Help! I’m timed! Don’t know what to do and I’ve already failed this twice
Answer
m∠DFC = 80⁰
Explanation
From the figure given;
m∠AFE = m∠BFD (Vertical opposite angles are equal
Since m∠BFD = 125⁰ from the figure
Then m∠AFE is also = 125⁰
But m∠AFE = m∠BFC + m∠DFC
From the figure, m∠BFC = 45⁰
Therefore, 125⁰ = m∠DFC + 45⁰
And m∠DFC = 125⁰- 45⁰
m∠DFC = 80⁰
Devin invested money into a bank account. The table below is the value of Devin’s investment over time.
given
Table which shows the value of Devin's investment over time.
Find
a) type of equation
b) regression equation
c) y - intercept
d) strong correlation or not?
e) value of investment after 6 years?
Explanation
let X = year
Y = value
[tex]\begin{gathered} \sum_^X=72 \\ \\ \sum_^Y=242300 \\ \\ \sum_^X\cdot Y=3568900 \\ \sum_^X^2=1038 \\ \sum_^Y^2=12600850000 \end{gathered}[/tex]a) linear equation would best fit the data.
b) equation of regression line is y = ax + b
where
[tex]\begin{gathered} b=\frac{(n\sum_^XY-\sum_^X\sum_^Y)}{(n\sum_^X^2-(\sum_X)^2)} \\ \\ b=3800.575 \end{gathered}[/tex]and
[tex]\begin{gathered} a=\frac{(\sum_^Y-(b\sum_^X))}{n} \\ \\ a=-5223.563 \end{gathered}[/tex]so , equation of regression is
y = -5223.563 + 3800.575X
c) y- intercept is the value when x = 0
so , y - intercept is -5223.563
d) there is strong and positive correlation between variables.
because
[tex]r=\frac{(N\sum_^XY)-\sum_^X\sum_^Y}{\sqrt{N\sum_(X)^2-(\sum^X)^2-N\sum_(Y)^2-(\sum^Y)^2}}[/tex]r = 0.945
e) when X = 6
[tex]\begin{gathered} Y=-5223.563+3800.575\times6 \\ Y=17579.89\approx17580 \\ \end{gathered}[/tex]Final Answer
Hence , the above are the required answers
use words to tell how to find 249+201
Let's begin by identifying key information given to us:
249 means Two hundreds, Four tens & Nine ones
201 means Two hundreds, Zero tens & One one
To obtain the sum of 249 & 201, we will sum the numbers having the same place value together, we have:
249 + 201 = Two hundreds plus Two hundreds, Four tens plus Zero tens & Nine ones plus One one
We have; Four hundreds, Four tens & Ten ones
"Ten ones" means that one is added to the digit in the tens place value. That is, Four tens plus One ten
Hence, the sum is given as:
Four hundreds, Five tens & Zero one
-Quadratic Equations-Determine the number and nature of the solutions to each equation; then find the solution.
Given the quadratic equation:
[tex]x^2+14x+49=0[/tex]By factoring the equation:
[tex]\begin{gathered} (x+7)(x+7)=0 \\ (x+7)^2=0 \end{gathered}[/tex]so, the number of solutions = 1 (real solution)
We will find the value of x:
[tex]\begin{gathered} x+7=0 \\ x=-7 \end{gathered}[/tex]Write the slope-intercept from of the equations for the line A. Y= 1/2x + 3/10B. Y=-10/3x +1/2C. Y=-10/3x + 1/2 D. Y= 3/10x + 1/2
Explanation:
To find the equation, we first need to calculate the slope of the line. So, we can calculate the slope of the equation as follows:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Where (x1, y1) and (x2, y2) are two points in the line. So, replacing (x1, y1) by (5, -1) and (x2, y2) by (-5, 2), we get:
[tex]m=\frac{2-(-1)}{-5-5}=\frac{2+1}{-10}=\frac{3}{-10}=-\frac{3}{10}[/tex]Now, the equation of the line can be found as:
[tex]y-y_1=m(x-x_1)[/tex]Then, replacing the slope by -3/10 and (x1, y1) by (5, -1), we get:
[tex]undefined[/tex]r equals 80x , C=267000+50x where ex is the number of units process access or so
Given the equation:
[tex]R=C[/tex]You know that:
- The manufacturer has a total revenue given by this function:
[tex]R=80x[/tex]Where "x" is the number of units that gives break-even for the product.
