Answer:
The parents are green and the children are green.
Explanation:
They all have the green recessive (y). So, the parents are green and the children are green.
Part
A certain gas is present in a 110 L cylinder at 2.0 atm pressure. If the pressure is increased to 4.0 atm, the volume of the gas
decreases to 5.5 L. Find the two constants k. the initial value of k, and kr, the final value of k, to verify whether the gas obeys Boyle's
law.
Express your answers to two significant figures separated by a comma.
View Available Hint(s)
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ΑΣΦ
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2) ?
k ke =
Submit
Answer:
See explanation
Explanation:
Recall that from Boyle's law;
Volume is inversely proportional to pressure at constant temperature
V α 1/P
V = k/P
k = PV
Hence, for Boyle's law, PV = constant
In the first case;
P = 2.0 atm , V= 110 L
PV = 110 * 2.0 = 220
In the second case;
P = 4.0 atm , V= 5.5 L
PV = 4.0 * 5.5 = 22
Since PV is not constant in both cases, the gas does not obey Boyle's law.
Describing Radiation Detection Instruments
Describe the nature and variety of instruments used to detect radiation.
Answer:A Geiger counter is an instrument used for detecting and measuring ionizing radiation. Also known as a Geiger–Müller counter (or Geiger–Muller counter), it is widely used in applications such as radiation dosimetry, radiological protection, experimental physics, and the nuclear industry.
Answer:
Geiger counter
scintillation counter
dosimeter
film badge
detection of ionizing radiation
detection of radiation in the environment
determination of the concentration of radio isotopes in the body
film sensitive to radiation
Explanation:
on edg
A chemist must prepare 0.200 L of aqueous silver nitrate working solution. He'll do this by pouring out some aqueous silver nitrate stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in of the silver nitrate stock solution that the chemist should pour out. Be sure your answer has the correct number of significant digits.
A chemist must prepare 0.200 L of 1.00 M aqueous silver nitrate working solution. He'll do this by pouring out 1.82 mol/L aqueous silver nitrate stock solution into a graduated cylinder and diluting it with distilled water. How many mL of the silver nitrate stock solution should the chemist pour out?
Answer: 0.110 L
Explanation:
According to the dilution law,
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1[/tex] = molarity of stock silver nitrate solution = 1.82 M
[tex]V_1[/tex] = volume of stock silver nitrate solution = ?
[tex]M_1[/tex] = molarity of diluted silver nitrate solution = 1.00 M
[tex]V_1[/tex] = volume of diluted silver nitrate solution = 0.200 L
Putting in the values we get:
[tex]1.82M\times V_1=1.00M\times 0.200L[/tex]
[tex]V_1=0.110L[/tex]
Therefore, volume of silver nitrate stock solution required is 0.110 L
Large cities in the U.S. often formed near the ocean.
What benefit does the ocean provide for people in nearby large cities?
Answer:
a means of work
Explanation:
since its near oceans they are closer to the fish
Reaction 1: Solid sodium hydroxide dissolves in water to form an aqueous solution of ions. ????????????H(????) → ????????+(????????) + ????H −(????????) + x1????????
Reaction 2: Solid sodium hydroxide reacts with an aqueous solution of hydrogen chloride to form water and an aqueous solution of sodium chloride. ????????????H(????) + H +(????????) + ????????−(????????) → H2????(????) + ????????+(????????) + ????????−(????????) + x2????????
Reaction 3: An aqueous solution of sodium hydroxide reacts with an aqueous solution of hydrogen chloride to form water and an aqueous solution of sodium chloride. ????????+(????????) + ????H −(????????) + H +(????????) + ????????−(????????) → H2????(????) + ????????+(????????) + ????????−(????????) + x3????J
Procedure Reaction
1 a. In the glassware menu, take out a 50 mL graduated cylinder and a foam cup. From the tools menu, take out the scale. From the solutions stockroom, move the distilled water and solid NaOH onto the workbench.
b. Transfer 50.0 mL of water to the foam cup. To do this, drag the carboy of water onto the graduated cylinder. (Before you release the mouse button, the cursor will show a "plus sign" to indicate that it is the recipient). A transfer textbar will appear, enter "50.0" mL and click on pour. (You will notice that the graduated cylinder now reads 50.0 mL).
c. Weigh about 1 gram of solid sodium hydroxide pellets, NaOH(s), directly into the foam cup and record its mass to the nearest 0.01 gram. To do this, place the foam cup on the balance so it registers a mass, then click the "Tare" button. Drag the NaOH bottle onto the foam cup. (When you release the mouse, the bottle will be tipped to show that it is in the pour mode). Next, type "1.00" grams into the transfer bar and then click pour. Note that the balance now reads the mass of the transferred NaOH. You may now take the cup off of the scale.
d. Click on the graduated cylinder, record its temperature and then drag it onto the foam cup. (When you release the mouse, the graduated cylinder will be tipped to show that it is in pour mode.) Enter "50.0" mL in the transfer bar and then click pour. Record the highest temperature. e. Remove the foam cup and graduated cylinder from the workbench. (Right click on the item and select "remove.")
