Answers
Change in the length of a material due to a change in temperature, ΔT is given as,
[tex]\Delta L=\alpha L\Delta T[/tex]Where L is the initial length of the material and α is the coefficient of linear expansion.
It is clear from the above equation that the expansion of a material is proportional to its coefficient of linear expansion.
From the table, Coefficient of expansion of steel,α₁=12.00
and, Coefficient of expansion of brass is, α₂=19.00
As the coefficient of expansion of brass is more than that of steel, brass will expand more than steel.
Related Questions
Which of the following is the largest unit of heat energy?a.)jouleb.)calorie c.)Btud.)kilocalorie
Answers
ANSWER
d) kilocalorie
EXPLANATION
One calorie is equivalent to approximately 4.18 Joules, so 1 cal represents a greater amount of heat energy than 1 J.
Then, 1 kilocalorie is equivalent to 1000 calories, so 1 kcal represents a greater amount of heat energy than 1 cal.
Finally, 1 kcal is equivalent to approximately 3.96 BTU, so 1 kcal represents a greater amount of heat energy than 1 BTU.
Hence, of these options, the largest unit of heat energy is kilocalorie.
Why are nuclear transformations involving neutrons generally easier to accomplish than those involving protons or alpha particles ?
Answers
Recall that neutrons have no charge whereas protons and alpha particles are charged particles.
The electrostatic force of these charged particles always wants to push them apart from each other and this force gets stronger the closer you put them together.
Neutrons, on the other hand, have no electric charge and hence cannot feel this force.
Therefore, it is easier to accomplish nuclear transformations using neutrons due to their uncharged property.
What is the critical angle of diamond in air ?
Answers
ANSWER
24.4° (if the refractive index of diamond is 2.42)
EXPLANATION
The critical angle is the incidence angle at which the angle of refraction is 90°,
By Snell's Law, we have that the critical angle is,
[tex]\theta_c=\sin^{-1}\left(\frac{n_2}{n_1}\right)[/tex]For n₁ > n₂.
In this case, we have to find the critical angle of diamond in air, so if the refractive index of diamond is n₁ = 2.42, the refractive index of air is n₂ = 1, then the critical angle is,
[tex]\theta_c=\sin^{-1}\left(\frac{1}{2.42}\right)\approx24.4\degree[/tex]Hence, the critical angle of diamond in air is 24.4°, rounded to the nearest tenth of a degree.
Home Page Physics Interactives Newton's Laws Click/tap the Launch Interactive button. Resize the Interactive as des Explore Use the Interactive to explore the following questions: 1. With Friction and Air Drag furned off, describe the effect that an applied force has upon the velocity? Also, draw the force diagram at the right Label the forces using F for Applied force, Fun for Normal force from the ground, and Fra for the Weight of the sled.
Answers
The force diagram is shown below:
Now, the applied force will accelarate the particle to the right. This means that the velocity of the particle will increase in that direction.
what is uniform circular motion?
Answers
When an object moves in a circular path with uniform speed, it's motion is called Uniform Circular Motion.
QUESTION 1Jim pushes on a large bookcase that has a mass of 35kg with a horizontal force of 150N. The coefficient of friction between the wooden floor and bookcaseis 0.6. If the bookcase does not move what is the magnitude of the static frictional force (from the floor) acting on the bookcase? Answer in Newtons.
Answers
Given data
*The given mass of the bookcase is m = 35 kg
*The given horizontal force is F = 150 N
*The coefficient of friction between the wooden floor and bookcase is
[tex]\mu=0.6[/tex]The formula for the magnitude of the static frictional force acting on the bookcase is given as
[tex]\begin{gathered} F_s=\mu N \\ =\mu mg \end{gathered}[/tex]*Here N = mg is the normal force
*Here g is the acceleration due to the gravity
Substitute the known values in the above expression as
[tex]\begin{gathered} F_s=(0.6)(35)(9.8) \\ =205.8\text{ N} \end{gathered}[/tex]Hence, the magnitude of the static frictional force acting on the bookcase is 205.8 N
True or false Is it possible for an object to exert a force on another object without feeling a force in return?
Answers
ANSWER
It is not possible
EXPLANATION
According to Newton's third law, for every action (force), there is always a reaction (reactive force).
This means that forces occur in pairs and so if an object exerts a force on another object, it must feel the same amount of force in return.
