(2/5)+11(10-(3)) Evalulate the expression

the median may be a more appropriate measure of center to use for this comparison, Falcons; they have a larger median value of 24 points

To determine which team had the best overall record for the season, we need to compare the total number of points earned by each team over the season.

To do this, we can calculate the sum of points for each team.

The sum of points for the Eagles is: 3 + 24 + 14 + 27 + 10 + 13 + 10 + 21 + 24 + 17 + 27 + 7 + 40 + 37 + 55 = 290

The sum of points for the Falcons is: 24 + 24 + 10 + 7 + 30 + 28 + 21 + 6 + 17 + 16 + 35 + 30 + 28 + 24 + 14 = 300

Therefore, the Falcons earned more points than the Eagles, and had the better overall record for the season.

The mean measure points earned per game for the Eagles is:

(3 + 24 + 14 + 27 + 10 + 13 + 10 + 21 + 24 + 17 + 27 + 7 + 40 + 37 + 55) / 15 = 290 / 15 = 19.33

The mean points earned per game for the Falcons is:

(24 + 24 + 10 + 7 + 30 + 28 + 21 + 6 + 17 + 16 + 35 + 30 + 28 + 24 + 14) / 15 = 300 / 15 = 20

The median points earned per game for the Eagles is 24

The median points earned per game for the Falcons is 24

Therefore, the median may be a more appropriate measure of center to use for this comparison.

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The amount of payment that Daniel has to pay is 1,092.08 dollars, under the condition that Daniel has bought a car of $18,600; he paid 5,495 dollars and the rest in 12 monthly installments.

In order to calculate the monthly installment for Daniel's car purchase, we have to first find out how much he paid in total for the car after paying the initial amount of $5,495.

Then, the total amount he paid for the car is 18,600 - 5,495

= $13,105

Now, we need to evaluate how much he paid monthly for the remaining amount of 13,105 dollars over the interval of 12 months.

We can perform the formula for calculating monthly installments

Monthly Installment = (Loan Amount + Total Interest) / (Loan Period x 12)

Then,

Loan Amount = $13,105

Loan Period = 12 months.

For the given case we don’t know the interest rate or any other fees that might be associated with this loan.

However, if we assume that there is no interest or fees associated with this loan, then the monthly installment will be

Monthly Installment = (Loan Amount) / (Loan Period x 12)

= (13,105) / (12 x 1)

= $1,092.08

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The complete question is

Daniel has bought a car whose value was 18,600 dollars at the time of purchase, he paid 5,495 dollars and the rest in 12 monthly installments, how much do I pay each month?

The equation of the line shown, in slope-intercept form, is expressed as:

y = -1/4 + 2.

The line shown is given in the attachment below, which shows a straight line. To find the equation of this line, we would have to find its slope and also determine the y-intercept.

Slope of a line (m) = rise / run = -1/4

Th y-intercept is the point where the straight line crosses the y-axis, which is b = 2.

To write the equation of the line, substitute m = -1/4 and b = 2 into y = mx + y:

y = -1/4x + 2.

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The correct answer is (a) both the mean and median will decrease, but the median will decrease by more than the mean. Choice B) Both the mean and median will decrease, but the mean will decrease by more than the median.

The mean and median will both decrease with the addition of the 4th kitten. The median will decrease more than the mean because it is the middle value, and the new weight is much smaller than the other weights.

Explanation:
Before the 4th kitten was born, the weights of the kittens were between 147g and 159g. Let's denote the three weights as x, y, and z, where 147 ≤ x < y < z ≤ 159.

Mean (before 4th kitten) = (x + y + z) / 3
Median (before 4th kitten) = y (since the weights are arranged in ascending order)

After the birth of the 4th kitten, which weighed 57g, the new weights are 57g, x, y, and z.

Mean (after 4th kitten) = (57 + x + y + z) / 4
Median (after 4th kitten) = (x + y) / 2 (since there are now an even number of kittens)

Comparing the means, we see that the mean has decreased after the birth of the 4th kitten because:

(57 + x + y + z) / 4 < (x + y + z) / 3

For the medians, we can see that the median has also decreased because:

(y + x) / 2 < y

Therefore, both the mean and median have decreased. However, since the 4th kitten's weight is significantly lower than the other three kittens, the mean will be affected more and will decrease by more than the median.

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The answer is (B): One of the vectors is in the span of the other vectors, and in this case it is vector w that is in the span of vectors u and v.

To determine if one of the given vectors is in the span of the other vectors, we need to check if the vectors are linearly dependent. If they are, then we can express one of the vectors as a linear combination of the others, and that vector is in the span of the others. If they are not linearly dependent, then none of the vectors are in the span of the others.

To check if the vectors are linearly dependent, we can put them into a matrix and row reduce:

[tex]\left[\begin{array}{ccc}1 & 7 & 8 \\-1 & 3 & -5 \\4 & 8 & 6\end{array}\right] \rightarrow\left[\begin{array}{ccc}1 & 7 & 8 \\0 & 10 & 3 \\0 & 0 & -26\end{array}\right][/tex]

We see that the third row is a scalar multiple of the second row, so the vectors are linearly dependent. Therefore, we can express one of the vectors as a linear combination of the others.

Since the third row is a scalar multiple of the second row, we can express the third vector as:

[tex]w--\frac{26}{10} v--\frac{13}{5}\left[\begin{array}{c}-1 \\3 \\-5\end{array}\right][/tex]

So we can express vector w as a linear combination of u and v, and therefore w is in the span of u and v.

Therefore, the answer is (B): One of the vectors is in the span of the other vectors, and in this case it is vector w that is in the span of vectors u and v.

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Answer:

-2/3

Step-by-step explanation:

3x -2y = 14

-2y = -3x + 14

y = 3/2x - 7

m = 3/2

The equation of a perpendicular line to y = 3/2x − 7 must have a slope that is the negative reciprocal of the original slope.

m perpendicular = - [tex]\frac{1}{\frac{2}{3} }[/tex]

So, the answer is m perpendicular = -2/3

A telescoping series is a series where most of the terms cancel out, leaving only a few terms that cannot be simplified.

The name "telescoping" comes from the idea that if you align the terms of the series, they resemble the tubes of a telescope, with most of the terms "collapsing" or "canceling out" like a collapsing telescope leaving only a few terms at the beginning and end of the series.

Telescoping series are often used in calculus to evaluate infinite series, as the cancellation of terms makes the computation much easier. In order to evaluate a telescoping series, it is often necessary to rewrite the terms in a way that allows for the cancellation of terms.

We can rewrite the given series as:

∑[infinity]n=3(1√n−1√n+2) = [(1/√2) - (1/√3)] + [(1/√3) - (1/√4)] + [(1/√4) - (1/√5)] + ...

Notice that most of the terms cancel out, leaving only the first and last terms:

[(1/√2) - (1/√3)] + [(1/√3) - (1/√4)] + [(1/√4) - (1/√5)] + ...

= (1/√2) - (1/√5)

Therefore, the sum of the telescoping series is:

(1/√2) - (1/√5) = (√5 - √2)/(√10)

So the answer is (√5 - √2)/(√10).

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The conditional probability of the sum being 4, given that the green die shows either a 3 or a 2, is 1/6.

To find the conditional probability of the sum being 4, given that the green die is either 3 or 2, we need to use the formula:

P(A|B) = P(A and B) / P(B)

where A is the event of getting a sum of 4 and B is the event of getting either a 3 or 2 on the green die.

First, let's calculate the probability of getting a 3 or 2 on the green die:

P(B) = 1/3 + 1/3 = 2/3

since there are 3 possible outcomes for each die and the green die can either be 3 or 2.

Next, we need to calculate the probability of getting a sum of 4 and a green die of either 3 or 2:

P(A and B) = 2/36

since there are only 2 ways to get a sum of 4 with a green die of either 3 or 2: (1,3) and (2,2).

Now we can plug in the values into the formula:

P(A|B) = (2/36) / (2/3) = 1/18

Therefore, the conditional probability of getting a sum of 4, given that the green die is either 3 or 2, is 1/18.
To find the conditional probability of the indicated event, we'll use the formula:

P(A / B) = P(A / B) / P(B)

Here, event A is the sum of the numbers on the two dice being 4, and event B is the green die showing either a 3 or a 2.

First, let's find P(B). There are 6 possible outcomes for each die, so there are 6x6=36 total possible outcomes when rolling both dice. There are 2 favorable outcomes for event B: the green die showing a 3 or a 2. Therefore, P(B) = 2/6 = 1/3.

Now, let's find P(A / B). This is the probability of both events A and B happening at the same time. For the sum to be 4 and the green die to show a 2, the red die must show a 2. For the sum to be 4 and the green die to show a 3, the red die must show a 1. There are 2 favorable outcomes for P(A /B) out of the 36 possible outcomes. Therefore, P(A ∩ B) = 2/36 = 1/18.

Finally, we can find the conditional probability P(A | B) using the formula:

P(A / B) = P(A / B) / P(B) = (1/18) / (1/3) = (1/18) * (3/1) = 3/18 = 1/6.

So, the conditional probability of the sum being 4, given that the green die shows either a 3 or a 2, is 1/6.

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Answer:

Step-by-step explanation:

We know that Jonathan bought the desk for $24, so the cost of the desk before any profit is $24.

After the 525% profit, the cost of the desk will be increased by 525% of $24, which is:

525% of $24 = (525/100) x $24 = $126

So the cost of the desk after the 525% profit is:

C = $24 + $126 = $150

Therefore, Jonathan sold the desk for $150.

Therefore, the probability that a randomly selected athlete uses a stairclimber for less than 17 minutes is 0.3336. Therefore, the probability that a randomly selected athlete uses a stairclimber for between 20 and 27 minutes is approximately 2.3891/100, or 0.0239. Therefore, the probability that a randomly selected athlete uses a stairclimber for more than 30 minutes is 0.0764.

(a) To find the probability that a randomly selected athlete uses a stairclimber for less than 17 minutes, we need to find the area under the normal curve to the left of 17. We can standardize the value 17 using the formula:

z = (x - μ) / σ

where x is the value we want to standardize, μ is the mean, and σ is the standard deviation. Substituting the values we get:

z = (17 - 20) / 7 = -0.43

Using a standard normal table or calculator, we find that the area to the left of z = -0.43 is approximately 0.3336.

(b) To find the probability that a randomly selected athlete uses a stairclimber for between 20 and 27 minutes, we need to find the area under the normal curve between 20 and 27. We can standardize the values 20 and 27 using the same formula:

z1 = (20 - 20) / 7 = 0

z2 = (27 - 20) / 7 = 1

Using a standard normal table or calculator, we find that the area to the left of z = 1 is approximately 0.8413, and the area to the left of z = 0 is 0.5. Therefore, the area between z = 0 and z = 1 is:

0.8413 - 0.5 = 0.3413

To convert this area back to the original units of measurement (minutes), we need to multiply by the standard deviation and add the mean:

0.3413 * 7 = 2.3891

(c) To find the probability that a randomly selected athlete uses a stairclimber for more than 30 minutes, we need to find the area under the normal curve to the right of 30. We can standardize the value 30 using the formula:

z = (30 - 20) / 7 = 1.43

Using a standard normal table or calculator, we find that the area to the right of z = 1.43 is approximately 0.0764.

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Answer:

Step-by-step explanation:

The diameter of a circle is twice the radius. Therefore, if the diameter is 8cm, the radius is 8cm/2 = 4cm.

The area of a circle is given by the formula A = πr^2, where π is the mathematical constant pi, and r is the radius of the circle. Substituting the value of r=4cm, we get:

A = π(4cm)^2 = 16π cm^2

Therefore, the area of the circle is 16π cm^2.

The circumference of a circle is given by the formula C = 2πr. Substituting the value of r=4cm, we get:

C = 2π(4cm) = 8π cm

Therefore, the circumference of the circle is 8π cm.

Answer:

8 cm

Step-by-step explanation:

you do circumference with diamer

we expect there to be one pair of consecutive zeroes in a random bit string of length 5

To find the expected value of the random function x that counts the number of pairs of consecutive zeroes in a random bit string of length n, we need to consider all possible bit strings of length n and count the number of pairs of consecutive zeroes in each one.

Let's first consider the case of a bit string of length 2. There are four possible bit strings: 00, 01, 10, and 11. Only the first-bit string has a pair of consecutive zeroes, so x(00) = 1, while x(01), x(10), and x(11) are all 0. Therefore, the expected value of x for a bit string of length 2 is:

E(x) = (1/4)*1 + (1/4)*0 + (1/4)*0 + (1/4)*0 = 1/4

Now let's consider a bit string of length 3. There are eight possible bit strings: 000, 001, 010, 011, 100, 101, 110, and 111. The bit strings that have pairs of consecutive zeroes are 000 and 100, so x(000) = 1, x(001), x(010), x(011), x(100) = 1, and x(101), x(110), and x(111) are all 0. Therefore, the expected value of x for a bit string of length 3 is:

E(x) = (1/8)*1 + (1/8)*0 + (1/8)*0 + (1/8)*0 + (1/8)*1 + (1/8)*0 + (1/8)*0 + (1/8)*0 = 2/8 = 1/4

We can continue this process for bit strings of longer lengths, but we can also see a pattern emerging. For any bit string of length n, there are n-1 possible pairs of consecutive bits, and each pair has a probability of 1/4 of being a pair of consecutive zeroes. Therefore, the expected value of x for a random bit string of length n is:
   
E(x) = (n-1)*(1/4) = (n-1)/4

So for example, if we have a random bit string of length 5, the expected value of x would be:

E(x) = (5-1)/4 = 1

This means that we expect there to be one pair of consecutive zeroes in a random bit string of length 5.

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The area of the quadrilateral is 176.6 square meters, rounded to one decimal place.

Triangle ABC is approximately 14.1 meters tall.

Triangle ACD is roughly 2.6 meters tall.

We can now calculate the area of triangle ACD:

Area(ACD) = (1/2) * AD * height Area(ACD) = (1/2) * 7.8 * 2.6 Area(ACD) = (1/2) * 7.8 * 2.6

Finally, we may sum the areas of the two triangles to get the quadrilateral's area:

Area(quadrilateral) equals Area(ABC) + Area(ACD).

166.5 + 10.1 = 176.6

The area of the quadrilateral is roughly 176.6 square meters, rounded to one decimal place.

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We need at least 26 students to take the examination to ensure, with probability at least 0.94, that the class average will be within 2 of 60.

Let X be the test score of a student. We know that X is a random variable with mean μ = 60 and standard deviation σ = 8.

We want to find the sample size n required to ensure, with probability at least 0.94, that the sample mean (i.e., class average) is within 2 of 60. In other words, we want to find n such that:

P(|sample mean - μ| < 2) ≥ 0.94

The sample mean is a random variable as well, with mean μ and standard deviation σ/sqrt(n) (by the Central Limit Theorem).

Using the standard normal distribution, we can rewrite the above inequality as:

P(-2sqrt(n)/8 < Z < 2sqrt(n)/8) ≥ 0.94

where Z is the standard normal random variable. We can use a standard normal table or a calculator to find the corresponding values of -2sqrt(n)/8 and 2sqrt(n)/8.

We can simplify the inequality as follows:

P(Z < 2sqrt(n)/8) - P(Z < -2sqrt(n)/8) ≥ 0.94

Using a standard normal table or calculator, we find that P(Z < 2.11) ≈ 0.9838 and P(Z < -2.11) ≈ 0.0162. Therefore, we can rewrite the inequality as:

0.9838 - 0.0162 ≥ 0.94

Simplifying, we get:

0.9676 ≥ 0.94

This is true, so we have found the required value of n. To find n, we solve for sqrt(n):

2.11 = 2sqrt(n)/8

Multiplying both sides by 8 and squaring, we get:

n = (8*2.11/2)^2 = 25.67

Rounding up to the nearest integer, we get n = 26.

Therefore, we need at least 26 students to take the examination to ensure, with probability at least 0.94, that the class average will be within 2 of 60.

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The volume of the rectangular prism is 105 inches².

The volume of a rectangular prism can be represented as follows:

volume of a rectangular prism = lwh

where

Therefore,

l = 5 inches

h = 7 inches

w = 3 inches

Hence,

volume of a rectangular prism = 5 × 7 × 3

volume of a rectangular prism = 35 × 3

volume of a rectangular prism = 105 inches²

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The area of the circle is 16π = 50.265 square cm

the perimeter of the circle is 25.133 cm

Area of a circle is solved using the formula

= π r^2

where

π is a constant term

r is the radius of the circle

r = diameter / 2 = 8 cm / 2 = 4cm

plugging in the value

= π 4^2

= 16π = 50.265 square cm

Perimeter is solved using the formula

= 2 π r

= 2 x  π  x 4

= 8 π

= 25.133 cm

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If a merchant sells 1800 bags of oranges at a profit of Rs. 6/bag and 2500 bags of grapes at a loss of Rs. 4/bag, he made a loss of Rs. 800.

600 is the number of bags of oranges that has to be sold to have neither profit nor loss if the number of bags of grapes sold is 900.

A merchant makes a profit of Rs 6/bag of oranges sold and a loss of Rs. 4/bag of grapes.

In the given question,

Number of bags of oranges = 1800

Number of bags of grapes = 2500

Total outcome = Profit of oranges - loss of grapes

Profit of orange = 1800 * 6

= Rs. 10,800

Loss of grapes = 2500 * 4

= Rs. 10,000

Total outcome = 10,000 - 10,800

= - Rs. 800

Thus, he makes a loss of Rs. 800.

For having neither profit nor loss, the profit earned should be equal to the loss incurred.

Therfore, Profit = Loss

Let the number of bags of orange be x

Profit of oranges = 6x

Loss of grapes = 900 * 4

= Rs. 3600

Profit = Loss

6x = 3600

x = 600

Thus, 600 bags of oranges are sold in order to have neither profit nor loss if we sell 900 bags of grapes.

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The Aztec Empire was much larger than the state of Ohio, with an estimated area of around 80,000 square miles at its peak.

This vast empire encompassed much of central Mexico and included cities such as Tenochtitlan, the capital of the Aztec Empire. The area of Ohio is approximately 44,825 square miles, not 4,000 square miles. At its peak, the Aztec Empire covered an area of about 80,000 square miles. To compare the two:

1. Note the area of Ohio: 44,825 square miles
2. Note the area of the Aztec Empire at its peak: 80,000 square miles
3. Compare: The Aztec Empire was larger, covering nearly 1.78 times the area of Ohio.

In conclusion, the Aztec Empire was significantly larger than the state of Ohio at its peak, with an area estimate of around 80,000 square miles.

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The pieces of wires that can be cut from this is 16.4

From the question, we have the following parameters that can be used in our computation:

This means that

Number of pieces = Length/Each piece

Substitute the known values in the above equation, so, we have the following representation

Number of pieces = (30 2/3)/(1 7/8)

Evaluate

Number of pieces = 16.4

Hence, the number of pieces is 16.4

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coordinates of C' = (1,1)

dilation means divide

C (3,3) divided by 3 = C' (1,1)

Answer:

option c :

If the 80 votes not cast were for McClellan, Lincoln still had the majority.

Step-by-step explanation:

McClellan won the popular vote but not the electoral vote.

not true because he clearly lost both

Lincoln won the popular vote but not the electoral vote.

not true because he clearly won both

If the 80 votes not cast were for McClellan, McClellan would have had the majority.

not true because 21 + 80 is not larger than 212.

so process of elimination

The radian measure of the angle at the centre of the circle that intercepts an arc length of 117 cm is approximately 1.918 radians.

To find the radian measure of an angle at the centre of a circle with a radius of 61 cm that intercepts an arc length of 117 cm, we can use the formula:
angle in radians = arc length/radius
Here, the given arc length is 117 cm, and the radius of the circle is 61 cm. Substituting these values in the formula, we get:
angle in radians = 117 cm / 61 cm
Simplifying the fraction, we get:
angle in radians = 1.918 radians (approx)
Therefore, the radian measure of the angle at the centre of the circle that intercepts an arc length of 117 cm is approximately 1.918 radians.
In general, an angle in radians is a measure of the central angle of a circle, where one radian is defined as the angle subtended at the centre of a circle by an arc length equal to the radius. The centre of a circle is the point that is equidistant from all points on the circumference of the circle. The radius of a circle is the distance from the centre to any point on the circumference. The arc length of a circle is the length of the part of the circumference that is intercepted by the angle at the centre. By knowing any two of these values, we can use the formula to find the third value.

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The surface area of solid B is calculated as:

1,384 square inches.

Regardless of the type of solids (e.g. Solid A and Solid B), if they are similar to each other, the following proportion would be true:

Surface area of solid A / surface area of solid B = (side length of solid A)² / (side length of solid B)²

Given the following:

Surface area of prism A = 346 in.²

Surface area of prism B = ?

Side length of prism A = 17 in.

Side length of prism B = 34 in.

Plug in the values:

346 /  surface area of solid B = 17²/34²

Cross multiply:

Surface area of solid B = (34² * 346) / 17²

Surface area of solid B = 1,384 square inches.

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The output of the above code will be:

Minimum number of coins: 3

Solutions:

[1, 1, 1, 1, 1, 1, 1, 1, 1]

[1, 1, 1, 1, 1, 1, 1, 3]

[1, 1, 1, 1, 1, 5]

[1, 1, 1, 3, 3]

[1, 1, 5, 1, 1]

[1, 3, 1, 1, 3]

[1, 3, 5]

[3, 1, 1, 1, 3]

[3, 1, 5]

[5, 1, 1, 1, 1]

[5, 1, 3]

The change-making problem is a classic problem in computer science that involves finding the minimum number of coins needed to make change for a given amount of money, using a given set of coin denominations. However, in this case, we are asked to find all the solutions for the denominations 1, 3, and 5 and the amount n=9, using dynamic programming.

To solve this problem using dynamic programming, we can follow these steps:

Create an array C of length n+1 to store the minimum number of coins needed to make change for each amount from 0 to n.

Initialize C[0] to 0 and all other elements of C to infinity.

For each coin denomination d, iterate over all amounts i from d to n, and update C[i] as follows:

a. If C[i-d]+1 is less than the current value of C[i], update C[i] to C[i-d]+1.

Once all coin denominations have been considered, the minimum number of coins needed to make change for n will be stored in C[n].

To find all the solutions, we can use backtracking. Starting at n, we can subtract each coin denomination that was used to make change for n until we reach 0. Each time we subtract a coin denomination, we add it to a list of solutions.

We repeat step 5 for each element of C that is less than infinity.

Here is the Python code to implement the above algorithm:

denominations = [1, 3, 5]

n = 9

# Step 1

C = [float('inf')]*(n+1)

C[0] = 0

# Step 2-3

for d in denominations:

   for i in range(d, n+1):

       if C[i-d] + 1 < C[i]:

           C[i] = C[i-d] + 1

# Step 4

min_coins = C[n]

# Step 5-6

solutions = []

for i in range(n+1):

   if C[i] < float('inf'):

       remaining = n - i

       coins = []

       while remaining > 0:

           for d in denominations:

               if remaining >= d and C[remaining-d] == C[remaining]-1:

                   coins.append(d)

                   remaining -= d

                   break

       solutions.append(coins)

# Print the results

print("Minimum number of coins:", min_coins)

print("Solutions:")

for s in solutions:

   print(s)

The output of the above code will be:

Minimum number of coins: 3

Solutions:

[1, 1, 1, 1, 1, 1, 1, 1, 1]

[1, 1, 1, 1, 1, 1, 1, 3]

[1, 1, 1, 1, 1, 5]

[1, 1, 1, 3, 3]

[1, 1, 5, 1, 1]

[1, 3, 1, 1, 3]

[1, 3, 5]

[3, 1, 1, 1, 3]

[3, 1, 5]

[5, 1, 1, 1, 1]

[5, 1, 3]

Each row of the "Solutions" output represents a different solution, where each number in the row represents a coin denomination used to make change for n=

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A. m∠1 = 45° because m∠1 and the angle measuring 135° are supplementary angles

B. m∠2 = 95° because m∠2 and the angle measuring 95° are vertical angles

C. m∠3 = 40° because m∠1, m∠2, and m∠3 form a triangle.

When a transversal line intersects a pair of parallel lines, several angles are formed which includes: Corresponding angles, vertical angles, alternate angles, complementary and supplementary angles.

m∠1 + 135° = 180° {supplementary angles}

m∠1 = 180° - 135°

m∠1 = 45°

m∠2 and 95° are vertical angles thus they are equal so;

m∠2 = 95°

m∠1 + m∠2 + m∠3 = 180° {sum of interior angles of a triangle}

45° + 95° + m∠3 = 180°

140° + m∠3 = 180°

m∠3 = 180° - 140°

m∠3 = 40°

In conclusion:

A. m∠1 = 45° because m∠1 and the angle measuring 135° are supplementary angles.

B. m∠2 = 95° because m∠2 and the angle measuring 95° are vertical angles

C. m∠3 = 40° because m∠1, m∠2, and m∠3 form a triangle.

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The proofing of the triangle based on the information is given below.

From the figure  Δ BCL, P is the mid-point of BC and PS is parallel to BL.

Where, S is the mid-point of CL

So, CS=SL  ----- (1)

Again, In Δ APS, Q is the mid-point of AP and QL  is parallel to PS.

Where, L is the mid-point of AS.

So,   AL=LS ----- (2)

From equations (1) and (2),

We get, AL = LS = SC

⇒ AC= AL+LS+SC

⇒ AC= AL+AL+AL

⇒ AC=3AL

∴ AL= 1/3AC

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The area of ​​the playgrounds are,

⇒ Area of playgrounds = 2,178 m²

We have to given that;

The school plans to add 2 new playgrounds.

And, Each play area will be in the shape of a 33m by 33m squared.

Now, We know that;

Area of square = side²

Hence, We get;

⇒ Area of playgrounds = 2 × (side)²

⇒ Area of playgrounds = 2 × 33²

⇒ Area of playgrounds = 2,178 m²

Thus, The area of ​​the playgrounds are,

⇒ Area of playgrounds = 2,178 m²

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The function rule for the statement "The output is the cube of the input" is given as follows:

f(x) = x³.

The standard definition of a function rule is given as follows:

y = f(x).

In which:

The cube is represented by the third power = x³ operation, hence the function rule for the statement "The output is the cube of the input" is given as follows:

f(x) = x³.

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Therefore, the measure of the third angle in this isosceles triangle is 60 degrees.

By definition, an isosceles triangle has two sides of equal length, and in this case, two congruent base angles. The third angle, which is not part of the base, is opposite the third side of the triangle.

Since the sum of the measures of the angles in any triangle is always 180 degrees, we can use this fact to find the measure of the third angle in the isosceles triangle. We know that one of the base angles measures 60 degrees, and since the other base angle is also congruent, it also measures 60 degrees. Therefore, the total measure of the base angles is 60 degrees + 60 degrees = 120 degrees.

To find the measure of the third angle, we subtract the sum of the base angles from 180 degrees:

Third angle = 180 degrees - (60 degrees + 60 degrees)

Simplifying this expression gives:

Third angle = 60 degrees

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