Answer:
1/3
Step-by-step explanation:
the multiples of three is three, six, and nine
which is 3/9 bc the total is 9
hope this helps
If Q(x) = x2 – X – 2, find Q(-3).
Answer:
10
Step-by-step explanation:
for this you need to sub the value of -3 for x
Q(-3)=(-3)^2-(-3)-2
=9+3-2
=10
Answer:
Q= x - X/x - 2/x
Step-by-step explanation:
hope this helps !
There are (7^13)^3 x 7^0 strawberries in a field . What is the total number of strawberries in the field
Answer:
Step-by-step explanation:
[tex]7^{0}=1[/tex]
[tex](7^{13})^{3}*7^{0}=7^{13*3}*1\\\\=7^{39}[/tex]
Enter a range of value for x.
Answer:
-2 < x < 35
Step-by-step explanation:
We have that the larger side has a larger opposite angle and the smaller sides and a smaller opposite angle.
The opposite angle of the 14 unit side is 37 °.
The opposite angle of the 13-unit side is (x + 2) °.
Since 13 <14, it would be:
x + 2 <37
we subtract 2 on both sides
x <35
The value of x must be less than 35.
Now, to form a triangle, the angle must be greater than 0.
x + 2> 0
we subtract 2 on both sides
x> -2
The value of x must be greater than - 2.
Therefore the answer would be:
-2 <x <35
The tread life of a particular brand of tire is normally distributed with mean 60,000 miles and standard deviation 3800 miles. Suppose 35 tires are randomly selected for a quality assurance test. Find the probability that the mean tread life from this sample of 35 tires is greater than 59,000 miles. You may use your calculator, but show what you entered to find your answer. Round decimals to the nearest ten-thousandth (four decimal places).
Answer:
P [ x > 59000} = 0,6057
Step-by-step explanation:
We assume Normal Distribution
P [ x > 59000} = (x - μ₀ ) /σ/√n
P [ x > 59000} = (59000 - 60000)/ 3800
P [ x > 59000} = - 1000/3800/√35
P [ x > 59000} = - 1000*5,916 /3800
P [ x > 59000} = - 5916/3800
P [ x > 59000} = - 1,55
We look for p value for that z score n z-table and find
P [ x > 59000} = 0,6057
Rachel measures the lengths of a random sample of 100 screws. The mean length was 2.6 inches, with a standard deviation of 1.0 inches. Using the alternative hypothesis (µ < µ0), Rachel found that a z-test statistic was equal to -1.25. What is the p-value of the test statistic? Answer choices are rounded to the thousandths place.
Answer:
Step-by-step explanation:
Using the alternative hypothesis (µ < µ0),
To find the p-value with test statistic -1.25 and assuming a standard level of significance of 0.05, using a p value calculator, the p-value is 0.1057 which is great that 0.05. Thus, the results is not significant.
Using the p value calculation.
1. Check the left tailed z table as the test statistic is negative,
2. Then find the probabilitythat z is greater than your test statistic (look up your test statistic on the z-table- the value under 1.2 and 0.05 which is 0.8944
3. Then, find its corresponding probability, and subtract it from 1 to get your p-value- 1-0.8944 = 0.1056.
Use the table to identify values of p and g that can be used to factor X2 - x - 12
as (x + 2)(x + 9).
e
р
2
-2
ptq
-4
9
-6
6
-4
4
4
6
3
-3
-1
1
O A. -3 and 4
unctions
ving
O B-2 and 6
O C. 2 and -6
deling
O D. 3 and 4
Answer:
D. 3 and -4
Step-by-step explanation:
Given the expression, x² - x - 12, let's factorise to find the value of p and q using the table, for which we would have the expression simplified as (x + p)(x + q)
From the table, let's find the values of p and q that would give us -12 when multiplied together, and would also give us -1 when summed together.
Thus, from the table given, the row containing the values of p(3) and q(-4) gives us = -1 (p+q) . p = 3, q = -4 would be our values to use to factor x² - x - 12, as multiplying both will also give us "-12".
Thus, x² - x - 12 would be factorised or simplified as (x + 3)(x - 4)
Therefore, the answer is: D. 3 and -4
Answer:
D a p e x
Step-by-step explanation:
On a piece of paper Graph Y=-3x-2
Answer:
hope it helps uh......
