Answer:
Since this is means data and we do not know the populations standard deviation, a t-interval
needs to be used. The justification is found in checking the conditions needed for a t-interval. The
problem stated it was a random sample so we will assume this is sufficient. Since the sample size is
slightly under 30, we will still check for the data being roughly normal. Either a boxplot or normal
probability plot would suffice. In both cases there is no reason to doubt the sample data are roughly
normally distributed so we can proceed to the calculations.
The interval would be (69, 76)
Explanation:
Hope this helps if this happens to be wrong tell me
ㅤ ㅤ ㅤ ㅤ ㅤ ㅤ ㅤ ㅤ ㅤ ㅤ ㅤ ㅤ ㅤ ㅤ ㅤ ㅤ
Answer:
ok
Explanation:
A card is drawn from a pack of 52 cards. What is the
probability that the card will be odd numbered?
Answer:
more infromation
Explanation:
Determine the area under the standard normal curve that lies to the left (a) Z= 1.34, (b) The area to the left of 2 = – 0.25 is (Round to four decimal places as needed.) (c) The area to the left of Z = 1.66 is 0.949 (Round to four decimal places as needed.)
The areas under the standard normal curve is determined as follows:
(a) Using a standard normal distribution table, the area to the left of Z = 1.34 is 0.9099. (to four decimal places)
(b) Using a standard normal distribution table, the area to the left of Z = -0.25 is 0.4013 (to four decimal places)
(c) Using a standard normal distribution table, the area to the left of Z = 1.66 is 0.9515 (to four decimal places).
What does Area under the Standard Normal Curve mean and why is it important?The area under the standard normal curve represents the probability of a standard normal variable taking a value within a certain range.
It is important because it allows us to calculate probabilities and make statistical inferences using the standard normal distribution, which is a fundamental concept in statistical analysis. It is also used in many fields such as finance, engineering, and social sciences to model and analyze data.
One real-life application of the standard normal curve is in finance, where it is used to model stock prices and calculate the probabilities of different investment outcomes.
Learn more about Normal Curve on:
https://brainly.com/question/28330675
#SPJ1
A good study group moderator will
Ask a strong opening question
b. Keep the group discussion on track
c. Validate group member statements
d. All of these
e. None of these
Please select the best answer from the choices provided
Answer:
D
Explanation:
i did the test
The parallelogram shown below has an area of
60 units?
b
10
11
Find the missing base.
b=
units
Answer:
81 units po
Explanation:
sana makatulong
In which type of US election is it possible for the winning candidate to get fewer popular votes than the opposing candidate
A. most state government elections
B. House elections
C. Senate elections
D. most local government elections
E. presidential elections
Answer:
The correct answer is E)Presidential elections.
The presidential election is not determined by popular vote. Rather, it is determined by a system known as the electoral college. The electoral college system involves each state having a certain number of electoral votes roughly based on their population size. In this system, states with larger populations have more electoral votes.
In the electoral college, a candidate must receive 270 electoral votes in order to become president. If a candidate reaches this threshold they win, regardless of the popular vote results.
All of the other elections mentioned in the answer choices are determined by popular vote.
Explanation:
Answer: Presidential Elections
Explanation:
What must students do with the 10 grid-ins on the math section of the PSAT?
A. Mark the correct answer on a grid
B. Mark the incorrect answer on a grid
C. Arrive at an answer by creating a grid
D. Arrive at an answer and put it in a grid
An action which students must do with the 10 grid-ins on the math section of the PSAT is to: D. arrive at an answer and put it in a grid.
What is PSAT?PSAT is an acronym for Preliminary Scholastic Aptitude Test and it can be defined as type of multiple-choice test that is designed and developed to test the knowledge of high school students on a particular subject.
This ultimately implies that, an action which students must perform with the 10 grid-ins on the math section of the PSAT is to arrive at an answer and put it in a grid.
