18. A 35.0 G piece of metal wire is heated and the temperature changes from 21°C to 52°C the specific heat of the metal is 0.900 J/G degrees Celsius how much energy was required to heat the metal please show work

Answers

Answer 1

Answer:

Q = 976.5 J.

Explanation:

Hello there!

In this case, according to the thermodynamic definition of the heat in terms mass, specific heat and temperature change, we can write:

[tex]Q=mC(T_2-T_1)[/tex]

Thus, by plugging in the given data, we obtain:

[tex]Q=35.0g*0.900\frac{J}{g\°C} (52\°C-21\°C)\\\\Q=976.5J[/tex]

Regards!


Related Questions

List the three different temperature scales

Answers

Answer:

Celcius

Farenheit

Kelvin

Explanation:

What does Bolsa suggest as the next step in their investigation?

Answers

who’s bolsa? I’m confused is there anything else to this question?

Answer:

A) call Billy Jo Jim Bob

Explanation:

please help ill give brainly !!

when air is heated what happens to its density?

A ) It is increased because the molecules are moving together.
B ) It is increased because the molecules are moving apart.
C ) It is decreased because the molecules are moving together.
D ) It is decreased because the molecules are moving apart

Answers

Answer:

B.

Explanation:

The molecules are moving apart meaning that they move faster when heated and move slower when cooled

Directions: Select the correct planet.
The diagram below shows the orbits of the inner planets around the Sun Based on the diagram, which inner planetas the longest
year?
Nenus
Mercury
Mars
Earth
Sun and planets
not drawn to scale

Answers

Answer:

Mars

Explanation:

It's the furthest away from the sun so it has the longest orbit

Answer:

the anser is mars

Explanation:

Which option identifies all the bonds broken during this chemical reaction?
2H2 +O2 --> 2H2O
A. The bonds between the two hydrogen atoms and between the two oxygen atoms
B. The bonds between the two oxygen atoms
C. The bonds between oxygen and hydrogen atoms
D. The bonds between the two hydrogen atoms ​

Answers

Answer:

the bond b/w oxygen and hydrogen atom

Answer: A, the bonds between the two hydrogen atoms and between the two oxygen atoms.

Which of the following is an example of a process that absorbs energy?

gas converting to a liquid

solid coverting to a liquid

a substance freezing

temperature of a substance decreasing

Answers

Answer:

-Gas converting to a liquid

-Solid converting to a liquid

Explanation:

Endothermic process. It's absorb heat

2.56 x 10^13 molecules of HgO equates to how many moles of HgO?

Answers

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

[tex]n = \frac{N}{L} \\[/tex]

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

We have

[tex]n = \frac{2.56 \times {10}^{13} }{6.02 \times {10}^{23} } \\ \\ \\ = 4.25 \times {10}^{ - 11} \: \: \: moles[/tex]

Hope this helps you

the maximum amount of copper sulfate that can be dissolved in 45.0g of water at 70C is 20.0g. what is the solubility of copper sulfate at that temperature?
(in grams per 100g water)​

Answers

Answer:

That depends on the amount. Solubility is the maximum amount of salt dissolved in 100 g of water. So, if the amount is within limit, then yes. Solubility of anhydrous copper sulfate is 24.3 g/100 g water, so it is not bad. Put it in perspective, the solubility of NaCl is about 35 g/100 g water at room temperature. If the amount of copper sulfate is unknown, qualitative I'd say solid copper sulfate will dissolve in water completely.

Explanation:

If you use the pentahydrate CuSO4.5H2O then the solubility at 20°C is 20.8g/100ml H2O

If you use the anhydride, CuSO4. then the solubility at 20°C is 36.2g/100ml H2O

*An element has three naturally occuring isotopes with the following masses and abundances
Isotopic mass(amu):
27.977
28.976
29. 974
Fractional abundance:
0.9221
0.0470
0.0309

a. calculate the atomic weight of this element
b.What is the identity of the element?​

Answers

Answer:

a. 28.08 amu

b. Silicon

Explanation:

Step 1: Given data

Isotope         Isotopic mass (mi)         Fractional abundance (abi)

 ²⁸X               27.977 amu                   0.9221

 ²⁹X               28.976 amu                  0.0470

 ³⁰X               29. 974 amu                 0.0309

Step 2: Calculate the atomic weight (aw) of this element

We will use the following expression.

aw = ∑mi × abi

aw = 27.977 amu × 0.9221 + 28.976 amu × 0.0470 + 29. 974 amu × 0.0309

aw = 28.08 amu

Looking at the periodic table, the element with atomic weight = 28.08 amu is silicon.