Solve by completing the square. x2−12x=−27 Select each correct answer. −9 −3 3 9 15
Answer:
x=9,3
Step-by-step explanation:
x²-12x=-27
x²-12x+(12/2)²=-27+(12/2)²
x²-12x+6²=-27+36
(x-6)²=9
x-6=[tex] \frac{ + }{ - } \sqrt{9} [/tex]
x-6=+3 and x-6=-3
x=9 and 3
What is the value of 500$ invested at 4% interest compounded annually for 7 years
Answer:
657.96
Step-by-step explanation:
use formula A=P(1+r/n)^nt
A=500(1+.04/1)^1*7
A=500(1.04)^7
A=500(1.3159~)
A= 657.96~
Given that a function, h, has a domain of -3 ≤ x ≤ 11 and a range of 1 ≤ h(x) ≤ 25 and that h(8) = 19 and h(-2) = 2, select the statement that could be true for h
Answer:
C
Step-by-step explanation:
We know that A is not true because we know that h(8) is 19, not 21. B is also not true because the value of h(x) can't be -1. D can't be true because x can't be 13, therefore the answer is C.
Which data set is accurate and precise based on a correct value of 30?
Set 1: 30, 35, 32, 30, 29
Set 2: 15, 16, 12, 15, 14
Set 3: 19, 30, 78, 43, 30
Set 4: 30, 30, 67, 12, 90
Answer:
Set 1: 30, 35, 32, 30, 29
Step-by-step explanation:
Let's first clarify what is accurate and precise:
Precise is based on how close two or more measured values are to each other. While something is said to be accurate, when the standard value values are close, which in our case is 30.
Therefore, we analyze each set:
Set 1: 30, 35, 32, 30, 29
This set is precise and accurate, since 2 values are 30 and all their values are close to each other.
Set 2: 15, 16, 12, 15, 14
This set is precise, because all of its values are close but not accurate.
Set 3: 19, 30, 78, 43, 30
This set is somewhat accurate because there are 2 values of 30, but it is not precise because its values are separate.
Set 4: 30, 30, 67, 12, 90
It is the same case of Set 3.
Therefore the answer is Set 1.
Answer:
Set 1: 30, 35, 32, 30, 29
Step-by-step explanation:
How do you write 89,700,000,000 in scientific notation? ___× 10^____
Answer:
It's written as
[tex]89.7 \times {10}^{9} [/tex]
Or
[tex]8.97 \times {10}^{10} [/tex]
Hope this helps you
Answer:
8.97 * 10 ^10
Step-by-step explanation:
We want one nonzero digit to the left of the decimal
8.97
We moved the decimal 10 places to the left
The exponent is positive 10 since we moved 10 places to the left
8.97 * 10 ^10
the length of a rectangular sheet of metal is 9.96m and it's breadth is 5.08m. Find the area of the metal.Correct the answer to 2 significant figures and then correct the answer to 0.1 meter square
Answer:
The area of the sheet is approximately 50.59 m² or 50.6 m²
Step-by-step explanation:
The area of a rectangle is given by the following expression:
[tex]area = width*height[/tex]
Since breadth is the same as the width of the sheet, we can calculate its area as shown below:
[tex]area = 9.96*5.08 = 50.59[/tex]
The area of the sheet is approximately 50.59 m² or 50.6 m²
The quotient of y and 3
Answer:
[tex]\frac{y}{3}[/tex]
Step-by-step explanation:
Well the quotient is the answer if y divided by 3.
So y divided by 3 is y over 3 y/3.
Solve the system by the method of elimination.
Answer:
no solution
Step-by-step explanation:
4x+3y = 6
8x + 6y = 5
Multiply the first equation by -2
-2(4x+3y) = 6*-2
-8x -6y = -12
Add this to the second equation
-8x-6y = -12
8x + 6y = 5
---------------------
0x + 0y = -7
0 = -7
Since this is never true there is no solution
Answer:
X = 8/3, y= -14/9
Step-by-step explanation:
using elimination method:
subtract equation 1 from equation 2
8x-4x + 6y-3y = 5-6
4x+3y= -1
4x= -1-3y
divide both sides by 4
x = -1-3y÷4
substitute x = -1-3y/4 in equation 2
8(-1-3y)/4 +6y = 5
-8-24y/4+ 6y =5
-8-24y+6y/4 =5
-8-18y/4 = 5
Cross multy
-8-18y × 1 = 4×5
-8-18y = 20
collect like terms
-18y = 20+8
-18y = 28
divide both sides by-18
y = 28/-8
y = -14/9
put y = -14/9 in equation 1
4x+3(-14/9) = 6
4x-42/9 = 6
42/9 = 14/3
so, 4x=6+14/3
LCM =3
4x = 18+14/3
4x= 32/3
cross multiply
4x×3 = 32
12x = 32
divide both sides by 12
12x/12= 32/12
x = 8/3
so, x = 8/3, y = -14/9
check:
first equation:
4(8/3) + 3(-14/9)
32/3 - 14/3( 3 cancels 9 rem 3)
LCM= 3
32 - 14/3
= 18/3
= 6
Before the pandemic cancelled sports, a baseball team played home games in a stadium that holds up to 50,000 spectators. When ticket prices were set at $12, the average attendance was 30,000. When the ticket prices were on sale for $10, the average attendance was 35,000.
(a) Let D(x) represent the number of people that will buy tickets when they are priced at x dollars per ticket. If D(x) is a linear function, use the information above to find a formula for D(x). Show your work!
(b) The revenue generated by selling tickets for a baseball game at x dollars per ticket is given by R(x) = x-D(x). Write down a formula for R(x).
(c) Next, locate any critical values for R(x). Show your work!
(d) If the possible range of ticket prices (in dollars) is given by the interval [1,24], use the Closed Interval Method from Section 4.1 to determine the ticket price that will maximize revenue. Show your work!
Optimal ticket price:__________ Maximum Revenue:___________
Answer:
(a)[tex]D(x)=-2,500x+60,000[/tex]
(b)[tex]R(x)=60,000x-2500x^2[/tex]
(c) x=12
(d)Optimal ticket price: $12
Maximum Revenue:$360,000
Step-by-step explanation:
The stadium holds up to 50,000 spectators.
When ticket prices were set at $12, the average attendance was 30,000.
When the ticket prices were on sale for $10, the average attendance was 35,000.
(a)The number of people that will buy tickets when they are priced at x dollars per ticket = D(x)
Since D(x) is a linear function of the form y=mx+b, we first find the slope using the points (12,30000) and (10,35000).
[tex]\text{Slope, m}=\dfrac{30000-35000}{12-10}=-2500[/tex]
Therefore, we have:
[tex]y=-2500x+b[/tex]
At point (12,30000)
[tex]30000=-2500(12)+b\\b=30000+30000\\b=60000[/tex]
Therefore:
[tex]D(x)=-2,500x+60,000[/tex]
(b)Revenue
[tex]R(x)=x \cdot D(x) \implies R(x)=x(-2,500x+60,000)\\\\R(x)=60,000x-2500x^2[/tex]
(c)To find the critical values for R(x), we take the derivative and solve by setting it equal to zero.
[tex]R(x)=60,000x-2500x^2\\R'(x)=60,000-5,000x\\60,000-5,000x=0\\60,000=5,000x\\x=12[/tex]
The critical value of R(x) is x=12.
(d)If the possible range of ticket prices (in dollars) is given by the interval [1,24]
Using the closed interval method, we evaluate R(x) at x=1, 12 and 24.
[tex]R(x)=60,000x-2500x^2\\R(1)=60,000(1)-2500(1)^2=\$57,500\\R(12)=60,000(12)-2500(12)^2=\$360,000\\R(24)=60,000(24)-2500(24)^2=\$0[/tex]
Therefore:
Optimal ticket price:$12Maximum Revenue:$360,000Can you help me please solve
Answer:
(-0.5, 0)
Step-by-step explanation:
Coordinates of endpoints of segment are:
A= (-2, 1)
B= (1, - 1)
By mid-point formula:
The midpoint of [tex] \overline{AB} [/tex]
[tex] = \bigg(\frac{ - 2 + 1}{2}, \: \: \frac{1 + ( - 1)}{2} \bigg) \\ \\ = \bigg(\frac{ - 1}{2}, \: \: \frac{0}{2} \bigg)\\ \\ = \bigg(\frac{ - 1}{2}, \: \: 0 \bigg)\\ \\ = ( - 0.5, \: \: 0 )[/tex]
Find the slope-intercept form of the line with slope 6 that passes through the point (3,5).
Answer:
y=6x-13
Step-by-step explanation:
Since we are given a point and a slope, we can use the slope intercept formula.
