2. Solve 4.3(n + 6) > 47.3. Then graph the solution.

Answer:

The present value of leasing the towers is $19,576,000 while the present value of erecting new towers is $20,273,000. Therefore, the company should lease the towers.

Step-by-step explanation:

The probability of yellow or has an odd number is 8/9

From the question, we have the following parameters that can be used in our computation:

Green = 1 to 3

Yellow = 1 to 6

This means that

Odd = 2 + 3

Odd = 5

So, we have

P(Yellow) = 6/9

P(Odd) = 5/9

P(Yellow and Odd) = 3/9

The probability of yellow or has an odd number is

P = 6/9 + 5/9 - 3/9

Evaluate

P = 8/9

Hence, the probability is 8/9

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The  inequality given that the function f is increasing over it s domain

f(x²-2)<f (7x-8), Df =  (-∞,2) is: x ∈ (-∞,1) U (6,2).

We know the  values of x within the domain by setting the intersection points of the two functions f(x2-2) and f(7x-8).

f (x²-2) = f (7x-8)

So,

x²-2 = 7x-8

Simplify and find x

x² - 7x + 6 = 0

(x - 1)(x - 6) = 0

x = 1 or x = 6

The domain (-,2) is divided into the intervals (-,1), (1,6), and (6,2). Now let assess the interval endpoints because f is rising:

For x < 1:

x² - 2 < 7x - 8

x² - 7x + 6 < 0

(x - 1)(x - 6) < 0

For 1 < x < 6:

x² - 2 < 7x - 8

x² - 7x + 6 < 0

(x - 1)(x - 6) > 0

For x > 6:

x² - 2 < 7x - 8

x² - 7x + 6 < 0

(x - 1)(x - 6) < 0

Since f is rising across its domain the inequality f(x2-2) f(7x-8) has the following solution: x ∈ (-∞,1) U (6,2).

Therefore the inequality is  x ∈ (-∞,1) U (6,2).

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Thus the numbers that we are looking for are 8 and -6.

We would have to use a method in which we would call the  numbers that we want to find x and y.

We know that we have to solve the problem as a simultaneous equation so that we can be able to obtain the numbers that we seek.

If

xy = -48 ---(1)

x + y =2 --- (2)

y = -48/x ---(3)

Substitute (3) into (2)

x - 48/x = 2

x^2 - 48 = 2x

x^2 -2x - 48 = 0

x = 8 and x = -6

Thus;

8 + y = 2

y = -6

Or

-6 + y = 2

y = 8

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Missing parts:

What numbers multiply to -48 and add to 2 at the same time

The location of point T on the number line is 3

From the question, we have the following parameters that can be used in our computation:

A = -6

B = 9

T = three-fifths of the distance from A to B.

Using the above as a guide, we have the following:

T = A + 3/5 *(B - A)

Substitute the known values in the above equation, so, we have the following representation

T = -6 + 3/5 *(9 + 6)

Evaluate

T = 3

Hence, the location is 3

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Brenda's class left for the field trip at 10:16 A.M.

We have,

Let's break down the time of Brenda's class field trip:

50 minutes to drive to the museum

3 hours and 45 minutes (or 225 minutes) at the museum

56 minutes to drive back to school

Adding up all of these times, we get:

50 + 225 + 56 = 331 minutes

So the field trip took a total of 331 minutes.

If the class arrived back at school at 3:47 P.M., and we subtract 331 minutes from 3:47 P.M., we can determine the time they left for the field trip:

3:47 P.M. - 331 minutes

= 10:16 A.M.

Therefore,

Brenda's class left for the field trip at 10:16 A.M.

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Answer:

correct answer is D

Step-by-step explanation:

The value of the missing length of the enlarged triangle in the simplest form would be = 60mm.

To calculate the missing length, the formula for scale factor should be used such as follows;

Scale factor = Larger dimensions/smaller dimensions

length of ∆T = 10mm

length of ∆S = 3mm

scale factor = 10/3 = 3.33

If the width of ∆S = 18mm

width of ∆ T = 18×3.33

= 59.94 = 60mm

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The relation between lengths of AB and BC are,

⇒  Lenght of AB and BC are different.

We have to given that;

Triangles ABD and BDC are given.

Here, All the angles of a triangle ABD are different from angles of BDC.

Hence, We get;

Both triangle ABD and BDC are congruent.

So, All the sides of ΔABD are different from the sides of different from ΔBDC.

Hence, Lenght of AB and BC are different.

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The range of the function f(x) = |x| + 5 include the following; B. R: {f(x) ∈ ℝ | f(x) ≥ 5}.

