Answer:
lícita; de navegar y comerciar; de peticionar a las autoridades; de entrar, permanecer, transitar y salir del territorio argentino; de publicar sus ideas por la prensa sin censura
11. A bowling ball has a mass of 7 kg and a velocity of 3 m/s.
(A) What is the ball's momentum?
Answer: 21 kg x m/s
Momentum can be found using the equation p = mv, or momentum = mass times velocity.
Therefore, to find the momentum of the bowling bowl, you can plug the mass and velocity values into the equation to get p = (7kg)(3m/s)
Solve the equation to get a momentum of 21kg x m/s
I hope I could help :)
A water rocket of mass 2.5 kg is launched vertically upwards from the surface of the Earth. It produces a steady thrust of 75 N. What is its acceleration?
Answer:
a = 30 [m/s²]
Explanation:
To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration. In this way, we have the following equation.
∑F = m*a
where:
m = mass = 2.5 [kg]
a = acceleration [m/s²]
F = force = 75 [N]
Now replacing:
[tex]75=2.5*a\\a=75/2.5\\a=30[m/s^{2} ][/tex]
An airplanes velocity has an x-component of -155 mph and a y-component of -45 mph. What are the magnitude and direction of the plane's velocity
Answer:
161.4 mph due southwest
A 2000 Kg car is driving 15 m/s. It drives head-on into a giant spring attached
to a brick wall. The spring compresses 8 meters after the impact. What is the
spring coefficient of the giant spring? *
Answer:
The spring constant is k=7031.25
Explanation:
We start by using the conservation of mechanical energy:
Ui + Ki = Uf + Kf
the Ui (initial potential energy) is zero since the spring is relaxed.
In the final situation, the Kf (final kinetic energy is zero since the car and spring are NOT in motion)
Then we have:
[tex]K_i=U_f\\\frac{1}{2} m*v^2=\frac{1}{2} k*(\Delta x)^2\\\frac{1}{2} 2000*15^2=\frac{1}{2} k*(8)^2\\k=7031.25[/tex]
Ans: 10.0096 cm
What should be the initial lengths of steel and copper rods so that the length of steel rod is 5 cm
larger than the copper rod at all temperatures?
An iron sphere has a radius of 10 cm at a temperature of 0°C. Calculate the change in volume of the
Ans: 1.383 cm
sphere it is heated 100°. 9.3710-
Ans: 17 cm, 12 cm
Answer:
dab is the answerjdjdjnejee
A student carries a backpack for one mile , another student carries the same back pack for two miles . Compared to the first student , how much work did the second student do ?
Answer:
he did twice as much since the first student carried the backpack for 1 mile whilst the second one carried it for 2 miles
Explanation:
Answer:
2miles-1mile
the second person carried the for one mile longer.
So as your sentence you would sat
Compared to the first person the second person carried the backpack one mile longer.
What is the momentum of a 1.5 * 10 ^ 3 - kil kilogram car as it travels at 30. meters per second due east for 60. seconds ?
Answer:
45000kgm/s due east
Explanation:
Given parameters:
Mass of the car = 1.5 x 10³kg
Velocity = 30m/s
Time taken = 60s
Unknown:
Momentum = ?
Solution:
Momentum is the quantity of motion a body possess,
Momentum = mass x velocity
So;
Momentum = 1.5 x 10³ x 30 = 45000kgm/s due east
can somewon help me with this qustion?
Mercury is a liquid metal having a density of 13.6 g/mL. What is the
volume of 0.45 kg of mercury metal?
Answer:
[tex]\boxed {\boxed {\sf v \approx 33.088 \ mL}}[/tex]
Explanation:
The formula for density is:
[tex]d= \frac{m}{v}[/tex]
where m is the mass and v is the volume.
The mass is 0.45 kilograms and the density is 13.6 grams per milliliter. The density is given in grams, so we must convert the mass.
There are 1000 grams in 1 kilogram or [tex]\frac{1000 \ g} {1 \ kg}[/tex]. We can multiply the mass by this ratio.
[tex]0.45 \ kg * \frac{1000 \ g} {1 \ kg} = 0.45 * 1000 \ g = 450 \ g[/tex]
Now we have values for the mass and density:
[tex]13.6 \ g/mL =\frac{450 \ g}{ v}[/tex]
Cross multiply.
[tex]\frac {13.6 \ g/mL}{1} =\frac{450 \ g}{ v}[/tex]
[tex]13.6 \ g/mL * v=450 \ g * 1 \\13.6 \ g/mL * v=450 \ g[/tex]
We are trying to find the volume, so we must isolate that variable.
13.6 and v are being multiplied. The inverse of multiplication is division. Divide both sides by 13.6
[tex]\frac {13.6 \ g/mL*v } { 13.6 \ g/mL} = \frac{ 450 \ g} {13.6 \ g/mL}[/tex]
[tex]v= \frac{ 450 \ g} {13.6 \ g/mL}[/tex]
The grams will cancel.
[tex]v= 33.0882353 \ mL\\v \approx 33.088 \ mL[/tex]
The volume is about 33.088 milliliters.
HELP!!!!!
Explain how the sea star reproduce and why the fisherman returned to more sea stars. (page 29 - 32) (book in case needed: california inspire science reproduction of organisms grade 6 integrated unit 2 student edition) (Two parts for full points - 10 points for how the sea star reproduces including what it is called and 10 points to explain why the fisherman found more stars.) <----- That is part of a question not the points i can give you,
Answer:
A sea star that has the ability to regenerate amputated limbs must first undergo a repair phase to heal the exposed wound. Once the wound is healed, the sea star can begin to generate new cells, which in turn, sparks new growth. Regeneration can take anywhere from several months to years. Reproduction: Sea stars are broadcast spawners. Males release sperm into the water and females release eggs. The fertilized eggs hatch into a larval form that lives as plankton, sometimes for months, before settling on the sea floor in its adult form..
Which does NOT affect how much a building shakes in an earthquake?
*If it is on soft sediment or hard rock.
*How close it is to the fault.
*If it is in a valley or on a hill.
*The weather.
*How the building is constructed.
If an object is not moving, does that mean there are no forces acting up on it? Why or why not?
Answer:
If an object is at rest, then there are no forces acting upon the object.
Explanation:
It would take an unbalanced force to keep an object in motion at a constant velocity. It is the natural tendency of all objects to eventually come to a rest position.
A 5Kg ball rolling to the right at a velocity of 5m/s hits a stationary 10Kg ball. It is an elastic collision and the final velocity of the 5Kg ball is 0m/s. What is the final velocity of the 10Kg ball?
Answer:
magnitude of v = 2.5 m/s, and in the same direction as the initial velocity of the 5 kg ball.
Explanation:
We use conservation of linear momentum in an elastic collision to solve for the unknown velocity v:
Pi = Pf
5 kg * 5 m/s + 10 kg * 0 m/s = 5 kg * 0 m/s + 10 kg * v
25 kg m/s = 10 kg * v
v = 25/10 m/s
v = 2.5 m/s
and in the same direction as the initial velocity of the 5 kg ball.