[tex]y-y_{1} = m(x-x_{1} )[/tex]
where (x1, y1) is a point and m is the slope.
We know that the slope is 6 and the point is (3,5). Therefore,
x1= 3
y1= 5
m=6
Substitute these into the formula.
[tex]y-5 = 6(x-3 )[/tex]
Distribute the 6. Multiply each term inside the parentheses by the number outside the parentheses.
[tex]y-5= (6*x) + (6*-3)[/tex]
[tex]y-5=6x-18[/tex]
We want to find the slope-intercept form, or y=mx+b. Therefore, we must get y by itself.
5 is being subtracted from y. The inverse of subtraction is addition. Add 5 to both sides.
[tex]y-5+5=6x-18+5[/tex]
[tex]y= 6x-18+5[/tex]
[tex]y= 6x -13[/tex]
What is the greatest common factor of the polynomial below?
20x^3 - 14x
Answer:
the correct answer is 2x
Answer:
D. 2x
Step-by-step explanation:
20x² : 1, 2, 4, 5, 10, 20, x
14x : 1, 2, 7, 14, x
The greatest common factor of the polynomial is 2x.
2x(10x² - 7)
Abox in the shape of a rectangular prism, with dimensions 12 inches by 18 inches by 12 inches, can hold exactly 12
cubes measuring 6 inches on each side.
If the length and width of the base are doubled, how many cubes could the new box hold?
18
0 24
48
o 96
Answer:
48
Step-by-step explanation:
You are doubling 2 dimensions, so you just multiply the volume by 2 each time. Since you are doing it twice, you multiply the volume by 4. 12*4=48. You could also brute force it and just do 24*36*12/216(the volume of the 6 inch cube).
Given that, a box in the shape of a rectangular prism, with dimensions 12 inches by 18 inches by 12 inches, can hold exactly 12 cubes measuring 6 inches on each side.
We need to find that how many cubes it holds if the length and width of the base are doubled,
We know that,
Volume of a rectangular prism = length × width × height
Volume of the new rectangular prism, = 2length × 2width × height
= 4(length × width × height)
= 4(12·12·18)
= 4×2592
= 10,368
Volume of the cube = side³
= 6³ = 216
The number of cube that the new rectangular prism can hold = Volume of the rectangular prism / Volume of the cube
= 10,368 / 216
= 48
Hence, the new rectangular prism, can hold 48 cubes.
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WILL GIVE BRAINLIEST What is the perimeter of the track, in meters? Use π = 3.14 and round to the nearest hundredth of a meter. plz help me
Answer:
P ≈ 317.08 m
Step-by-step explanation:
Circumference: C = πd
Step 1: Find circumference of both domes
C = π(50)
Since it's a dome, we divide by 2
50π/2 = 25π
Since we have 2 domes, we simply multiply by 2 again
25π(2) = 50π
Step 2: Find perimeter of track
50π + 80(2)
P = 50π + 160
P = 317.08 m
On the "Compiled Information" tab, a VLOOKUP formula has been pre-entered into cell E3. This formula was written correctly, and it uses references to the numbers in cells E1 through G1 to determine the correct index_number parameter. Fill in cells F1 and G1 with the correct index numbers, then copy the formula in cell E3 down to all the rows in columns E, F, and G. What number did you enter into cell G1?
Answer:
3
Step-by-step explanation:
Vlookup is a technique in excel which enables users to search for criterion values. It is vertical lookup function in excel which return a value from a different column. The formula for Vlookup function is:
=Vlookup'select cell you want to look up in' select cell you want to lookup from' select column index number' true/false.
where true is approximate match and false is exact match.
AT&T would like to test the hypothesis that the proportion of 18- to 34-year-old Americans that own a cell phone is less than the proportion of 35- to 49-year-old Americans. A random sample of 200 18- to 34-year-old Americans found that 126 owned a smartphone. A random sample of 175 35- to 49-year-old Americans found that 119 owned a smartphone. If Population 1 is defined as 18- to 34-year-old Americans and Population 2 is defined as 35- to 49-year-old Americans, the correct hypothesis statement for this hypothesis test would be
Answer:
The null and alternative hypothesis can be written as:
[tex]H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0[/tex]
Step-by-step explanation:
This is a hypothesis test for the difference between proportions.
The claim is that the proportion of 18- to 34-year-old Americans that own a cell phone is less than the proportion of 35- to 49-year-old Americans.
