13. Given sulfur has an electron configuration of 1s22s22p63s23p4, what oxidation numbers would you expect for sulfur? (Hint: Think about how to achieve a full outer shell.)

A. –2,–4
B. +4, +6, –2
C. +2, –4,–6
D. +4,–4

Answer:

540,000 (5.4X10^5)

Explanation:

kj means Kilojoules, while we are converting to joules.

- Kilo, or k, represents our base value, Joules, multiplied by 10^3. To convert to joules, we would simply multiply by 10^3 (which is 1000)

E= hf

so shorter lambda = larger f= more energy

Answer is A

The wavelength of an EM wave related to its energy as "The shorter the wavelength of a wave, the higher its energy".

Electromagnetic radiation is a type of energy that is all around us and takes many forms, such as radio waves, microwaves, X-rays and gamma-rays. Sunlight is also a form of electromagnetic energy, but visible light is only a small portion of the electromagnetic spectrum, which contains a broad range of wavelengths.

In order from highest to lowest energy, the sections of the EM spectrum are named: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves. In order from highest to lowest wavelength, the series is just opposite.

Electromagnetic radiations don't require any medium to travel and also travel in speed of light. They have Electric field vector and magnetic field vector that is perpendicular to each other and also are perpendicular to the direction of propagation.

Therefore, the wavelength of an EM wave related to its energy as "The shorter the wavelength of a wave, the higher its energy".

Learn more about EM wave, here:

https://brainly.com/question/18729221

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Answer:

36.16 amu

Explanation:

From the question given above, the following data were obtained:

1st Isotope:

Mass of 1st isotope = 35.01 amu

Abundance of 1st isotope = 35%

2nd isotope:

Mass of 2nd isotope = 36.01 amu

Abundance of 2nd isotope = 15%

3rd isotope:

Mass of 3rd isotope = 37.02 amu

Abundance of 3rd isotope = 50%

Atomic mass of element A =?

The atomic mass of element A can be obtained as follow:

Atomic mass = [(mass of 1st × Abundance)/100] + [(mass of 2nd × Abundance)/100] + [(mass of 3rd × Abundance)/100]

= [(35.01 × 35)/100] + [(36.01 × 15)/100] + [(37.02 × 50)/100]

= 12.25 + 5.40 + 18.51

= 36.16 amu

Thus, the atomic mass of element A is 36.16 amu

Answer:

A B D

Explanation:

Answer:  A: Being the power source of stars

                B: Forming heavier elements from light elements

                D: Being used in thermonuclear weapons

Explanation: (Edmentum)

Answer:

C, energy cannot be created nor destroyed.

Explanation:

Answer:

The answers to your questions are given below.

Explanation:

1. __H₂ + __O₂ —> __H₂O

The above equation can be balance as follow:

H₂ + O₂ —> H₂O

There are 2 atoms of O on the left side and 1 atom on the right side. It can be balance by writing 2 before H₂O as shown below:

H₂ + O₂ —> 2H₂O

There are 2 atoms of H on the left side and a total of 4 atoms on the right side. It can be balance by writing 2 before H₂ as shown below:

2H₂ + O₂ —> 2H₂O

Now the equation is balanced.

Elements >>> Reactants >>> Products

H >>>>>>>>> 4 >>>>>>>>>>> 4

O >>>>>>>>> 2 >>>>>>>>>>> 2

2. __ P₄ + __O₂ —> __P₂O₃

The above equation can be balance as follow:

P₄ + O₂ —> P₂O₃

There are 4 atoms of P on the left side and 2 atoms on the right side. It can be balance by writing 2 before P₂O₃ as shown below:

P₄ + O₂ —> 2P₂O₃

There are 2 atoms of O on the left side and a total of 6 atoms on the right side. It can be balance by writing 3 before O₂ as shown below:

P₄ + 3O₂ —> 2P₂O₃

Now, the equation is balanced

Elements >>> Reactants >>> Products

P >>>>>>>>> 4 >>>>>>>>>>> 4

O >>>>>>>>> 6 >>>>>>>>>>> 6

answer of this question is [Ar]3d8 4s2

Answer: [Ar] 3d8 4s2

Explanation: Wikipedia

Explanation:

2nacl+baso4

the orginal equation is

Na2so4+Bacl2

then na react with cl and ba react with so4

Answer:

By measuring out 3.9 grams of cobalt (II) chloride up to a volume of 1.0 L of solution.