Reaction 2
a. Take the 0.5 M HCl from the strong acids cabinet and a fresh foam cup and a fresh 50 mL graduated cylinder from the glassware menu and place them on the workbench. The procedure for Reaction 2 is the same as for Reaction 1 except that 50.0 mL of 0.50 M hydrochloric acid solution is used in place of the water. After measuring 50.0 mL of the HCl solution into the graduated cylinder, proceed as before with steps b-e of the procedure for Reaction 1.
Reaction 3
a. Take out a 25 mL graduated cylinder, a fresh foam cup, the 1.0 M HCl and the 1.0 M NaOH. (If you are running out of room on the workbench, you may remove the previously used chemicals.) Use the graduated cylinder to measure and transfer 25.0 mL of 1.0 M HCl into the foam cup. Pour an equal volume of 1.0 M sodium hydroxide solution into a clean graduated cylinder.
b. Record the temperature of each solution to the nearest 0.1 oC. Pour the sodium hydroxide solution into the foam cup and record the highest temperature obtained during the reaction.
Data and Analysis
Reaction 1Reaction 2Reaction 3
Mass of solution* (g) 1.03g 1.03g
Initial temperature(°C) 25oC 25OC 25OC
Maximum temperature (°C) 30.3oC 37oC 31.7oC
Temperature change (∆T)
Heat energy q (kJ)
Moles of NaOH
Molar heat of reaction (-q/mol) also known as Enthalpy change,
DH (kJ/mol)
The conversion of more than one substance reactant into one or more distinct substances, products, and subsequent discussion can be characterized as follows:
Reaction Calculation:Calculating the Reaction 1:
[tex]NaOH\ (s) \rightarrow Na^+ \ (aq) + OH^- \ (aq) + X_1\ \ KJ ......................... (1)[/tex]
[tex]NaOH[/tex] mass = [tex]1\ g[/tex]
[tex]H_2O[/tex] mass = [tex]50 \ mL = 50\ g[/tex]
water heat of [tex]s_p[/tex] = [tex]4.186\ \frac{ J}{ g\ ^{\circ}C}[/tex]
[tex]\Delta T[/tex] = final temp - initial temp [tex]= 30.3 - 25 = 5.3^{\circ} \ C\\[/tex]
Therefore
Calculating the releasing heat
= mass × sp heat × [tex]\Delta T[/tex]
= 50 × 4.186 × 5.3 J
= 1109.3 J
Calculating the [tex]NaOH[/tex] mass [tex]= 1\ g = \frac{1}{ 40}\ mole= 0.025 \ mole[/tex]
Calculating the releasing heat per mole:
[tex]\to NaOH = \frac{1109.3}{ 0.025} = 44372\ J = 44.4\ KJ[/tex]
Thus
[tex]\to X_1 = 44.4\ KJ[/tex]
Calculating the Reaction 2:
[tex]NaOH \ (s) + H^+\ (aq) + Cl^- \ (aq) \rightarrow Na^+ \ (aq) + Cl^- \ (aq) + H_2O + X_2 \ KJ\\[/tex]
Calculating the net ionic from the equation:
[tex]NaOH\ (s) + H^+\ (aq) \rightarrow Na^+ \ (aq) + H_2O \ (l) + X_2 \ KJ ................................... (2)[/tex]
Calculating the [tex]NaOH[/tex] mass:
[tex]= 1\ g = \frac{1 }{ 40} = 0.025\ mole[/tex]
Calculating the [tex]HCl[/tex] mass:
[tex]= 50\ mL = 50\ g[/tex] [ density = 1 approx]
sp heat of the solution [tex]= 4.186 \frac{J}{g\ ^{\circ}C}[/tex] [ assume the sp heat same as water]
[tex]\Delta T[/tex] = final temp - initial temp [tex]= 36.97 - 25 = 11.97^{\circ} \ C[/tex]
Calculating the releasing heat:
= mass × sp heat × [tex]\Delta T[/tex]
= 50 × 4.186 × 11.97 J
= 2505.3 J
Calculating the releasing heat per mole in [tex]NaOH[/tex]:
[tex]= \frac{ 2505.3 }{ 0.025} = 100212\ J = 100.2 KJ[/tex]
Thus
[tex]X_2 = 100.2 \ KJ[/tex]
Calculating the Reaction 3:
[tex]Na^+ \ (aq) + OH^-\ (aq) + H^+ \ (aq) + Cl^- \ (aq) \rightarrow Na^+\ (aq) + Cl^-\ (aq) + H_2O + X_3\ KJ[/tex]
