25. Which is the solution set of the equation
2x² + 3x - 2 = 0?
(1) (-1/2,2}
(2) {1/2,-2}
(3) {1/2,2}
(4) {-1/2,-2}

Answer: Of the two numbers you provided, +3 is greater than -7. So, +3 is the most upper of the two numbers.

Answer: +3

Step-by-step explanation: Positive 3 is greater than negative 7. Therefore, +3 is the greater value.

The probability that the mean clock life would be less than 13.6 years in a sample of 40 wall clocks is 0.1337

The probability that the mean clock life would be less than 13.6 years in a sample of 40 wall clocks can be calculated using the t-distribution since the population variance is unknown. The formula for t-distribution is:

t = (x-bar - μ) / (s / √n)

where x-bar is the sample mean, μ is the hypothesized population mean (14 years), s is the sample standard deviation (the square root of the sample variance), and n is the sample size (40).

Using the given variance, we can calculate the sample standard deviation as √16 = 4. Plugging in the values, we get:

t = (13.6 - 14) / (4 / √40) = -1.118

Using a t-distribution table with degrees of freedom (df) = n - 1 = 39, we find that the probability of getting a t-value less than -1.118 is 0.1337. Therefore, the probability that the mean clock life would be less than 13.6 years in a sample of 40 wall clocks is 0.1337 (rounded to four decimal places).

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The probability that the mean annual salary of a random sample of 64 teachers from state X is less than $52,000 is approximately 0.005 or 0.5%.

The sampling distribution of the mean is normally distributed with a mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size.

Here, we are given that the population mean is $54,000 and the population standard deviation is $5,000. We are also told that the sample size is n = 64.

To find the probability that the mean annual salary of a random sample of 64 teachers is less than $52,000, we need to standardize the sample mean using the sampling distribution of the mean.

Z = (x' - μ) / (σ / √n)

where x' is the sample mean, μ is the population mean, σ is the population standard deviation, and n is the sample size.

Substituting the given values, we get:

Z = (52,000 - 54,000) / (5,000 / √64)

= -2.56

We can then look up the probability of a standard normal variable being less than -2.56 using a standard normal table or calculator, which gives us a probability of approximately 0.005.

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Complete question is:

The annual salary of teachers in a certain state X has a mean of $54,000 and standard deviation of σ = $5,000. What is the probability that the mean annual salary of a random sample of 64 teachers from this state is less than $52,000?

Answer:

Step-by-step explanation:

y = abx

a is the y-intercept

y = 16bx

Now substitute 2 for x and 1296 for y

1296 = 16(b)2

81 = b2

b = 9

y = 16(9)x

The number of hamburgers sold on Sunday was 89

Let's assume that the number of hamburgers sold on Sunday was x.

According to the problem, the number of cheeseburgers sold was three times the number of hamburgers sold.

Therefore, the number of cheeseburgers sold can be expressed as 3x.

The total number of hamburgers and cheeseburgers sold was 356.

Therefore, we can write an equation to represent this information:

x + 3x = 356

Simplifying the left-hand side of the equation, we get:

4x = 356

Dividing both sides by 4, we get:

x = 89

Therefore, the number of hamburgers sold on Sunday was 89, and the number of cheeseburgers sold was 3 times that, or 267.

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Answer:

  $9.50

Step-by-step explanation:

You want Suzie's hourly rate on Saturday if she babysat for 3.5 hours on Friday, earning 8.50 per hour, and for 4.5 hours on Saturday, earning a total of 72.50 from both jobs.

For (hours, rates) of (h1, r1) and (h2, r2), Suzie's total earnings for the two jobs are ...

  earnings = h1·r1 +h2·r2

Filling in the known values, we can find r2:

  72.50 = 3.5·8.50 +4.5·r2

  72.50 = 29.75 +4.5·r2 . . . . . . . simplify

  42.75 = 4.5·r2 . . . . . . . . . . . subtract 29.75

  9.50 = r2 . . . . . . . . . . . . divide by 4.5

Suzie earned $9.50 per hour on Saturday.