Therefore, it is not possible.
A 1.2 KG rubber ball is being thrown in the air if the ball is traveling at 2.0 M/S when it is 3.0 M off the ground what is the total energy
Answers
ANSWER:
STEP-BY-STEP EXPLANATION:
We have that the total energy is given by the following formula:
[tex]\begin{gathered} E_T=E_C+E_P \\ E_C=\frac{1}{2}\cdot m\cdot v^2 \\ E_P=m\cdot g\cdot h \end{gathered}[/tex]We replace and calculate the total value of the energy:
[tex]undefined[/tex]what is formula for speed wave . what does f and A symbols represent and what unit is speed wave measured in
Answers
The pilot of an airplane wishes to fly due north but there is 65km/h wind blowing toward the east. (a) In what direction should the pilot head her plane if it's speed relative to the air is 340km/h. (b) draw a vector diagram that illustrates your results in part a. (c) if the the pilot decreases the air speed of the plane but still wants to head due north should the angle found in part (a) be increased or decreased
Answers
ANSWER
(a) 11.02° west of north
(b) see diagram in EXPLANATION
(c) increased
EXPLANATION
(a) The pilot wants the airplane to fly north. There's a speed relative to the air that is 340km/h and the air speed is 65km/s. Drawing a vector diagram (b) we can see how to find the direction the plane should head:
If the wind is blowing east, it is clear that the plane has to go in opposite direction but still heading north. So the direction is θ degrees west of north. Now we just have to find this angle. The vectors form a right triangle where the direction the angle should take is the hypotenuse and the direction of the wind is the opposite side to the angle θ. Using the sine of the angle:
[tex]\sin \theta=\frac{65\operatorname{km}/h}{340\operatorname{km}/h}[/tex][tex]\sin \theta=\frac{13}{68}[/tex]Solving for θ:
[tex]\theta=\sin ^{-1}\frac{13}{68}=11.02\degree[/tex](c) Let's draw a new diagram with a smaller red vector:
If the red vector (which represents the speed of the plane) is exaggeratedly smaller than before we can see graphically that the angle is increased if the speed of wind's vector is the same.
if you don't mind can you also answer 2 more questions
Answers
Take into account that conduction is the process at which heat is propagated by the termical motion of the molecules, without a real desplacement of the molecules.
Based on the previous definition, the following is an example of heat transfer by condu
Two identical conducting spheres carry charges of +3 coulombs (3C) and –1 coulombs (-1C), respectively. If the spheres are brought into contact and separated, the final charge on each is: a. +1C (b) +2C (c) –1C (d) –2C
Answers
Net charge /2
Q1 = 3 C
Q2= -1 C
Net charge = Q1 +Q2= 3 + (-1) = 2 C
2C/2 = 1C
Answer: +1C (option a )
(Electron Charge) What charge does a balloon have if it has lost 9.4E12 electrons?
Answers
One coulomb (C) of charge represents an excess or deficit of 6.24 x 10¹⁸ electrons, therefore:
[tex]\begin{gathered} \frac{9.4}{6.24\times10^{18}}=1.5\times10^{-18} \\ \\ Since_{\text{ }}it_{\text{ }}has_{\text{ }}lost_{\text{ }}electrons: \\ \\ +1.5\times10^{-18} \end{gathered}[/tex]Answer:
+1.5x10⁻¹⁸ C
As shown in the diagram below, a 5.0 kg space rock is located 2.5 x 107 m from the center of the Earth. The mass of the Earth is 6.0 x 1024 kg.ADetermine the force of gravity acting on the space rock, due to the Earth. Calculate the magnitude and state the direction.BCalculate the acceleration the rock would experience.
Answers
Given data
*The given mass of the space rock is m = 5.0 kg
*The given mass of the Earth is M = 6.0 × 10^24 kg
*The separation distance is r = 2.5 × 10^7 m
*The value of the gravitational constant is G = 6.67 × 10^-11 N.m^2/kg^2
(A)
The formula for the force of gravity acting on the space rock, due to the Earth is given as
[tex]F=\frac{GmM}{r^2}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} F=\frac{(6.67\times10^{-11})(5.0)(6.0\times10^{24})}{(2.5\times10^7)^2} \\ =3.2\text{ N} \end{gathered}[/tex]Hence, the force of gravity acting on the space rock, due to the Earth is F = 3.2 N
(B)
The expression for the acceleration of the rock would experience is given as
[tex]\begin{gathered} F=ma \\ a=\frac{F}{m} \end{gathered}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} a=\frac{3.2}{5} \\ =0.64m/s^2 \end{gathered}[/tex]Hence, the acceleration the rock would experience is a = 0.64 m/s^2
A man has a mass of 150 kg. What does he weigh on earth expressed in N?