Read more on PSAT here: https://brainly.com/question/496200
#SPJ2
A restaurant serviced 730 customers at the first week and
696 customers at the second week. If the difference between
the first week and the second week is 4% of the third week,
how many customers did the restaurant service at the third
week?
ANSWER:
850customers were served in the third week.
Explanation:
First week = 730 customers
Second week = 696 customers
Difference between the first and second week = 730 - 696
= 34
4/100 x (customers served in the third week) = 34
4 x customers served in the third week = 34 x 100
4 x customers served in the third week = 3400
customers served in the third week = 3400/4
customers served in the third week = 850
The television show began at 10:00 P.M. and ended at 10:30 P.M. How long did the television show last
Hepepepepepep yoooo so
Helppp
Answer:
bru
Explanation:
This data set shows the ages of the last 12 winners of a
prestigious film award for Actress in a Leading Role.
61, 32, 33, 45, 29, 62, 22, 44, 54, 26, 28, 60
Calculate the statistics of mean and standard deviation
of the data set. Round to the nearest hundredth, if
necessary.
O mean 38.50 and standard deviation - 14.89
O mean 38.50 and standard deviation = 40
O mean = 41.33 and standard deviation = 40
mean 41.33 and standard deviation - 14.89
Answer:
D. mean is 41.33, and standard deviation is 14.89
Explanation:
Given the data set: 61, 32, 33, 45, 29, 62, 22, 44, 54, 26, 28, 60 of 12 winners.
i. The mean of the data set = [tex]\frac{sum of data set}{number of data set}[/tex]
= [tex]\frac{61 + 32 + 33 + 45 + 29 + 62 + 22 + 44 + 54 + 26 + 28 + 60}{12}[/tex]
= [tex]\frac{496}{12}[/tex]
= 41.3333
The mean of the data set = 41.33
ii. Standard deviation = [tex]\sqrt{\frac{Sum(x_{i} - U) ^{2} }{N} }[/tex]
Where: [tex]x_{i}[/tex] is the value of each data set given, U is the mean, N is the number of data set.
Sum ([tex]x_{i}[/tex] - U) = [tex](61 - 41.33)^{2}[/tex] + [tex](32 - 41.33)^{2}[/tex] + [tex](33 - 41.33)^{2}[/tex] + [tex](45 - 41.33)^{2}[/tex] + [tex](29 - 41.33)^{2}[/tex] + [tex](62 - 41.33)^{2}[/tex] + [tex](22 - 41.33)^{2}[/tex] + [tex](44 - 41.33)^{2}[/tex] + [tex](54 - 41.33)^{2}[/tex] + [tex](26 - 41.33)^{2}[/tex] + [tex](28 -41.33)^{2}[/tex] + [tex](60 - 41.33)^{2}[/tex]
= 386.91 + 87.05 + 69.39 + 13.47 + 152.03 + 427.25 + 373.65 + 7.13 + 160.53 + 235.01 + 177.69 + 348.57
= 2438.68
Standard deviation = [tex]\sqrt{\frac{2438.68}{12} }[/tex]
= 14.26
Therefore, the statistics mean is 41.33 and standard deviation is 14.89
Answer:
D
Explanation:
Guidewords are located at the bottom of a dictionary page.
Please select the best answer from the choices provided
T
F
(Answer is false.)
Answer:
Why are you giving us the answer..?
Answer:
FALSE
Explanation:
edg 2021
A population of values has a normal distribution with μ = 21.9 μ = 21.9 and σ = 47.4 σ = 47.4 . You intend to draw a random sample of size n = 96 n = 96 . Find the probability that a single randomly selected value is between 12.7 and 20.4. P(12.7 < X < 20.4) = Find the probability that a sample of size n = 96 n = 96 is randomly selected with a mean between 12.7 and 20.4. P(12.7 < M < 20.4) = Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
Answer:
Olá, boa tarde. Caso precise, estou a disposição para a realização de trabalhos acadêmicos, entre em contato comigo, Fernanda 21994321300
Explanation: