1.5 x 10-3 standard notation

Answers

Answer 1
I may be a little late but the answer is -11.5

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HELP PLEASE!!!
An 85-kg clown is fired from rest out of a 480-kg cannon. If the clown’s speed is 18 meters per second after the firing, then what is the recoil speed of the cannon?

Answers

Answer:

101.65 m/s

Explanation:

Step one:

Given data

m1= mass of gun.= 480kg

m2= mass of bullet.  = 85kg

v1=

v2= final velocities of bullet. = 18 meters per second

m1u1+m2u2=m1v1+m2v2

u1=0; u2=0

0=m1v1+m2v2

Step two:

Recoil velocity v1= -(m1/m2)v2

v1= -(480/85)18

v1= 5.64*18

v1=101.65 m/s

Friction converts Kinetic energy to what type of energy?​

Answers

Answer: Friction between the two surfaces converts kinetic energy into thermal energy.

Explanation: Friction occurs because no surface is perfectly smooth. Rougher surfaces have more friction between them. Friction produces heat because it causes the molecules on rubbing surfaces to move faster and have more energy.

A car moves with a velocity of 54km/h to a velocity of 72lm/h for 5 minutes. determine the distance covered

Answers

Answer:

The distance covered is 5250 meters

Explanation:

Motion With Constant Acceleration

It's a type of motion in which the velocity of an object changes uniformly in time.

The change of velocities is given by the following equation :

[tex]v_f=v_o+at\qquad\qquad [1][/tex]

Where:

a   = acceleration

vo = initial speed

vf  = final speed

t    = time

The distance traveled by the object is given by:

[tex]\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2][/tex]

Solving [1] for a:

[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]

The car changes its speed from vo=54 Km/h to vf=72 Km/h in t=5 minutes. Let's convert all to meters and seconds.

vo=54 Km/h * 1000/3600 = 15 m/s

vf=72 Km/h * 1000/3600 = 20 m/s

t = 5 min * 60 = 300 s

Now we calculate the acceleration:

[tex]\displaystyle a=\frac{20-15}{300}[/tex]

[tex]\displaystyle a=\frac{5}{300}[/tex]

[tex]a=0.0167\ m/s^2[/tex]

Now for the distance:

[tex]\displaystyle x=15*300+\frac{0.0167*300^2}{2}[/tex]

[tex]\displaystyle x=4500+750=5250[/tex]

x = 5250 m

Note: We have shown only some of the decimals for the acceleration, but we have used all the decimals stored in the calculator to present accurate results.

The distance covered is 5250 meters

How much force is required to raise a 0.2 kg mass?

please only answer if you know it.

Answers

since f= ma and your givens are m=0.2 kg and gravity (also acceleration) is 9.8 m/s [down], to find the force sub the two into the equation so that: f= (0.2)(9.8) which should equal 1.96 N.

We have that for the Question "How much force is required to raise a 0.2 kg mass?" it can be said that

The Force required to raise W=1.962N will be F=1.962N since F=W

F=1.962N

From the question we are told

How much force is required to raise a 0.2 kg mass?  

Generally the equation for the Weight   is mathematically given as

[tex]W=M*g\\\\W=0.2*9.81\\\\W=1.962N\\\\[/tex]

Therefore

The Force required to raise W=1.962N will be F=1.962N since F=W

F=1.962N

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what is meant by si unit?

Answers

Answer:

The SI base units are the standard units of measurement defined by the International System of Units (SI) for the seven base quantities of what is now known as the International System of Quantities: they are notably a basic set from which all other SI units can be derived.

Explanation:

John sees Linda Running towards him at 11 m/s. while running, Linda throws a ball at 5m/s. what is the speed of the ball as observed by John?​

Answers

11m/s Bc of the fact that he sees her running at 11m/s
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