Calculating the net ionic in the given equation
[tex]H^+ + OH\rightarrow H_2O\ (l) + X_3\ KJ .............................................................. (3)[/tex]
Calculating the volume of [tex]NaOH[/tex]:
[tex]= 25 \ mL\ of\ 1.0\ M = 25 \times \frac{1 }{ 1000} \ mole = 0.025 \ mole[/tex]
Calculating the volume of HCl:
[tex]= 25 \ mL\ of\ 1.0\ M = 25 \times \frac{1 }{ 1000} \ mole = 0.025 \ mole[/tex]
Calculating the total volume
[tex]= 50 \ mL = 50\ g[/tex] { density = 1]
Calculating the sp heat in the solution
[tex]= 4.186 \frac{J}{ g \ ^{\circ} C}[/tex] [ assumed the sp heat is the same as water]
[tex]\Delta T[/tex] = final temp - initial temp [tex]= 31.7- 25 = 6.7^{\circ}\ C[/tex]
Calculating the releasing heat
= mass × sp heat × [tex]\Delta T[/tex]
= 50 × 4.186 × 6.7 J
= 1402.3 J
Calculating the releasing heat per mole in [tex]NaOH[/tex]:
[tex]=\frac{1402.3 }{ 0.025} \ J\\\\= 56092\ J\\\\= 56,09\ KJ[/tex]
Therefore
[tex]X_3 = 56.09 \ KJ\\\\X_1 = 44.4\ KJ\\\\X_2 = 100.2\ KJ\\\\X_3 = 56.09\ KJ\\\\X_2 - [ X_1+ X_3 ] = 100.2 - [44.4 + 56.09]\ = 100.2 - 100.49= -0.29[/tex]
So, the difference is equal to zero.
[tex]\to X_2 = X_1 + X_3[/tex]
This is due to the fact that if we add the reaction (1) and (3) we get the reaction (2)
Calculating the difference percentage:
[tex]= [\frac{0.29 }{100.2} ] \times 100 = 0.29\%[/tex]
The number of joules released in reaction 1 would be 4 times what is released in the calculation if we used 4 g of [tex]NaOH[/tex].
[tex]\to 4 \times 1109.3\ J = 4437.2 \ J\\\\[/tex]
Calculating the [tex]NaOH[/tex] moles [tex]= \frac{4}{40} = 0.1[/tex]
[tex]\to X_1 = \frac{4437.2}{ 0.1} = 44372 \ J = 44.4\ KJ[/tex]
As a result, it has no bearing on the solution's molar heat.
Find out more about the reaction here:
brainly.com/question/17434463
Balance the following skeleton reaction in acidic solution (if the coefficient is 1, put 1; if the coefficient is 0, put O) and identify the oxidizing and reducing agents. For the oxidizing and reducing agent, enter numbers and +/- directly for superscripts and subscripts.
(eg. enter HCO3- for HCO3-, Cu2+ for Cu2+)
Cr2012-(aq) + Zn(s) — Zn2+(aq) + Cr3+(aq)
Cr20-2-(aq) + Zn(s) + H+(aq) +
H20(1) —> Zn2+(aq) + Cr3+(aq) +
H+(aq) + H2O(1) (acidic)
Oxidizing agent:
Reducing agent:
Answer:
jdjdjsjdjkxjejf
Explanation:
djdjsjsdkdkdk
How might the population of owls be affected if the population of grasshoppers were to suddenly decrease
Answer:
The population of grasshoppers would increase becuase there arent as many owls to hunt?feed on them.
Explanation:
Hope this helps
The oceanic crust is mostly associated with the —————.
A. Thermosphere
B. Hydrosphere
C. Asthenosphere
D. Volcanoesphere
E. Atmosphere
Write the balanced NET IONIC equation for the reaction that occurs when ammonium bromide and sodium hydroxide are combined. This reaction is classified as fill in the blank 6 . A. Strong Acid Strong Base B. Weak Acid Strong Base C. Strong Acid Weak Base D. Weak Acid Weak Base The extent of this reaction is: fill in the blank 7 . A. ... Below 50% B. ... 50% C. ... Above 50% D. ... 100%
Answer:
c
Explanation:
How much energy is required to raise the temperature of 10.6 grams of gaseous neon from
20.0 °C to 37.9 °C ?
Answer:
Approximately [tex]1.95 \times 10^{2}\; \rm J[/tex].
Explanation:
Look up the specific heat of gaseous neon:
[tex]c = 1.03 \; \rm J \cdot g^{-1} \cdot K^{-1}[/tex].
Calculate the required temperature change:
[tex]\Delta T = (37.9 - 20.0)\; \rm K = 17.9\; \rm K[/tex].
Let [tex]m[/tex] denote the mass of a sample of specific heat [tex]C[/tex]. Energy required to raise the temperature of this sample by [tex]\Delta T[/tex]:
[tex]Q = c \cdot m \cdot \Delta T[/tex].
For the neon gas in this question:
[tex]c = 1.03\; \rm J \cdot g^{-1}\cdot K^{-1}[/tex].[tex]m = 10.6\; \rm g[/tex].[tex]\Delta T = (37.9 - 20.0)\; \rm K = 17.9\; \rm K[/tex].Calculate the energy associated with this temperature change:
[tex]\begin{aligned}Q &= c \cdot m \cdot \Delta T \\ &= 1.03\; \rm J \cdot g^{-1}\cdot K^{-1} \times 10.6\; \rm g \times 17.9\; \rm K \\ &\approx 1.95 \times 10^{2}\; \rm J\end{aligned}[/tex].
Please help I will give you brainly
Observe the activity in your classroom. You can observe people, objects, and parts of your actual classroom as you
begin to notice changes in matter. Collect data for two examples of changes in matter. Use the Changes in Matter
observation questions to determine if your examples are physical or chemical changes.
Your answer should include the following: two examples, the type of change for each, and how the examples were
formed. You can use this format:
Example 1
Type of Change:
How examples were formed:
Please help me
Answer: Microphones are a type of transducer - a device which converts energy from one form to another. Microphones convert acoustical energy (sound waves) into electrical energy (the audio signal). Different types of microphone have different ways of converting energy but they all share one thing in common! Furthermore, Example 1: Crushing a can.
Type of change:
Developmental – May be either planned or emergent; it is first order, or incremental. ...
Transitional – Seeks to achieve a known desired state that is different from the existing one. ...
Transformational – Is radical or second order in nature.
True or False:
The geocentric model of the solar system is correct.
Answer:
True
Explanation:
A cold drink has been placed outside on a hot day. As time passes, the outside of the cup forms water droplets on it. What phase change has occurred?
A. Melting
B. Freezing
C. Condensing
D. Vaporizing
Answer:
the answer is c. condensing
A solution has a pH of 9.5. Is the solution an acid or a base?
Answer:
The solution is Basic
Determine whether each described process is endothermic or exothermic.
Wood burns in a fireplace Choose...
Ice melts into liquid water Choose...
Solid dissolves into solution, making ice pack feel cold Choose...
A process with a calculated positive q Choose...
A process with a calculated negative q Choose...
Acid and base are mixed, making test tube feel hot Choose...
Answer:
Following are the responses to the given choices:
Explanation:
Air woods is a smoking process as it releases heat.Incasereaction produces reaction energy, the response is then exothermic, while absorbs react energy, therefore the response is exothermic.Heat is essential for melting ice. Correspondingly, ice melts into liquid water as well as other reactions stop.Feel cold due to fuel absorption. That ice pack thus feels cold and brings another micro reaction to the stop.Unless the reaction's heat is positive, that process is endothermal.The reaction is exothermic unless the heat from the reaction is bad.Feel hot due to its loosening energy. A test tubefeelhot is, thus, an exothermic reaction.A buffer solution contains 0.20 mol of propionic acid (CH3CH2COOH) and 0.25 mol of sodium propionate (CH3CH2COONa) in 1.50 dm3.
What is the pH of this buffer?
Enter your answer using two decimal places.
Answer:
I don't know how to do it the subject
Most acids are strong acids.
A. True
B. False
Answer:
False, There are only a few strong acids, so many people choose to memorize them. All the other acids are weak
Explanation:
What product(s) would be formed when these are the reactants? C5H12 + O2 (limited)
Answer:
Carbon dioxide and water I believe because it is a combustion reaction
A _________________ is the path of energy transfer from producer to consumers.