Answers
ANSWER:
1470 N
STEP-BY-STEP EXPLANATION:
Given:
Mass (m) = 150 kg
Earth gravity (g) = 9.8 m/s²
We can calculate the weight as follows:
[tex]\begin{gathered} W=m\cdot g \\ \\ \text{ We replacing:} \\ \\ W=150\cdot9.8 \\ \\ W=1470\text{ N} \end{gathered}[/tex]The weight of this man on earth is 1470 N
A pure silver lions fan throws a roll of toilet paper at 7.2 m/s from her seat at Ford‘s field during a recent game. how fast is the 0.4 KG roll going when it strikes an opposition player 16. 1 m below?
Answers
Given:
The mass of the roll is m =0.4 kg.
The velocity of the roll is v = 7.2 m/s at a height h = 16.1 m.
To find the velocity when it strikes the opposition player, where height h'= 0 m
Explanation:
According to the law of conservation of energy, the total energy is always conserved, so
[tex]\begin{gathered} (P\mathrm{}E\mathrm{})_h+(K\mathrm{}E.)_h=(P.E.)_{h^{\prime}}+(K.E.)_{h^{\prime}} \\ mgh+\frac{1}{2}mv^2=mgh^{\prime}+\frac{1}{2}mv^{\prime2} \end{gathered}[/tex]Here, g = 9.8 m/s^2 is the acceleration due to gravity.
On substituting the values, the velocity will be
[tex]\begin{gathered} 0.4\times9.8\times16.1+\frac{1}{2}\times0.4\times(7.2)^2=0.4\times9.8\times0+\frac{1}{2}\times0.4v^{\prime2} \\ 63.112+10.368=0+0.2v^{\prime2} \\ v^{\prime}=19.17\text{ m/s} \end{gathered}[/tex]Final Answer: The velocity of the roll when it strikes the player is 19.17 m/s
What is one way to change water from a liquid to a solid?decrease the massdecrease the temperatureincrease the massincrease the temperature
Answers
Decrease the temperature
Explanation
Freezing, or solidification, is a phase transition in which a liquid turns into a solid when its temperature is lowered to or below its freezing point.
When liquid water loses thermal energy, it undergoes freezing : changing state from a liquid to a solid.
so, the lose of thermal energy means
Decrease the temperature
I hope this helps you
Looking at the spectral lines from the hydrogenspectrum of light, pictured below, and give theWavelength (m), Frequency (Hz), Velocity (m/s),Energy (J) for line c. Use scientific notation asneeded and 3 significant figures ex. 1.23E5.
Answers
ANSWER and EXPLANATION
We want to identify the parameters of the line in the electromagnetic spectrum.
The wavelength of line c is given as 486.13 nanometers. Converting this to meters, we have that the wavelength of line c is:
[tex]\begin{gathered} \lambda=486.13*10^{-9} \\ \lambda=4.86E-7\text{ }m \end{gathered}[/tex]To find the frequency of line c, apply the relationship between the velocity of light and wavelength:
[tex]f=\frac{c}{\lambda}[/tex]where c = velocity of light in a vacuum
f = frequency of the light
Hence, the frequency of line c is:
[tex]\begin{gathered} f=\frac{3.00*10^8}{4.85*10^{-7}} \\ f=6.19E14\text{ }Hz \end{gathered}[/tex]The velocity of light in a vacuum is given by:
[tex]c=3.00E8\text{ }m\/s[/tex]The energy of the line can be found using the formula:
[tex]E=hf[/tex]where E = energy
h = Planck's constant = 6.63E-34 Js
Hence, the energy of line c is:
[tex]\begin{gathered} E=6.63*10^{-34}*6.19*10^{14} \\ E=4.10E-19\text{ }J \end{gathered}[/tex]Those are the answers.
Vector A represents displacement of 50 m towards North and vector B represents 90 m displacement towards west. Find the resultant vector (A+B)
Answers
ANSWER
[tex]A+B=-90i+50j[/tex]EXPLANATION
We want to find the resultant vector of the two vectors A and B.