Explanation:

Hello there!

In this case, considering this question about molarity, it turns out possible for us to calculate the required mass of cobalt (II) chloride by firstly compute the moles present in 1.0L of the given 0.03-M solution:

[tex]M=\frac{n}{V} \\n=V*M\\\\n=1.0L*0.03\frac{molCoCl_2}{L}\\\\n=0.03molCoCl_2[/tex]

Next, since the molar mass of cobalt (II) chloride is 129.84 g/mol, we compute the grams we need to measure out in order to prepare this solution:

[tex]m_{CoCl_2}=0.03molCoCl_2*\frac{129.84gCoCl_2}{1molCoCl_2} \\\\m_{CoCl_2}=3.9gCoCl_2[/tex]

Regards!

Answer:

well when you eat some food you will get many tastes mixed with base and acid but salt from NA2CO3 can be a base if it is contained with weak acid.

Explanation:

Basically SALT can be one common base that is NOT harmful to the body when ingested AND a product, or way, in which it is used.

Magnesium hydroxide (Mg(OH)2) is not harmful to our body when ingested AND a product, or way, in which it is used. It is commonly used to get relief from acidity, that is caused when our stomach releases excessive acid. It neutrelises the acid and gives us relief. It is also called Milk of Magnesia commonly.

Answer:

Can you translate it on English so we can understand

Answer:

pH = 10.95

Explanation:

To solve this question we must, as first, find pKb of dimethylamine. Then, using H-H equation we can solve the pH of the buffer:

pKb dimethylamine:

Based on the equilibrium:

(CH3)2NH(aq) + H2O(l) ⇄ (CH3)2NH2⁺(aq) + OH-(aq)

Kb is defined as:

Kb = [OH-] [(CH3)2NH2⁺] / [(CH3)2NH]

Both (CH3)2NH2⁺(aq) + OH- comes from the same equilibrium, that means:

[OH-] = [(CH3)2NH2⁺]

And: [(CH3)2NH] = 0.457M

[OH-] can be obtained from pH as follows:

14 -pH = pOH

14-12.2 = 1.8 =pOH

10^-pOH = [OH-] = 0.01585M

Replacing:

Kb = [0.01585M] [(0.01585M] / [0.457M]

Kb = 5.50x10⁻⁴

pKb = -logkb = 3.26

pH of the buffer:

Using H-H equation for bases:

pOH = pKb + log [conjugate acid] / [weak base]

pOH = 3.26 + log [0.280M] / [0.457M]

pOH = 3.05

pH = 14 - pOH

Answer:

a.

Explanation:

electromagnetism

Answer:

92.1 g

Explanation:

Answer: 92.1 grams

I hope this helped :3

Answer:

IUPAC

Explanation:

International Union of Pure and Applied Chemistry

Answer:

[tex]d=9.5g/L[/tex]

Explanation:

Hello there!

In this case, according to the given information, it i possible for us to calculate the density of this gas via the ideal gas equation, according to the following setup:

[tex]PV=nRT\\\\P=\frac{mRT}{V*MM} \\\\\frac{m}{V}=d=\frac{P*MM}{RT}[/tex]

Thus, we plug in the variables (pressure in atm and temperature in K) to obtain:

[tex]d=\frac{113.6368atm*2.02g/mol}{0.08206\frac{atm*L}{mol*K}*(21+273)K} \\\\d=9.5g/L[/tex]

Regards!

