2
Which expression is equivalent to 7a^3(6a^2+a)^2-4a^6?

Answer:25

Step-by-step explanation:

Answer:

I think it is 3x-7y=-28

Answer:

2

Step-by-step explanation:

Slope equation: (y2-y1)/(x2-x1)

y2 = 4, y1 = -2, x2= 5, x1 = 2

4 – -2 = 6

5 - 2=3

6/3 = 2

Answer:

50

Step-by-step explanation:50 is the right answer!!

Answer:

Step-by-step explanation:

From the question,

Hence, she worked for a total of (14 + 2 + 13 + 3) hours.

(14 + 2 + 13 + 3) hours = 32 hours

Hence, she worked for a total of 32 hours last week.

To calculate the amount of money Hannah earns per hour for walking dogs, that will be

$93 ÷ 32 hours = $2.9/hour

Hence, Hannah earns $2.9 per hour for walking dogs

For the equation that can be used to determine the amount of money, m, Hannah earns when she works h hours walking dogs,

If she works h hours for working dogs, then she will earn

$2.9 × h = $2.9h

Hence,

m = $2.9h

Where m is the amount of money Hannah earns in dollars

and h is the number of hours she spends walking dogs.

Answer:

5/12

Step-by-step explanation:

i just looked it up...

====================================================

Explanation:

Multiply top and bottom of 5/8 by 3 to get 15/24

This means 5/8-5/24 is the same as 15/24-5/24

The denominators are the same, so we can subtract the numerators to have them placed over the common denominator

15/24 - 5/24 = (15-5)/24 = 10/24

Then we reduce by dividing each part of the fraction by the GCF 2

10/2 = 5

24/2 = 12

Meaning that 10/24 = 5/12

Note how multiplying top and bottom of 5/12 by 2 leads to 10/24 again.

So overall,

5/8 - 5/24 = 5/12

Answer:

[tex]A = 97.50 + H[/tex]

Step-by-step explanation:

Given

Stocks: AT&T and IBM HockUnx

Required

Determine the algebraic expression

Represent AT&T with A and IBM HockUnx with H.

Since AT&T is 97.5 more than IBM HockUnx;

The required expression is:

[tex]A = 97.50 + H[/tex]

Answer:  y=759

Step-by-step explanation:

y = (25 - 2) (35 - 2)

y = (23) (33)

y = 759

Answer:

y = 759

Step-by-step explanation:

subtract the numbers

y = 23 (35 - 2)

y = 23 x 33

Multiply the numbers

y = 759

Solution

y = 759

Answer:

Step-by-step explanation:

The number of rectangles and combinations:

Total

Now the number of,

Rectangles and combinations are,

→ 1 rectangle = 6

→ 2 rectangles = 5

→ 3 rectangles = 4

→ 4 rectangles = 3

→ 5 rectangles = 2

→ 6 rectangles = 1

Then the total number is,

→ 6+5+4 + 3+2+1

→ 15 + 6 = 21

Hence, total number is 21.

Answer:

a

Step-by-step explanation:

Answer:

he can make 6 goodie bags

Step-by-step explanation:

Answer:

6.532 x 10^-9

Step-by-step:

1. 0.000000006532

2. move the decimal to where the first number is greater than or equal to 1 and less than 10. In this case we move the decimal to the right 9 times. You will get 6.532

3. We moved the decimal to the right meaning the power to 10 would be a negative number. The number is how many times we moved the decimal by 1 spot, in this problem we moved it 9 times. 6.532 x 10^-9 is what you should get for scientific notation

Answer:

[tex]x = 4y[/tex]

Step-by-step explanation:

Given

[tex]y = kx[/tex]

See attachment for options.

Required

Determine which of the options answers the question

Analyzing the option one after the other:

[tex]\frac{x}{y} = 4[/tex]

Multiply through by y

[tex]y * \frac{x}{y} = 4 * y[/tex]

[tex]x = 4y[/tex]

Divide through by 4

[tex]\frac{x}{4} = \frac{4y}{4}[/tex]

[tex]\frac{x}{4} = y[/tex]

This can be rewritten as

[tex]y = \frac{x}{4}[/tex]

[tex]y = \frac{1}{4} x[/tex]

By comparison with [tex]y = kx[/tex]

we have:

[tex]y = y[/tex]

[tex]x = x[/tex]

[tex]k = \frac{1}{4}[/tex]

Hence: this answers the question.

Answer:

x= 4.3125

Step-by-step explanation:

Answer:

x=4+7i and x=4-7i

Step-by-step explanation:

Rewrite the given quadratic equation by completing the square.

x^2-8x=-65

x^2-8x+16=-65+16

x^2-8x+16=-49

(x-4)^2=-49

Now, solve the equation by applying the square root property and isolating x.

(x-4)^2=-49

√(x-4)^2 = √-49

x-4=+7i

x=4+7i

So, the solutions to the given quadratic equation are x+4+7i and x=4-7i.