__

Additional comment

The steps of the "multistep" problem are ...

Effectively, these are the steps to solving the equation we wrote.

1.  The radius of V is approximately 14.04 meters.2.The circumference of V is approximately 88.24 meters. 3.mST arc is  26.85 degrees. 4.the length of ST arc is approximately 6.61 meters. 5.34.69 meters. 6.88.24m.

In geometry, a sector is a part of a circle enclosed by two radii and an arc. Essentially, a sector is a slice of a circle. The two radii that form the sector are equal in length and share a common endpoint, which is the center of the circle. The arc of the sector is a portion of the circumference of the circle and its length is proportional to the measure of the central angle that it subtends.

We can use the given information to solve for the following:

1. Radius of V:

The area of a circle is given by the formula A = πr². We are given the area of V as 624.36 square meters, so we can solve for the radius r as:

A = πr²

624.36 = πr²

r² = 624.36/π

r ≈ 14.04 meters

Therefore, the radius of V is approximately 14.04 meters.

2. Circumference of V:

The circumference of a circle is given by the formula C = 2πr. Using the radius we just found, we can solve for the circumference of V as:

C = 2πr

C = 2π(14.04)

C ≈ 88.24 meters

Therefore, the circumference of V is approximately 88.24 meters.

3. mST arc:

The area of the sector SVT is given as 64.17 square meters. The area of a sector is given by the formula A = (θ/360)πr², where θ is the central angle of the sector in degrees. We are not given the value of θ, but we can solve for it as:

A = (θ/360)πr²

64.17 = (θ/360)π(14.04)²

θ ≈ 26.85 degrees

Therefore, the central angle of the sector SVT is approximately 26.85 degrees, and mST arc is also 26.85 degrees.

4. Length of ST arc:

The length of an arc of a circle is given by the formula L = (θ/360)C, where θ is the central angle of the arc in degrees, and C is the circumference of the circle. We can use the values we have already calculated to solve for the length of ST arc as:

L = (θ/360)C

L = (26.85/360)(88.24)

L ≈ 6.61 meters

Therefore, the length of ST arc is approximately 6.61 meters.

5. Perimeter of shaded region (sector):

The perimeter of a sector is the sum of the length of the arc and the lengths of the two radii that form the sector. Using the values we have already calculated, we can solve for the perimeter of the shaded sector as:

Perimeter = L + 2r

Perimeter = 6.61 + 2(14.04)

Perimeter ≈ 34.69 meters

Therefore, the perimeter of the shaded region (sector) is approximately 34.69 meters.

6. Perimeter of unshaded region (remaining circle part):

The perimeter of a circle is given by the formula C = 2πr. Using the radius we previously calculated, we can solve for the perimeter of the unshaded region as:

Perimeter = 2πr

Perimeter = 2π(14.04)

Perimeter ≈ 88.24 meters

Therefore, the perimeter of the unshaded region (remaining circle part) is approximately 88.24 meters.

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The area of the small triangle is 4 sq.cm.. The area of the medium triangle is 12 sq.cm. The area of the large triangle is 24 sq. cm.

With three sides, three angles, and three vertices, a triangle is a closed, two-dimensional object. A polygon also includes a triangle.

Given data:

Dimensions-

area of triangle = 1/2 *base * height

The area of the small triangle = 1/2*2*4 = 4 sq.cm.

The area of the medium triangle = 1/2*4*6 = 12 sq.cm.

The area of the large triangle = 1/2*6*8 = 24 sq. cm

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Complete question:

Dimensions-

small triangle: base = 2 cm, height = 4cm

medium triangle: base = 4 cm , height = 6 cm

Larger triangle: base = 6 cm ,height = 8 cm

The area of the small triangle is_______

The area of the medium triangle is______

The area of the large triangle is______

1. x = 4.7 for f(x) and x = 25 for g(x), f(x) reaches 50 first.

