly rising; it is already greater than at any time in the last 3.6 million years. The ocean absorbs much of the carbon dioxide that is released from burning fossil fuels. This extra carbon dioxide is lowering the ocean’s pH, through a process called ocean acidification. Ocean acidification interferes with the ability of marine organisms (including corals, Dungeness crabs, and snails) to build their shells and skeletons.

An aerial view of Century City section of Los Angeles, California.

Atmospheric carbon dioxide rebounds as global pollution rates approach pre-Covid levels

Global carbon emissions are projected to bounce back to after an unprecedented drop caused by the response to the coronavirus pandemic, according to an annual report by the Global Carbon Project.

EDUCATION CONNECTION

Take a bite of dinner, breathe in air, or a drive in a car — you are part of the carbon cycle. The resources in this collection provide real world examples of the changes occurring in the cycle. There is much to learn about this essential topic, and some of the resources highlight exciting career opportunities in this field of study.

Explanation: learn from a middle schooler like me smart

Carbon was formed in stars through nuclear fusion and scattered into space when the star died. Carbon was incorporated into organic molecules through photosynthesis and eventually became part of animals' bodies. The carbon cycle involves the uptake of carbon dioxide by plants, transfer to animals, and release back into the atmosphere through respiration and decomposition, and human activities have disrupted this cycle.

Carbon was formed in the universe through nuclear fusion reactions that took place in the cores of stars. These reactions fused lighter elements into heavier ones, including carbon. When the star eventually died in a supernova explosion, the carbon and other elements were scattered into space.

The carbon, along with other elements, eventually formed clouds of gas and dust that coalesced to form new stars and planets. On our planet, carbon was incorporated into organic molecules through photosynthesis by plants and other photosynthetic organisms. These organic molecules were then consumed by animals, which allowed the carbon to become part of their bodies.

The carbon cycle is the process by which carbon moves through the Earth's atmosphere, oceans, and biosphere. This cycle involves the uptake of carbon dioxide by plants through photosynthesis, the transfer of carbon from plants to animals through the food chain, and the release of carbon back into the atmosphere through respiration and decomposition. Human activities, such as the burning of fossil fuels, have disrupted this cycle, leading to increased levels of carbon dioxide in the atmosphere and contributing to climate change.

Therefore, Nuclear fusion in stars produces carbon, which is then released into space when the star dies. By photosynthesis, carbon was added to organic molecules, eventually becoming a component of animal bodies. Human activities have interrupted the carbon cycle, which involves the intake of carbon dioxide by plants, its transport to animals, and its release back into the atmosphere through respiration and decomposition.

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The energy lost to friction and air resistance is 186 J.

option B.

The energy lost to friction and air resistance is calculated from the change in the mechanical energy of the pendulum.

The initial potential energy of the pendulum at the initial position is calculated as;

PEi = mghi

where;

P.Ei = 12 kg x 9.8 m/s² x 20 m

P.Ei = 2,352 J

The final kinetic energy of the pendulum is calculated as follows;

K.Ef = 0.5 x 12 kg x (19 m/s)²

K.Ef = 2,166 J

ΔE = 2,166 J - 2,352 J

ΔE = -186 J

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The super red giant star is the aging star and it is a dying star in the final stage of stellar evolution. From the burst of the super red giant star, magnesium is formed from the core of the red giant star.

The super red giant star has a larger mass and produces greater gravitational pressure. The giant red star is in the final stage of dying and the core of the red star has heavier elements like nitrogen, carbon, etc.

In the core of stars, nuclear fusion takes place. Nuclear fusion is the process of two lighter nuclei fusing or joining together to form a heavier nucleus.

The hydrogen fuses to form helium and helium fuses together to form carbon atoms. Carbon atoms fuse together to form oxygen atoms and it forms heavier elements like magnesium and iron.

Hence, from the burst of a super red giant star, heavier elements like magnesium, iron, carbon, and helium ions are formed.

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The gas's final volume is 0.129 m³ times its beginning volume.

The work done by the gas is -2.6226 kJ, indicating that work is being done on the gas.

The transmitted thermal energy is also -2.6226 kJ.

Using the ideal gas law to solve for the final volume of the gas:

PV = nRT

where P = pressure, V = volume, n = number of moles, R = gas constant, and T = temperature.

Since the process is isothermal, the temperature remains constant at 170 K, therefore:

P₁V₁ = P₂V₂

where P₁ and V₁ = initial pressure and volume, and P₂ and V₂ = final pressure and volume.

Substituting the given values:

(0.23 atm)(V₁) = (1.78 atm)(V₂)

Solving for V₂:

V₂ = (0.23/1.78)V₁ = 0.129 V₁

So the final volume of the gas is 0.129 times the initial volume.

To find the work done by the gas, use the formula:

W = -∫PdV

where the integral is taken from the initial volume V₁ to the final volume V₂. Since the process is isothermal:

W = -nRT ln(V₂/V₁)

Substituting the given values:

W = -(2 mol)(8.31451 J/K·mol)(170 K) ln(0.129) = -2622.6 J = -2.6226 kJ

So the work done by the gas is -2.6226 kJ, which means work is done on the gas.

The thermal energy transferred during the process is equal to the work done by the gas, since the process is isothermal and there is no change in internal energy. Therefore, the thermal energy transferred is also -2.6226 kJ.

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The maximum height the container can be lifted before bursting is  970 meters above sea level, and the maximum depth the container can be taken before imploding is 35 meters below the surface of the ocean.

Gauge pressure is the pressure measured relative to the atmospheric pressure at a particular location. It does not take into account the atmospheric pressure and only represents the pressure above or below the atmospheric pressure.

A) To find the maximum height h in meters above the ground that the container can be lifted before bursting, we need to find the new gauge pressure at this higher altitude. We can use the relationship between pressure and altitude:

P = P0 + ρgh

where P is the gauge pressure at the new altitude, ρ is the density of air, g is the acceleration due to gravity (assumed constant), and h is the height above sea level. Solving for h, we get:

h = (P - P0) / (ρg)

We know that the maximum pressure difference the container can withstand is ΔPmax = 2.35 × 105 Pa, so the new gauge pressure at the higher altitude can be found by adding this to the sea level pressure:

P = Pa + ΔPmax = 1.01 × 105 Pa + 2.35 × 105 Pa = 3.36 × 105 Pa

Substituting this into the equation above, along with the given values for ρ and g, we get:

h = (3.36 × 105 Pa - 2.02 × 105 Pa) / (1.20 kg/m3 × 9.81 m/s2) ≈ 970 meters

So, the maximum height the container can be lifted before bursting is approximately 970 meters above sea level.

B) To find the maximum depth dmax in meters below the surface of the ocean that the container can be taken before imploding, we need to find the new gauge pressure at this depth. We can use a similar equation to the one used above, but with the density of seawater instead of the density of air:

P = P0 + ρsgd

where g is the acceleration due to gravity (assumed constant), d is the depth below the surface of the ocean, and ρs is the density of seawater. Solving for d, we get:

d = (P - P0) / (ρsg)

We know that the maximum pressure difference the container can withstand is ΔPmax = 2.35 × 105 Pa, so the new gauge pressure at the maximum depth can be found by subtracting this from the sea level pressure:

P = P0 - ΔPmax = 2.02 × 105 Pa - 2.35 × 105 Pa = -0.33 × 105 Pa

(Note that this gives a negative value for pressure, which means the container will implode rather than burst.)

Substituting this into the equation above, along with the given values for ρs and g, we get:

d = (-0.33 × 105 Pa - 1.01 × 105 Pa) / (1025 kg/m3 × 9.81 m/s2) ≈ -35 meters

So, the maximum depth the container can be taken before imploding is approximately 35 meters below the surface of the ocean.

Therefore, The container can be lifted to a maximum height of 970 meters above sea level without bursting, and it can be submerged to a maximum depth of 35 meters without imploding.

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The weight of the box is determined as 21.56 N.

The weight of the box is calculated by applying Newton's second law of motion as shown below;

F = mg

where;

The weight of the box is calculated as follows;

W = 2.2 kg x 9.8 m/s²

W = 21.56 N

Thus, the weight of the box is determined by multiplying the mass and acceleration due to gravity.

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The acceleration of the object is  2.5 m/s^2

The idea that should be at the back of your mind when you hear the use of the term acceleration is the change in the velocity of the object with respect to the time.

