2) The same liquor store owner wants to do a similar comparison but for high end wines to see if there is a difference. The owner samples 16 white wines finding an average of $45.13 (s=5.10) and samples 16 red wines and finds an average of $48.69 (s=5.23). Use alpha=0.05.
2a) What is the standard error?
2b) What is the test statistic?
2c) What is the p-value?
2d) What can you conclude about cost of high end wines?

Answer: El precio unitario de las palomitas es de $60 y el precio unitario del refresco es de $70.

Primero, podemos descomponer el costo total de la primera visita al cine en el costo de las palomitas y el costo de los refrescos:

- 5 palomitas + 7 refrescos = $630

- Palomitas = $x, Refrescos = $y

- 5x + 7y = 630

Luego, podemos descomponer el costo total de la segunda visita al cine en el costo de las palomitas y el costo de los refrescos:

- 8 palomitas + 11 refrescos = $1000

- Palomitas = $x, Refrescos = $y

- 8x + 11y = 1000

Ahora podemos resolver este sistema de ecuaciones para encontrar el precio unitario de las palomitas y del refresco. Primero, despejamos y de la primera ecuación:

- 5x + 7y = 630

- 5x = 630 - 7y

- x = (630 - 7y) / 5

Luego, sustituimos esta expresión para x en la segunda ecuación:

- 8x + 11y = 1000

- 8[(630 - 7y) / 5] + 11y = 1000

- 504 - 45.6y + 11y = 1000

- 65.4y = 496

- y = 7.58

Finalmente, podemos sustituir este valor para y en la primera ecuación para encontrar el valor de x:

- 5x + 7(7.58) = 630

- 5x = 578.86

- x = 115.77

Por lo tanto, el precio unitario de las palomitas es de $60 y el precio unitario del refresco es de $70.

Step-by-step explanation:

In terms of deviation from the average salary, David is doing better in his company than Andrew is in his. However, it's important to note that there may be other factors that impact their overall job performance and success within their respective companies.

To determine who is doing better in comparison to their coworkers, we need to calculate the z-scores for both Andrew and David. The z-score measures the number of standard deviations a data point (in this case, their salaries) is away from the mean (average salary). The formula for the z-score is:

z = (X - μ) / σ

where X is the individual's salary, μ is the average salary, and σ is the standard deviation.

For Andrew:
X = $45,000 EC
μ = $41,000 EC
σ = $7,000 EC

z = ($45,000 - $41,000) / $7,000
z = $4,000 / $7,000
z = 0.5714

For David:
X = $38,000 EC
μ = $35,000 EC
σ = $1,700 EC

z = ($38,000 - $35,000) / $1,700
z = $3,000 / $1,700
z = 1.7647

Comparing these deviations, we can see that David is doing better in comparison to his coworkers than Andrew is. David's deviation is larger than Andrew's, which means that his salary is further above the average salary in his company than Andrew's is in his.

A higher z-score indicates a better position compared to coworkers. In this case, David has a higher z-score (1.7647) compared to Andrew (0.5714), meaning that David is doing better in comparison to their coworkers.

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we write the iterated integral of a continuous function f over the region using the order dy dx. Since the region is symmetric with respect to the x-axis, we can integrate over the top half of the region and then multiply by 2.
Here, "region" refers to the part of the circle of radius 5 centered at the origin that lies in the first quadrant, "integral" refers to the calculation of the area or volume under a curve or surface, and "quadrant" refers to one of the four regions obtained by dividing a plane into four equal parts by the x- and y-axes.

Step 1: Sketch the region
The region (R) is in the first quadrant, which means x ≥ 0 and y ≥ 0. The region is bounded by a circle with radius of 5 centered at the origin (0,0). This circle can be represented by the equation x^2 + y^2 = 25.

Step 2: Write the iterated integral
To find the iterated integral of a continuous function f over the region R using the order dy dx, we first need to find the bounds for y and x.
The limits of integration for y are from 0 to the y-coordinate of the top half of the circle, which is √(25-x^2). The limits of integration for x are from 0 to 5. Therefore, the iterated integral is:
∫ from 0 to 5 ∫ from 0 to √(25-x^2) f(x,y) dy dx

For y: Since R is in the first quadrant and bounded by the circle, the lower bound for y is y = 0. The upper bound for y, given x, is the equation of the circle's top half, solving for y: y = sqrt(25 - x^2).

For x: Since R is in the first quadrant, the lower bound for x is x = 0, and the upper bound is x = 5 (the radius of the circle).

Now we can write the iterated integral using these bounds:
∫(from x=0 to x=5) ∫(from y=0 to y=sqrt(25-x^2)) f(x,y) dy dx

This iterated integral represents the continuous function f over the specified region R in the first quadrant, using the order dy dx.

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A field variant changes value with space or time transformation while an invariant field remains the same.

Field variant and invariant are terms used in mathematics and physics to describe how certain quantities or properties change or remain constant within a specific context.

A field variant is a quantity or property that changes when the system's parameters, such as location or time, are altered. For example, the temperature in a room may vary from one point to another, so it would be considered a field variant. In physics, electric and magnetic fields are often considered field variants, as their strength and direction can change depending on the observer's position.

On the other hand, a field invariant is a quantity or property that remains constant regardless of the system's parameters. In mathematics, a scalar quantity is often invariant, such as the length of a vector or the magnitude of a force. In physics, an example of a field invariant is the speed of light in a vacuum, which remains constant at approximately 299,792 kilometers per second, irrespective of the observer's position or motion.

In summary, field variants are properties that change with respect to a specific context, while field invariants remain constant. Understanding these concepts is essential for solving problems in mathematics, physics, and various scientific fields.

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Answer:

r=4

Step-by-step explanation:

r=19-5p

r=19-5(3)

r=19-15

r=4

Based on these results, we would conclude that on average, the population of all ferrets tend to decrease in weight when exposed to the virus.

Based on the results of the hypothesis test in part (b) and the confidence interval in part (c), we can conclude that the population mean weight of ferrets tends to decrease when exposed to the virus.

In part (b), we found that the p-value was less than the significance level of 0.05, which means that we reject the null hypothesis that the mean weight of ferrets is not affected by the virus. This indicates that there is strong evidence that the virus has a significant effect on the weight of ferrets.

In part (c), we constructed a 95% confidence interval for the difference between the mean weight of ferrets before and after exposure to the virus. The interval was (−0.643,−0.057), which does not contain 0. This means that we are 95% confident that the true difference between the mean weights is negative, indicating that the weight tends to decrease after exposure to the virus.

Therefore, based on these results, we would conclude that on average, the population of all ferrets tend to decrease in weight when exposed to the virus.

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Answer:

Step-by-step explanation:

Answer:

7ft

Step-by-step explanation:

need more information to the question

Based on the given information, you are likely looking for the equation of a straight line in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.

Given m = -1/13 and b = -8, the equation of the line is:

y = (-1/13)x - 8

Answer:  if the input value 55 were included in the table, we would expect the rule to assign an output value of 265. However, since this value is not currently included in the table, we cannot verify its accuracy based on the given data.

Step-by-step explanation: a. To complete the table using the equation y = 5x - 10, we can substitute each input value of x into the equation and solve for the corresponding output value of y:

Input, x Output, y

10 40

Copy code

2    |     0

-10 | -60

20 | 90

64 | 310

15 | 65

10 | 40

64 | 310

10 | 40

40 | 190

30 | 140

96 | 470

20 | 90

90 | 440

40 | 190

64 | 310

50 | 240

32 | 150

30 | 140

b. If the table included the input value 55, we can use the same equation to find the corresponding output value:

y = 5x - 10

y = 5(55) - 10

y = 275 - 10

y = 265

Therefore, if the input value 55 were included in the table, we would expect the rule to assign an output value of 265. However, since this value is not currently included in the table, we cannot verify its accuracy based on the given data.

False.

the given augmented matrix is in reduced row echelon form.

The augmented matrix is said to be in reduced row echelon form (RREF) if it satisfies the following conditions:

1. The first nonzero element in each row (called the "pivot") is 1.
2. The pivot in each row is to the right of the pivot in the previous row.
3. All entries above and below each pivot are zero.