The main function of the ozone layer is to shield the earth from the harmful ultraviolet rays of the sun.

O True
O False

Answers

Answer:

The Awnser is True. Hope that helps.

Answer:

true

Explanation:

Determine the number of moles in 258.45 grams of iron (III) chloride (FeCl3). Show and explain all
your work for full credit. Make sure you show all units.

Answers

Answer:

[tex]\boxed {\boxed {\sf 1.5935 \ mol \ FeCl_}}[/tex]

Explanation:

To convert from grams to moles, we must use the molar mass. This can be found on the Periodic Table. First, find the molar mass of iron and chlorine.

Fe: 55.84 g/mol Cl: 35.45 g/mol

Check the formula. There is a subscript of 3 after Cl, so there are 3 atoms of chlorine in 1 molecule. Multiply iron's molar mass by 3, then add iron's molar mass.

FeCl₃: 55.84 + 3(35.45) = 55.84+106.35=162.19 g/mol

Use this number as a ratio.

[tex]\frac {162.19 \ g\ FeCl_3}{1 \ mol \ FeCl_3}[/tex]

Multiply by the given number of grams.

[tex]258.45 \ g \ FeCl_3 *\frac {162.19 \ g\ FeCl_3}{1 \ mol \ FeCl_3}[/tex]

Flip the ratio so the grams of iron (III) chloride cancel.

[tex]258.45 \ g \ FeCl_3 *\frac {1 \ mol \ FeCl_3}{162.19 \ g\ FeCl_3}[/tex]

[tex]258.45 *\frac {1 \ mol \ FeCl_3}{162.19}[/tex]

[tex]\frac {258.45 \ mol \ FeCl_3}{162.19}[/tex]

[tex]1.59350144892 \ mol \ FeCl_3[/tex]

The original measurement of grams has 5 significant figures, so our answer must have the same. For the number we calculated, that is the ten thousandth place.

[tex]1.5935 \ mol \ FeCl_3[/tex]

258.45 grams is approximately 1.5935 moles of iron (III) chloride.

Look at the diagram of a fuel cell below.

Which part of the fuel cell does A represent?
A. air
B. anode
C. cathode
D. electrolyte

Answers

Answer:

It is a electrolyte.

Explanation:

I took the test.

It represents an electrolyte.

What happens if electrolytes are low in the body?

A level under three can cause muscle weakness, spasms, cramps, paralysis, and respiratory problems. If it continues, kidney problems may occur.

What do electrolytes do for your body?

Electrolytes are substances that have a natural positive or negative electrical charge when dissolved in water. They help your body regulate chemical reactions, maintain the balance between fluids inside and outside your cells, and more.

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I NEED HELP ASAP PLZ LOOK AT THE PICTURE CAREFULLY!!!!

Answers

Answer:

it is a little fuzzy

Explanation:

If 45 grams of solid aluminum and 301 grams of ammonium perchlorate are reacted. How much excess reactant is left over? Show your work using equation editor.

Answers

Answer: Your balanced equation is 2Al + 3S --> Al_2S_3. In two separate equations, first use the 48.5g of Al to find the amount (in moles) of Al_2S_3. Then use the 62.8g of S to find the amount (in moles) of Al_2S_3. By doing these, you find which reactant (the Al or the S) produces the least amount of Al_2S_3. Since it's the S, that's the limiting reactant: you then use that 62.8g of S to find how many grams of Al will be used in the reaction. (Use the same balanced equation.) You find that 35.2g of Al will be used, then find the excess by subtracting that 35.19 from the original 48.5g. Your excess amount is 13.3g of Al!

Explanation:

hopefully this is what you were looking for <3 :)

The amount of excess reactant that left over the chemical reaction between aluminum and ammonium perchlorate is 0.9 moles.

How do we convert mass into moles?

Mass into moles (n) will be converted by using the below equation as:

n = W/M, where

W = given mass

M = molar mass

Moles of 45g of Aluminum = 45g / 27g/mol = 1.66 mol

Moles of 301g of ammonium perchlorate = 301g / 117.4g/mol = 2.56 mol

Both reactants are reacted with each other and one of the reactant is fully consumed, so the excess reactant will be calculated as:

Excess reactant = 2.56mol - 1.66mol = 0.9 moles

Hence amount of excess reactant is 0.9 moles.

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Aeronautical engineers have to consider the weight, trust, life, and drag of an airplane to determine whether or not…

Answers

Answer:

the plane will crash, or if it is usable or not.