2. x = 9.7 for f(x) and x = 50 for g(x), f(x) reaches 100 first.

1. Which function reaches 50 first?

To answer this, we need to solve for x in each function when the output is 50:

For f(x): 50 = 10x + 3

47 = 10x

x = 4.7

For g(x): 50 = 2x

x = 25

Since x = 4.7 for f(x) and x = 25 for g(x), f(x) reaches 50 first.

2. Which function reaches 100 first?

Similarly, we'll solve for x in each function when the output is 100:

For f(x): 100 = 10x + 3

97 = 10x

x = 9.7

For g(x): 100 = 2x
x = 50

Since x = 9.7 for f(x) and x = 50 for g(x), f(x) reaches 100 first.

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Answer:

191 ounces at the end of 12 weeks

Step-by-step explanation:

a) The zero rates for the five maturities are: 1 year is 2.01%, 2 years is 2.48%, 3 years is 2.77%, 4 years is 1.73%, and 5 years is 4.32%.

b) The price of the security is $128.31.

a) To find the zero rates for all 5 maturities, we can use the formula for the present value of a bond:

PV = C / [tex](1+r)^n[/tex]

where PV is the present value,

C is the coupon payment,

r is the zero rate, and

n is the number of years to maturity.

We can solve for r by rearranging the formula:

r = [tex](C/PV)^{(1/n) }[/tex]- 1

Using the bond data given in the question, we can calculate the zero rates for each maturity as follows:

For the 1-year bond, PV = 98 and C = 0, so r = 2.01%.

For the 2-year bond, PV = 101, C = 2.48, and n = 2, so r = 2.48%.

For the 3-year bond, PV = 103, C = 2.91, and n = 3, so r = 2.77%.

For the 4-year bond, PV = 101, C = 2, and n = 4, so r = 1.73%.

For the 5-year bond, PV = 103, C = 5, and n = 5, so r = 4.32%.

Alternatively, we can use linear algebra to find the zero rates. We can write the present value equation in matrix form:

PV = A × x

where A is a matrix of coefficients, x is a vector of unknowns (the zero rates), and PV is a vector of present values.

To solve for x, we can use the equation:

x = ([tex]A^{-1}[/tex]) x PV

where ([tex]A^{-1}[/tex]) is the inverse of matrix A.

Using this method, we can solve for the zero rates as follows:

[2.01% ]

[2.48% ]

[2.77% ] = x

[1.73% ]

[4.32% ]

PV = [tex]A^{-1}[/tex] x  [98]

                   [101]

                   [103]

                   [101]

                   [103]

PV =   [-0.0201]

          [ 0.0248]

          [ 0.0277]

          [-0.0173]

          [ 0.0432]

b) To find the price of the security which pays cash flows of $10 in one year, $25 in two years, and $100 in four years, we can use the formula for the present value of a series of cash flows:

PV = [tex]C1/(1+r)^1 + C2/(1+r)^2 + C3/(1+r)^4[/tex]

where PV is the present value, C1, C2, and C3 are the cash flows, r is the zero rate, and the exponents correspond to the number of years until each cash flow is received.

Using the zero rates calculated in part (a), we can calculate the present value of each cash flow:

PV1 = $10 /(1+2.01 % [tex])^1[/tex] = $9.80

PV2 = $25/(1+2.48%[tex])^2[/tex] = $22.15

PV3 = $100/(1+1.73%[tex])^4[/tex] = $81.36

Then, the price of the security is the sum of the present values:

PV = $9.80 + $22.15 + $81.36 = $128.31

Therefore, the price of the security is $128.31.

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Answer: -37.5

Step-by-step explanation: You can simply do this in the calculator by doing 3 times -12.5. the parenthesis is a sign to multiply

Answer:

the answer is -75/2= - 37.5

The drive-thru with typically more wait time is Burger Quick, because it has a larger median. The Option A.

