-13=m-7 please help!

Answer:

what is the question yaaar

Answer:36

Step-by-step explanation: 6 sided dice = 6 possible outcomes

6×6=36

The required number of outcomes is 36 after rolling all six dice. Option B is correct.

Jane has to roll a set of six standard dice and record the results of each
trial. She wonders how many different outcomes are possible after rolling all six dice. the total number of possible outcomes for each trial to be determined.

Probability can be defined as the ratio of favorable outcomes to the total number of events for a system of the certain events.

For 1 dice, sample space = { 1  2  3  4  5  6}
total possible outcome = 6
Now 6 dice roll at once and the total outcome = 6 * 6
                                                                                = 36
Meanwhile, Jane has a total of 36 outcomes.

Thus, the required number of outcomes is 36 after rolling all six dice. Option B is correct.

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Answer:

Step-by-step explanation:

Answer:

[tex]+\sqrt{55i}[/tex]

Step-by-step explanation:

Khan <3

Answer:

n=5

Step-by-step explanation:

6n=30

n=30 /÷6

n=5

Answer:

Figure 0 = 5 tiles

Figure 1 = 5 + 7 = 12 tiles

So, the equation is:

y = 7x + 5

because, it adds 7 tiles in every new figure.

The equation is y = 7x +5.

Answer is y = 7x +5

Answer:

(a) [tex]A = 1500(1 - e^{-0.01t})[/tex]

(b) [tex]t = 0[/tex]

Step-by-step explanation:

Given

[tex]V= 300gal[/tex] --- Volume of tank

[tex]B = 5lb/gal[/tex] --- Brine solution

[tex]R_1 = 3gal/min[/tex]  --- Rate in, in gallon/min

[tex]R_2 = 6gal/min[/tex] --- Rate out, in gallon/min

Required

Determine A(t)

First, calculate the rate in (R in) and (R out) in lb/min

[tex]R_{in} = B * R_1[/tex]

[tex]R_{in} = 5lb/gal * 3gal/min[/tex]

[tex]R_{in} = 15lb/min[/tex]

R(out) is calculated by multiply the rate at which brine leaves the tank (lb/gal) * R2

So, we have:

[tex]R_{out} = \frac{A(t)}{300} lb/gal * 3gal/min[/tex]

[tex]R_{out} = \frac{3*A(t)}{300} lb/min[/tex]

[tex]R_{out} = \frac{A(t)}{100} lb/min[/tex]

The change in the amount of brin e in the tank at time t is given as:

[tex]A'(t) = R_{in} - R_{out}[/tex]

[tex]A'(t) = 15 - \frac{A(t)}{100}[/tex]

Rewrite:

[tex]\frac{dA}{dt} = 15 - \frac{A}{100}[/tex]

Multiply through by dt

[tex]dA = [15 - \frac{A}{100}]* dt[/tex]

Make dt stand alone

[tex]\frac{dA}{15 - \frac{A}{100}} = dt[/tex]

[tex]ln|15 - \frac{A}{100}| = -0.01t + ln\ c[/tex]

Express as exponents

[tex]15 - \frac{A}{100} = ce^{-\frac{t}{100}}[/tex]

Multiply through by 100

[tex]1500 - A = 100ce^{-\frac{t}{100}}[/tex]

[tex]A = 1500 - 100ce^{-\frac{t}{100}}[/tex]

[tex]A = 1500 - 100ce^{-0.01t}[/tex]

Apply initial conditions

[tex]A(0) = 0[/tex]

Substitute 0 for t in: [tex]A = 1500 - 100ce^{-0.01t}[/tex]

[tex]0 = 1500 - 100ce^{-0.01*0}[/tex]

[tex]0 = 1500 - 100ce^{0}[/tex]

[tex]0 = 1500 - 100c[/tex]

[tex]100c = 1500[/tex]

[tex]c = 15[/tex]

Substitute 15 for c in [tex]A = 1500 - 100ce^{-0.01t}[/tex]

[tex]A = 1500 - 100*15e^{-0.01t}[/tex]

[tex]A = 1500 - 1500e^{-0.01t}[/tex]

Factorize:

[tex]A = 1500(1 - e^{-0.01t})[/tex]

How long to empty the tank

Set A to 0

[tex]1500(1 - e^{-0.01t}) = 0[/tex]

Divide through by 1500

[tex]1 - e^{-0.01t} = 0[/tex]

Collect Like Terms

[tex]e^{-0.01t} = 1[/tex]

Take ln of both sides

[tex]ln\ (e^{-0.01t}) = ln\ 1[/tex]

[tex]-0.0t = 0[/tex]

[tex]t = 0[/tex]

Answer:

6 / 8 or 3 / 4

Step-by-step explanation:

Subtraction lol

Answer:

scalene triangle

..... .

Answer:

[tex]q=31.7\\p=28.4[/tex]

Doing all calculations with 3 significant figures.

Step-by-step explanation:

First, we'll obtain the value of 'q', this by realizing how the two angles together form a right triangle with inner angles of 30, 60, 90.

Furthermore, the opposite side of the angle of 30 is 'q' and its adjacent is given as 55. Hence, we can solve for 'q' using tangent as follows:

[tex]tan(30)=\frac{q}{55} =.577[/tex]

We solve for 'q':

[tex]q=.577*55=31.7[/tex]

Now to solve for 'p', we first will calculate what '55-p' is equal to.

First, we realize '55-p' corresponds to the adjacent side to the angle of 50 inside the small right triangle (the one with inner angles of 50, 40, 90) and q (which we now know is 31.7) correspond to the opposite side. Hence, we again use tangent as follows:

[tex]tan(50)=\frac{q}{55-p} =\frac{31.7}{55-p} =1.19[/tex]

We solve for 'p':

[tex]1.19(55-p)=31.7\\65.5-1.19p=31.7\\1.19p=33.8\\p=\frac{33.8}{1.19}=28.4[/tex]

Answer:

y = -x - 1

y = 1.5x + 6

(-3, 2)

Step-by-step explanation:

y = mx + b

y-intercepts are plotted on the graph

slope = rise over run

Solution is plotted on the graph

Answer:

the answer is (-3, 2)

value of x = -3

value of y = 2

Answer: 1.7004 × 10^2

Step-by-step explanation:

Answer:

5u-15=10 |+15

5u=25 |:5

u=5

The solution is 25

I hope it helps

have anice day

Answer:

B

Step-by-step explanation:

2/5 is equal to 40 percent

Answer:

c=5/72

Step-by-step explanation:

5/9=14c-5/12

Switch sides

14c-5/12=5/9

Add 5/12 tp both sides

14c-5/12+5/12=5/9+5/12

Simplify;

14c-5/12+5/12

=14c

Simplify;

5/9+5/12

LCM of 9, 12;

36

The least common multiplier of a, b is the smallest positive number that is divisible by both a and b.

Prime factorization of 9;

3*3

Prime factorization of 12;

2*6

=2*2*3

=3*3*2*2

=36

5/9=5*4/9*4=20/36

5/12=5*3/12*3=15/36

=20/36+15/36

20+15/36

=35/36

14c=35/36

14c/14=35/36/14

14c/14=c

35/36*14

=35/504

=5/72

Answer c=5/72

Answer to the following question is as follows;

Value of C = 5 / 72

Step-by-step explanation:

Given:

[tex]\frac{5}{9} = 14c - \frac{5}{12}\\\\[/tex]

Find:

Value of C

Computation:

[tex]\frac{5}{9} = 14c - \frac{5}{12}\\\\[/tex]

By taking 5/12 to LHS Side

[tex]\frac{5}{9} + \frac{5}{12} = 14c\\\\[/tex]

By taking LCM;

[tex]\frac{(4)(5) + (3)(5)}{36} = 14c\\\\[/tex]

[tex]\frac{20 + 15}{36} = 14c\\\\[/tex]

[tex]\frac{35}{36} = 14c\\\\[/tex]

By transfer 14 to LHS side

[tex]\frac{35}{36 \times 14 } = c\\\\[/tex]

[tex]\frac{5}{36 \times 2 } = c\\\\[/tex]

[tex]\frac{5}{72} = c\\\\[/tex]

Value of C = 5 / 72

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Answer:

angle 7

Step-by-step explanation:

Answer:

angle 7 angle forms a pair of alternate

exterior angles with angle 2.

Answer: See attached image.

The total volume of the composite figure is 530 cm³.

To find the volume of the composite figure, we need to calculate the volumes of the individual prisms and then add them together.

Triangular Prism:

The volume of a triangular prism is given by the formula:

Volume = base area × height

The base of the triangular prism is a triangle with a base of 5 cm and a height of 5 cm.

Therefore, the base area is:

Base area = (1/2) × base × height = (1/2) × 5 cm × 5 cm = 12.5 cm².

Now, we can calculate the volume of the triangular prism:

Triangular prism volume = base area × height = 12.5 cm² × 4 cm = 50 cm³.

So, the volume of the triangular prism is 50 cm³.

Rectangular Prism:

The volume of a rectangular prism is given by the formula:

Volume = length × width × height.

Given the dimensions of the rectangular prism as length = 6 cm, width = 10 cm, and height = 8 cm, we can calculate its volume:

Rectangular prism volume = length × width × height = 6 cm × 10 cm × 8 cm = 480 cm³.

So, the volume of the rectangular prism is 480 cm³.

Total Volume of Composite Figure:

To find the total volume of the composite figure, we add the volumes of the individual prisms:

Total Volume = Triangular prism volume + Rectangular prism volume = 50 cm³ + 480 cm³ = 530 cm³.

Therefore, the total volume of the composite figure is 530 cm³.

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Answer:

it's less than

Step-by-step explanation:

12/8 simplified is 3/2

11/6 cannot be further simplified

3/2<11/6

Answer:

5.5×5.5=30.5

we rounded 30.25 in nearest tenth it becomes 30

Answer:

C.] 5.5

Step-by-step explanation:

It is mentioned that the number was multiplied by the number itself.

Let's take 'x' as the number. It was multiplied by itself and the product is 30. So the equation will be:

x × x = 30

[tex]x^{2}[/tex] = 30

x = [tex]\sqrt{30}[/tex]

x = 5.47 = 5.5 (to the nearest tenth)

Answer:

The Binomial model is inappropriate because the Trials are independent of each other

Step-by-step explanation:

Given data :

probability of a company started by a person  failing with 2 years = 0.3

14 start-ups ( 98 people ) are followed for 2 years

The probability that at least 42 of these 98 people will fail in 2 years

Reason why the Binomial model is inappropriate for finding the probability that at least 42 of these 98 people will fail

The Binomial model is inappropriate because the Trials are independent of each other

Answer:

1.1.1) -61

1.1.2) Term 42

Step-by-step explanation:

Tn= dn (difference) + t0 (term 0)

Tn= -4n+ 11

You can now take this general rule to find out the other terms.

Tn= -4(18)+11

Tn= -61

And the term -157

Tn= -4n+11

-157= -4n + 11

-157 - 11= - 4n

-168= -4n

-168/-4= n

42= n

Answer:

<8 corresponds with <3

Answer:

0.9692 = 96.92% probability of getting someone in the 22-29 age bracket or someone who agreed to respond.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Find the probability of getting someone in the 22-29 age bracket or someone who agreed to respond.

357 people.

281 in the 22-29 age bracket + 65 in the 18-21 that agree to respond. So

[tex]p = \frac{281+65}{357} = 0.9692[/tex]

0.9692 = 96.92% probability of getting someone in the 22-29 age bracket or someone who agreed to respond.

Answer:

[tex]f(x) = 3(x - 1)^2-3[/tex]

Step-by-step explanation:

Given

[tex]f(x) = 3x^2 - 6x + 6[/tex]

Required

Write as:

[tex]f(x) = a(x - h)^2 + k[/tex]

In [tex]f(x) = 3x^2 - 6x + 6[/tex], the coefficient of x is -6

Divide by 2: -3

Square: 9

Add 9 - 9 to the above equation

[tex]f(x) = 3x^2 - 6x +9-9+ 6[/tex]

Split to 2

[tex]f(x) = [3x^2 - 6x +9]-[9- 6][/tex]

[tex]f(x) = [3x^2 - 6x +9]-[3][/tex]

Factorize:

[tex]f(x) = [3x^2 - 3x -3x+9]-[3][/tex]

[tex]f(x) = [3x(x - 1) -3(x-1)]-[3][/tex]

[tex]f(x) = [(3x - 3)(x-1)]-[3][/tex]

Factorize 3x - 3

[tex]f(x) = [3(x - 1)(x-1)]-[3][/tex]

[tex]f(x) = 3(x - 1)^2-[3][/tex]

[tex]f(x) = 3(x - 1)^2-3[/tex]

She bought $27.40 worth of roast beef.