The pyruvic acid from glycolysis can be converted to acetic acid, which can enter the citric acid cycle. Because this process is a cycle, the atoms entering the cycle must balance the atoms that leave. Consider carbon balance in the citric acid cycle. How many CO2 molecules leave the cycle for each acetic acid molecule that enters? For this question, assume that carbon only enters as acetic acid and exits as CO2 . Note that acetic acid has two carbon atoms. You can determine the number of carbon atoms in carbon dioxide from its formula, CO2 .

Answers

Answer:

The correct answer is - 2CO2 or two molecules of carbon dioxide.

Explanation:

The TCA cycle or citric acid cycle is a central pathway of cellular respiration that helps in unifying several metabolites and generates energy for cellular functions. It takes place over eight different steps:

Step 1:  Acetyl CoA enters the citric acid cycle that is a 2-carbon compound and attaches with 4-carbon compound oxaloacetate to form citrate a 6 carbon compound

Step 2: This 6-carbon compound isocitrate

Step 3: 5 carbon compound alpha-ketoglutarate is produced by oxidizing the isocitrate and release the release of carbon dioxide. One NADH molecule is formed.

Step 4: This 5 carbon molecule is oxidized again to form a four-carbon compound that binds with CoA to make forming succinyl CoA. A second molecule of NADH is produced, alongside a second molecule of carbon dioxide.

Step 5: Succinyl CoA is then converted to succinate with GTP formation

Step 6: Succinate is converted into fumarate with the generation of FADH₂ molecule.

Step 7: Fumarate is converted to malate

Step 8: oxaloacetate is formed with the NADH molecule.

Calculate the percent mass of hydrogen in ethane (C2H6).

Answers

Answer:

80.% carbon and 20.% hydrogen

Explanation:

Ethane has molecular formula C2H6. So What is the composition of carbon and hydrogen in ethane. its alot to explain but yea thats wht i got

How do separate the pure ethanol from the mixture of coloured aqueous solution with ethanol​

Answers

Answer:

Fractional distillation is a method for separating a liquid from a mixture of two or more liquids. For example, liquid ethanol can be separated from a mixture of ethanol and water by fractional distillation. This method works because the liquids in the mixture have different boiling points. When the mixture is heated, one liquid evaporates before the other.

Formal charge of Cl in CHCl3

Answers

FC(C) = 4 - 0.5*8 - 0 = 0) FC(Cl) = 7 - 0.5*2 - 6 = 0

An inventor claims to have developed a new perfume that lasts a long time because it doesn't evaporate. Comment on this claim.
a. This would be impossible to make because the perfume would have to be pressurized in order to not evaporate.
b. This product is sure sweep the market making many happy customers.
c. In order to smell something, the molecules must evaporate and reach your nose. If the new perfume doesn't evaporate, it will not have an odor.
d. A perfume that does not evaporate could be toxic since the molecules never leave the skin.

Answers

Answer:

C

Explanation:

Perfume needs to evaporate in order to smell.  If this perfume didn't evaporate, it would stay as a liquid and never smell.  

It wouldn't be D, as no toxic perfumes is sold.

It's not A because perfume doesn't have to be pressurized in order to not evaporate.

It's not B, as it is a hasty conclusion to the claim.  Plus, if the perfume did have an odor, even while not evaporating, the sales would be low as the product is that good.  

or the formula C6H14 , calculate the index of hydrogen deficiency (IHD) and select all the types of unsaturation that might be present in the molecule based on the IHD. The IHD is Which types of unsaturation might be present

Answers

Answer:

See explanation

Explanation:

The term IHD means index of hydrogen deficiency. It tells us the number of missing hydrogen atoms from a given chemical formula. This number of missing hydrogen atoms corresponds to the number and type of multiple bonds in a given compound.

The formula for IHD is; IHD = C + 1 + N/2 – H/2 – X/2

C = Number of carbon atoms

N = Number of nitrogen atoms

H = Number of hydrogen atoms

X = Number of halogen atoms

Since;

N=0, X=0

Then;

IHD = C + 1 – H/2

Hence;

IHD = 6 + 1 - 14/2

IHD = 7 -7

IHD = 0

An IHD of 0 implies that there is no hydrogen deficiency or multiple bond in the molecule. It is purely a saturated compound.

Molecules on the surface of the ice escaping into the water happen in ————.

A. Boiling
B. Freezing
C. Condensation
D. Melting
E. Sublimation

Answers

D melting hope this was right

_______is the division of the cytoplasm at the end of mitosis.
A
Gamete
B
Anaphase
C Prophase
D Cytokinesis

Answers

Answer: D. CYTOKINESIS

Explanation:

Mitosis ends with telophase, or the stage at which the chromosomes reach the poles. ... Telophase is followed by CYTOKINESIS, or the division of the cytoplasm into two daughter cells.