Step-by-step explanation:

Given data

Let the cheese be x

And strawberry be y

So

6x+6y=96-------1

x+4y=52----------2

Solving 1 and 2 simultaneously

Let us multiply equation 2 by 6 we have

6x+6y=96

6x+24y=312

-0-18y=-216

18y=216

y=216/18

y=12

Put y=12 in equation 2

x+4*2=52----------2

x+8=52

x=52-8

x=44

cheese =44

strawberry =12

Answer:will hope it help to find the answer with an unqualified

Step-by-step explanation:

Answer:

y=sin2x+3

Step-by-step explanation:

Answer:

yes also what is the question

Answer:

21/4 x 51/2 - k use the app Photomate if wrong

========================================================

Explanation:

Consider a triangle with side lengths a,b,c such that a < b < c

a = 3 and b = 19 are the two known sides

Let c be the missing side length

The missing side has the property that...

b-a < c < b+a

19-3 < c < 19+3

16 < c < 22

Meaning that if c is a whole number then it can take on any of these values {17, 18, 19, 20, 21}

So c = 21 is the largest possible third side, where only whole number sides are considered.

We can't have a third side of 22 because the two other sides add to a+b = 3+19 = 22 and a triangle wouldn't form (instead only a straight line would). I recommend cutting out strings of paper trying this out yourself.

---------------

Side note: The inequality b-a < c < b+a is a variation of the triangle inequality theorem.

Answer:

15

Step-by-step explanation:

y +15-8 =22

y +15 =22 +8

y +15 =30

y =30-15

y=15

Answer:

b y= 3x+6 is the ans but not sure

Answer:

y=-1.9x-1

Step-by-step explanation:

i'm not sure how much the lanes are, so i'm gonna list the prices of pairs of shoes so you can just add the price of the lanes and find the answer:

1 pair - 2.95

2 pairs - 5.90

3 pairs - 8.85

4 pairs - 11.80

5 pairs - 14.75

6 pairs  - 17.70

7 pairs - 20.65

8 pairs - 23.60

(thats the highest amount of shoes he could get)

Answer:

C.50

Step-by-step explanation:

It would be 50 because there are 2 sides to the coin. So if you take 100/2 you get 50. that would be the best estimate answer in my opinion

Number of times the coin will land heads will be 50

Number of trials or observation when each trial has the same probability of attaining one particular value. It determines the probability of observing a specified number of successful outcome in a specific number of trial.

Here , number of times the coin had tosses: 100

P(probability of getting a head in a coin ) : number of time head can come when flipped once / total number of observations

 since , head can come once and there are two possibility either head or tail

hence P= 1/2

this implies number of times heads land up = n*P = 100 *(1/2) = 50

option c) 50

Let us learn more about binomial distribution:

https://brainly.com/question/13634543?referrer=searchResults

#SPJ2

Answer:

Step-by-step explanation:

The weights in pounds of the defensive linemen were :

254,311, 297, 323, 260, 242, 300, 252, 303, 274

Ascending order: 242 ,252 ,254 ,260 ,274 ,297 ,300 ,303 ,311 ,323

The weights in pounds of the offensive linemen were :

310 ,315, 305, 318, 298, 301, 321, 332, 320

Ascending order:298 ,301 ,305 ,310 ,315 ,318 ,320 ,321 ,332

a)

Offensive line       Stem        Defensive line

                               24     |            2

                               25     |            2 , 4

                               26     |            0

                               27     |            4

         8             |      29     |           7

      1,5              |      30     |           0,3

     0,5,8           |      31      |           1

     0,1               |      32     |           3

      2                |      33     |

Five number summary of offensive line:

1) minimum: 298

2) maximum: 332

3)

Lower quartile:298 ,301 ,305 ,310

Q1 is the median of lower quartile

[tex]Q1=\frac{301+305}{2}=303[/tex]

4)

Upper quartile:318 ,320 ,321 ,332

Q3 is the median of upper quartile

[tex]Q3=\frac{320+321}{2}=320.5[/tex]

5)

Q2 is the median

 298 ,301 ,305 ,310 ,315 ,318 ,320 ,321 ,332

Mid value =[tex]\frac{9+1}{2}[/tex]=5th term = 315

Q2=315

Five number summary of defensive line:

1) minimum: 242

2) maximum: 323

3)

Lower quartile:242 ,252 ,254 ,260 ,274

Q1 is the median of lower quartile

Q1=254

4)

Upper quartile:297 ,300 ,303 ,311 ,323

Q3 is the median of upper quartile

Q3=303

5)

Q2 is the median

 242 ,252 ,254 ,260 ,274 ,297 ,300 ,303 ,311 ,323

Mid value =\frac{274+297}{2}=285.5

Q2=285.5

c) Mean weight of offensive line = [tex]\frac{298+301+305+310+315+318+320+321+332}{9}=313.33[/tex]

Mean weight of defensive line = [tex]\frac{242+252+254+260+274+297+300+303+311+323}{10}=281.6[/tex]

Mean weight of offensive line is more

So, Offensive group of players tends to be heavier

Answer:

D

Explanition:

Answer:

x=2

Step-by-step explanation:

12=12 2=2

the sides have the same x