In this case, we have to look at the graph that we have been given in the question. It is a graph of the velocity against the time and the slope of the graph is the acceleration of the motion that is under consideration.

a = 100 - 0/40 - 0

= 2.5 m/s^2

We have the acceleration as 2.5 m/s^2

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Sentences 20, 21, 22, and 23 can be completed as follows:

20. B. Ultraviolet is used to observe star birth and far away galaxies.

21.  D. Radio waves is used to observe the depths of the Milky Way galaxy.

22. C. Gamma rays are used to observe supernova explosions and radioactive decay.

23. C. Wernher von Braun developed the V-2 rocket.

Rays are beams of light and radiation that can be harmful when used wrongly or advantageous for scientific purposes.

As scientists study extraterrestrial bodies, they often have to use rays for their findings. Gamma rays are known for their use in observing supernova explosions. Also, Wernher Braun is attributed to the development of the V-2 rocket.

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The volume of the solid immersed in the liquid is  5 x 10⁻⁵ m³.

The volume of the solid is calculated as follows;

V = (Ws - Wa) / (ρg)

where;

Ws = 0.2 kg x 9.8 m/s²

Ws = 1.96 N

Wa = 0.16 kg x 9.8 m/s²

Wa = 1.568 N

ρ = 0.8 x 1000 g/km³ = 800 kg/m³

The volume is calculated as;

V = (1.96 - 1.568 )/(800 x 9.8)

V = 5 x 10⁻⁵ m³

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The vertical reaction force R can be calculated as R = -8.1*m N, where the negative sign indicates that it acts in the opposite direction to the initial acceleration (which is upward in this case).

A reaction force is a force that is equal in magnitude but opposite in direction to an action force. It arises from Newton's third law of motion, which states that every action has an equal and opposite reaction. Whenever an object exerts a force on another object, the second object exerts a reaction force on the first object in the opposite direction.

The vertical reaction of the spacecraft on the astronaut is equal in magnitude but opposite in direction to the force that the astronaut exerts on the spacecraft, according to Newton's third law of motion.

The initial vertical acceleration of the spacecraft is 5g, so the force that the spacecraft exerts on the astronaut is F = ma = m(5g), where m is the mass of the astronaut.

Using the acceleration due to gravity on the moon, g = 1.62 m/s^2, we can calculate the force as:

F = m*(5g) = m*(51.62) = 8.1m N

Therefore, the vertical reaction of the spacecraft on the astronaut is equal in magnitude but opposite in direction, so it is:

R = -8.1*m N

Note that the negative sign indicates that the reaction force is in the opposite direction to the initial acceleration, which is upward in this case.

Hence, R = -8.1*m N is the reaction force.

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The statement that is true about the periodic table is The periodic table is organized by atomic number. Option B

The periodic table is arranged by atomic number, which denotes the number of protons in an atom's nucleus.

Elements are organized in ascending atomic number sequence from left to right and top to bottom.

Given that the elements in the same column (group) often have comparable qualities due to the same amount of valence electrons, this organization allows the elements to be categorized based on their chemical properties.

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The heat supplied the engine per second is 736 kJ and the heat discarded by the engine per second is 526 kJ.

A gasoline engine has a power output of 210kW and the effciency of engine is 28.5%. The Work done of the engine in time 1s is,

Work done = power × time

                   = 210 × 1

                  = 210 kJ

The work done of the engine is,W = 210 kW.

The efficiency of the engine,η = Work / (Qh)

Qh is the heat suppllied to the engine, η is the efficiency and is equal to 28.5 %

Qh = 210kW / (0.285)

    = 736.8 kW

The heat discarded by the engine,

(Qc) = Qh - W'

       =  736.8 - 210

       =526.8 kW

The heat discarded by the engine, (Qc) = 526.8 kW

The heat supplied to the engine, (Qh) = 736.8 kW.

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Academic career planning mainly needs, coordination of your educational requirements with your job ambitions.

ACP, or academic career planning, is a student-driven, adult-supported process whereby students develop their own distinct, knowledge-based visions for success after high school through self-exploration and career-reflection as well as the acquisition of career management and planning skills.

It requires the understanding of your abilities, values, and interests relate to potential occupations or jobs matching your abilities, matching your financial needs and career ambitions, etc.

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Answer:

The Correct answer is A

cycle

Answer:

A. Cycle A cycle is a series of events or processes that is repeated again and again, always in the same order.

Explanation:

At t = 2.0 s, the rider is 43.0 m east of the marker.

To solve this problem, use the kinematic equation:

x = x₀ + v₀×t + (1/2)at²

where x = final position,

x₀ = initial position, v₀ = initial velocity,

a = acceleration, and t is the time.