This claim will be reflected in the alternnative hypothesis, that will state that the population proportion 1 (18 to 34) is significantly smaller than the population proportion 2 (35 to 49).
On the contrary, the null hypothesis will state that the population proportion 1 is ot significantly smaller than the population proportion 2.
Then, the null and alternative hypothesis can be written as:
[tex]H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0[/tex]
The significance level is assumed to be 0.05.
The sample 1, of size n1=200 has a proportion of p1=0.63.
[tex]p_1=X_1/n_1=126/200=0.63[/tex]
The sample 2, of size n2=175 has a proportion of p2=0.68.
[tex]p_2=X_2/n_2=119/175=0.68[/tex]
The difference between proportions is (p1-p2)=-0.05.
[tex]p_d=p_1-p_2=0.63-0.68=-0.05[/tex]
The pooled proportion, needed to calculate the standard error, is:
[tex]p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{126+119}{200+175}=\dfrac{245}{375}=0.653[/tex]
The estimated standard error of the difference between means is computed using the formula:
[tex]s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.653*0.347}{200}+\dfrac{0.653*0.347}{175}}\\\\\\s_{p1-p2}=\sqrt{0.001132+0.001294}=\sqrt{0.002427}=0.049[/tex]
Then, we can calculate the z-statistic as:
[tex]z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.05-0}{0.049}=\dfrac{-0.05}{0.049}=-1.01[/tex]
This test is a left-tailed test, so the P-value for this test is calculated as (using a z-table):
[tex]\text{P-value}=P(z<-1.01)=0.1554[/tex]
As the P-value (0.1554) is bigger than the significance level (0.05), the effect is not significant.
The null hypothesis failed to be rejected.
There is not enough evidence to support the claim that the proportion of 18- to 34-year-old Americans that own a cell phone is less than the proportion of 35- to 49-year-old Americans.
The table shows three unique functions. (TABLE IN PIC) Which statements comparing the functions are true? Select three options. Only f(x) and h(x) have y-intercepts. Only f(x) and h(x) have x-intercepts. The minimum of h(x) is less than the other minimums. The range of h(x) has more values than the other ranges. The maximum of g(x) is greater than the other maximums.
Answer:
(A)Only f(x) and h(x) have y-intercepts.
(C)The minimum of h(x) is less than the other minimums.
(E)The maximum of g(x) is greater than the other maximums.
Step-by-step explanation:
From the table
f(0)=0 and h(0)=0, therefore, Only f(x) and h(x) have y-intercepts. (Option A)
Minimum of f(x)=-14Minimum of g(x)=1/49Minimum of h(x)=-28Therefore, the minimum of h(x) is less than the other minimums. (Option C).
Maximum of f(x)=14
Maximum of g(x)=49
Maximum of h(x)=0
Therefore, the maximum of g(x) is greater than the other maximums. (Option E)
Answer: It's B,C, and E
Step-by-step explanation:
Jacqueline and Maria set up bug barns to catch lady bugs. Jacqueline caught ten more than three times the number of lady bugs that Maria caught. If c represents the number of lady bugs Maria caught, write an expression for the number of lady bugs that Jacqueline caught.
Answer:
(CX3)+10
Step-by-step explanation:
Answer:
c×3+10= j
Step-by-step explanation:
A travel agent is booking trips for tourists who travel from New York to Chicago. Tourists have three choices for how to travel from New York to Chicago. They can take an airplane for $350, a bus for $150, or a train for $225. Once they arrive in Chicago, they can travel by van to their hotel for $60 or take a cab for $40. If each option is equally likely to occur, what is the probability that a tourist will spend more than $275 on these 2 legs of the trip?
Answer:
P = 1/2
Step-by-step explanation:
If the tourist spends more than 275$, they must not arrive in Chicago by bus.
( 150 + 60 < 275, 150 + 40 < 275)
The total options the tourist can make:
3 x 2 = 6
(1st leg: 3 possible options, 2nd leg: 2 possible options)
The number of options the tourist can make after excluding bus option:
2 x 2 = 4
(1st leg: 2 remaining possible options, 2nd leg: 2 possible options)
The number of options the tourist can make after excluding the bus option and spend more than 275$:
4 - 1 = 3
(excluding the case of selecting train and cab, because 225 + 40 < 275)
=> The probability that the tourist will spend more than 275$ on these 2 legs of the trip:
P = 3/6 = 1/2
Probability helps us to know the chances of an event occurring. The probability that a tourist will spend more than $275 on these 2 legs of the trip is 0.5.
What is Probability?Probability helps us to know the chances of an event occurring.
[tex]\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}[/tex]
Given that Tourists have three choices for how to travel from New York to Chicago. They can take an aeroplane for $350, a bus for $150, or a train for $225. Also, when they arrive in Chicago, they can travel by van to their hotel for $60 or take a cab for $40. Therefore, the cost of different routes is,
Aeroplane($350) + Van($60) = $410Aeroplane($350) + Cab($40) = $390Bus($150) + Van($60) = $210Bus($150) + Cab($40) = $190Train($225) + Van($60) = $285Train($225) + Cab($40) = $265As it can be seen that there are 3 cases where a tourist will spend more than $275, while the total number of cases is 6. Therefore, the probability that a tourist will spend more than $275 on these 2 legs of the trip is,
Probability = 3/6 = 1/2 =0.5z
Hence, the probability that a tourist will spend more than $275 on these 2 legs of the trip is 0.5.
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The following observations were made on fracture toughness of a base plate of 18% nickel maraging steel (in ksi √in, given in increasing order)].
68.6 71.9 72.6 73.1 73.3 73.5 75.5 75.7 75.8 76.1 76.2
76.2 77.0 77.9 78.1 79.6 79.8 79.9 80.1 82.2 83.7 93.4
Calculate a 90% CI for the standard deviation of the fracture toughness distribution. (Give answer accurate to 2 decimal places.)
Answer:
A 90% confidence interval for the standard deviation of the fracture toughness distribution is [4.06, 6.82].
Step-by-step explanation:
We are given the following observations that were made on fracture toughness of a base plate of 18% nickel maraging steel below;
68.6, 71.9, 72.6, 73.1, 73.3, 73.5, 75.5, 75.7, 75.8, 76.1, 76.2, 76.2, 77.0, 77.9, 78.1, 79.6, 79.8, 79.9, 80.1, 82.2, 83.7, 93.4.
Firstly, the pivotal quantity for finding the confidence interval for the standard deviation is given by;
P.Q. = [tex]\frac{(n-1) \times s^{2} }{\sigma^{2} }[/tex] ~ [tex]\chi^{2} __n_-_1[/tex]
where, s = sample standard deviation = [tex]\sqrt{\frac{\sum (X - \bar X^{2}) }{n-1} }[/tex] = 5.063
[tex]\sigma[/tex] = population standard deviation
n = sample of observations = 22
Here for constructing a 90% confidence interval we have used One-sample chi-square test statistics.
So, 90% confidence interval for the population standard deviation, [tex]\sigma[/tex] is ;
P(11.59 < [tex]\chi^{2}__2_1[/tex] < 32.67) = 0.90 {As the critical value of chi at 21 degrees
of freedom are 11.59 & 32.67}
P(11.59 < [tex]\frac{(n-1) \times s^{2} }{\sigma^{2} }[/tex] < 32.67) = 0.90
P( [tex]\frac{ 11.59}{(n-1) \times s^{2}}[/tex] < [tex]\frac{1}{\sigma^{2} }[/tex] < [tex]\frac{ 32.67}{(n-1) \times s^{2}}[/tex] ) = 0.90
P( [tex]\frac{(n-1) \times s^{2} }{32.67 }[/tex] < [tex]\sigma^{2}[/tex] < [tex]\frac{(n-1) \times s^{2} }{11.59 }[/tex] ) = 0.90
90% confidence interval for [tex]\sigma^{2}[/tex] = [ [tex]\frac{(n-1) \times s^{2} }{32.67 }[/tex] , [tex]\frac{(n-1) \times s^{2} }{11.59 }[/tex] ]
= [ [tex]\frac{21 \times 5.063^{2} }{32.67 }[/tex] , [tex]\frac{21 \times 5.063^{2} }{11.59 }[/tex] ]
= [16.48 , 46.45]
90% confidence interval for [tex]\sigma[/tex] = [[tex]\sqrt{16.48}[/tex] , [tex]\sqrt{46.45}[/tex] ]
= [4.06 , 6.82]
Therefore, a 90% confidence interval for the standard deviation of the fracture toughness distribution is [4.06, 6.82].