In Mathematics and Geometry, a domain is the set of all real numbers for which a particular function is defined.

Additionally, the vertical extent of any graph of a function represents all range values and they are always read and written from smaller to larger numerical values, and from the bottom of the graph to the top.

By critically observing the graph shown in the image attached above, we can reasonably and logically deduce the following domain and range:

Domain = {-∞, ∞} or -∞ ≤ x ≤ ∞.

Range = {5, ∞} or 5 ≤ f(x) ≤ ∞.

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The new coordinates of dilated rectangle by scale factor of 1/4 are J(1, 2), K(3, 2), L(3, 1), and M(1, 1) we can draw figure.

We are given the coordinates of the vertices of a rectangle J(4,8), K(12,8), L(12,4), and M(4,4).

To dilate the rectangle by a scale factor of 1/4, we need to multiply each coordinate by 1/4.

Multiplying each x-coordinate by 1/4

x-coordinate of J: 4 * 1/4 = 1

x-coordinate of K: 12 * 1/4 = 3

x-coordinate of L: 12 * 1/4 = 3

x-coordinate of M: 4 * 1/4 = 1

Multiplying each y-coordinate by 1/4

y-coordinate of J: 8 * 1/4 = 2

y-coordinate of K: 8 * 1/4 = 2

y-coordinate of L: 4 * 1/4 = 1

y-coordinate of M: 4 * 1/4 = 1

Therefore, the coordinates of the dilated rectangle are: J(1,2), K(3,2), L(3,1), and M(1,1).

Using these new coordinates, we can draw the dilated rectangle by plotting the four vertices on a coordinate plane.

The dilated rectangle has the same shape and orientation as the original rectangle, but it has been reduced in size by a scale factor of 1/4.

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The percentage of boxes with green lamps is 60%, the correct option is C.

We are given that;

Number of boxes= 40

Green lamp boxes= 24

Now,

To calculate the percentage of boxes that contain green lamps, you need to divide the number of boxes with green lamps by the total number of boxes and then multiply by 100. This is according to the formula for finding a percentage of a number12.

=(24 / 40) x 100 = 60%

Therefore, by percentage the answer will be 60%.

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The common ratio between the sum of a certain infinite geometric series is 2. the sum of the squares of all the terms is 3 is, - 1/9

Now, We can formulate;

⇒ { a/ 1-r} = 2

And, a²/ (1 - r²) = 5

⇒ 2a/ ( 1+r ) = 5

⇒ 2(2 - 2r)/ 1 + r = 5

⇒ 4 - 4r = 5 + 5r

⇒ 9r = - 1

⇒ r = - 1/9

Thus, The common ratio between the sum of a certain infinite geometric series is 2. the sum of the squares of all the terms is 3 is, - 1/9

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The solution to the inequality is x >= -2 for inequality 3x-5≥-11

The given inequality is 3x-5≥-11

Three times of x greater than or equal to minus eleven

x is the variable

3x - 5≥ -11:

Adding 5 to both sides, we get:

3x ≥ -6

Dividing both sides by 3, we get:

solution is  x≥-2

Therefore, the solution to the inequality is x >= -2.

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Answer:

< - 1, 5 >

Step-by-step explanation:

a = < - 5, 2 >

b = < 4, 3 >

a + b

= < - 5, 2 > + < 4, 3 >

add corresponding elements

= < - 5 + 4, 2 + 3 >

= < - 1, 5 >

The solutions for the inequality, in order from smallest to largest, are:

-7, -4, -2, 0, 0.9, 0.99, 0.999, 1

Here we have the inequality:

y ≤ 1

All the values that make the inequality true are the values equal or smaller than 1.

So we just need to list these in order from smaller to larger.

The correct order will be:

-7, -4, -2, 0, 0.9, 0.99, 0.999, 1

These are the solutions in order.

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Answer:A frequency table is a type of statistic used to organize and display data.

What is data set?

A data set is a collection of related data records or observations, usually containing information about a particular subject or area of study. Data sets can be used to analyze trends, make predictions, and provide insights into various phenomena. Data sets can be collected from a variety of sources, such as surveys, experiments, simulations, or other research methods. They are typically organized into tables and can include both quantitative and qualitative data.

It is a chart that shows how often something occurs within a given set of data. The categories in a frequency table are the different values or categories of data, and the frequencies are the number of times each category occurs.

Relative frequency is the ratio of the number of times a category occurs in the data set to the total number of values in the data set. It is usually expressed as a percentage or decimal. For example, if the data set contains 20 values and the category "A" occurs 5 times, the relative frequency of "A" is 25%.