- The manufacturer has a total cost given by:
[tex]C=267000+50x[/tex]Therefore, knowing that:
[tex]R=C[/tex]You can set up this equation:
[tex]80x=267000+50x[/tex]Now you can solve for "x":
- Apply the Subtraction Property of Equality by subtracting this term from both sides:
[tex]50x[/tex]Then:
[tex]80x-(50x)=267000+50x-(50x)[/tex][tex]30x=267000[/tex]- Apply the Division Property of Equality by dividing both sides of the equation by 30:
[tex]\frac{30x}{30}=\frac{267000}{30}[/tex][tex]x=8900[/tex]Hence, the answer is: Option C.
Jennifer works 3 1/2 hours eachmorning at the clinic How manyRoutine physicals could she compete in one morning? Serious injury 1 1/4 hrsDental scaling 3/4 hrs Routine physicals 1/3 hrs.Sick Animal visit 1/2 hrNew patient 3/4 hrs Immunizations 1/4 hrs
Answer
Jennifer can perform 10 Routine Physicals in the morning
Solution
- The question tells us that Jennifer works 3 1/2 hours each morning and we are asked to find how many Routine physicals she can perform in the morning if 1 Routine physical takes 1/3 hours.
- In order to find the number of Routine physicals that can be performed in 3 1/2 hours, we simply need to assume that Jennifer can perform n number of Routine physicals. That is:
[tex]\begin{gathered} \text{ Total number of Routine physicals:} \\ \frac{1}{3}+\frac{1}{3}+\frac{1}{3}+\cdots=n\times(\frac{1}{3}) \\ \text{ } \\ \text{ If we take this as the total number of Routine Physicals possible within }3\frac{1}{2}\text{ hours, and r is the number } \\ \text{ of minutes left before }3\frac{1}{2}\text{ hours are completed, we have:} \\ \\ \frac{1}{3}+\frac{1}{3}+\frac{1}{3}+\cdots+r=3\frac{1}{2}=\frac{(3\times2)+1}{2}=\frac{7}{2} \\ \\ \therefore n\times(\frac{1}{3})+r=\frac{7}{2} \end{gathered}[/tex]Thus, to find the number of Routine Physicals, n, we simply make n the subject of the formula:
[tex]\begin{gathered} n=3(\frac{7}{2}-r) \\ \\ \text{This implies that the number of Routine Physicals is divisible by 3. This means that n is a multiple of 3} \\ \text{Thus, we can test values with multiples of 3.} \\ \\ \text{when n = 3:} \\ 3\times(\frac{1}{3})=1\text{hour} \\ \\ \text{when n= 6}\colon \\ 6\times(\frac{1}{3})=2\text{hours} \\ \\ \text{when n = 9:} \\ 9\times(\frac{1}{3})=3\text{hours} \\ \\ \text{when n= 12:} \\ 12\times(\frac{1}{3})=4hours \\ \\ \text{This implies that the number of Routine Physicals cannot be greater than or equal to 12. It also } \\ \text{implies that the number of Routine Physicals cannot be less than 9 since 9 physicals would take} \\ 3\text{ hours.} \\ \\ This\text{ means that the number of possible hours is between 10 or 11.} \\ \\ when\text{ n = 10:} \\ 10\times(\frac{1}{3})=3+\frac{1}{3}\text{ hours}<3\frac{1}{2}\text{ hours} \\ \\ \text{when n = 11:} \\ 11\times(\frac{1}{3})=3+\frac{2}{3}\text{ hours}>3\frac{1}{2}\text{ hours} \\ \\ \text{Thus, we can conclude that Jennifer can only do 10 Routine Physicals in the morning} \end{gathered}[/tex]Final answer
Jennifer can perform 10 Routine Physicals in the morning
Jonas is also running a 6 mile race. there are water stops but they are every 1/3 mile including a the finish line. how many stop are there?
hello
in the quesion, for every 1/3 mile, he has a water stop
let's calculate the total number of water stop
[tex]undefined[/tex]The function h(t) = negative 8 * t plus 1000 models the number of gallons of water remaining in a 1,000 - gallons tank after water has been draining for t hours.What is the y- intercept? What does it represent in this problem?