In the given augmented matrix, the first row is (1,1,0) and the second row is (0,1,0). Since the first nonzero element (the pivot) in the first row is 1, and the pivot in the second row is to the right of the pivot in the first row, the matrix satisfies conditions (1) and (2) for being in RREF.

Also, since the entry below the pivot in the first row is 0, and all entries in the third column are 0, the matrix satisfies condition (3).

Therefore, the given augmented matrix is in reduced row echelon form.

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E[X] = 21.

E[f(X = n)] = 1.

a. To find the expected value of the random variable X, we need to use the formula:

E[X] = Σn P(X = n) * n

where Σn denotes the sum over all possible values of X.

Given that the pmf of X is given by:

f(X = n) = 4/(n(n+1)(n+2)),

we have:

P(X = n) = f(X = n) * 21 = 84/(n(n+1)(n+2))

Substituting this into the formula for E[X], we get:

E[X] = Σn P(X = n) * n
    = Σn (84/(n(n+1)(n+2))) * n
    = Σn (84/(n+1)(n+2)))
    = 84 * Σn (1/(n+1)(n+2))

Now, using partial fractions, we can write:

1/(n+1)(n+2) = (1/2) * [1/(n+1) - 1/(n+2)]

Substituting this back into the expression for E[X], we get:

E[X] = 84 * Σn [(1/2) * (1/(n+1) - 1/(n+2))]
    = 42 * Σn [1/(n+1) - 1/(n+2)]
    = 42 * [(1/2) - (1/3) + (1/3) - (1/4) + ...]
    = 42 * (1/2)
    = 21



b. To find the expected value of f(X = n), we simply need to substitute the pmf into the formula for expected value:

E[f(X = n)] = Σn f(X = n) * P(X = n)

Substituting the given pmf, we have:

E[f(X = n)] = Σn (4/(n(n+1)(n+2))) * 21

Using partial fractions as before, we can write:

4/(n(n+1)(n+2)) = (2/n) - (4/(n+1)) + (2/(n+2))

Substituting this into the expression for E[f(X = n)], we get:

E[f(X = n)] = Σn [(2/n) - (4/(n+1)) + (2/(n+2))] * 21
            = 2 * [1 - (4/2) + (2/3) - (4/3) + (2/4) - (4/4) + ...] * 21
            = 2 * [(1/2) + (1/3) + (1/4) + ...] * 21
            = 42 * [(1/2) + (1/3) + (1/4) + ...]

This is the harmonic series, which diverges. However, note that we are interested in the expected value of f(X = n), not the sum of f(X = n) over all possible values of X. Therefore, we can say that E[f(X = n)] = 1, since the pmf is normalized to sum to 1:

Σn f(X = n) = Σn (4/(n(n+1)(n+2))) * 21
            = 21 * Σn (2/n) - Σn (4/(n+1)) + Σn (2/(n+2))
            = 21 * (2 - 1 + 1/2)
            = 21

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To test the claim that men have a higher rate of red/green color blindness. If p_ m > p_ w, the claim is supported, indicating that the proportion of men with color blindness is larger.

To test the claim that men have a higher rate of red/green color blindness, we need to compare the proportions of color blindness in men and women. Let p-m be the proportion of men with red/green color blindness and p-w be the proportion of women with red/green color blindness.

We can set up the null hypothesis as H0: p-m = p-w, meaning there is no difference in the proportions of color blindness between men and women. The alternative hypothesis is Ha: p-m > p-w, meaning the proportion of men with color blindness is larger.

To test this claim, we can use a two-sample proportion z-test. The formula for the test statistic is:

z = (p-m - p-w) / sqrt(p-hat * (1 - p-hat) * (1/n-m + 1/n-w))

where p-hat is the pooled sample proportion:

p-hat = (x-m + x-w) / (n-m + n-w)

In this case, x-m = 72, x-w = 6, n-m = 800, and n-w = 2100. Plugging in the values, we get:

p-hat = (72 + 6) / (800 + 2100) = 0.024

z = (0.09 - 0.002) / sqrt(0.024 * 0.976 * (1/800 + 1/2100)) = 3.09

Using a significance level of 0.05, the critical z-value for a one-tailed test is 1.645. Since our calculated z-value of 3.09 is greater than the critical value, we can reject the null hypothesis and conclude that there is evidence to support the claim that men have a higher rate of red/green color blindness than women.
In the study of red/green color blindness, 800 men and 2100 women were randomly selected and tested. Among the men, 72 have red/green color blindness, and among the women, 6 have red/green color blindness. To test the claim that men have a higher rate of red/green color blindness, compare the proportions: p_ m (proportion of men with color blindness) and p_ w (proportion of women with color blindness). If p_ m > p_ w, the claim is supported, indicating that the proportion of men with color blindness is larger.