Cumulative frequency is the sum of the frequencies up to a given point in the data set. It is used to show how many values are below or above a certain category. For example, if the data set contains 20 values and the category "A" occurs 5 times, the cumulative frequency of "A" is 5. This means that there are 5 values that are below or equal to "A" in the data set.

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well, presumably the best deal is the cheaper one, so let's check how much is it for each

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{15\% of 45.99}}{\left( \cfrac{15}{100} \right)45.99} ~~ \approx ~~ 6.90\hspace{5em}\underset{ Store~1 }{\stackrel{ 45.99~~ - ~~6.90 }{\approx\text{\LARGE 39.09}}}\checkmark \\\\[-0.35em] ~\dotfill[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em} \stackrel{\textit{20\% of 52.99}}{\left( \cfrac{20}{100} \right)52.99} ~~ \approx ~~ 10.60\hspace{4em}\underset{ Store~2 }{\stackrel{ 52.99~~ - ~~10.60 }{\approx\text{\LARGE 42.39}}}[/tex]

The solid formed when the right triangle is rotated around the side length of 5 is two cones with a radius of 1.5 units and a height of 1.8 units and 3.2 units.

The volume of the smaller cone is approximately 3.82 cubic units, and the surface area is approximately 20.94 square units.

The volume of the larger cone is approximately 6.04 cubic units, and the surface area is approximately 20.94 square units.

We have,

When the right triangle is rotated around the side length of 5, it forms two cones with different heights and radii.

Now,

r = base / 2 = 3 / 2 = 1.5 units

h = height = 4 units

Using the Pythagorean theorem,

l = √(1.5² + 4²) = √(18.25) ≈ 4.27 units

The first cone has a radius of 1.5 units and a height of 1.8 units (5 - 4.27)

The second cone has a radius of 1.5 units and a height of 3.2 units (5 - 1.8).

Now,

The volume of a cone.

V = (1/3)πr^2h

The surface area of a cone.

A = πrl + πr^2

For the first cone:

V = (1/3)π(1.5)²(1.8) = 3.82 cubic units

A = π(1.5)(4.27) + π(1.5)² = 20.94 square units

For the second cone:

V = (1/3)π(1.5)²(3.2) = 6.04 cubic units

A = π(1.5)(4.27) + π(1.5)² = 20.94 square units

Thus,

The solid formed when the right triangle is rotated around the side length of 5 is two cones with a radius of 1.5 units and a height of 1.8 units and 3.2 units.

The volume of the smaller cone is approximately 3.82 cubic units, and the surface area is approximately 20.94 square units.

The volume of the larger cone is approximately 6.04 cubic units, and the surface area is approximately 20.94 square units.

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The value of solution of the equation is,

⇒ tan x = 1 / 3

We have to given that;

The expression is,

⇒ - 2 tan (-x) = 5 tan (x) - 1

Now,, We can simplify as;

⇒ - 2 tan (-x) = 5 tan (x) - 1

⇒ - 2 (-  tan (x) ) = 5 tan (x) - 1

⇒ 2 tan (x) = 5 tan (x) - 1

⇒ 5 tan x - 2 tan x = 1

⇒ 3 tan x = 1

⇒ tan x = 1 / 3

Thus, The value of solution of the equation is,

⇒ tan x = 1 / 3

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The volume of the solid figure is 75 ft³

An equation is an expression that can be used to show the relationship between two or more numbers and variables using mathematical operators.

The area of a figure is the amount of space it occupies in its two dimensional state.

The volume of a figure is the amount of space it occupies in its three dimensional state.

To get the surface area:

Area of base = (6 ft * 2 ft) + (7 - 6)ft * 3 ft  = 15 ft²

Volume of figure = area of base * height = 15 ft² * 5 ft = 75 ft³

The volume of the figure is 75 ft³

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Answer:

Exponential decay is represented by the equation:

y = a * e^(-bx)

where:

y is the final value

a is the initial value

b is the decay rate

x is the time variable

The exponential decay rate, b, can be found by taking the natural logarithm (ln) of both sides of the equation, then rearranging to isolate the decay rate:

ln(y/a) = -bx

b = -ln(y/a)/x

So, to find the exponential decay rate, you would need to know the initial value (a), the final value (y), and the time elapsed (x). Then, you can use the formula above to calculate the decay rate, b.

The expressions "1+b" and "1-b" are not sufficient to find the exponential decay rate, as they do not contain enough information about the specific scenario or data set.

if this helps, can you please mark my answer brainliest?

The critical value for a two-tailed test at the 0.05 significance level is 1.96.

The null hypothesis is that there is no difference in the proportion of men and women intending to vote for Donald Trump, and the alternative hypothesis is that there is a difference.

The test statistic is given by:

z = (p1 - p2) /√[(p×(1-p)×(1/n1 + 1/n2),

where p = (x1 + x2) / (n1 + n2) and x1 and x2 are the number of successes in samples 1 and 2 respectively, and n1 and n2 are the sample sizes of samples 1 and 2 respectively.

In this case, x1 = 120, x2 = 132, n1 = 250, and n2 = 240.

Plugging these values into the equation gives us z = 0.906.

Since the test statistic does not exceed the critical value, we fail to reject the null hypothesis. That is, there is not convincing evidence that there is a difference in the proportion of all men and the proportion of all women in this city who intended to vote for Trump at the 0.05 significance level.

Therefore, the critical value for a two-tailed test at the 0.05 significance level is 1.96.

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The requried measure of the angles is given as:

(1) ∠OLQ = 32, (2) ∠NQP = 38°, (3) ∠NLP = 38°, and (4) ∠NPL = 52°.

As shown in the figure,
(1) Following the property of angle subtended by an arc on the center of the circle and at a point on the circumference of a circle,
∠OLQ = ∠OQL = 64/2 = 32°.

(2)

Following the figure,
∠NQP = ∠LQP - ∠LQN
          = ∠LQP-[∠OQL+∠MQN]
          = 90 - [32+20]
          = 38°

Similarly,
∠NLP = 38°
∠NPL = 52°

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If the two angles are complementary, then their sum is 90 degrees.

The inclination is the separation seen between planes or vectors that meet. Degrees are another way to indicate the slope. For a full rotation, the angle is 360°.

Complementary angle - Two angles are said to be complementary angles if their sum is 90 degrees.

If the two angles are complementary, then their sum is 90 degrees.

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The result of -3u + 5v is the vector (12, -34).

Let's start by defining the two given vectors u and v:

u = (1, 3)

v = (3, -5)

To find the dot product of two vectors, we need to multiply their corresponding components and then add up the results. The formula for the dot product of two vectors can be written as:

u · v = u₁v₁ + u₂v₂ + ... + uₙvₙ

where u₁ and v₁ are the first components of vectors u and v, u₂ and v₂ are the second components, and so on up to un and vₙ, which are the nth components.

Using this formula, we can find the dot product of u and v as follows:

u · v = (1)(3) + (3)(-5)

= 3 - 15

= -12

So, the dot product of vectors u and v is -12.

Next, we need to calculate -3u + 5v. To do this, we need to multiply each component of vector u by -3 and add it to the corresponding component of vector v multiplied by 5. We can write this as follows:

-3u + 5v = (-3)(u₁, u₂) + (5)(v₁, v₂)

= (-3)(1, 3) + (5)(3, -5)

= (-3, -9) + (15, -25)

= (12, -34)

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It will take the team 65 days to complete the maintenance of the entire sewage pipe

From the question, we have the following parameters that can be used in our computation:

Sewage pipe = 52 miles

Distance covered each day = 4/5 miles

Using the above as a guide, we have the following:

Number of days = Sewage pipe /Distance covered each day

Substitute the known values in the above equation, so, we have the following representation

Number of days = 52/(4/5)

Evaluate the quotient

Number of days = 65

Hence, the number of days is 65

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The Venn diagram for (D ⋃ E) ⋃ F will be the ovarlapped region of D,E and F.

To represent the sets D, E, and F in the Venn diagram, we first construct three overlapping circles. Then, beginning with the innermost operation and moving outward, we shade the regions corresponding to the set operations in the expression.

We shade the area where the circles for D and E overlap because the equation (D ⋃ E)  denotes the union of the sets D and E. All the elements in D, E, or both are represented by this area.

The union of (D ⋃ E) with F is the next step. This indicates that we darken the area where the circle for F crosses over into the area that we shaded earlier. All the components found in sets D, E, F, or any combination of these sets are represented in this region.

The final Venn diagram should include three overlapping circles, with (D ⋃ E) ⋃ F shaded in the area where all three circles overlap.

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The graph is a function: A. yes

The domain of this function is: E. x ≥ -3.

The range of this function: G. all real numbers.

In Mathematics and Geometry, a domain is the set of all real numbers for which a particular function is defined.

Additionally, the vertical extent of any graph of a function represents all range values and they are always read and written from smaller to larger numerical values, and from the bottom of the graph to the top.

By critically observing the graph shown in the image attached above, we can reasonably and logically deduce the following domain and range:

Domain = {-3, ∞}, x ≥ -3, or -3 ≤ x ≤ ∞.

Range = {-∞, ∞} or all real numbers.

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