2. If the reaction of 5.75 moles of sodium with excess hydrofluoric acid is able to produce 2.49 mol H2, what is the percent yield of hydrogen gas?

Unbalanced equation:
Na + HF –> NaF + H2

94.2%
86.5%
43.3%
23.1%​

Answers

Answer 1

Answer:

86.5%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2Na + 2HF –> 2NaF + H2

Next, we shall determine the theoretical yield of the hydrogen gas, H2. This is illustrated:

From the balanced equation above,

2 moles of Na reacted to produce 1 mole of H2.

Therefore, 5.75 moles of Na will react to produce = (5.75 x 1)/2 = 2.88 moles of H2.

Therefore, the theoretical yield of Hydrogen gas, H2 is 2.88 moles.

Finally, we shall determine the percentage yield of Hydrogen gas, H2. This can be obtained as follow:

Actual yield of H2 = 2.49 moes

Theoretical yield of H2 = 2.88 moles

Percentage yield of H2 =.?

Percentage yield = Actual yield /Theoretical yield x 100

Percentage yield = 2.49/2.88 x 100

Percentage yield = 86.5%

Therefore, the percentage yield of Hydrogen gas, H2 is 86.5%.


Related Questions

Consider preparing ammonia gas by the following reaction:
N2(g) + 3H2(g)
===>
2NH3(g)
If you have 28.02 g of N2 and excess H2, how many grams of NH3(g) can be produced.
6.06 g
14.01 g
34.08 g
68.16 g
28.02 g

Answers

Answer:

34.08 g

Explanation:

Take the atomic mass of N=14.0, H=1.0/

no. of moles=mmass/molar mass

no. of moles of N2 used = 28.02 / (14x2)

=1.0007mol

From the equation, the mole ratio of N2 : NH3 = 1: 2,

so one mole of N2 produces 2 moles of NH3.

Using this ratio, we can deduce that the no. of moles of NH3 = 1.0007x2

= 2.001428mol

mass = no. of moles x molar mass

Hence,

mass of NH3 produced = 2.001428 x (14+1x3)

= 34.03

≈C

The correct name for molecule I is

Molecule I

I
|
CH3-CH-CH3


a. Iodopropane

b. 2-iodylpropane

c. 2-iodopropane

D. Propyliodine



14. The correct name for molecule III is


Molecule III

F
|
C= CH
——-


a. 2-Fluoroeth 1-yne

b. Fluoroethyne

C. Fluoroethene

D. Methylfluorine



16. Synthetic chlorinated hydrocarbons such as dioxins and furans are usually greater pollution hazard then natural organic substances because synthetic hydrocarbons are

a. More volatile

b. Less water soluble

C. Less Biodegradable

D. More chemically reactive



Question 17.

Sources of pollutants

1. High temperature combustion

2. Pulp and paper industry


3. Pesticides

4. Sour gas plants


Match each source of pollutant as numbered above with its pollutant as listed below. Use each number only once



17. Dioxins/furans


18. SO2(g)

19. Nox(g)

20. Phosphates


Answers

Answer:

c). 2-iodopropane

14) C). Fluoroethene

16) D). More chemically reactive

17) 1). High temperature combustion  - Dioxins/furans

2). Pulp and paper industry  - SO2(g)

3). Pesticides  - Phosphates

4). Sour gas plants - Nox(g)

Explanation:

The correct name for molecule I would be '2-iodopropane' where the number 2 reflects the position of iodine. There are three carbons and 8 hydrogen atoms which reflect that it is an alkane compound. In the given carbon chain. In this chain of three carbons, iodine is present on the second carbon. Therefore, option C is the correct answer.

14). The appropriate name for molecule III exemplifies Fluoroethene as it consists of two carbons due to which it belongs to the 'ethane' group and it bears the prefix 'fluoro as it belongs to fluorine group and the suffix '-ene' due to double bond.

16). Synthetic hydrocarbons are 'more chemically reactive' and therefore, it generates greenhouse gases and leads to climate change, global warming, depletion of the ozone layer, etc.

17). 1). Dioxins are generated as a result of high-temperature combustion processes like commercial waste incineration or burning of fuels.

2). Pulp and paper industry releases various gases like nitrogen oxide, sulfur dioxide SO2(g), carbon dioxide, etc.

3). Phosphate is the pollutant released from pesticides that badly affects the fertility of the soil.

4). Nox(g) nitrogen oxide released by sour gas plants and coal-fired emissions is a major contributor to increased greenhouses gases and global warming.

procedure to find out if the penny is real copper with copper wire

Answers

Answer:

Four ways to test a copper penny are given below:-

Explanation:

Firstly, take a quick look only at the color of the penny. Zinc pennies may appear patchy, irregular whereas copper-gold coins may seem more probable to be orange or even chocolate. Secondly, drop your penny on the floor and hear the noise it's making. The copper penny would have a "started to ring" sound in this situation, whereas the zinc penny should "clunk." Third, you can weigh the centimeter. You'll need an accurate scale weighing in grams. The penny of copper will weigh 3.11 grams while the penny of zinc weighs 2.5 grams. In the end, look at the date. If your penny was taken out of circulation before 1982, 95 percent copper and 5 percent zinc will be made. Beginning in 1982, pennies had just 2.5 percent copper and 97.5 percent zinc in them. Pennies from any of the two formulations made in 1982 may be produced.

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