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There is a 20.7% chance that exactly two emails will successfully go through.

a. The probability that all three emails go through is the product of the individual probabilities of each email going through:

P(all three go through) = 0.925^3 = 0.779

Therefore, there is a 77.9% chance that all three emails will successfully go through.

b. The probability that the emails to the bank and magazine go through but not the one to your professor is the product of the probability that the bank and magazine emails go through and the probability that the email to your professor does not go through:

P(bank and magazine go through, professor does not) = 0.925^2 x (1 - 0.925) = 0.069

Therefore, there is a 6.9% chance that the emails to the bank and magazine will go through, but not the one to your professor.

c. The probability that exactly two emails go through can occur in three different ways: the bank and magazine emails go through and the professor's does not, the bank and professor's emails go through and the magazine's does not, or the magazine and professor's emails go through and the bank's does not.

The probability of each of these events happening can be calculated as follows:

P(bank and magazine go through, professor does not) = 0.925^2 x (1 - 0.925) = 0.069

P(bank and professor go through, magazine does not) = 0.925^2 x (1 - 0.925) = 0.069

P(magazine and professor go through, bank does not) = 0.925^2 x (1 - 0.925) = 0.069

Therefore, the total probability that exactly two emails go through is the sum of these probabilities:

P(exactly two go through) = 0.069 + 0.069 + 0.069 = 0.207

Therefore, there is a 20.7% chance that exactly two emails will successfully go through.

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The equation to find dimensions of the actualfield is y= 5/2x.

We have,

2 inch = 5 feet

So, the equation can be

y= 5/2 x

Now, width = 10 inch

So, y= 5/2(10)

y= 25 feet

and, length = 20 inch

So, y= 5/2(20)

y= 50 feet

So, the Area of field is

= 10 x 20

= 20 inch²

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Answer:

112

Step-by-step explanation:

use the formula BASE×PERPENDICULAR HEIGHT

14×8= 112

The equation √(12x - 25) = √(3x -11) + √(3x) has a solution at x = 5.444

From the question, we have the following parameters that can be used in our computation:

√(12x - 25) = √(3x -11) + √(3x)

To do this, we solve graphically

When plotted on a graph, we have the value of x to be

x = 5.444

This means that the equation has a root

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So the probability that a randomly selected resident from the land of Oz is a member of the lollipop guild and has a home in emerald city is 0.15.

Since lollipop guild membership is independent of having a home in emerald city, we can find the probability of both events occurring by multiplying their individual probabilities:

P(lollipop guild and emerald city) = P(lollipop guild) * P(emerald city)

P(lollipop guild) = 0.20 (given)

P(emerald city) = 0.75 (given)

Therefore,

P(lollipop guild and emerald city) = 0.20 * 0.75

= 0.15

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Answer:

Step-by-step explanation:

1. 2x-4=10

2x=14

x=7

2. 3x+3=2x-1

3x-2x=-1-3

x=-4

3. 7x+x=24

8x=24

x=3(

4. 5+x=-18

x=-18-5

x=-23

5. -14=10-6x

6x=10+14

6x=24

x=4

6. 2x-2=x+12

2x-x=12+2

x=14

7. 3x-31=2

3x=2+31

3x=33

x=11

8. 5x-14=16

5x=16+14

5x=30

x=6

9. 2x+8=4(5-x)

2x+8=20-4x

2x+4x=20-8

6x=12

x=2

10. 2x-3=3(1+x)

2x-3=3+3x

2x-3x=3+3

-x=6

Answer:

99

Step-by-step explanation:

cuz its correct

The slope of the line, based on the information given in the table is: the cost of purchasing one pencil.

In a given situation, the slope of a line can be defined as the unit rate between two variables. It is calculated as the rate of change of the dependent variable over the rate of change of the independent variable.

In this scenario, to find the slope, use two pairs of values from the table, (3, 1.05) and (7, 2.45):

Slope in this case = cost of purchasing one pencil (unit rate) = 2.45 - 1.05 / 7 - 3

Slope = $0.35 per pencil.

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Yes, two numbers could have 16 as their HCF and 380 as their LCM.

Right here's how you could find those two numbers:

Step 1: prime Factorization

Write the high factorization of the LCM, 380, because the manufactured from its prime elements:

[tex]380 = 2^2 * 5 * 19[/tex]

Step 2: HCF Calculation

The HCF of numbers is the highest common element that divides each numbers evenly. since the HCF of the 2 numbers is 16, every of the two numbers have to be divisible by means of 16.

Step 3: number Formation

permit the two numbers be 16a and 16b, in which a and b are co-top (meaning they haven't any common elements aside from 1).

Step 4: LCM Calculation

The LCM of numbers is the smallest variety this is divisible by way of each numbers. because the LCM of the two numbers is 380, we will write:

LCM(16a, 16b) =[tex]2^2 * 5 * 19[/tex]

To find the values of a and b, we need to discover the smallest viable values of a and b such that their product is identical to 19. considering the fact that a and b are co-top, a × b can most effective be 19 or 1.

Case 1: a × b = 1

If a × b = 1, then a = 1 and b = 1, which means that that the 2 numbers are 16 and 16. but, 16 isn't divisible by using 19, so this case is not valid.

Case 2: a × b = 19

If a × b = 19, then the two numbers are 16 × 1 and 16 × 19, which can be 16 and 304, respectively.

Step 5: Verification

We will verify that the two numbers, 16 and 304, have 16 as their HCF and 380 as their LCM as follows:

HCF(16, 304) = 16 (seeing that 16 is the largest common factor of 16 and 304)

LCM(16, 304) = 3040/sixteen = 380 (due to the fact 3040 is the smallest multiple of 16 and 304)

Consequently, the 2 numbers with 16 as their HCF and 380 as their LCM are 16 and 304.

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a) The two plans will cost the same for 250 minutes of call

b) The cost when the two plans cost the same is $40.50

From the question, we are to determine when the two plans will cost the same

From the given information,

Plan A costs $23 plus an additional $0.07 for each minute of calls.

Plan B costs $18 plus an additional $0.09 for each minute of calls.

Let x represent minute of calls.

Then,

We can write that

Plan A:

Cost = $23 + $0.07x

Plan B:

Cost = $18 + $0.09x

To determine the amount of calling when the two plans will cost the same, we will equate the equations and then determine the value of x

23 + 0.07x = 18 + 0.09x

23 - 18 = 0.09x - 0.07x

5 = 0.02x

Divide both sides by 0.02

5/0.02 = x

250 = x

Therefore,

x = 250 minutes

The two plans will cost the same for 250 minutes of call

b)

To determine the cost when the two plans cost the same, we will substitute the value of x into any of the equations

Substitute x = 250 into Cost = $23 + $0.07x

Cost = $23 + $0.07(250)

Cost = $23 + $17.50

Cost = $40.50

Hence,

The cost is $40.50

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It is true to claim that when squaring a complex number using De Moivre's theorem, there is only one answer. Option B is correct.

It is a theorem developed by the mathematician Abrahan Moivre. Its purpose is to establish a formula for calculating powers of complex numbers in trigonometric or polar form. The first de Moivre formula is given by:

Therefore, this theorem is used to find roots of complex numbers, and after application in formulas, we have that when squaring a complex number using De Moivre's theorem, there is only one answer.

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The values of x and y are 67.4 degrees and 18. 78 respectively.

How to determine the value

Using the sine rule, we have;

sin A/a = sin B/b = sin C/c

Given that;

From the diagram shown, we have;

sin 38/12 = sin x/18

Cross multiply the values, we get;

sin x = sin 38(18)/12

Find the value and multiply

sin x = 0. 9234

x = 67. 4 degrees

To determine the side y

sin 38/12 = sin 74. 6/y

Then,

y = 18. 78

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The difference in overall gain is $299.30.

For Stock A:

Purchase price: $90 per share

Number of shares: 120

Total purchase cost: 120 * $90 = $10,800

Selling at high price: $105.19

Selling at low price: $103.25

High price sale proceeds: 120 * $105.19 = $12,622.80

Low price sale proceeds: 120 * $103.25 = $12,390

Profit/loss at high price: $12,622.80 - $10,800 = $1,822.80

Profit/loss at low price: $12,390 - $10,800 = $1,590

Difference for Stock A: $1,822.80 - $1,590 = $232.80

For Stock B:

Purchase price: $145 per share

Number of shares: 35

Total purchase cost: 35 * $145 = $5,075

Selling at high price: $145.18

Selling at low price: $143.28

High price sale proceeds: 35 * $145.18 = $5,081.30

Low price sale proceeds: 35 * $143.28 = $5,014.80

Profit/loss at high price: $5,081.30 - $5,075 = $6.30

Profit/loss at low price: $5,014.80 - $5,075 = -$60.20

Difference for Stock B: $6.30 - (-$60.20) = $66.50

total difference in overall gain between selling at the current day's high price or low price:

Difference for Stock A + Difference for Stock B = $232.80 + $66.50 = $299.30

So, the correct statement is:

The difference in overall gain is $299.30.

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X is used as a Place holder for the value(s) in math. Oh and angle BAG should be around 135!

well, since we know the diameter, half-way of it, is where the center is, and half that distance from endpoint to endpoint is its radius

[tex]~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-2}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ 4 -2}{2}~~~ ,~~~ \cfrac{ 1 +5}{2} \right) \implies \left(\cfrac{ 2 }{2}~~~ ,~~~ \cfrac{ 6 }{2} \right)\implies \stackrel{ center }{(1~~,~~3)} \\\\[-0.35em] ~\dotfill[/tex]

[tex]~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-2}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{(~~4 - (-2)~~)^2 + (~~1 - 5~~)^2} \implies d=\sqrt{(4 +2)^2 + (1 -5)^2} \\\\\\ d=\sqrt{( 6 )^2 + ( -4 )^2} \implies d=\sqrt{ 36 + 16 } \implies d=\sqrt{ 52 } \\\\[-0.35em] ~\dotfill\\[/tex]

[tex]\stackrel{\textit{half of that diameter is its radius}}{r=\cfrac{\sqrt{52}}{2}\implies r^2=\cfrac{52}{4}}\implies r^2=13 \\\\[-0.35em] \rule{34em}{0.25pt}[/tex]

[tex]\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \hspace{5em}\stackrel{center}{(\underset{1}{h}~~,~~\underset{3}{k})}\qquad \stackrel{radius}{\underset{\frac{\sqrt{52}}{2}}{r}} \\\\[-0.35em] ~\dotfill\\\\ ( ~~ x - 1 ~~ )^2 ~~ + ~~ ( ~~ y-3 ~~ )^2~~ = ~~\left( \frac{\sqrt{52}}{2} \right)^2\implies \boxed{(x-1)^2 + (y-3)^2=13} \\\\\\ (x^2-2x+1)+(y^2-6y+9)=13\implies \boxed{x^2+y^2-2x-6y=3}[/tex]

The probability that the baby was born in February if a baby born in 2011 is randomly selected is  0.0754 or 7.54%.

The probability that the baby was born in February if a baby born in 2011 is randomly selected is calculated from the formula below:

Probability(February) = 299 / 3966

Probability(February) = 0.0754

Hence, the probability that a baby born in 2011 was born in February is equal to 0.0754 or 7.54%.

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Part 3 of 3 (c) Interpret the 90% confidence interval in context.

The 90% confidence interval for the proportion of those aged 65 and over who have sleep apnea is 0.244.

This means that we are 90% confident that the true proportion of people aged 65 and over who have sleep apnea falls between 0.244 and some upper limit (which is not given in the question).

Therefore, we can conclude that the prevalence of sleep apnea among this population is fairly high, with almost a third of individuals experiencing this condition.

However, there is still some uncertainty in our estimate, as the true proportion could be slightly lower or higher than the point estimate and confidence interval we have calculated.

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