1/4 to the 6th power

Answer:

I'm on Edulastic.com taking a 100 Q test and this question is on it!

Step-by-step explanation:

Imao im fgging confused

The graph of the required line [tex]\bold{y=\frac{x}{4}+2}[/tex] is given below.

An equation of line with slope m and passing through point (p, q) is:

(y - q) = m × (x - p)

We have been given the slope of the line m = 1/4,

and a point (p, q) = (0, 2)

Using the slope-point form equation of line would be,

⇒ (y - 2) = 1/4 × (x - 0)

⇒ (y - 2) = 1/4(x)    

⇒ y = x/4 + 2                          ...............................(1)

So, the equation of the line is [tex]y=\frac{x}{4} +2[/tex].

To plot the line we need at least  two coordinate points.

We have been given a point (0, 2).

We need to find another point.

Substitute x = -4 in equation (1),

⇒ y = (-4)/4 + 2

⇒ y  = -1 + 2

⇒ y = 1

So, another point on the line would be (-4, 1).

Now, we plot points (0, 2) and (-4, 1) on coordinates plane.

Then the graph of the line [tex]\bold{y=\frac{x}{4}+2 }[/tex] is as shown in figure.

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#SPJ2

Answer:

transitive property of equality

Step-by-step explanation:

I know cus i took the test also sorry it took so long dude

Answer:

k>3/2

Step-by-step explanation:

To solve this, you need to do fraction cross-multiplying.

So, If a/b=c/d, then a*d=c*b

After you cross-multiply, you get this: (11k-15)*4>3(5-2k)

If you simplify 3(5-2k), you get 15-6k

Then, simplify the next side as well

The full simplified expression should be: 44k-60>15-6k

If you add 60 to both sides, you get 44k>-6k+75

Then add 6k to both sides 50k>75

Then all you have to do is divide both sides by 50 and you get:

K>3/2 OR k>1.5

Answer:

I want the free points. Sorry :)

Answer:

Step-by-step explanation:

Answer:

ill help you with my long shalong

Step-by-step explanation:

Answer:

48 lbs

Step-by-step explanation:

say that the cat weighs x pounds. then the dog weighs 8x pounds. together they weigh 54 pounds. So our equation is x+8x=54. solve for x to get the cat's weight, and you get x=6. The cat weighs 6 lbs. all I need to do now is multiply 6 by 8 so this the dog weighs 8 times as much as the cat. 8•6=48. the dog weighs 48 pounds.

Answer:

2/5

Step-by-step explanation:

Answer:

2.25 is your answer

Step-by-step explanation:

Sadly the question is incomplete, so we can not see the described transformation of the parent function, thus we can't see the error in that description.

What we can do is describe the transformation shown here.

Here we can see the parent function:

f(x) = x^2

This function opens upwards, so what we see in the graph is this function reflected across the horizontal axis (the x-axis). So the transformation is just a reflection across the x-axis.

(notice that it passes through (-1, -1) and (1, -1), so there is no dilation nor contraction)

For a general function f(x), a reflection across the x-axis is just:

g(x) = -f(x)

So here the transformed function is:

g(x) = - x^2

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Is there more information so that I solve?

Domain: hours worked

Domain Values: 1,2,3,4

Range: dollars charged

Range Values: 165, 215, 265

The relation is a function. Each domain value is paired with exactly one range value.

Answer: 33

Step-by-step explanation:

(9,-4) and (5,3)

=9*5+(-4)*3

=33

Your answer would be C.

He did not go insane

Answer:

y = 3x - 13

Step-by-step explanation:

Answer:

ROC

Step-by-step explanation:

ROC. rate of change

On a table or graph, the constant change is same as the unit rate, rate of change or slope, which can be denoted as m.

Constant change on a graph or table simply refers to the rate of change of the output (y) over the change in input (x).

Constant change in a graph or table is the same as the unit rate or the slope value which is dented by the letter m.

Constant rate of change, unite rate, and slope can be denoted as m of a graph or table.

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Answer:they are both neagtive numbers.

Step-by-step explanation:

they say it right in front of you.

Answer:

A is the endpoint ray

Step-by-step explanation:

Point A is the ray's endpoint. One way to think of a ray is a line with one end. A ray starts at a given point and goes off in a certain direction forever, to infinity. The point where the ray starts is called (confusingly) the endpoint.

Answer:

0.20

Step-by-step explanation:

Answer:

Tulips

Step-by-step explanation:

7÷2 is 3.50$ Each Rose costs 3.50$

9÷3 is 3$ Each Liliy costs 3$

11÷4 is 2.75$ Each Tulip costs 2.75$

Answer:

0 . 4  =  2 / 5

Step-by-step explanation:

Answer:

y = - 3x - 2

Step-by-step explanation:

Step 1:

y = mx + b     Slope Intercept Form

Step 2:

y = - 3x + b     Input Slope

Step 3:

4 = - 3 ( - 2 ) + b     Input x and y

Step 4:

4 = 6 + b     Multiply

Step 5:

- 2 = b       Subtract 6 on both sides

Answer:

y = - 3x - 2

Hope This Helps :)

Answer:

56 - 38 = 18

Step-by-step explanation:

Answer:

18 paper clips

Step-by-step explanation:

56 paperclips originally - x paperclips = 38 paperclips

56 - x = 38

    + x    + x

56      = 38 + x

- 38       - 38

18       =         x  

x = 18

Answer:

24

Step-by-step explanation:

Lets say 4 boys to 6 girls if there are 36 girls do 4x6 to figure out the ratio of boys would be 24 boys and 36 girls if the other way around it would be 24 girls and 36 boys

Answer:

Terminating

Step-by-step explanation:

1/16=0.0625, 1/8=0.125, 1/4=0.25, 1/2=0.5; which are all terminating.

