3 ÷ 6/7 i really need help! i will give you brainliest pls HELP​

Answer:

59 Degrees!!

Step-by-step explanation:

Answer:

59°

Step-by-step explanation:

180 - (57 + 64) =

180 - 121 = 59

Answer:

4.332 x 10 to the 3 power I do believe

Step-by-step explanation:

Answer:

4.332 times 10^3

Step-by-step explanation:

ion kno if thats right but i tried.

Answer:

2nd) which is 4 multiplied by 5 multiplied by 2

Answer: 6 miles

Step-by-step explanation:

WEDNESDAY + FRIDAY (# OF MILES)

The Miles Covered by Each Lap = 3x

The Miles on Top of That = 6

TUESDAY + SUNDAY (# OF MILES)

The Miles Covered by Each Lap = 5x

The Miles on Top of That = 2

You want to now put that into an equation! Therefore, you want to put the number of miles from Wednesday and Friday on one side and the number of miles from Tuesday and Sunday on the opposite side.

SOLVING EQUATION FOR MILES PER LAP

Step 1) 3x + 6 = 5x + 2

given equation from what we put together.

Step 2) -3x + 3x + 6 = 5x + 2 -3x

subtract 3x from both sides.

Step 3) -2 + 2x + 2 = 6 -2

subtract 2 from both sides.

Step 4) 2 × x = 4

divide both sides by 2 because you want to put the variable (x) on one side.

Step 5) x = 2 miles for each lap

Now you want to go look back at the equation and plug in 2 for the variable x.

Step 6) 5 ×2 + 2 = 12

PEMDAS!

Step 7) 12 ÷ 2 = 6

SHE RUNS 2 MILES ON SATURDAYS!

Dimensions of the rectangular box with largest volume if the total surface area is given as 4 cm² : (√2/3 , √2/3 ,√2/3)

Given, rectangular box with largest volume.

Let f(x , y , z) = xyz

Ф ≡ xy + yz + xz - 2  = 0

[tex]F =[/tex] [tex]f + \lambda[/tex][tex]\phi[/tex]

[tex]F = xyz + \lambda (xy + yz + xz - 2)[/tex]

[tex]F_x = 0\\yz + \lambda(y + z) = 0......1\\\\F_y = 0\\xz + \lambda(x+z)= 0......2\\\\F_z = 0\\xy + \lambda(x + y) = 0..........3[/tex]

xy + yz + xz - 2 = 0........4

Solving the above 4 equations,

[tex]yz + \lambda(y + z) = 0\\\lambda = -yz/(y+z)\\\\xz + \lambda(x + z) = 0\\\lambda = -xz / (x+z)[/tex]

Evaluating the lambda values,

x = y

Similarly, y = z

Therefore, x² + x² + x² - 2 = 0

x = √2/3

y = √2/3

z = √2/3

Hence, Dimensions : (x , y , z) = (√2/3 , √2/3 ,√2/3)

Know more about rectangle,

https://brainly.com/question/31663437

#SPJ4

The required height of the parallelogram is 2/3. Option B is correct.

Given that,
The area of a parallelogram is 24 square units. One side of the parallelogramis 36 units long. The other side is 4 units long. Which could be the parallelogram's height is to be determined.

A parallelogram is a quadrilateral consisting of pairs of parallel side.

Here,
We have given the area of the parallelogram and the measure of its base. So,
Area of the parallelogram = base * height
                                       24 = 36 * height
                                       height = 2 / 3

Thus, the required height of the parallelogram is 2/3. Option B is correct.
 

Learn more about parallelogram here:
https://brainly.com/question/14984005

#SPJ2

Answer:

1:11

Step-by-step explanation:

4(hearts):44(all) in simplest form is 1:11 because 4 and 44 are divisible by 4.

Answer:4:40

Step-by-step explanation:

Answer:

89

eighty-nine

Question:

The capacity of a dump truck is listed by the manufacturer as 10 yd^3. A construction site requires the removal of 200 m^3 of dirt, and the contractor has three identical trucks. How many trips will each need to make?

Answer:

7 trips

Step-by-step explanation:

Given

[tex]Capacity = 10yd^3[/tex]

[tex]Dirts = 200m^3[/tex]

[tex]Trucks = 4[/tex]

Required

Determine the number of trips of each truck

Divide the volume of dirts by 4 to get the portion of each truck

[tex]Each\ Truck = \frac{200m^3}{4}[/tex]

[tex]Each\ Truck = 50m^3[/tex]

Divide the portion of each truck by capacity of each truck to get the number of trip

[tex]Trip = \frac{50m^3}{10yd^3}[/tex]

Convert m^3 to yd^3

[tex]Trip = \frac{50 * 1.30795yd^3}{10yd^3}[/tex]

[tex]Trip = \frac{65.3975yd^3}{10yd^3}[/tex]

[tex]Trip = \frac{65.3975}{10}[/tex]

[tex]Trip = 6.53975[/tex]

Approximate:

[tex]Trip = 7[/tex]

Answer:

a.No, Common Bank will save Sharon more money.

Step-by-step explanation:

There are two banks i.e. first state bank and the common bank that should be compared in the table depend upon the prices of both the banks

On seeing it we get to know that the first state bank would charged a fee on a monthly basis i.e. $4 while on the other hand the common bank has no fee on the monthly basis

Also the unsufficient bonds are more cheaper in the common bank if we compared with the first state bank

Moreover, the $7 is charged in the first state bank and $3 charged in the common bank.

Therefore the common bank would become cheaper

Hence, the correct option is a.

Answer:

Sharon wants to open a checking account from which to pay bills. She wants online services, and a debit card, which both banks provide for free. Based upon past experience, she expects to accidentally overdraft the account 1 time per year, due to unexpected charges and miscommunications. She expects no 2nd copies of statements, and to use network ATMs 4 times per month with either bank. She has $3300 in an emergency savings account at First State Bank, and thinks that the balance will be enough to cover overdrafts in the future if automatic transfers are made when needed.

A 4-column table with 5 rows. Column 1 is labeled First State Bank with entries monthly fee, non-sufficient funds fee, second copy of statement, network A T M usage, non-sufficient funds protection from a First State Bank savings account. Column 2 is labeled Description with entries 4 dollars, 36 dollars, 7 dollars, 3 dollars each transaction, 4 dollars on each day that a transfer occurs to cover an overdraft. Column 3 is labeled Common Bank with entries monthly fee, non-sufficient funds, second copy of statement, network A T M usage, non-sufficient funds protection from a Common Bank savings account. Column 4 is labeled Description with entries 0 dollars, 24 dollars, 4 dollars, 2 dollars each transaction, not offered with this account.

Based on the tables of fees, above, if Sharon chooses First State Bank, will it save her money over choosing Common Bank?

Step-by-step explanation:

Edge 2021

Answer:

x =  - 2

Step-by-step explanation:

Distribute

4(x + 1) = -3x - 10

4x + 4 = -3x - 10

Subtract 4  from both sides of the equation

4x + 4 = -3x - 10

4x + 4 − 4 = −3x − 10 − 4

Simplify

Subtract the numbers

4x+4−4=−3x−10−4

4  =  − 3  − 1 0  −  4

Subtract the numbers  again

4  =  −  3  −  14

Add  3x  to both sides of the equation

4  =  −   3 x  −  1 4

4 + 3 = − 3 − 1 4 + 3

Simplify

Combine like terms

4 + 3 = -3x-14+3x

7x =−3x−14+3x

Divide both sides of the equation by the same term

7 = − 1 4

7 /7 = -14/7

Cancel terms that are in both the numerator and denominator

7x/7 = -14/7

x = -14/7

Divide the numbers

 =  − 1 4 /7

=  − 2

Answer:

450

Step-by-step explanation:

9+6= 15

90/3= 30

30*15=450

Answer:

it will cost 5.99

Step-by-step explanation:

because each person getting half and there are 2 peeps so add up the meet to make on pound

Step-by-step explanation:

A.

Cost of 4 lots for $48,000= 48000*4

=$192,000

Sales made from all 7 lots = 33000*7

= $213,000

Profit =213,000-192,000

Profit =$39,000

Percent profit =(39000/192000) *100

=0.20*100

=20%

B.

