Answer:
m1 v1 + m2 v2 = m1 V1 + m2 V2 conservation of momentum
m1 = 3 m2 = 6
v2 = -4.6
V1 = -4.2
V2 = -1.5
v1 = (m1 V1 + m2 V2 - m2 v2) / m1
v1 = (3 * -4.2 + 6 * -1.5 - 6 * -4.6) / 3
v1 = (-12.6 - 9 + 27.6) / 3 = 2 initial velocity of 3 kg ball
Check:
3 * 2 + 6 * -4.6 = -21.6
3 * -4.2 + 6 -1.5 = -21.6
If a chemical reaction has a AH value of -125 kJ, it would be considered what?
A. an exothermic reaction
B. a reaction that absorbs energy
C. an endothermic reaction
D. A reaction that probably gets cold
exothermic
Explanation:
negative means it's losing energy
A force of 20 N acts upon a 5000g block. Calculate the acceleration of the object
Answer:
a = 4 m/s²
Explanation:
Given: 5000 g, 20N
To find: Acceleration (a)
Solution: Firstly, convert 5000g to kilograms
1000g = 1kg
∴ 5000g = 5kg if divided by 1000
A = F ÷ m
= 20 ÷ 5
= 4 m/s²
Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.
A toy train moves round a circular track of radius 0.50 m.
How many radians has the trained turned through in moving 1.4 m along a track?
Answer:
2.8 radians
Explanation:
[tex]s = r \beta \\ 1.4 = 0.50 \beta \\ \beta = 2.8 \: rad[/tex]
Expresa en notación científica los siguientes números en notación científica estándar: a) 9367421= b) 7241= c) 0.0005519= d) 0.02=
Answer:
so yeah it is Respuesta
That minimum coefficient of static friction between the tyres and the road that will allow the car that will round safely.
Answer:
The answer is "[tex]0.13562748[/tex]"
Explanation:
Please find the complete question in the attached file.
Using formula:
[tex]\bold{U_s=\frac{v^2}{rg}}[/tex]
Given:
[tex]r=1.60 \times 10^2 \ m\\\\g=9.8\\\\v= 52.5\ \frac{km}{hr}= 14.583\ \frac{m}{s}[/tex]
put the value into the above-given formula:
[tex]U_s= \frac{14.583^2}{160 \times 9.8}[/tex]
[tex]= \frac{212.663889}{1568}\\\\=0.13562748[/tex]
Un atleta tiene en un instante dado una velocidad de 4 m/s. Si a partir de ese instante y durante 2 s adquiere un MRUA con una aceleración de 3 m/s2. Calcula la velocidad que alcanza al cabo de esos 2 s.
Answer:
Velocidad final, V = 8 m/s
Explanation:
Dados los siguientes datos;
Velocidad inicial, u = 4 m/s
Aceleración, a = 2 m/s²
Tiempo, t = 2 segundos
Para encontrar la velocidad final (v), usaríamos la primera ecuación de movimiento;
V = u + at
Sustituyendo en la fórmula, tenemos;
V = 4 + 2*2
V = 4 + 4
Velocidad final, V = 8 m/s
HELP ASAP Which statement describes the water particles when condensation takes place?
A. The particles gain heat energy and move closer to each other
B. The particles lose heat energy and move closer to each other
C. The particles gain heat energy and move away from each other
D. The particles lose heat energy and move away from each other
After the collision, car 1 has a final velocity of 6m/s south. What is the final velocity of car2?
a) 35m/s north
b) 35m/s south
c) 81 m/s north
d) 81 m/s south
6CO2 + 6H20 → C6H12O6 + 602
What type of model is shown?
a
b
computer model
conceptual model
physical model
C
mathematical model
Answer:
C. physical model
Explanation:
Sana nakatulong
Find the electric field a distance z above the midpoint between equal and opposite charges,a distance d apart
Answer:
Ex = [tex]2 k q \frac{x}{(x^2 + z^2) ^{3/2}}[/tex] , E_z =0
Explanation:
To find the electric field of each charge, let's use
E = k q / r²
where the field for a positive charge is outgoing and for a negative charge it is incoming.