In an acid-base titration,
a. acid is never added to base.
b. base is added to acid or acid is added to base.
c. acid is always added to base.
d. base is always added to acid.

Answers

Answer:

b

Explanation:

An acid-base titration is an experimental procedure used to determined the unknown concentration of an acid or base by precisely neutralizing it with an acid or base of known concentration. ... It is filled with a solution of strong acid (or base) of known concentration.

A solution contains some or all of the ions Cu2+, Al3+, K+, Ca2+, Ba2+, Pb2+, and NH4+. The following tests were performed, in order, on the solution.
Addition of 6 M HCl produced no reaction.
Addition of H2S with 0.2 M HCl produced a black solid.
Addition of (NH4)2S produced a white solid.
Addition of (NH4)2HPO4 in NH3 produced no reaction.
The final supernatant when heated produced a purple flame.
Identify which of these ions were present in the solution, which were absent, and for which ones no conclusions can be drawn.

Answers

Answer:

See explanation

Explanation:

If we look at the tests to be performed on the compounds carefully, we will notice that;

i) Addition of H2S with 0.2 M HCl produced a black solid. This black solid may result from the reaction;

H2S + Cu2+ ---->CuS(balck solid) + H2

or

H2S + Pb2+  ---->PbS(balck solid) + H2

Hence, Cu2+ or Pb2+  may be present

ii) Addition of (NH4)2S produced a white solid. This means that  K^+ may be present because the white precipitate is formed during metathesis.

iii) Potassium ion is known to burn with a purple flame.

Hence the suspected ions are;

Cu2+ , Pb2+ and  K^+

In this equation Ry stands for the Rydberg energy, and n stands for the principal quantum number of the orbital that holds the electron. (You can find the value of the Rydberg energy using the Data button on the ALEKS toolbar.) Calculate the wavelength of the line in the absorption line spectrum of hydrogen caused by the transition of the electron from an orbital with

Answers

The question is incomplete, the complete question is;

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: =E−Ryn2 In this equation Ry stands for the Rydberg energy, and n stands for the principal quantum number of the orbital that holds the electron. (You can find the value of the Rydberg energy using the Data button on the ALEKS toolbar.) Calculate the wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron from an orbital with =n10 to an orbital with =n8. Round your answer to 3 significant digits.

Answer:

162 * 10^-7 m

Explanation:

The Rydberg formula is;

1/λ= R(1/n2^2 - 1/n1^2)

R = Rydberg constant = 1.097 * 10^7 m-1

n2 = final state of the electron = 8

n1 = initial state of the electron = 10

Substituting values;

1/λ= 1.097 * 10^7(1/8^2 - 1/10^2)

1/λ= 1.097 * 10^7(1/64 - 1/100)

  1 / λ = 1.097 10⁷ (0.015625 - 0.01)

1 /λ = 0.006170625 10⁷

λ = (0.006170625 10⁷)^-1

λ = 162 * 10^-7 m

What is the type of the synthesis reaction between Chromium + oxygen???

Answers

Answer:

Explanation: Reaction of oxygen with chromium(II) and chromium(III) porphyrins and synthesis of a .mu.-oxo chromium porphyrin derivative.

tion:

Based on this information which of the following conclusions can be drawn about the growth rate of grass? hurry

Answers

A is the answer I know bc I take biology

Arrange the following molecules in order of increasing bond polarity (highest bond polarity at the bottom):

a. NF3
b. NCl3
c. Nbr3
d. CF4

Answers

NF3– 0.94– third
NCl3–0.12– second
NBr3–0.08– first
CF4–1.43– fourth

NBr3—NCl3—NF3—CF4
Lowest. Highest

Which method is most appropriate for finding the age of the earth in years?

a.absolute dating
b.mass number counting
c.atomic number counting
d.radiometric dating

Answers

Answer: D

Explanation:

The radioactive dating is also called the radiometric dating. It involves the use of several radioactive substances like Argon, uranium, etc. The correct option is D.

What is radioactive dating?

The method of dating rocks and minerals using the radioactive isotopes is defined as the radioactive dating. This method is very helpful to determine the age of igneous and metamorphic rocks which cannot be measured using correlation method.

Many different radioactive isotopes and methods can be used for dating. The elements like uranium and potassium contain a number of different isotopes whose half life is known exactly and thus the concentration of these isotopes within a rock or mineral can measure the age.

The method radiocarbon dating is also used for determining the age of archaeological carbonaceous objects such as wood samples or animal fossils by measuring the radioactivity of ¹⁴C present in them.

Thus the correct option is D.

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