Can you help me with this question
Answer:
-1.67
Step-by-step explanation:
Can someone help me with the below question???
Answer:
so 2a+3b=±13
Step-by-step explanation:
4a²+9b²=97
ab=6
2a+3b=?
by using formula
(a+b)²=a²+b²+2ab
(2a+3b)²=(2a)²+(3b)²+2(2a)(3b)
(2a+3b)²=4a²+9b²+12ab
putting values
(2a+3b)²=97+12(6)
(2a+3b)²=97+72
(2a+3b)²=169
taking square root on both sides
√(2a+3b)²=√169
2a+3b=±13
i hope it will help you
Answer:
2a+3b = 13
Step-by-step explanation:
Using this formula
[tex](x+y)^2 = x^2+y^2+2xy[/tex]
Where,
x = 2a and y = 3b
Putting in the above formula
=> [tex](2a+3b)^2=4a^2+9b^2+12ab[/tex]
Putting 4a²+9b² = 97 and ab = 6
=> (2a+3b)² = 97+12(6)
=> (2a+3b)² = 97+72
=> (2a+3b)² = 169
Taking sqrt on both sides
=> 2a+3b = 13
Find the volume of this square
based pyramid.
10 in
12 in
[ ? ]
Answer:
480 in.^3
Step-by-step explanation:
volume of pyramid = (1/3) * (area of base) * height
Since this pyramid has a square for the base, the area of the base is
A = s^2, where s = length of the side of the square
volume = (1/3) * s^2 * h
volume = (1/3)(12 in.)^2 * (10 in.)
volume = (1/3)(144)(10) in.^3
volume = 480 in.^3
The volume of the square-based pyramid is 480 cubic inches as per the concept of the pyramid.
To find the volume of a square-based pyramid, we can use the formula:
Volume = (1/3) x base area x height.
In this case, the base of the pyramid is a square with a side length of 12 inches, and the height of the pyramid is 10 inches.
First, we calculate the base area of the pyramid, which is the area of the square base:
Base area = side length x side length
= 12 in x 12 in
= 144 square inches.
Now, we can substitute the values into the volume formula:
[tex]Volume = \frac{1}{3} \times 144 \times 10[/tex].
Multiplying these values, we get:
[tex]Volume = \frac{1}{3} \times1440 {in}^3[/tex]
Simplifying the expression, we have:
[tex]Volume = 480\ in^3[/tex].
To learn more about the pyramid;
https://brainly.com/question/17615619
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