Given the function :
[tex]h(t)=-8t+1000[/tex]Where : h is the number of gallons and t is the number of hours
y - intercept is the value of h when t = 0
So, when t = 0
[tex]h(0)=-8\cdot0+1000=1000[/tex]So, y - intercept = 1000
And it represents the number of gallons at the beginning , which mean the tank is full with its 1000 gallons
which equation describes the function in the table below a. y = 1.3 + 10
From the table we notice that the change in x is always 5, and the change in y is always 6.5, then this is a line.
The equation of a line is given by:
[tex]y=mx+b[/tex]where m is the slope and b is the y-intercept.
From the table we notice that b=10, this comes from the fact that the y-intercept happens when x=0.
Now, the slope is given by:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]using the first two points on the table we have:
[tex]\begin{gathered} m=\frac{16.5-10}{5-0} \\ =1.3 \end{gathered}[/tex]plugging the values into the equation we have:
[tex]y=1.3x+10[/tex]Therefore the answer is A.
can you help me with this question
ok
[tex]\text{Interval = (-}\infty,\text{ 1)}[/tex]( - infinity , 1)
done
What is the area of a circle with radius of 11 inches? Use pi = 3.14
We have to find the area of a circle with a radius of 11 in.
We will use the formula for the area of a circle, that is:
[tex]A=\pi\cdot r^2[/tex]Then, replacing with r=11 and pi=3.14, we get:
[tex]\begin{gathered} A=\pi\cdot r^2 \\ A=3.14\cdot(11\text{ in})^2 \\ A=3.14\cdot121\text{ in}^2 \\ A=379.94\text{ in}^2 \end{gathered}[/tex]The area of a circle with radius 11 inches is A=379.94 sq in.
how did work umm 1+2
The answer to the addition is 3
Here, we want to give the result of the addition of one integer to another
Mathematically, we evaluate this by;
[tex]1\text{ + 2 = 3}[/tex]Find the unit price.7 tomatoes for $8.75?
To find out the unit price, divide the total cost by the number of tomatoes
so
$8.75/7=$1.25
therefore
the unit price is $1.25 per tomatoIf ABCD is dilated by a factor of 3, thecoordinate of C' would be:6ол5С43B2. 1-6 -5 4-3 -2 -1 012 345-1NOADC' = ([?], [ 12.3
From the question provided, if every coordinate on the quadrilateral is dilated by a factor of 1/2, then the coordinates of every point would be multiplied by 1/2.
Therefore, using the factor of 1/2 to dilate, the coordinates of pont C would be;
[tex]\begin{gathered} C=(2,4) \\ \text{Dilated by }\frac{1}{2}; \\ C^{\prime}=(2\times\frac{1}{2},4\times\frac{1}{2}) \\ C^{\prime}=(1,2) \end{gathered}[/tex]ANSWER:
The coordinates of C' would therefore be;
[tex]C^{\prime}(1,2)[/tex]how do I find the least common multiple of "14x^4y^6z^3" and "24x^6y^2z^8"
The given expressions are
[tex]\begin{gathered} 14x^4y^6z^3 \\ 24x^6y^2z^8 \end{gathered}[/tex]First, we look for the least common multiply for the numbers 14 and 24.
24 14 | 2
12 7 | 2
6 7 | 2
3 7 | 3
1 7 | 7
1 1
We have the product 2x2x2x3x7=168.
The least common multiple for the numbers is 168.
Now, we find the least common multiples for the variables.
The least common multiple of x variables is
[tex]x^6[/tex]The least common multiple for y variables.
[tex]y^6[/tex]The least common factor for z variables is
[tex]z^8[/tex]Remember that the least common multiple of variables is the one with the greatest exponent.