Someone please help
Answer: Food chain
Explanation: none
explain the importance of changing states of matter
As a result, when a substance absorbs enough energy then its atoms or molecules move around. And, when increase in this energy takes place then atoms tend to collide frequently with each other. Hence, it causes change in state of a substance. Therefore, changes in matter are important for the conservation of energy
mark brainliest if right
I NEED HELP WITH THIS CHEMISTRY QUESTION PLS
Answer:
Iron, according to:
[tex]2Al(s)+3Fe(NO_3)_2(aq)\rightarrow 3Fe(s)+2Al(NO_3)_3(aq)[/tex]
Explanation:
Hi there!
In this case, according to the law of conservation of mass, which states that matter cannot be neither created nor destroyed, it is possible for us to figure out the missing element in the reaction by taking into account this is a single displacement reaction in which Al goes with NO3 to produce the Al(NO3)3, and therefore the other element would be iron (Fe) as can be seen on the following chemical reaction:
[tex]2Al(s)+3Fe(NO_3)_2(aq)\rightarrow 3Fe(s)+2Al(NO_3)_3(aq)[/tex]
Best regards!
how many types of hybridization does carbon undergo?
Answer:
For carbon the most important forms of hybridization are the sp2- and sp3- hybridization. Besides these structures there are more possiblities to mix dif- ferent molecular orbitals to a hybrid orbital. An important one is the sp- hybridization, where one s- and one p-orbital are mixed together.
What is the frequency of light (in per seconds) that has a wavelength of 670 nm?
Answer:
[tex]f=4.47\times 10^{14}\ Hz[/tex]
Explanation:
Given that,
The wavelength of light, [tex]\lambda=670\ nm=670\times 10^{-9}\ m[/tex]
We need to find the frequency of the light. The relation between the frequency and wavelength is given by :
[tex]v=f\lambda[/tex]
The speed of light is equal to c.
So,
[tex]f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{670\times 10^{-9}}\\\\f=4.47\times 10^{14}\ Hz[/tex]
So, the frequency of light is equal to [tex]4.47\times 10^{14}\ Hz[/tex].
Use the information to answer the following question.
A machinist creates a solid steel part for a wind turbine. The part has a volume of 1,015 cubic centimeters. Steel can be purchased for $0.29 per kilogram and has a density of 7.95 g/cm3.
If the machinist makes 500 of these parts, what is the total cost of the steel?
A.
$2.34
B.
$1,152.75
C.
$2,340.08
D.
$1,170.84
Answer: D
Explanation:
Please help!!!!!!!!!!!!!!
Answer:
my guy we need to read lesson cuz int know what any of that mean
Explanation:
Which of these statements BEST describes a possible environmental
consequence in constructing a large-scale wind farm to generate
electricity?
A Wind farms alter the regional climate.
B. Wind farms can disrupt migrating wildlife.
C. Wind farms use a renewable energy source.
D. Wind farms generate direct current electricity.
Answer:
Option B. is correct
Explanation:
Wind turbines collect the kinetic energy of wind using the turbine blades. The blades turn an electric generator as they are connected to a drive shaft, which in turn produces electricity.
These turbine blades can disrupt flying wildlife including bats and birds.
So,
wind farms can disrupt migrating wildlife.
Option B. is correct.
what is the freezing point of glucose?
Answer:
In Fahrenheit it is 294.8°F and in Celsius it is 146°C.
5
How many J of energy are needed to raise the temperature of 18.3 g of
water from 11.88°C to 49.32°C?*
2540 J
1740 J
2870 J
3570 J
Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat, and ΔT is the change in temperature (T₂-T₁). The specific heat of water is 4.184 J/g °C. We are given the mass of water (m = 18.3 g), the final temperature (T₂ = 49.32 °C), and the initial temperature (T₁ = 11.88 °C). The change in temperature, ΔT, equals 49.32 °C - 11.88 °C = 37.44 °C. With all these values at hand, we can solve for the amount of energy needed, Q:
Q = (18.3 g)(4.184 J/g °C)(37.44 °C) = 2866.7 J ≈ 2870 J (three sig figs).
If the Sun suddenly lost all of its gravity, which statement would best describe how the planets would move?
a
The planets would stop moving.
b
The planets would all collide into each other.
c
The planets would travel in a straight line.
d
The planets would continue moving in a circular path.
Answer:
It's B
Explanation:
It's the sun's gravitational pull that keeps our planets revolving around it and as soon as it's gone it's a high chance of it being a pinball machine and everything colliding into each other.
Deep water currents are formed partly due to the amount of _________________ in the water.
Answer:
Density differences
Explanation:
The water transports cool masses of air and hot air, the transports is driven by the amount of changes of Temperature and Salinity (ThermoHaline)