Answer:

The value of a and b are 8 and 1 respectively

Step-by-step explanation:

[tex]f_{x,y}(x,y)=\left\{\begin{matrix}cxy ,\text{if} 0 \leq x \leq y \leq 1\\ 0 , \text{otherwise}\end{matrix}\right.[/tex]

[tex]\int_{0}^{1}\int_{x}^{1}cxy \text{dy dx}=1\\\\c\int_{0}^{1}x\left ( \frac{y^2}{2}\right )_{x}^{1} \text{ dx}=1\\\\\frac{c}{2}\int_{0}^{1}x\left ( 1-y^2\right )\text{dx}=1\\\\\frac{c}{2}\int_{0}^{1}(x-x^3)\text{dx}=1\\\\\frac{c}{2}\left [ \frac{x^2}{2}-\frac{x^5}{4} \right ]_{0}^1=1\\\\\frac{c}{2}\left [ \frac{1}{2}-\frac{1}{4} \right ]=1\\\\\frac{c}{2}\left ( \frac{1}{4} \right )=1\\\\c=8[/tex]

Conditional pdf of [tex]f_{x,y}(x|0.5)[/tex]

[tex]f_{x,y}(x|0.5)=\frac{f_{xy}(x,y=0.5)}{f_{y}y}[/tex]

Normalizing pdf of 1

[tex]f_{y}y=\int_{0}^{y} 8yx \text{dx}[/tex]

[tex]f_{y}y=8y[\frac{x^2}{2}]_{0}^{y}\\f_{y}y=4y(y^2)\\f_{y}y=4y^3\\f_{x|y}(x|0.5)=\frac{8x(0.5)}{4(0.5)^3}=\frac{2x}{0.25}=8x[/tex]

We are given that PDF [tex]f_{x|y}(x|0.5)[/tex] is of the form [tex]ax^b[/tex]

So, on comparing 8x with [tex]ax^b[/tex]

So, a = 8 , b = 1

So, the value of a and b are 8 and 1 respectively

The resulting value of a and b given  the conditional PDF of fX|Y(x|0.5) is mathematically given as

a = 8 , b = 1 .

Question Parameters:

a joint PDF of the form fX,Y(x,y)={cxy,0,if 0≤x≤y≤1,

For x∈[0,0.5]

the conditional PDF fX|Y(x|0.5)

Generally, the equation for the function of (x,y)   is mathematically given as

[tex]f_{x,y}(x,y)=\left\{\begin{matrix}cxy ,\text{if} 0 \leq x \leq y \leq 1\\ 0 ,\end{matrix}\right.[/tex]

Therefore

[tex]\int_{0}^{1}\int_{x}^{1}cxy \text{dy dx}=1[/tex]

[tex]c\int_{0}^{1}x\left ( \frac{y^2}{2}\right )_{x}^{1} \text{ dx}=1[/tex]

[tex]\frac{c}{2}\left [ \frac{x^2}{2}-\frac{x^5}{4} \right ]_{0}^1=1[/tex]

[tex]\\\\\frac{c}{2}\left ( \frac{1}{4} \right )=1[/tex]

C=8

Where, the conditional PDF fX|Y(x|0.5)

[tex]f_{x,y}(x|0.5)=\frac{f_{xy}(x,y=0.5)}{f_{y}y}[/tex]

We have

[tex]f_{y}y=8y[\frac{x^2}{2}]_{0}^{y}\[/tex]

[tex]f_{y}y=4y^3[/tex]

[tex]f_{x|y}(x|0.5)=\frac{8x(0.5)}{4(0.5)^3}[/tex]

f_{x|y}(x|0.5)=8x

In conclusion. with the pdf in the form of ax^2

8x comparing ax^b

The value of a = 8 , b = 1 .

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m= 46

I know this becuase i just did this on khan :)))))

Answer:

12 t-shirts

Step-by-step explanation:

12 x 75% = 9 = 9 t-shirts

Answer:

x= - 8/9

Step-by-step explanation:

Answer:

1. r1 || r2 because of the same side or consecutive interior theorem

2. l1 || l2 because they are corresponding angles

The angle formed between two parallel lines having a common transversal have several common properties

The correct responses are;

1.  Lines r₁ and r₂ are parallel

2. Lines, l₁ and l₂ are parallel

lines r₁ and r₂, are parallel

The reason why the given lines are parallel are as follows:

1. The given figures are presented as shown in the attached diagram

From the diagram, we have that the same side interior angles formed by the common transversal l₂ the lines r₁ and r₂ are 63° and 117°, which are supplementary angles (63° + 117° = 180°)

Therefore, lines r₁ and r₂ are parallel given that same side interior angles formed by two parallel lines having the same transversal are supplementary

2. From the attached diagram, we have;

The alternate exterior angles formed between the lines, l₁ and l₂ that have the common transversal r₁ are equal, therefore;

Lines, l₁ and l₂ are parallel, given that the alternate exterior angles formed by two parallel lines having a common transversal are equal

From the diagram, we also have that the other angle of the linear pair angle with the 63° angle is 117°, and the second angle of the linear pair angle is both either corresponding angle and alternate interior angle with the given 117°

Therefore, lines r₁ and r₂, are parallel given that corresponding angles and the alternate interior angles formed between parallel lines having a common transversal are equal

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