The median is a measure of central tendency that represents the middle value of a set of data. In this case, the median wait time at Burger Quick is 15.5 minutes, while the median wait time at Super Fast Food is 12 minutes.

This indicates that, on average, customers at Burger Quick experience a longer wait time compared to customers at Super Fast Food. The larger median at Burger Quick suggests that there may be some longer wait times skewing the data towards the higher end which could be due to various factors such as slower service, or other operational issues at Burger Quick resulting in a longer wait time for customers at their drive-thru.

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Approximately 0.357 or 35.7% of customers require more than 12 minutes to check out.

Since the checkout times are exponentially distributed with a mean of 5.5 minutes, we can use the exponential distribution formula to find the probability that a customer will take more than 12 minutes to check out:

P(X > 12) = 1 - P(X ≤ 12)

where X is the checkout time.

To find P(X ≤ 12), we can use the cumulative distribution function (CDF) of the exponential distribution, which is:

F(x) = 1 - e^(-λx)

where λ is the rate parameter of the distribution. For an exponential distribution with mean μ, the rate parameter λ is equal to 1/μ.

So, in our case, λ = 1/5.5 = 0.1818, and we can calculate P(X ≤ 12) as:

P(X ≤ 12) = F(12) = 1 - e^(-0.1818 × 12) ≈ 0.643

Therefore, the probability that a customer will take more than 12 minutes to check out is:

P(X > 12) = 1 - P(X ≤ 12) ≈ 1 - 0.643 ≈ 0.357

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The sample may not be representative of the population's preferences for frozen desserts.

Sampling technique that Keziah is using is convenience sampling. Convenience sampling is a non-probability sampling technique.

The researcher selects the easiest and most convenient individuals to participate in the study.

Keziah is simply surveying shoppers who are exiting a grocery store on the west side of her town without any predetermined criteria for selection.

As a result, the sample may not be representative of the population's preferences for frozen desserts.

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The cardholder will pay an additional $1,471.66 in interest by making monthly payments of $200 until the balance is paid off instead of paying off the current balance in full.

First, we need to calculate the total interest that will accrue on the current balance of $4,528.34. We can do this using the formula

Interest = Balance x (APR/12)

where APR is the annual percentage rate and is divided by 12 to get the monthly interest rate. Plugging in the values, we get:

credit card Interest = $4,528.34 x (22.99%/12) = $87.80

So the total interest that will accrue on the current balance is $87.80.

Next, we need to calculate how long it will take to pay off the balance by making monthly payments of $200. We can use a credit card repayment calculator to do this, but we'll use a simplified formula here

Months = -log(1 - (Balance x (APR/12))/Payment) / log(1 + (APR/12))

where Payment is the monthly payment amount. Plugging in the values, we get

Months = -log(1 - ($4,528.34 x (22.99%/12))/$200) / log(1 + (22.99%/12)) = 29.6 months

So it will take about 30 months (or 2.5 years) to pay off the balance by making monthly payments of $200.

Finally, we can calculate how much more the cardholder will pay in total by subtracting the current balance from the total amount paid over 30 months

Total amount paid = $200 x 30 = $6,000

Total interest paid = $6,000 - $4,528.34 = $1,471.66

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Since a side of the triangle below has been extended to form an exterior angle of 67°, the value of x is equal to 52°.

In Mathematics, the exterior angle theorem or postulate can be defined as a theorem which states that the measure of an exterior angle in a triangle is always equal in magnitude (size) to the sum of the measures of the two remote or opposite interior angles of that triangle.

By applying the exterior angle theorem, we can reasonably infer and logically deduce that the sum of the measure of the two interior remote or opposite angles in the given triangle is equal to the measure of angle x (∠x);

∠y + 67° = 180°

∠y = 180° - 67°

∠y = 113°

∠x = 180° - (15° + 113°)

∠x = 52°

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Answer:

Step-by-step explanation:

a) The system of equations modeling this scenario is as follows:

C = 11.50 + 0.9n

C = 13.25 + 0.55n.

b) The number of toppings where the cost is the same at either Pizza Palace or Tasty Pizza is 5.