First, let us make a sketch of the two vectors:
Let us write the two vectors in component form taking the North as the positive y-direction and the West as the negative x-direction:
[tex]\begin{gathered} A=0i+50j \\ B=-90i+0j \end{gathered}[/tex]Therefore, the resultant vector is:
[tex]\begin{gathered} A+B=0i+50j+(-90i+0j) \\ A+B=0i-90i+50j+0j \\ A+B=-90i+50j \end{gathered}[/tex]That is the answer.
Two balloons of the same volume are filled with helium. The kinetic energy of the helium molecules in Balloon 1 is higher than the kinetic energy of the helium molecules in Balloon 2. What can you conclude about these balloons?A.The temperature is lower in the Balloon 1.B.The temperature is lower in Balloon 2.C.Balloon 1 has more helium in it than balloon 2.D.The balloons have two different kinds of helium.
Answers
To find:
Which of the given statement is true?
Explanation:
The kinetic energy of a gas is directly proportional to its temperature.
When the temperature of a gas is more, molecules of the gas vibrate more and thus they will have more kinetic energy.
Thus the balloon with lower kinetic energy has a lesser temperature.
Final answer:
The correct answer is option B.
Gabrielle and Pierre are trying to move a 52 kg box by pushing it across the floor. Gabrielle is pushing with a force of 40 N [east], while Pierre is pushing with a force of 32 N [west]. There is also a friction force of 3 N [west] on the box. Assume the box travels 4 m [east].A. Draw a system diagram and a free-body diagram of the box.B. Calculate the net force in the horizontal direction on the box. In which direction is the net horizontal force?C. Calculate the net force in the vertical direction on the box. In which direction is the net vertical force?
Answers
Explanation
Step 1
a)system diagram and Free body diagram
F.B.D.
Step 2
B)
Net force:
Let
positive to the rigth, negative to the left, so
[tex]\begin{gathered} Net\text{ force=40 N-32N-3N=5 N} \\ Net\text{ force=5 N} \end{gathered}[/tex]so, the net force is 5 N (east)
Step 3
net force in the vertical direction:
as the box is not moving on the y-axis, the sum of forces equals zero, hence
[tex]\begin{gathered} N-mg=0 \\ N=weight=mg=52kg*9.8\frac{m}{s^2} \\ Normal\text{ force=509.6 N} \end{gathered}[/tex]so
the net force in the vertical direction is zero
I hope this helps you
When a pitcher throws a baseball, it reaches a top speed of 39 m/s. If thebaseball takes 1.5 seconds to travel from the pitcher to the catcher, what isits acceleration? (Assume the ball is moving at 0 m/s right before it leavesthe pitcher's hand.)A. 23 m/s2B. 17 m/s2C. 11 m/s2D. 26 m/s2
Answers
Given,
The final velocity of the ball, v=39 m/s
The initial velocity of the ball, u=0 m/s
The time duration, t=1.5 s
The final velocity of an object upon which an accleration, a, acts for a duration of t seconds is given by one of the equations of motion as
[tex]v=u+at[/tex]By substituting the known values and simplifying the resulting equation we will get the acceleration of the ball.
Thus,
[tex]\begin{gathered} 39=0+a\times1.5 \\ \Rightarrow a=\frac{39}{1.5} \\ 26m/s^2 \end{gathered}[/tex]Thus the acceleration of the ball is 26 m/s²
Therefore the right answer is option 4.
2) How long does it take sound to travel
a. 30m?
b. 1000m?
Answers
one thousand meters(1000m)
Two objects are placed so their centers are 1.19 meters apart, and the force between them is 8.16 x 10-10 newtons. What is the mass of each object if one has twice the mass of the other? Include units in your answers. Answers must be in 3 significant digits.
Answers
Given that the mass of object 1 is m and the mass of object 2 is 2m.