Therefore, the least common factor for the given expressions is[tex]168x^6y^6z^8[/tex]3. Observe what is happening to the star in the picture. What would you expect the next star to look like?
SOLUTION
Consider the image given in the question.
The shaded portion changes in a clockwise direction looking at the image from left to right
The next image will occupy the forth position as in the image below
Therefore the third option is correct (C)
Yolanda received 5/8 of the 72 votes cast for class secretary. How many votes did she receive?
The number of votes Yolanda received is equal to 45.
Number of votes Yolanda received = 5/8 of the total votes
total number of people who voted = 72
Thus to find the number of people who voted for her
we simply need to multiply the given fraction of votes by the total number of votes;
thus number of votes Yolanda received = 5/8 X 72
This implies the number of votes yolanda received = 5 X 9
which is equal to 45 votes
Thus from above we can conclude that Yolanda received 45 votes out of the 72 votes.
To know more about fraction , you may go through the link which is mentioned below:
https://brainly.com/question/13678136
#SPJ1
2) María compró 6 refrescos y se tomó un tercio. ¿Cuántos refrescos se tomó en total?
Manejo de fracciones
El total de refrescos que compró María es 6.
De esos refrescos se tomó un tercio, o también, la tercera parte.
Esa parte consumida se puede expresar con la fracción 1/3
Para saber cuántos refrescos se tomó, debemos multiplicar 6 por 1/3
[tex]6\cdot\frac{1}{3}[/tex]Multiplicamos el 6 por el numerador sólamente:
[tex]\frac{6}{3}[/tex]La fracción resulta en una división exacta igual a 2
En resumen, María se tomó 2 refrescos en total
Solve for X in the following triangle using cosine law. Show your work
Given:
Required:
We need to find the value of X by using cosine law
Explanation:
First the formula to find angle by cosine law is
[tex]X=\cos^{-1}(\frac{c^2+b^2-a^2}{2cb})[/tex]where
a is the length of BC
b is the length of AC
c is the length of AB
X is the opposite angle of a
now put all the values
[tex]X=\cos^{-1}(\frac{110^2+100^2-70^2}{2*110*100})=38.57\degree[/tex]Final answer:
value of X is 38.57 degree
One adult ticket for a school play cost $10 and one student ticket cost $6. One evening 750 people attended the play and the total receipts were $6860 how many of each type of ticket were sold a full algebraic a solution is required
Given:
Adult ticket cost = $10
Student ticket cost = $6
Total people = 750 people
Total amount = $6860
Find-:
How many of each type of ticket were sold
Explanation-:
Let student is "x."
The adult is "y."
The total people is 750 people,
[tex]\begin{gathered} \text{ Total people }=750\text{ people} \\ \\ x+y=750..............(1) \end{gathered}[/tex]The total amount is $6860
[tex]\begin{gathered} 6x+10y=6860 \\ \\ 3x+5y=3430.................(2) \end{gathered}[/tex]Solve the equation is:
[tex]\begin{gathered} x+y=750 \\ \\ 3x+3y=2250.......................(1)^{\prime} \end{gathered}[/tex]Then eq(2) - eq(1)' then value of "y" is:
[tex]\begin{gathered} 3x+5y-(3x+3y)=3430-2250 \\ \\ 3x+5y-3x-3y=3430-2250 \\ \\ 2y=1180 \\ \\ y=\frac{1180}{2} \\ \\ y=590 \end{gathered}[/tex]Adult member is 590
Student ticket is:
[tex]\begin{gathered} x+y=750 \\ \\ x+590=750 \\ \\ x=750-590 \\ \\ x=160 \end{gathered}[/tex]The number of students is 160.
State the property that justifies each statement.11. If 2x+19=27, then 2x=8
2x + 19 = 27
Using the subtraction property of equality, we can subtract 19 at both sides of the equation, as follows:
2x + 19 - 19 = 27 - 19
2x = 8
Please correct me if my answer is wrong, that is all, thanks!
The correctanswert is option 2.