18 is divisible by both 2 and 3 it is also divisible by 2 into 36 similarly a number is divisible by both 4 and 6 can we say that the number must also be divided by 4 and 2 6 24 if not give an example to justify your answer
Answer:
no; 12
Step-by-step explanation:
A number divisible by 4 and 6 will be divisible by their least common multiple, 12. If it is an odd multiple of 12, it will not be divisible by 24.
Examples:
12÷4 = 3; 12÷6 = 2; 12 is not divisible by 24
24÷4 = 6; 24÷6 = 4; 24 is divisible by 24
36÷4 = 9; 36÷6 = 6; 36 is not divisible by 24
Thomas Kratzer is the purchasing manager for the headquarters of a large insurance company chain with a central inventory operation. Thomas's fastest-moving inventory item has a demand of 6,100 units per year. The cost of each unit is $101, and the inventory carrying cost is $8 per unit per year. The average ordering cost is $31 per order. It take about 5 days for an order to arrive, and the demand for 1 week is 120 units. (This is a corporate operation, and the are 250 working days per year.)A) What is the EOQ?B) What is the average inventory if the EOQ is used?C) What is the optimal number of orders per year?D) What is the optimal number of days in between any two orders?E) What is the annual cost of ordering and holding inventory?F) What is the total annual inventory cost, including cost of the 6,100 units?
Answer and Step-by-step explanation:
The computation is shown below:
a. The economic order quantity is
[tex]= \sqrt{\frac{2\times \text{Annual demand}\times \text{Ordering cost}}{\text{Carrying cost}}}[/tex]
[tex]= \sqrt{\frac{2\times \text{6,100}\times \text{\$31}}{\text{\$8}}}[/tex]
= 217 units
b. The average inventory used is
[tex]= \frac{economic\ order\ quantity}{2}[/tex]
[tex]= \frac{217}{2}[/tex]
= 108.5 units
c. The optimal order per year
[tex]= \frac{annual\ demand}{economic\ order\ quantity}[/tex]
[tex]= \frac{6,100}{217}[/tex]
= 28 orders
d. The optima number of days is
[tex]= \frac{working\ days}{optimal\ number\ of\ orders}[/tex]
[tex]= \frac{250}{28}[/tex]
= 8.9 days
e. The total annual inventory cost is
= Purchase cost + ordering cost + carrying cost
where,
Purchase cost is
[tex]= \$6,100 \times \$101[/tex]
= $616,100
Ordering cost = Number of orders × ordering cost per order
= 28 orders × $31
= $868
Carrying cost = average inventory × carrying cost per unit
= 108.50 units × $8
= $868
So, the total would be
= $616,100 + $868 + $868
= $617,836
The average duration of labor from the first contraction to the birth of the baby in women over 35 who have not previously given birth and who did not use any pharmaceuticals is 16 hours. Suppose you have a sample of 29 women who exercise daily, and who have an average duration of labor of 17.8 hours and a sample variance of 77.4 hours. You want to test the hypothesis that women who exercise daily have a different duration of labor than all women. Calculate the t statistic. To do this, you first need to calculate the estimated standard error. The estimated standard error is s M
Answer:
There is not enough evidence to support the claim that women who exercise daily have a significantly different duration of labor than all women.
Standard error sm = 1.634
Test statistic t = 1.102
P-value = 0.28
Step-by-step explanation:
This is a hypothesis test for the population mean.
The claim is that women who exercise daily have a significantly different duration of labor than all women.
Then, the null and alternative hypothesis are:
[tex]H_0: \mu=16\\\\H_a:\mu\neq 16[/tex]
The significance level is 0.05.
The sample has a size n=29.
The sample mean is M=17.8.
As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=√77.4=8.8.
The estimated standard error of the mean is computed using the formula:
[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{8.8}{\sqrt{29}}=1.634[/tex]
Then, we can calculate the t-statistic as:
[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{17.8-16}{1.634}=\dfrac{1.8}{1.634}=1.102[/tex]
The degrees of freedom for this sample size are:
[tex]df=n-1=29-1=28[/tex]
This test is a two-tailed test, with 28 degrees of freedom and t=1.102, so the P-value for this test is calculated as (using a t-table):
[tex]\text{P-value}=2\cdot P(t>1.102)=0.28[/tex]
As the P-value (0.28) is bigger than the significance level (0.05), the effect is not significant.
The null hypothesis failed to be rejected.
There is not enough evidence to support the claim that women who exercise daily have a significantly different duration of labor than all women.