Answer:

magnetism of water

Explanation:

Not sure

Explanation:

To show - from E=mc²=hv show that wavelength=h/mv​

Proof -

Given that,

E = mc²

E = hν

By equating both the equations, we get

mc² = hν

Because real particles do not travel at the speed of light, De Broglie submitted velocity ( v ) for the speed of light ( c ).

mv² = hν

Through the equation  λ , de Broglie substituted  v/λ  for  ν  and arrived at the final expression that relates wavelength and particle with speed.

mv² = hv/λ

⇒λ = hv/mv²

⇒λ = h/mv

Hence showed.

Answer: There are 1.53 moles present in [tex]9.23 \times 10^{23}[/tex]  molecules of water in a beaker.

Explanation:

According to the mole concept, there are [tex]6.022 \times 10^{23}[/tex] molecules present in 1 mole of a substance.

So, number of moles present in [tex]9.23 \times 10^{23}[/tex] molecules are calculated as follows.

[tex]Moles = \frac{9.23 \times 10^{23}}{6.022 \times 10^{23}}\\= 1.53 moles[/tex]

Thus, we can conclude that there are 1.53 moles present in [tex]9.23 \times 10^{23}[/tex]  molecules of water in a beaker.

Answer:

HCl(aq) + NaOH(aq) ⇒ NaCl(aq) + H₂O(l)

H⁺(aq) + OH⁻ ⇒ H₂O(l)

Explanation:

Let's consider the balanced chemical equation (molecular equation) for the reaction between hydrochloric acid and sodium hydroxide. This is a neutralization reaction.

HCl(aq) + NaOH(aq) ⇒ NaCl(aq) + H₂O(l)

The complete ionic equation includes all the ions and the molecular species.

H⁺(aq) + Cl⁻(aq) + Na⁺(aq) + OH⁻ ⇒ Na⁺(aq) + Cl⁻(aq) + H₂O(l)

The net ionic equation includes only the ions that participate in the reaction (not spectator ions) and the molecular species.

H⁺(aq) + OH⁻ ⇒ H₂O(l)

Answer:

whats the question?

Explanation:

Answer:

Isomerism is the phenomenon in which more than one compounds have the same chemical formula but different chemical structures. Chemical compounds that have identical chemical formulae but differ in properties and the arrangement of atoms in the molecule are called isomers. Therefore, the compounds that exhibit isomerism are known as isomers.

The word “isomer” is derived from the Greek words “isos” and “meros”, which mean “equal parts”. This term was coined by the Swedish chemist Jacob Berzelius in the year 1830.

Explanation:

Answer:

D

Explanation:

Answer:

D

Explanation:

Because it is true

Answer:

m = 4.58 g.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to realize this problem is solved via the ideal gas equation:

[tex]PV=nRT[/tex]

As we can calculate the moles of propane given the pressure, temperature and volume as shown below:

[tex]n=\frac{PV}{RT} \\\\n=\frac{1.10atm*2.00L}{0.08206\frac{atm*L}{mol*K}*258K} \\\\n=0.104mol[/tex]

Finally, since the molar mass of propane is 44.1 g/mol, we calculate the mass by following the shown below mole-mass conversion factor:

[tex]m=0.104mol*\frac{44.1g}{1mol}\\\\m= 4.58g[/tex]

Regards!

Answer:

????

Explanation:

Answer:

Metal oxide + acid —> salt + water

Explanation:

Answer:

ummm u ok?

Explanation:

Answer:

[tex]CH_3COOH+CH_3CH_2CH_2CH_2OH\rightarrow CH_3COOCH_2CH_2CH_2CH_3+H_2O[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to realize this is a question about esterification, process whereby a carboxylic acid and an alcohol react to produce water an an ester, we can set it up as shown below:

[tex]CH_3COOH+CH_3CH_2CH_2CH_2OH[/tex]

For the reaction between ethanoic acid and butanol; and therefore, the products side is:

[tex]CH_3COOCH_2CH_2CH_2CH_3+H_2O[/tex]

It means that the overall equation is:

[tex]CH_3COOH+CH_3CH_2CH_2CH_2OH\rightarrow CH_3COOCH_2CH_2CH_2CH_3+H_2O[/tex]

And the ester product is butyl ethanoate.

Regards!