This graph shows a relationship between the height of a giraffe and its weight. Height versus Weight of Giraffes 1600 1400 1200 800 Weight (kg) 600 400 200 0 1 2 3 4 5 6 Height (m) Which term describes the dashed line shown in the graph? O A. Frequency distribution line O B. Line of central tendency O C. Dependent variable line O D. Line of best fit
The dash line represents the line of best fit. So the answer is
D. Line of best fit
Choose the law that connects to how you would simply each expression.
Given the exponent properties, we have:
[tex](a^9)^3=a^{27}[/tex]Answer: Power of power
[tex]\frac{m^8}{m^4}=m^{8-4}=m^4[/tex]
Answer: Quotient of powers
[tex]5x²*(-7x^4)=-35x^{2+4}=-35x^6[/tex]
Answer: Product of powers
factor f(x)= x² + x - 42
The factors of -42 that sum to 1 are 7 and -6, therefore:
[tex]x^2+x-42=(x+7)(x-6)[/tex]The following function represents the amount of money that Alisha has saved after w weeks:f(w)=20w+50A. What does the 20 represent in this situation?B. What does the 50 represent in this situation?C. How long would it take for Alisha to save $150?
The Solution:
Given that the function below represents the amount that Alisha saved after w weeks.
[tex]f(w)=20w+50[/tex]A.
The 20 represents the rate of change of Alisha's savings per week. That means it represents the amount by which Alisha's savings change from one week to another.
B.
The 50 represents the initial amount in Alisha's savings. That is, the amount in Alisha's saving at zero weeks.
C.
This means that we should find w when f(w)=$150
[tex]\begin{gathered} f(w)=20w+50 \\ f(w)=150,\text{ Substituting we get} \\ 150=20w+50 \end{gathered}[/tex]Collecting the like terms, we get
[tex]\begin{gathered} 150-50=20w \\ 100=20w \\ \text{Dividing both sides by 20, we get} \\ \frac{100}{20}=\frac{20w}{20} \\ \\ 5=w \\ w=5\text{ w}eeks \end{gathered}[/tex]Thus, it will take Alisha 5 weeks to save $150.
Triangle ABC has been reflected over the y-axis to create triangle A'B'C'. Which of the following statements is true?
B'C' = 2 True
1) In this Geometric Transformation, reflection.
This a Rigid Transformation so each side keeps its original dimension
from the Pre-image to the Image
Given that BC = 2
Hence
B'C' = 2 True
There is no other source of information to state anything about the other sides.
i need help to Find / solve for x. I know it’s easy but I can’t remember how with degrees.
Explanation
We are given the following information from the image:
• m∠EGF = 31x + 3
,• Arc angle = 192°
We are required to determine the value of x.
We know that the angle subtended by the arc at the center of the circle is the angle of the arc. Therefore, we have:
[tex]\begin{gathered} m\angle EGF=31x+3 \\ m\angle EOF=192\degree \\ where\text{ }O\text{ }is\text{ }the\text{ }center\text{ }of\text{ }the\text{ }circle \end{gathered}[/tex]We also know that one of the circle theorems states that the angle subtended by an arc at the center is twice the angle subtended at the circumference. This becomes:
[tex]\begin{gathered} m\angle EOF=2\times m\angle EGF \\ 192\degree=2(31x+3) \\ 192\degree=62x+6 \\ 62x=192-6 \\ 62x=186 \\ \frac{62x}{62}=\frac{186}{62} \\ x=3 \end{gathered}[/tex]Hence, the value of x is 3.
in a random drawing contest first place receives the grand prize of $10,000 second place receives $5,000 and third place receives $1,000 if 200 people enter this drawing in each other what is the total possibility outcome for first second and third place
The total possibility outcome is $80
Here, we want to get the total possibility outcome
From the question, each of the 200 have an equal chance
Now, out of the 200, we can only have a first, a second and a third
The probability that an entry wins first price would be 1/200 , so as the second price and the third
So, we have the total possibility outcome as follows;
[tex]\begin{gathered} (\frac{1}{200}\times10,000)\text{ + (}\frac{1}{200}\times5000)+\text{ (}\frac{1}{200}\times1000) \\ \\ =\text{ 50 + 25 + 5 = \$80} \end{gathered}[/tex]