Given that the motorcyclist has a constant acceleration of 4.0 m/s², and initially 5.0 m east of signpost moving east at a velocity of 15 m/s, initial position and velocity:

x₀ = 5.0 m

v₀ = 15 m/s

Now, find the position at t = 2.0 s:

t = 2.0 s

a = 4.0 m/s²

x = x₀ + v₀t + (1/2)at²

x = 5.0 m + 15 m/s(2.0 s) + (1/2)4.0 m/s²(2.0 s)²

x = 5.0 m + 30 m + 8.0 m

x = 43.0 m

Therefore, the position of the motorcyclist at t = 2.0 s is 43.0 m east of the signpost.

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The correct match is A - trough, B - amplitude, C - crest, and D - wavelength.

A - A trough is the lowest point on a wave, where the displacement of the medium or the amplitude of the wave is at its minimum.

B - Amplitude refers to the maximum displacement or distance moved by a point on a vibrating body or wave, from its equilibrium position.

C - A crest is the highest point on a wave, where the displacement of the medium or the amplitude of the wave is at its maximum.

D - Wavelength is the distance between two corresponding points on a wave, such as the distance between two consecutive crests or troughs. It is often measured in meters or other units of length.

Hence, A - trough, B - amplitude, C - crest, and D - wavelength.

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The good conductors of heat and electricity are Penny, and An aluminum soda can.

option A and B.

Good conductors of electricity are those materials that allow easy passage of electric current through them.

All metals are good conductors of electricity, and some of their examples include;

Aluminum

Copper

Silver

Zinc, etc

Poor conductors on the other hand do not allow easy passage of electric current through them.

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A true statement on the requirements of an academic career plan is that it can help you withstand challenges better as you know the direction you are trying to get to.

A student's personalized guide composed of their academic and professional objectives is known as an academic career plan. Such a plan illuminates the steps and resources they require to fulfill these aspirations.

It encompasses pinpointing said student's areas of expertise as well as areas in need of growth, discerning potential vocation paths, and determining which abilities, know-how, and experience they must accumulate. To efficiently reach their aims, they may utilize short and long-term goals, methodologies for accomplishing them, and frequent revisions to monitor progress.

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The current in the circuit is 2.5 A.

Voltage across the wire AX, V = 4 - 2 = 2V

Resistance per unit length of wire AX, R/l = 2 Ω/m

Length of the wire, l = 0.4 m

Resistance of the wire,

R = R/l x R

R = 2 x 0.4 = 0.8 Ω

According to Ohm's law, the current in the wire AX,

I = V/R

I = 2/0.8

I = 2.5 A

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The work done by Ali is 0 N

The work done by Amina is 72 N

The net force is 6 N

The work done by a body is defined as the product of the force applied and the distance through which the force is applied.

Mathematically;

The work done by Ali and Amina respectively is calculated using the formula above:

The work done by Ali = 12 * 0

The work done by Ali = 0 N

The work done by Amina = 18 * 4

The work done by Amina = 72 N

Net force = 18 - 12

Net force = 6 N

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Answer:

B. Pre-contemplation

Explanation:

Hope this helps :)

Answer :

Explanation :

According to the question, It's given that Two people hold a rope at either end. One person moves his end of the rope at a frequency of 4.0 Hz and a wavelength of 0.8 m.

We know the relationship between frequency and Wavelength. It states that wave speed is equal to the product of frequency and Wavelength .

where,

Substituting the values,

[tex]: \implies[/tex]v = 4.0 × 0.8

[tex]: \implies[/tex] v = 3.2 m/s

Therefore, At the speed of 3.2 m/s the wave travel through the rope.

If you apply a greater force the spring constant will remain the same, since it is a constant.

This law states that the force applied to an elastic material is directly proportional to the extension of the material.

That is as the force applied to an elastic material increases the extension of the elastic material increases provided the elastic limit of the material is not exceeded.

Mathematically, this law can be written as;

F = kx

where;

So when the force applied is increased, the extension of the material increases as well.

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The sphere will become negatively charged.

When a neutral metal sphere comes into touch with a negatively charged rod, some of the excess electrons from the rod move to the sphere, making it negatively charged.

The extra electrons that are delivered to the sphere will disperse uniformly across its surface, rejecting one another and maintaining the surface by means of electrostatic forces.

Until the negative charge is discharged or somehow neutralized, the sphere will remain negatively charged.

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