What is a system of equations?

A system of equations is two or more equations solved concurrently.

A system of equations is also called simultaneous equations because the equations are solved at the same time or simultaneously.

                              Pizza Palace    Tasty Pizza

Pizza cost per unit       $11.50             $13.25

Topping cost per unit  $0.90              $0.55

Let the number of toppings = n

Let the total cost for the pizza at each pizza place = c

Equations:

The total cost at Pizza Palace C = 11.50 + 0.9n... Equation 1

The total cost at Tasty Pizza, C = 13.25 + 0.55n... Equation 2

For the total cost, c, to be the same at the pizza places, Equation 1 must equate Equation 2:

That is, C = C.

Substituting the values of C:

11.50 + 0.9n = 13.25 + 0.55n

0.35n = 1.75

n = 5

The relative frequency of spinning a 1 is 0.32 or 32%.

The given table shows the results of spinning a spinner 50 times. The outcomes of the spins are listed in the first column, and the frequencies are listed in the second column. To find the relative frequency of spinning a 1, we need to divide the frequency of spinning a 1 by the total number of trials (50).

According to the table, the frequency of spinning a 1 is 16. Therefore, the relative frequency of spinning a 1 can be calculated as follows:

Relative frequency of spinning a 1 = (frequency of spinning a 1) / (total number of trials)

Relative frequency of spinning a 1 = 16 / 50

Relative frequency of spinning a 1 = 0.32 or 32%

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The number of batches of pancakes made by Hugo using 3 cups of milk is equal to 9 batches.

Number of cups of milk used by Hugo for each batch =  1/3 cup of milk ,

The total amount of milk used for b batches would be,

Total milk = (1/3) × b

The total milk used was 3 cups,

Substitute the value in the equation we have,

⇒ (1/3) × b = 3

Solve for b we get,

Multiply both sides of the equation by the reciprocal of 1/3,

Reciprocal of ( 1/3 ) = 3/1 or simply 3

⇒ (1/3) × b × 3 = 3 × 3

⇒ b = 9

Therefore, Hugo made 9 batches of pancakes.

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The above question is incomplete, the complete question is:

Hugo made a bunch of batches of pancakes for his summer camp. For each batch, Hugo used 1/3 cup of milk. Hugo used a total of 3 cups of milk. Let b represent the number of batches Hugo made . Find the value of b?

The smallest positive integer divisible by 6 and 2 that can be written using at least one 2 and one 6 is 6.

The smallest positive integer that is divisible by both 2 and 6 is their least common multiple (LCM), which is equal to the product of the highest power of each prime factor that appears in the factorization of 2 and 6.

The prime factorization of 2 is simply 2, while the prime factorization of 6 is 2 × 3. The highest power of 2 that appears in the factorization of 6 is just 2 itself, so the LCM of 2 and 6 is 2 × 3 = 6.

We are asked to write this integer using at least one 2 and one 6. We can do this by simply writing 6, which is the LCM of 2 and 6 and is divisible by both of them. Since 6 contains one 2 and one 6, this meets the requirement of the problem. Therefore, the smallest positive integer divisible by 6 and 2 that can be written using at least one 2 and one 6 is 6.

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a) The probability of a given woman in this age group having a cholesterol level less than 200mg/dl is 6.68%.

b) The probability of a given woman in this age group having a cholesterol level more than 200mg/dl is 93.32%.

c) The probability of a given woman in this age group having a cholesterol level between 190mg/dl and 210mg/dl is 15.87%.

d) If a woman in this age group has a cholesterol level higher than 230mg/dl, it is considered high and puts her at risk of heart disease

To calculate the probability of a given woman in this age group having a cholesterol level less than 200mg/dl, we need to find the z-score first. The z-score is the number of standard deviations that a given value is from the mean. The formula to calculate the z-score is:

z = (x - μ) / σ

where x is the given value, μ is the mean, and σ is the standard deviation.