The distance between two objects is r = 1.19 m
The force between two objects is
[tex]F=8.16\times10^{-10}\text{ N}[/tex]The formula for the force can be written as
[tex]F=\frac{Gm\times2m}{r^2}[/tex]Here, the universal gravitational constant is G = 6.67 x 10^(-11) m^3 kg^(-1)s^(-2)
The mass will be
[tex]m^{}=\sqrt{\frac{Fr^2}{2G}}[/tex]Substituting the values, the mass will be
[tex]\begin{gathered} m=\sqrt[]{\frac{8.16\times10^{-10}\times(1.19)^2}{2\times6.67\times10^{-11}}} \\ =\sqrt[]{8.662} \\ =2.943\text{ kg} \end{gathered}[/tex]The mass of object 1 is 2.94 kg and the mass of object 2 is
[tex]\begin{gathered} 2\times2.943 \\ =\text{ 5.886 kg} \end{gathered}[/tex]Use the table and the diagram below to correctly label the force that is shown by the arrow pointing RIGHT.
Answers
The frictional forces (including air resistance) always point to the direction which is opposite to the movement of an object. If the object is not moving and the frictional force corresponds to a static friction, then it points to the opposite direction of the applied force.
From the diagram, if we assume that the object is not moving, then the arrow that points towards the right corresponds to the applied force.
Therefore, the answer is:
[tex]\text{Applied Force}[/tex]Good morning I could really use help with this question please!
Answers
Given:
The charge of X is
[tex]q_x=\text{ 7.5}\times10^{-9}\text{ C}[/tex]The charge of Y is
[tex]q_y=-3.5\times10^{-9}\text{ C}[/tex]The distance between the charges is r = 80 cm.
To find whether there is an increase or decrease in the force of attraction/repulsion if the new charge of y is
[tex]q_y^{\prime}=-6.5\text{ }\times10^{-9}\text{ C}[/tex]and the distance between the charges is the same.
Explanation:
The charges q_x and q_y will have the force of attraction as they have opposite charges.
The magnitude of the force is given by the formula
[tex]F=k\frac{|q_x||q_y|}{r^2}[/tex]Here, the k is the electrostatic constant.
The distance between the charges is the same and the charge on X is also the same.
Thus, the force
[tex]F\propto\text{ \mid q}_y|[/tex]The new charge has a magnitude more than the old charge on Y.
Thus, the force of attraction will increase due to the increase in the magnitude of the charge.
Final Answer: The electrical force of attraction will increase.
Above is a distance/time graph showing an object in motion. Use the information
from the graph, write a scenario(story) about what the object is doing during each
section.
To answer, click the text tool or microphone icon in the tool
bar.
Answers
We will have the following:
From time 0 to 20: The object accelerated, until it reached maximum speed.
From time 20 to 30: The object moved at constant speed. [Acceleration 0]
From time 30 to 50: The object deccelerated, until it stopped.
An unknown radioactive element decays with a half life of 5.125 days. What is the decay constant for the element? Express your answer in 1/day.
Answers
Given
Half life is t=5.125 days
To find
The decay constant
Explanation
The decay constant is given by
[tex]\begin{gathered} \lambda=\frac{0.693}{t} \\ \Rightarrow\lambda=\frac{0.693}{5.125} \\ \Rightarrow\lambda=0.135 \end{gathered}[/tex]Conclusion
The decay constant is 0.135 /day
Moving a charge from point A, where the potential is 473.44 V, to point B, where the potential is 143.75 V, takes 0.34 milliJ of work. What is the value of the charge, in micro-Coulombs?
Answers
Can someone please help me with these two they go together to make one question
Answers
1) Since the truck is moving, it has kintic energy. The formula for calculating kinetic energy is expressed as
KE = 1/2mv^2
where
m = mass
v = velocity
From the information given,
m = 60000
v = 27
Thus,
Kinetic energy = 1/2 x 60000 x 27^2 = 21870000 J
The amount of work that must be done to stop the truck must be equal to or greater than the kinetic energy. Thus,
amount of work that must be done to stop the truck = 21870000 J
2) Net force applied = - 300000 N
Recall,
Net Force = mass x acceleration
acceleration = net force/mass
acceleration of the truck = - 300000 /60000 = - 5 m/s^2
Since the acceleration is negative, it is decelerating.
To find the distance before it stops, we would apply one of Newton's formula of motion which is expressed as
v^2 = u^2 + 2as
where
v = final velocity
u = initial velocity
a = acceleration
s = distance
From the information given,
v = 0(becuase it will stop moving)
u = 27
a = - 5
By substituting these values into the formula,
0^2 = 27^2 - 2 x 5 x s
0 = 729 - 10s
10s = 729
s = 729/10
s = 72.9
The truck will move 72.9 meters before stopping