Total interest formula=

Principal Loan Amount x Interest Rate x Time

Interest =30000x0.12x5

Interest = $18,000

Monthly payments for 5 years

= 18000/12*5

=18000/60

=$300

Answer:

(g-f)(x)

Step-by-step explanation:

You have to subtract expenses from revenue and multiply by yarn to equal profit

Answer:

0.8046

Step-by-step explanation:

We're asked to calculate the probability that the job will be ready by 1.01 pm

From the question, we can note that the parameter of an Exponential is E(X)= 15

Next, to calculate the third job probability, we will have to use Poisson Distribution with parameter 1/λ

Therefore, E(Y) = 1/15

Then, The third job will be ready for 1:01 pm, and thus E(Y) = 61/15

Therefore, the required probability is

P(X ≥ 3) = 1 - P(X < 3)

= 1 - Poisson(3,4, true)

= 1 - 0.1954

= 0.8046

Answer:

1044 girls in the school

Step-by-step explanation:

3/5*2610=1566 boys

2610-1566-1044 girls

it should be 1044 because

3/5=.6 or 60%boys and 40% girls

2610 * 60% or .6 = 1566 boys

2610 - 1566boys = 1044 girls

or

2610 * 40% or .4 = 1044 girls

so there are 1044 girls at the school

The correct and complete question is shown below;

The random variable X denotes the GMAT scores of MBA students who were accepted to top MBA programs in Fall 2012. Assume that is normally distributed with a mean [tex]\mu_x[/tex] = 675 and a standard deviation [tex]\sigma_x = 30[/tex]

Typically, an MBA student who has a GMAT score above 710 is eligible for financial support. Given that a student is eligible for financial support, what is the probability that the student’s GMAT score is higher than 725?

Answer:

The probability that the student's GMAT score is higher than 725 = 0.3928

Step-by-step explanation:

From the given information:

Let X be the random variable that follows a normal distribution;

Then;

[tex]X \sim N( \mu_x = 675, \sigma_x = 30)[/tex]

To objective is to determine the probability that [tex]P(X > 725 | X > 710)[/tex]

[tex]P(X > 725 | X > 710)= \dfrac{P(X > 725 \cap X > 710 )}{P(X > 725)}[/tex]

[tex]\dfrac{P(X > 725 )}{P(X > 710)}=\dfrac{1 - P(X < 725) }{1- P(X < 710)}[/tex]

By using the EXCEL FORMULA:  [tex]"= NORMDIST(x, \mu_x , \sigma_x , 1)"[/tex]

P(X< 725) = [tex]" = NORMDIST(725,675,30,1)"[/tex]

P(X< 725) = 0.9522

P(X< 710) = [tex]" = NORMDIST(710,675,30,1)"[/tex]

P(X< 710) =0.8783

[tex]P(X > 725 | X > 710)=\dfrac{1 - 0.9522}{1- 0.8783}[/tex]

[tex]P(X > 725 | X > 710)=\dfrac{0.0478}{0.1217}[/tex]

[tex]P(X > 725 | X > 710)=0.3928[/tex]

Answer:

567 miles

Step-by-step explanation:

9 hours x 63 miles per hour = 567 miles total

Answer:

[tex]y = Acos5x - Bsin5x[/tex]

Step-by-step explanation:

Given the differential equation y''-10y'+29y=0

First, we need to rewrite it as an auxiliary equation as shown:

Let y'' = m²y and y' = my

Substitute the values into the general equation

m²y-10my+29y = 0

Factor out y:

(m²-10m+29)y = 0 [The auxiliary equation]

Solve the auxiliary equation and find the roots of the equation

m²-10m+29 = 0

m = -b±√(b²-4ac)/2a

a = 1, b = -10, c = 29

m = -10±√(10²-4(1)(29))/2(1)

m = -10±√(100-116)/2

m = -10±√-16/2

m = (-10±4i)/2

m = -10/2 + 4i/2

m = -5+2i

Comparing the complex number with a+bi, a = -5 and b = 2

The general solution for complex solution is expressed as:

[tex]y = Acosax + Bsinax[/tex]

Substitute the value of a in the equation

[tex]y = Acos(-5)x + Bsin(-5)x\\y = Acos5x-Bsin5x[/tex]

Hence the general solution to the differential equation is [tex]y = Acos5x - Bsin5x[/tex]

Answer:

The function written in python is as follows:

import random

def simulate():

    count = 0

    for i in range(1,51):

         num = random.randint(200,1000)

         if num == 781:

              count = count + 1

    print(count)

Step-by-step explanation:

This line imports the random library

import random

This line defines the function

def simulate():

This line initializes count to 0

    count = 0

This line iterates from 1 to 50

    for i in range(1,51):

This line generates random number between 200 and 999

         num = random.randint(200,1000)

This line checks if random number is 781

         if num == 781:

If yes, the count variable is incremented by 1

              count = count + 1

This line prints the number of times 781 is generated

    print(count)

Answer:

turn it into an improper fraction then subtract

Step-by-step explanation:

5×6=30

30+1=31

31/6

3×6=18

18+5=21

21/6

31/6 - 21/6 = 10/6

simplify: 5/3 ♡

I'm not sure tho lol

Answer:

i think its B

Step-by-step explanation:

Ants

Step-by-step explanation:

The probability that the second pipe (with length Y) is more than 0.11 feet longer than the first pipe (with length X) is approximately 2.6092%.

Here,

Since the length of the pipes follows a uniform distribution on the interval [10 feet, 10.57 feet], the probability density function (PDF) for each pipe is:

f(x) = 1 / (10.57 - 10) = 1 / 0.57 ≈ 1.7544 for 10 ≤ x ≤ 10.57

Since the lengths of the pipes are independent, the joint probability density function (PDF) of X and Y is the product of their individual PDFs:

f(x, y) = f(x) * f(y) = 1.7544 * 1.7544 = 3.0805 for 10 ≤ x ≤ 10.57 and 10 ≤ y ≤ 10.57

Now, we want to find the probability that the second pipe (Y) is more than 0.11 feet longer than the first pipe (X).

Mathematically, we want to find P(Y > X + 0.11).

Let's set up the integral to calculate this probability:

P(Y > X + 0.11) = ∬[10 ≤ x ≤ 10.57] [y > x + 0.11] f(x, y) dx dy

We integrate with respect to x first and then with respect to y:

P(Y > X + 0.11) = ∫[10 ≤ y ≤ 10.57] ∫[10 ≤ x ≤ y - 0.11] f(x, y) dx dy

P(Y > X + 0.11) = ∫[10 ≤ y ≤ 10.57] [∫[10 ≤ x ≤ y - 0.11] 3.0805 dx] dy

P(Y > X + 0.11) = ∫[10 ≤ y ≤ 10.57] [3.0805 * (x)] from x = 10 to x = y - 0.11 dy

P(Y > X + 0.11) = ∫[10 ≤ y ≤ 10.57] [3.0805 * (y - (10 - 0.11))] dy

P(Y > X + 0.11) = 3.0805 * ∫[10 ≤ y ≤ 10.57] (y - 9.89) dy

P(Y > X + 0.11) = 3.0805 * [(y² / 2) - 9.89y] from y = 10 to y = 10.57

P(Y > X + 0.11) = 3.0805 * [((10.57)² / 2) - 9.89 * 10.57 - (((10)² / 2) - 9.89 * 10)]

P(Y > X + 0.11) = 3.0805 * [((111.7249 / 2) - 104.9135 - (50 / 2 - 98.9)]

P(Y > X + 0.11) = 3.0805 * [(55.86245 - 104.9135 + 49.9)]

P(Y > X + 0.11) = 3.0805 * [0.84895]

P(Y > X + 0.11) ≈ 2.6092

Therefore, the probability that the second pipe (with length Y) is more than 0.11 feet longer than the first pipe (with length X) is approximately 2.6092%.

To learn more on probability click:

brainly.com/question/11234923

#SPJ4

Answer:

1. Rational Algebraic Expression

2. 0

3. See explanation

Step-by-step explanation:

Solving (1):

From the list of given options, Option C. Rational Algebraic Expression answers the question.

And it is always of the form P/Q where P and Q are polynomials

Take for instance

P = x² - x + 2 and Q = x² + 2x - 4

P/Q = (x² - x + 2)/(x² + 2x - 4)

The above expression is a perfect example of a Rational Algebraic Expression

Solving (2): The denominator of a rational algebraic expression must not equal 0

Hence, option A answers the question

Solving (3): The options are missing.

However, a perfect example has been sighted on (1) above