Since the electric field is a vector magnitude, let's add its components at the point z
X axis
Eₓ = E₁ₓ + E₂ₓ
Eₓ = 2 E₁ₓ
Z axis
E_z = E_{1z} -E_{2z}
E_z= 0
Let's find the expression for the electric field
the distance from the charge to the test point, using the Pythagorean theorem is
r² = (x-0) ² + (0-z) ²
E = [tex]k \frac{q}{x^2 + z^2}[/tex]
with trigonometry we can find its components
cos θ = E₁ₓ / E
E₁ₓ = E cos θ
we substitute
Eₓ = 2 E cos θ
where the cosine
cos θ = x / r
Ex = [tex]2 k \frac{q}{x^2 + z^2} \ \frac{x}{\sqrt{x^2 + z^2} }[/tex]
Ex = [tex]2 k q \frac{x}{(x^2 + z^2) ^{3/2}}[/tex]
E_z = 0
Work done depends on
A. Force
B. Displacement
C. Both force and displacement
D. Neither force nor displacement
Answer:
C. Both force and displacement
Explanation:
Hope this helps
Waldo needs to know how much force to apply in order to move a 4000-kg object at 2 m/S2. Which law should he refer to
Answer:
Newton's second law of motion?
help please
which of the following reacts with most metals to form Hydrogen gas
A.acids
B.Bases
C.acids&bases
Answer:
acid and bases
Explanation:
If you walk for 1.5 hours at an average speed of 4 miles/hr. How far will you have walked?
A spherical conducting shell has charge -5 C. A particle with charge -8 C is placed at the center of the cavity. The charges (in C) on the inner surface and on the outer surface of the shell, respectively, are:
Answer:
Explanation:
The charge of - 5C will be spread on the outer surface of the shell . The presence of - 8C charge at the Centre will create + 8C charge on the inner surface and - 8C charge on the outer surface . The result is that the total charge on the outer surface of the shell will be - 5C + - 8C = - 13C and the inner surface will have charge of + 8C . + 8C charge will be locked to centrally situated - 8C charge and will not be neutralized by negative charge of outer surface .
Light waves travel at 3 × 10 8 m/s. If the light wave has a particular wavelength of 400 nm (400 × 10 –9 m), calculate its frequency.
Answer:
[tex]f=7.5\times 10^{14}\ Hz[/tex]
Explanation:
Given that,
The wavelength of light, [tex]\lambda=400\ nm=400\times 10^{-9}\ m[/tex]
The speed of light, [tex]c=3\times 10^8\ m/s[/tex]
We need to find the frequency of light. We know that,
[tex]c=f\lambda[/tex]
Where
f is the frequency
So,
[tex]f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{400\times 10^{-9}}\\\\f=7.5\times 10^{14}\ Hz[/tex]
So, the frequency of light is [tex]7.5\times 10^{14}\ Hz[/tex].
what type of beetle is this?
PLZZZZ HELPPPPPP MEEEEEE!!!!!! ASAP!!! ILL GIVE 20 POINTS AND BRAINLIEST!!!
:'(
I am soooooooooooo desperate.
Answer:
the answers the correct one is C
Explanation:
In radioactive decay processes, a very important concept is the half-life time, which is the time it takes for the parent nuclei to decompose into child nuclei.
expressed this mathematically is
N = N₀ [tex]e^{- \lambda t}[/tex]
for the average life time
N₀ / 2 = N₀ [tex]e^{- \lambda T_{1/2}[/tex]
T =[tex]\frac{ln 2x}{ \lambda}[/tex]
Analyzing this expression, the nuclei that decay are the so-called parents and the new nuclei called children appear.
when checking the answers the correct one is C
hence, the force needed to accelerate the 1000kg car by 3m/s2 is 3000N
Answer:
i'll answer your question but follow me first
A plastic rod is rubbed with a cloth and becomes positively charged. After charging, the rod is held close to the suspended table-tennis ball shown in Fig. 9.1. The table-tennis ball is covered with metal paint and is uncharged.
Describe what happens to the charges on the metal-painted table-tennis ball as the positively-charged rod is brought close to the ball.
what does heat trapped by pollution cause?
A. Acid rain
B. Decomposition
C. Greenhouse effect
Answer:
C. Greenhouse Effect
Explanation:
The greenhouse effect is caused by heat trapping pollution in the atmosphere.
A spring has an unstretched length of
12.0 cm. Its stiffness k is 8 N/cm. What load is
needed to stretch the spring to a length of 15.0 cm?
Answer:
24 N
Explanation:
Given,
Unstretched length or original length , x1 = 12cm
Stiffness constant, k = 8 N/cm
Load required to take spring to a length , x2 of 15cm
Recall the relation :
F = Ke
Where, e = extension
e = x2 - x1
e = (15 - 12) = 3
F = ke
F = 8 N/cm * 3cm
F = 24 N/cm*cm
F = 24 N
Hence, required load = 24 N
Two train cars with the same mass (30,000 kg) are traveling in the same direction when they collide.
Train Car A has a velocity of 10 m/s and Train Car B has a velocity of 5 m/s. What is their total
momentum after the collision? Make sure to show all your work and include proper units.
Answer:
25
Explanation:
I just did this
Define centre of mass.
Answer:
The center of mass is a position defined relative to an object or system of object
An eighth-grade class is studying the motion of objects. They have learned the following concepts about motion.
Motion occurs when there is a change in the position of an object with respect to a reference point.
While the speed of the object may change at various times during a trip the average speed for the trip is found by dividing the total distance by the total time.
The motion of the object can be changed by varying the amount of net force acting on the object or by varying the mass of the object.
The teacher asked students to design investigations to determine how changing the forces acting on an object or the mass of the object would change its motion.
The materials for the investigation included:
1 - toy cart
3 - 10N weights
1 - pulley
2 - meters of string
One group of students decided to design an investigation to determine how different amounts of mass on the toy cart would affect the speed of the toy cart. They set up their investigation as shown below:
The students performed several trials using different masses in the toy cart (M1). They hung a mass shown as (M2) to pull the toy cart as it dropped.
Below is a table they made to record their results.
Which of the following would be a way to test the effect changing the amount of force acting on the object has on the average speed of the object?
Move the cart at various speeds and determine the force at M1
Add varying numbers of weights to M1 and measure the speed of the car.
Add varying numbers of weights to M2 and measure the speed of the cart.
Move the cart at various speeds and determine the force exerted by M2
Add varying numbers of weights to M1 and measure the speed of the car.
Add varying numbers of weights to M2 and measure the speed of the cart.
How to test the effect of weight on the speed of object?In order to test the changing amount of force that is acting on the object has effect on the average speed of the object we have to change the amount of weight on the object and allows it to move to a certain point in this way we can check the effect of changing amount of weight on the speed of the object.
Learn more about weight here: https://brainly.com/question/2337612
Determine both the mass and the charge of a block of material consisting of 3 x 10^27 protons, 3 x 10^37 neutrons, and 3.1 x 10^27 electrons.
Answer:
The mass of the block of material is 3 x 10³⁷ g/mol
The charge of the material is 4.8 x 10⁸ C
Explanation:
Given;
number of protons of the material, P = 3 x 10²⁷
number of neutrons in the material, N = 3 x 10³⁷
number of electrons in the material, E = 3 x 10²⁷
The mass of the block of material is calculated as follows;
M = P + N
M = 3 x 10²⁷ + 3 x 10³⁷
M = 3 x 10³⁷ g/mol
The charge of the material is calculated as follows;
charge of 1 electron = 1.6 x 10⁻¹⁹ C
charge of 3 x 10²⁷ electrons = 3 x 10²⁷ electrons x 1.6 x 10⁻¹⁹ C
= 4.8 x 10⁸ C
A stationary hockey puck has a mass of 0.27 kg. A hockey player uses her stick to apply a 18 N force over a distance of 0.42 m. How much work does this force do on the puck?
Group of answer choices
7.6 J
-43 J
-7.6 J
28 J
43 J
Need help pls. It is for acellus
Answer:
The height of the water column = 1.62405[tex]\overline{30}[/tex] × 10⁻¹ m
Explanation:
The air cavity in the Coke bottle = 0.220 m deep
The fundamental (frequency) it plays when water is added to shorten the column and it is blown across the top, f = 528 Hz
The given speed of sound in air, v = 343 m/s
We note that the air cavity in the coke bottle is equivalent to a tube closed at one end
The fundamental frequency for a tube closed at one end, 'f', is given as follows;
f = v/(4·L) = v/λ
Where;
L = The height of the water column
λ = The wavelength of the wave
∴ 4·L = v/f = (343 m/s)/(528 Hz) = 0.6496[tex]\overline{21}[/tex] m
∴ L = 0.6496[tex]\overline{21}[/tex] m/4 = 0.162405[tex]\overline{30}[/tex] m
The height of the water column = 1.62405[tex]\overline{30}[/tex] × 10⁻¹ m.
Answer:
0.058
Explanation:
got it right on acellus
How much acceleration does a car need if it is to go a distance of 620 ft. In a time of 20 sec while it is speeding up
Whose atomic theory explains how atoms emit (release) and absorb light?
Bohr’s
Dalton’s
Rutherford’s
Thomson’s
Answer:
Bohr’s
Explanation:
Answer:
A
Explanation: