2+5*6
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Answer:

Explanation:

How many moles of solute are in 9.03 M solution with 15.8 L of solution?

Answer:

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Explanation:

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Answer: [tex]m=0.1625\ kg,\ ,V=125\ L[/tex]

Explanation:

Given

The length of the box is [tex]a=0.5\ m[/tex]

1 liter of air has a mass of 1.3 gm

So, the density of air is [tex]1.3\ g/L[/tex]

The volume of the box is

[tex]\Rightarrow a^3=0.5^3\\\Rightarrow 0.125\ m^3\ or\ 125\ L[/tex]

Mass of air in the box is

[tex]\Rightarrow m=\rho \times V\\\Rightarrow m=1.3\times 125\\\Rightarrow m=162.5\ gm\ or\ 0.1625\ kg[/tex]

Answer:

The correct answer is a

A property of water among the given properties It has a relatively high heat capacity. Hence Option (A) is correct

Heat capacity or thermal capacity is a physical property of matter, defined as the amount of heat to be supplied to an object to produce a unit change in its temperature.

The SI unit of heat capacity is joule per kelvin. Heat capacity is an extensive property.

Therefore, A property of water among the given properties It has a relatively high heat capacity. Hence Option (A) is correct.

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Answer:

This question is obviously true

Explanation:

I would expect

Answer:hydronium

Explanation:

Answer:

Evaporation of ocean water and the formation of sea ice both increase the salinity of the ocean.

Explanation:

Answer: The concentration of KOH is 0.1 M.

Explanation:

Given: Mass of KHP = 413 mg (1 mg = 0.001 g) = 0.413 g

Volume of KOH = 20.05 mL

Volume of solution = 41 mL

The molecular mass of KHP is 204.22 g/mol

Hence, moles of KHP are calculated as follows.

[tex]No. of moles = \frac{mass}{molar mass}\\= \frac{0.413 g}{204.22 g/mol}\\= 0.002 mol[/tex]

As molarity is the number of moles of a substance present in a liter of solution.

So, molarity of the given solution is as follows.

[tex]Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{0.002 M}{0.041 L}\\= 0.0493 M[/tex]

When the given solution is titrated with KOH then concentration of KOH is calculated as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]

Substitute the values into above formula.

[tex]M_{1}V_{1} = M_{2}V_{2}\\0.0493 M \times 41 mL = M_{2} \times 20.05 mL\\M_{2} = \frac{0.0493 M \times 41 mL}{20.05 mL}\\= 0.1 M[/tex]

Thus, we can conclude that the concentration of KOH is 0.1 M.

Answer:

A. cell potential.

Explanation:

Hello there!

In this case, according to the Nerst equation:

[tex]Ecell=E\°cell-\frac{0.0592}{n}log(Q)[/tex]

We can say that at equilibrium Ecell=0 and Q=K, so:

[tex]0=E\°cell-\frac{0.0592}{n}log(K)[/tex]

In such a way, we can solve for K as follows:

[tex]log(K)=\frac{nE\°cell}{0.0592}\\\\K=10^{\frac{nE\°cell}{0.0592}}[/tex]

Thus, we infer that E° in this equation is A. cell potential.

Regards!

Answer: the c thingy is where you be like burgundy sauce then be like racial slair is what it mean's so the name thingy

Explanation:

Answer:

0.0395 mol NaCl

Explanation:

¡Hola!

En este caso, es necesario para nosotros considerar que las relaciones masa-mol se desarrollan teniendo en cuenta las masas molares de los compuestos involucrados en el sistema. Ahora, dado que este sistema se compone de NaCl, cloruro de sodio como sal de mesa, es posible saber que la masa molar de este es alrededor de 58.44 g/mol.

De esta manera, las moles en 2.31 g se calculan como sigue:

[tex]=2.31gNaCl*\frac{1molNaCl}{58.44gNaCl}\\\\=0.0395molNaCl[/tex]

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Explanation:

[tex]1000 \: ml \: contain \: 0.750 \: moles \\ 25.00 \: ml \: will \: contain \: ( \frac{25 \times 0.75}{1000} ) \: moles \\ = 0.01875 \: moles \\ from \: reaction \: eqn \\ H _{2} C _{2} 0 _{4} + 2KOH - - > K _{2}C _{2} 0 _{4} +2H _{2} 0 \\ 1 \: mole \: of \: oxalic \: reacts \: with \: 2 \: moles \: of \: KOH \\ 0.01875 \: moles \: react \: with \: ( \frac{0.01875 \times 2}{1} ) \\ = 0.0375 \: moles \\ 0.0375 \: moles \: weigh \: 0.846g \\ 1 \: mole \: weighs \: 56g[/tex]

Answer:

(a) oxygen

(b) 154g (to 3sf)

(c) 79.9% (to 3sf)

Explanation:

mass (g) = moles × Mr/Ar

note: eqn means chemical equation

(a)

moles of P = 84.1 ÷ 30.973 = 2.7152 moles

moles of O2 = 85÷2(16) = 2.65625 moles

Assuming all the moles of P is used up,

moles of O2 / moles of phosphorus = 5/4 (according to balanced chemical eqn)

moles of O2 required = 5/4 × 2.7152moles = 3.394 moles (more than supplied which is 2.65625moles)

therefore there is insufficient moles of O2 and the limiting reactant is oxygen.

(b)

moles of P2O5 produced

= 2/5 (according to eqn) × 2.7152

= 1.08608moles

mass of P2O5 produced

= 1.08608 × [ 2(30.973) + 5(16) ]

= 154.164g

= approx. 154g to 3 sig. fig.

(c)

% yield = actual/theoretical yield × 100%

= 123/154 × 100%

= 79.870%

= approx. 79.9% (to 3sf)

Answer:

Any atom with six protons, regardless of how much other stuff it has, is a carbon atom. Having 7 neutrons, this would be an atom of Carbon 13 (C-13), a stable isotope of carbon making up 1.1% of natural carbon in the atmosphere and near the Earth's surface. As for the electrons, Carbon has six, but atoms may temporarily pick up or lose electrons in the hurly burly of chemical reactions, solar radiation and so forth. This is a negative ion of C13, which will soon pass on its extra election to an atom which needs it (a positive ion).

Explanation:

https://www.quora.com/What-element-has-6-protons-7-neutrons-and-7-electrons

Answer:

Graphite, because it has atoms of same atomic and electrovalent electrons

Answer:

A) 2-pentene

Explanation:

We count from side where we encounter double bond closest so that's going to be from left to the 2nd carbon. Total carbons are 5.

Thus pent- for prefix of 5 carbons and -ene as suffix for double bond.

2- for locant of double bond.

Thus, 2-pentene

Answer:

Na3PO4+3HCl —> H3PO4+3NaCl

The reaction type for this equation is a double displacement or acid-base reaction, where Na₃PO₄ and HCl exchange ions to form H₃PO₄ and NaCl.

A double displacement reaction is a type of chemical reaction in which the cations and anions of two different compounds exchange places, producing two new compounds. Double displacement reactions are also known as double replacement, metathesis, or ion-exchange reactions.

To balance the equation, you need to make sure that the number of atoms of each element is equal on both sides of the equation. Here is one possible balanced equation:

2Na₃PO₄+ 6HCl → 2H₃PO₄ + 6NaCl

In this balanced equation, there are:

6 sodium atoms (Na) on both sides

2 phosphorus atoms (P) on both sides

12 oxygen atoms (O) on both sides

6 hydrogen atoms (H) on both sides

Note that you can also write the equation in terms of formulas instead of names:

Na₃PO₄ + 3HCl → H₃PO₄ + 3NaCl

Both equations represent the same chemical reaction, but the second one is more concise.

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Answer:

The rock cycle is driven by two forces: (1) Earth's internal heat engine, which moves material around in the core and the mantle and leads to slow but significant changes within the crust, and (2) the hydrological cycle, which is the movement of water, ice, and air at the surface, and is powered by the sun.

Explanation:

Explanation:

1) Thermal and Electric conductivity

2) Metallic strength

Answer:

a thermal conductor

Explanation:

thats what its called

Answer:

No, it is not naturally occuring because it is man-made.

Answer:

The answer is "6.52 kg and 13.1 kg"

Explanation:

For point a:  

[tex]Actual\ yield = 6.52 \ kg\\\\Percent \ yield= 66\%\\\\Percent \ yield = \frac{Actual \ yield}{Theoretical\ yield} \times 100 \%\\\\Theoretical\ yield \ of \ MnO_2 = \frac{Actual \ yield}{Percent \ yield} \times 100\%\\\\=\frac{6.52 \ kg}{66 \%} \times 100\% =9.88 \ kg\\\\[/tex]

Equation:  

[tex]3MnCO_3 +O_2 \longrightarrow 2MnO_2 + 2CO_2\\\\[/tex]

Calculating the amount of [tex]MnCO_3[/tex]

[tex]= 9.88 \ kg \times \frac{1000 \ g}{1 \ kg} \times \frac{1 \ mol \ MnO_2}{86.94 \ g} \times \frac{2 \ Mol \ MnCO_3}{2 \ mol \ MnO_2} \times \frac{114.95\ g}{1 \ mol \ MnCO_3 }\times \frac{1\ kg}{1000\ g}\\\\= 13.1 \ kg[/tex]

For point b:

[tex]Actual\ yield = 4.0 \ kg\\\\Percent\ yield=97.0\%\\\\Percent \ yield = \frac{Actual \ yield}{Theoretical \ yield} \times 100 \% \\\\Theoretical \ yield\ of\ Mn = \frac{Actual \ yield}{Percent \ yield} \times 100\%\\\\[/tex]

[tex]=\frac{4.0 \ kg}{97.0\%} \times 100\% =4.12 \ kg[/tex]

Equation:  

[tex]3MnO_2 +4AL \longrightarrow 3Mn + 2AL_2O_3\\\\[/tex]

Calculating the amount of [tex]MnO_2:[/tex]  

[tex]= 4.12 \ kg \times \frac{1000 \ g}{1 \ kg} \times \frac{1 \ mol \ Mn}{54.94 \ g} \times \frac{3 \ Mol \ MnO_2}{3 \ mol \ Mn} \times \frac{86.94 \ g}{1 \ mol \ MnO_2 }\\\\= 6516 \ g \\\\=6.52 \ kg\\\\[/tex]

Answer:

305.15

Explanation:

32 celsius converted to kelvin is 305.15 kelvin

Formula

32°C + 273.15 = 305.15K

Answer:

I don't speak espanol

Explanation:

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Answer:

Hydrochloric acid + zinc = zinc chloride + hydrogen gas

sulfuric acid + magnesium oxide = zinc sulfate + water

nitric acid + lead carbonate = Lead nitrate + carbon dioxide

Sorry can't remember how to do the last one :(

Explanation:

Answer: The wavelength of yellow light with the energy of [tex]3.45 \times 10^{-19} J[/tex] is [tex]5.76 \times 10^{-7} m[/tex].

Explanation:

Given: Energy = [tex]3.45 \times 10^{-19} J[/tex]

Formula used to calculate the wavelength is as follows.

[tex]E = \frac{hc}{\lambda}[/tex]

where,

E = energy

h = Planck's constant = [tex]6.63 \times 10^{-34} Js[/tex]

c = speed of light = [tex]3 \times 10^{8} m/s[/tex]

[tex]\lambda[/tex] = wavelength

Substitute the values into above formula as follows.

[tex]E = \frac{hc}{\lambda}\\3.45 \times 10^{-19} J = \frac{6.63 \times 10^{-34} Js \times 3 \times 10^{8} m/s}{\lambda}\\\lambda = 5.76 \times 10^{-7} m[/tex]

Thus, we can conclude that the wavelength of yellow light with the energy of [tex]3.45 \times 10^{-19} J[/tex] is [tex]5.76 \times 10^{-7} m[/tex].

Answer:

pH = 4.45

Explanation:

We need to find the pH of [tex]3.5\times 10^{-5}\ M[/tex] solution of HCl. We know that, pH of a solution is given by :

[tex]pH=-log[H]^+[/tex]

Put all the values,

[tex]pH=-log[3.5\times 10^{-5}]\\\\pH=4.45[/tex]

So, the pH of the solution of HCl is 4.45.

Explanation:

The purpose of this seven-page lab report is to use simple and fractional distillation to purify volatile liquids. The boiling points were obtained from the distillate collected drops and the efficiency of the two methods of purification were compared. The introduction experiment, data, conclusion

Answer:

2.44 L

Explanation:

Step 1: Write the balanced equation

2 Ca + O₂ ⇒ 2 CaO

Step 2: Calculate the mass of O₂ required to form 11.2 g of CaO

The molar mass of O₂ is 32 g/mol and in the balanced reaction, there is 1 mole of O₂, that is, 1 mol × 32 g/mol = 32 g.

The molar mass of CaO is 56 g/mol and in the balanced reaction, there are 2 moles of CaO, that is, 2 mol × 56 g/mol = 112 g.

11.2 g CaO × 32 g O₂/112 g CaO = 3.2 g O₂

Step 3: Calculate the volume occupied by 3.2 g of O₂

Under the conditions of the task, 32 g of O₂ occupy 24.4 L.

3.2 g × 24.4 L/32 g = 2.44 L

Answer:

I'm not sure,

Explanation:

Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day!