2 points
13. The law of conservation of mass can be demonstrated by a chemical
reaction. Which of the following models of a chemical reaction best
represents the law of conservation of mass?
A
C
B
D.
8
8.
a.
Ο Ο Ο Ο

Answer:

Explanation:

For Doppler effect in radar the formula is as follows

Δf = f₀ x 2v /c

Δf is change in frequency in reflected wave , f₀ is original frequency , v is velocity of source and c is velocity of right .

Δf  = 2460 Hz , f₀ = 1.0525 x 10¹⁰ Hz , v = ? c is velocity of light .

2460 =  1.0525 x 10¹⁰ x 2 v / 3 x 10⁸

2460 = 105.25 x 2 v / 3

v = 2460 x 3 / (105.25 x 2 )

v = 35 .06 m /s .

(b)

Since the observed frequency is less , the source is moving away from the observer .

option (2) is correct .

Answer:

A,)FD= 114.1N

B)Torque=798.5Nm

Explanation:

We can model a pine tree in the forest as having a compact canopy at the top of a relatively bare trunk. Wind blowing on the top of the tree exerts a horizontal force, and thus a torque that can topple the tree if there is no opposing torque. Suppose a tree's canopy presents an area of 9.0 m^2 to the wind centered at a height of 7.0 m above the ground. (These are reasonable values for forest trees.)

If the wind blows at 6.5 m/s, what is the magnitude of the drag force of the wind on the canopy? Assume a drag coefficient of 0.50 and the density of air of 1.2 kg/m^3

B)What torque does this force exert on the tree, measured about the point where the trunk meets the ground?

A)The equation of Drag force equation can be expressed below,

FD =[ CD × A × ρ × (v^2/ 2)]

Where CD= Drag coefficient for cone-shape = 0.5

ρ = Density

Area of of the tree canopy = 9.0 m^2

density of air of = 1.2 kg/m^3

V= wind velocity= 6.5 m/s,

If we substitute those values to the equation, we have;

FD =[ CD × A × ρ × (v^2/ 2)]

F= [ 0.5 × 9.0 m^2 × 1.2 kg/m^3 ( 6.5 m/s/ 2)]

FD= 114.1N

B) the torque can be calculated using below formula below

Torque= (Force × distance)

= 114.1 × 7

= 798.5Nm

Answer:

A

Explanation:

6.02×10^23 hope this helps

According to Avogadro's constant, 1 mole of uranium-235 will contain 6.022×10⁻²³ atoms of uranium-235 (option-A).

A mole of any element has an atomic mass on the Periodic Table that is equal to its mass in grams. A mole of uranium weighs 238.03 grams.

The atomic structure of uranium has 92 protons and 92 electrons, as indicated by its atomic number of 92. The nucleus of U-238 contains 146 neutrons, but this number can range from 141 to 146.

12 grams of pure carbon-12 weigh exactly one mole, or 6.022 x 1023 atoms, making one mole equivalent to 12 grams of pure carbon-12. • Avogadro's Number is the quantity of particles included in one mole (6.0221421 x 10⁻²³).

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Answer:

the answer is d the world  trade organization

Explanation:

Complete question:

A person holds a 0.300 kg pomegranate at the top of a tower that is 96m high. Another person holds a 0.800 kg melon next to an open window 32m up the tower.

Calculate the gravitational potential energy of the pomegranate and melon.

Answer:

The gravitational potential energy of  pomegranate is 282.24 J

The gravitational potential energy of  melon is 250.88 J

Explanation:

Given;

mass of the  pomegranate, m₁ = 0.3 kg

height of the  pomegranate, h₁ = 96 m

mass of the melon, m₂ = 0.8 kg

height of the melon, h₂ = 32 m

The gravitational potential energy of  pomegranate is calculated as;

P.E₁ = m₁gh₁

P.E₁ = 0.3 x 9.8 x 96

P.E₁ = 282.24 J

The gravitational potential energy of  melon is calculated as;

P.E₂ = m₂gh₂

P.E₂ = 0.8 x 9.8 x 32

P.E₂ = 250.88 J

the one that answered this is correct so give him credit not me

Answer:

Complete question:

A person holds a 0.300 kg pomegranate at the top of a tower that is 96m high. Another person holds a 0.800 kg melon next to an open window 32m up the tower.

Calculate the gravitational potential energy of the pomegranate and melon.