For a cholesterol level of 200mg/dl, the z-score is:

z = (200 - 230) / 20 = -1.5

We can then use a z-table or calculator to find the probability of a z-score being less than -1.5, which is 0.0668 or approximately 6.68%.

Next, to find the probability of a given woman in this age group having a cholesterol level more than 200mg/dl, we can use the same process but subtract the probability of a z-score being less than -1.5 from 1 because the total probability is always 1.

So, the probability of a given woman in this age group having a cholesterol level more than 200mg/dl is:

1 - 0.0668 = 0.9332 or approximately 93.32%.

Finally, to find the probability of a given woman in this age group having a cholesterol level between 190mg/dl and 210mg/dl, we need to find the z-scores for both values.

For a cholesterol level of 190mg/dl, the z-score is:

z = (190 - 230) / 20 = -2

For a cholesterol level of 210mg/dl, the z-score is:

z = (210 - 230) / 20 = -1

We can then use the z-table or calculator to find the probability of a z-score being between -2 and -1, which is 0.1587 or approximately 15.87%.

Finally, a brief report on the guidance that you would give a woman having high cholesterol levels in this age group is:

It is essential to make lifestyle changes such as eating a healthy diet, exercising regularly, quitting smoking, and managing stress to lower cholesterol levels.

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The given information describes the measures of two angles, A and B. Angle A is represented as ∠A and has a measure of 6x-2 degrees. Angle B is represented as ∠B and has a measure of 4x+48 degrees. These measures are respectively shown in the colors #11accd and #28ae7b.

The question gives us two equations, one for angle A and one for angle B, in terms of x. We will have to solve for x and then find the measure of angle A.

To solve for x, we can set the expressions for ∠A and ∠B equal to each other and solve for x

∠A = ∠B

6x - 2 = 4x + 48

Subtracting 4x from both sides we get

2x - 2 = 48

Adding 2 to both sides we get

2x = 50

Dividing by 2 we get

x = 25

Now that we have found the value of x, we can substitute it into the expression for ∠A

∠A = 6x - 2

∠A = 6(25) - 2

By multiplying 6 with 25 we get

∠A = 150 - 2

By Subtracting we get

∠A = 148

Hence, the measure of angle A is 148 degrees.

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The value of "a" is approximately 1.83 given that the absolute value of the difference of the two roots of the quadratic equation "ax squared plus 5x minus 3 equals 0" is the square root of 61 divided by 3, and "a" is positive.

We are given that the absolute value of the difference between the two roots of the quadratic equation "ax squared plus 5x minus 3 equals 0" is the square root of 61 divided by 3, and "a" is positive. We need to find the value of "a".

Let the two roots of the equation be r1 and r2, where r1 is not equal to r2. Then, we have:

|r1 - r2| = √(61) / 3

The sum of the roots of the quadratic equation is given by r1 + r2 = -5 / a, and the product of the roots is given by r1 × r2 = -3 / a.

We can express the difference between the roots in terms of the sum and product of the roots as follows:

r1 - r2 = √((r1 + r2)² - 4r1r2)

Substituting the expressions we obtained earlier, we have:

r1 - r2 = √(((-5 / a)²) + (4 × (3 / a)))

Simplifying, we get:

r1 - r2 = √((25 / a²) + (12 / a))

Taking the absolute value of both sides, we get:

|r1 - r2| = √((25 / a²) + (12 / a))

Comparing this with the given expression |r1 - r2| = √(61) / 3, we get:

√((25 / a²) + (12 / a)) = √(61) / 3

Squaring both sides and simplifying, we get:

25 / a² + 12 / a - 61 / 9 = 0

Multiplying both sides by 9a², we get:

225 + 108a - 61a² = 0

Solving this quadratic equation for "a", we get:

a = (108 + √(108² + 4 × 61 × 225)) / (2 × 61)

Since "a" must be positive, we take the positive root:

a = (108 + √(108² + 4 × 61 × 225)) / (2 × 61) ≈ 1.83

Therefore, the value of "a" is approximately 1.83.