The gravitational potential energy of  pomegranate is 282.24 J

The gravitational potential energy of  melon is 250.88 J

Given;

mass of the  pomegranate, m₁ = 0.3 kg

height of the  pomegranate, h₁ = 96 m

mass of the melon, m₂ = 0.8 kg

height of the melon, h₂ = 32 m

The gravitational potential energy of  pomegranate is calculated as;

P.E₁ = m₁gh₁

P.E₁ = 0.3 x 9.8 x 96

P.E₁ = 282.24 J

The gravitational potential energy of  melon is calculated as;

P.E₂ = m₂gh₂

P.E₂ = 0.8 x 9.8 x 32

P.E₂ = 250.88 J

the one that answered this is correct so give him credit not me

Answer:

170 N

Explanation:

The following data were obtained from the question:

Mass (m) = 20 Kg

Angle (θ) = 30°

Acceleration due to gravity (g) = 9.8 m/s²

Weight (W) =?

The perpendicular component of the weight can be obtained by using the following formula:

W = mg × Cosθ

W = 20 × 9.8 × Cos 30

W = 196 × 0.866

W = 169.7 ≈ 170 N

Therefore, perpendicular component of the weight is 170 N

Solution :

Given :

Weight = 4 lb

Stretched of a spring in  equilibrium,Δ = 2 ft

a). We know that

F = kΔ

4 = k x 2

k = 2 lb/ft

∴ Stiffness of the spring is, k = 2 lb/ft

Motion is critically damped.

[tex]$\epsilon = 1$[/tex]

[tex]$\epsilon=\frac{C}{C_c} = 1$[/tex]

[tex]$C=C_c[/tex]

[tex]$C=C_c=\sqrt{4k_m}[/tex]

[tex]$C=\sqrt{4 \times 2 \times \left(\frac{4}{32.174}\right)}[/tex]

C = 0.99729 lb.s/ft.

b). Displacement

   [tex]$y(t)=y_0 \sin (\omega t)$[/tex]

[tex]$\dot{y}(t)= y_0 \omega \cos (\omega t)$[/tex]

[tex]$[\dot{y}(t)]_{mon}= y_0 \omega $[/tex]

Initial displacement = 6 inches

    [tex]$y_0 = 0.5 \ ft , \ \ \ \dot y (t) = 3 \ ft/sec$[/tex]

  [tex]$\Rightarrow 3=0.5 \times \omega$[/tex]

 [tex]$\Rightarrow \omega = 6$[/tex]

Therefore, displacement :

    [tex]$y(t)=y_0 \sin (\omega t)$[/tex]

   [tex]$y(t)=0.5 \sin (6 t)$[/tex]

Answer:

increases

Explanation:

due to less speed

Answer:

The Moon's monthly

cycle of phases

results from the

changing angle of

its illumination by the Sun.

Because its period of

revolution is the same as its

period of rotation, the Moon

always keeps the same face

toward Earth.

Answer:

A harmonica.

Explanation:

The structure of a harmonica is built in such a way that when the air is blown by the player in it, the air moves within the rectangular structure and making sound vibrations. Sound is heard when an object vibrates. The movement of this vibration creates sound waves, and these waves enter our ears in the form of music.

Therefore, the instrument that will make the slowest vibration among the given instrument will be the harmonica. Thus option D is correct.

Answer:

A temporary charge

Explanation:

Static electricity is not steady. Unlike current electricity, it does not have a  driving force either in the form of a voltage source or an electromotive force from a cell or a generator. Static electricity is usually due a temporary flow of charges between bodies due unbalanced charges within a system, continuing  until equilibrium is achieved.

Answer:

a is correct

Explanation:

Answer:

The coefficient of rolling friction will be "0.011".

Explanation:

The given values are:

Initial speed,

[tex]v_i = 4.0 \ m/s[/tex]

then,

[tex]v_f=\frac{4.0}{2}[/tex]

    [tex]=2.0 \ m/s[/tex]

Distance,

s = 18.2 m

The acceleration of a bicycle will be:

⇒ [tex]a=\frac{v_f^2-v_i^2}{2s}[/tex]

On substituting the given values, we get

⇒    [tex]=\frac{(2.0)^2-(4.0)^2}{2\times 18.2}[/tex]

⇒    [tex]=\frac{4-8}{37}[/tex]

⇒    [tex]=\frac{-4}{37}[/tex]

⇒    [tex]=0.108 \ m/s^2[/tex]

As we know,

⇒  [tex]f=ma[/tex]

and,

⇒  [tex]\mu_rmg=ma[/tex]

⇒       [tex]\mu_r=\frac{a}{g}[/tex]

On substituting the values, we get

⇒       [tex]=\frac{0.108}{9.8}[/tex]

⇒       [tex]=0.011[/tex]

Answer:

a) The car’s speed just after leaving the icy portion of the road is the first part

Explanation:

Answer:

False

Explanation:

I believe it's false.

Evidence not supporting the humanistic perspective is easily measured. So, the given statement is False.

Evidence is defined as an object or information introduced to make the existence of a fact more or less probable that of testimony, document, photograph, video, voice recording, DNA test, or other tangible objects. can take form.

Evidence is used to prove an argument made by individuals or groups that believe something is true or a fact that can be used to refute or disprove a fact or argument that people disagree with, or considered false.

Thus, Evidence not supporting the humanistic perspective is easily measured. So, the given statement is False.

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Answer:

D (not so sure, look in the explanation and judge yourself)

Explanation:

Assume that the acceleration due to gravity is 9.81 m/s^2 downwards

Minimum force required = 0.25 x 34 x 9.81

= 83.385 N

So technically the force need to be greater than 83.385 so the answer should be d, not really sure if it should be b though really depends on the acceleration due to gravity.

Answer:

Man will not slide down

Explanation:

Given:

Coefficient of static friction = 0.25

Angle = 13°

Computation:

Man will slide down if

tan13° > Coefficient of static friction

Tan 13 = 0.23

So,

0.23 < 0.25

So,

Man will not slide down

Answer:

While catching a ball, a cricket player lowers his hands, because by doing so, he increases the time of catch. That is, the person increases the time to bring about a given change in momentum, and hence rate of change of momentum decreases. Thus, a small force is exerted by ball on the hands.

Explanation:

:)

Answer:

it is your answer....... if it is helpful plzz like and comment

Answer:

~65.9m/min

Explanation:

Excuse the messy handwriting!

Answer:

the second one i gues

Explanation:

the stripes tells about the batery input/ the x is the lightbulbs/ and two switches

Answer:

A)2.811 × 10^-12 F

B)4.09V

Explanation:

(a) What is the capacitance?

Capacitance of coaxial cylinder can be determined using below expresion

C= (2π ε0 L)/ Ln[ rb/ra]

Where

ε0= permittivity of free space= 8.85×10^−12 Fm^-1

L= length of each cylinder =13.0 cm= 13×10^-2m

rb= radius of outer cylinder= 7.20 mm= 7.20×10^-3m

ra=radius of inner cylinder=0.550 mm= 0.550×10^-3 m

If we substitute the values we have,

C= (2π ε0 L)/ Ln[ rb/ra]

C= ( 2 × π × 8.85×10^−12 ×13×10^-2) / Ln[

7.20×10^-3/0.550×10^-3]

C=( 7.2288×10^-12 )/2.5729

C=2.811 × 10^-12 F

B) (b) What applied potential difference is necessary to produce these charges on the cylinders?

Vba= Q/C

Where Vba=potential difference

Q= charge on each = 11.5 pC. = 11.5×10^-12

C= capacitance= 2.811 × 10^-12 F

If we substitute the values we have

Vba=(11.5×10^-12)/2.811 × 10^-12

= 4.09V

Answer:

If 2N = 30mm

Then ? =35mm

2N×(35mm÷30mm)

2N×1.167

= 2.33N

To get the additional force required, subtract 2N from 2.33N

2.33N - 2N

= 0.33N

∴ The additional force needed is 0.33N

Explanation:

With this question, we establish the principles of proportion. That is, if more less divides and vice versa. If 2N is stretching the material to 30mm, then how  more force will be needed to stretch the material to 35mm?

Answer:

basically needing sunlight and water

Explanation:

hope it helps

Answer:

the impulse is 14 kg-m/s and the net force applied is 14000 N

Explanation:

Given that,

The mass of a baseball, m = 0.14 kg

Initial velocity of the baseball, u = -40 m/s

Final velocity, v = 60 m/s

Time, t = 0.001 s

We need to find the impulse and average net force applied to the ball by the bat.

Impulse = change in momentum

i.e.

J = m(v-u)

J = 0.14 × (60-(-40))

J = 14 kg-m/s

Now,

J = Ft

F is average force applied to the ball

So,

[tex]F=\dfrac{J}{t}\\\\F=\dfrac{14}{0.001}\\\\F=14000\ N[/tex]

So, the impulse is 14 kg-m/s and the net force applied is 14000 N.

Answer: A

Explanation:

Explanation:

Chem has to do with stored energy while nucleic deals with nucleic reactions.

Answer:

1 : b  2: d

Explanation:

In a series circuit, a common current flows through all the components of the circuit. While in a parallel circuit, a different amount of current flows through each parallel branch of the circuit. Whereas in the parallel circuit, the same voltage exists across the multiple components in the circuit.

Hope It Helps!