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The question is -

Given that the absolute value of the difference of the two roots of the quadratic equation "ax squared plus 5x minus 3 equals 0" is the square root of 61 divided by 3, and "a" is positive, what is the value of "a"?

The equation of the hyperbola is [tex](x + 3)^2/16 - (y - 5)^2/36[/tex] = 1.

The collection of all points in a plane such that the distance between any point on the curve and two fixed points (referred to as the foci) is constant is known as a hyperbola. Hyperbolas are a sort of conic section. A hyperbola contains two distinct branches and has the appearance of two curving branches that are mirror reflections of one another. A hyperbola's center, vertices, co-vertices, foci, and asymptotes are some of its most important characteristics. The center, which is the point around which the hyperbola is symmetric, is the midway of the line segment connecting the vertices.

Given that, the co-vertices are (1, 5) and (-7, 5).

Now, using the midpoint formula we have:

center = ((1+(-7))/2, (5+5)/2) = (-3, 5)

Now, the distance between center and vertex is a = 4.

Also, the distance between the center and each co-vertex is b = 6.

Now, the equation of the hyperbola is:

[tex](x - (-3))^2/4^2 - (y - 5)^2/6^2 = 1\\(x + 3)^2/16 - (y - 5)^2/36 = 1[/tex]

Hence, the equation of the hyperbola is [tex](x + 3)^2/16 - (y - 5)^2/36[/tex] = 1.

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Step-by-step explanation:

Use Pythagorean theorem to find the base of the right triangle

221^2 = 195^2 + b^2

b = 104 km

triangle area = 1/2 base * height =  1/2 * 104 * 195 = 10140 km^2

Now multiply by the height to find volume

10140 km^2  * 15 km  = 152100 km^3

The correct option is - D. (1,5). The solution to the system of equations for the given graph is at (1,5).

A collection of values for a variable that simultaneously fulfil each equation is the solution to a system of equations. A system of equations must be solved by identifying all possible sets of variable values that make up the system's solutions.

For the given graph, the solution of the system of equation is obtained as the point where the lines intersect.

The two lines in the graph intersect at the (1,5). Thus, the solution to the system of equations for the given graph is at (1,5).

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Sue works 5 out of 7 days a week, which implies that she has two days off. We need to discover how numerous conceivable plans there are for her to work on Tuesday or Friday or both.

There are two cases to consider:

1. Sue works on Tuesday as it were, Friday as it were, or both Tuesday and Friday.

2. Sue does not work on Tuesday or Friday.

For the primary case, there are three conceivable outcomes:

1. Sue works on Tuesday as it were and has Friday off.

2. Sue works on Friday as it were and has Tuesday off.

3. Sue works on both Tuesdays and Fridays.

For the moment case, there are two conceivable outcomes:

1. Sue works on one of the other 5 days of the week and has both Tuesday and Friday off.

2. Sue has Tuesday and Friday off.

In this manner, there are added up to 3 + 2 = 5 conceivable plans for Sue to work on Tuesday or Friday or both. 

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The number of students that would be expected to be unable to complete the exam in the allotted time is 8 students.

To find the number of students who would be unable to complete the exam in the allotted time, we need to calculate the number of students who take more than 90 minutes to complete the exam.

First, we calculate the z-score for the cutoff point of 90 minutes:

z = (90 - 80) / 10 = 1

Using a standard normal distribution table, we find that the probability of a student taking more than 90 minutes is approximately 0.1587.

Therefore, the expected number of students who would be unable to complete the exam in the allotted time is:

0.1587 x 50 = 7.935

Rounding up to the nearest integer, we can expect 8 students to be unable to complete the exam in the allotted time.

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The complete question is :

If a class of 50 students has an examination period of 90 minutes, and the average time a student takes to complete the exam is 80 minutes with a standard deviation of 10 minutes, how many students would be expected to be unable to complete the exam in the allotted time?