DNA fingerprinting would be helpful in a crime scene with blood because it was indicate whether the person was a victim or a victim's relative.
What is DNA fingerprinting?Paternity testing and other forensic applications as well as criminal investigations all make use of DNA fingerprinting.
In these cases, the goal is to "match" two DNA fingerprints, such as a DNA sample from a known person and one from an unknown person, with one another.
A chemical test called DNA fingerprinting can reveal a person's or another living thing's genetic makeup. It is used as testimony in court, to identify corpses, find blood relatives, and search for medical treatments.
Therefore, at a crime scene, it will be helpful to do DNA fingerprinting with any sample including blood, and hair.
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WILL GIVE BRAINLIEST
mutualism relates to which of the following relationships?
A. Both organisms benefit
B. One organism benefits; the other is harmed
C. Both organisms are harmed
D. Neither organisms benefit or is harmed
Answer:
A. Both organisms benefit
Explanation:
2. Write a word equation for the process of photosynthesis.
3. Why do plants test positive for starch?
modern scientific explanations of evolution
a. have replaced darwin’s thinking
b. combine the principles of natural selection and genetic inheritance
c. rely on genetics instead of natural selection
d. fail to explain how traits are inherited
Select ALL the correct answers.
A pitcher for a professional baseball team allows runs in the first nine games he starts this season. Let A be the set of the number of
runs allowed by the pitcher in his first nine starts.
A = {1, 4, 2, 2, 3, 1, 1, 2, 1}
In the tenth game he starts, he allows 9 runs. Let B represent the set of the number of runs allowed in all ten games he has started.
Select the true statements.
The median of B is 1 run more than the median of A.
The interquartile range of B is greater than the interquartile range of A.
The interquartile range of A is 1 less than the interquartile range of B.
The median of A is the same as the median of B.
Including the runs allowed in the tenth game does not cause the spread of the data to
change.
Answer:
(b) The interquartile range of B is greater than the interquartile range of A.
(d) The median of A is the same as the median of B.
Explanation:
Given
[tex]A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}[/tex]
[tex]10th\ run = 9[/tex]
So:
[tex]B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}[/tex]
Required
Select all true statements
(a) & (d) Median Comparisons
[tex]A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}[/tex] [tex]B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}[/tex]
[tex]n = 9[/tex] [tex]n = 10[/tex]
Arrange the data:
[tex]A = \{1, 1, 1, 1, 2, 2, 2,3, 4\}[/tex] [tex]B = \{1,1,1,1,2,2,2,3,4,9\}[/tex]
[tex]Median = \frac{n + 1}{2}th[/tex]
[tex]Median = \frac{9 + 1}{2}th[/tex] [tex]Median = \frac{10 + 1}{2}th[/tex]
[tex]Median = \frac{10}{2}th[/tex] [tex]Median = \frac{11}{2}th[/tex]
[tex]Median = 5th[/tex] [tex]Median = 5.5}th[/tex] --- average of 5th and 6th
[tex]Median = 2[/tex] [tex]Median = \frac{2+2}{2} = 2[/tex]
Option (d) is correct because both have a median of: 2
(b) & (c) Interquartile Range Comparisons
[tex]A = \{1, 1, 1, 1, 2, 2, 2,3, 4\}[/tex] [tex]B = \{1,1,1,1,2,2,2,3,4,9\}[/tex]
[tex]n = 9[/tex] [tex]n = 10[/tex]
First, calculate the lower quartile (Q1)
[tex]Q_1 = \frac{n + 1}{4}th[/tex][Odd n] [tex]Q_1 = \frac{n}{4}th[/tex] [Even n]
[tex]Q_1 = \frac{9 + 1}{4}th[/tex] [tex]Q_1 = \frac{10}{4}th[/tex]
[tex]Q_1 = \frac{10}{4}th[/tex] [tex]Q_1 = 2.5[/tex]
[tex]Q_1 = 2.5th[/tex]
This means that:
[tex]Q_1 = 2nd + 0.5(3rd - 2nd)[/tex] [tex]Q_1 = 2nd + 0.5(3rd - 2nd)[/tex]
[tex]Q_1 = 1 + 0.5(1- 1)[/tex] [tex]Q_1 = 1+ 0.5(1 - 1)[/tex]
[tex]Q_1 = 1[/tex] [tex]Q_1 = 1[/tex]
Next, calculate the upper quartile (Q3)
[tex]Q_3 = \frac{3}{4}(n + 1)th[/tex] [Odd n] [tex]Q_3 = \frac{3}{4}(n)th[/tex] [Even n]
[tex]Q_3 = \frac{3}{4}(9 + 1)th[/tex] [tex]Q_3 = \frac{30}{4}th[/tex]
[tex]Q_3 = \frac{30}{4}th[/tex] [tex]Q_3 = 7.5th[/tex]
[tex]Q_3 = 7.5th[/tex]
This means that:
[tex]Q_3 = 7th + 0.5(8th- 7th)[/tex] [tex]Q_3 = 7th + 0.5(8th- 7th)[/tex]
[tex]Q_3 = 2 + 0.5(3- 2)[/tex] [tex]Q_3 = 2+ 0.5(4 - 2)[/tex]
[tex]Q_3 = 2.5[/tex] [tex]Q_3 = 3[/tex]
The interquartile range is [tex]IQR = Q_3 - Q_1[/tex]
So, we have:
[tex]IQR = 2.5 - 1[/tex] [tex]IQR = 3 - 1[/tex]
[tex]IQR = 1.5[/tex] [tex]IQR =2[/tex]
(b) is true because B has a greater IQR than A
(e) This is false because some spread measures (which include quartiles and the interquartile range) changed when the 10th data is included.
The upper quartile and the interquartile range of A and B are not equal
What can you tell about bacteria that have been Gram stained?
A) Microscopic morphology
B) Macroscopic morphology
C) Gram reaction
D) A and C
Answer:
D) A and C
Explanation:
Gram staining is a laboratory technique used for bacterial species. It is used to differentiate between two groups of bacteria based on the components of their cell wall. Gram staining was developed by a scientist called Christian Gram in the year 1884. In the gram stain procedure, the following occurs:
- Due to the thick peptidoglycan component of their cell wall, GRAM POSITIVE bacteria retains the crystal violet due and stain VIOLET.
- On the contrary, due to the thin peptidoglycan component of their cell wall, GRAM NEGATIVE bacteria do not retain the crystal violet dye and hence stain, RED.
Based on this, a bacteria that has been gram stained has been tested for its GRAM REACTION and microscopic morphological characteristics, since it is a microbe.
Please answer the three questions. ☺️
d) Out of the 16 possible outcomes, how many have to yellow leaves?
e) Out of the 16 possible outcomes, how many have green leaves?
f)Out of the 16 possible outcomes, how many have green leaves and rough
seeds?
Answer:
12 out of 16 have yellow leaves
4 out of 16 have green leaves
1 out of 16 has green leaves and rough seeds
Explanation:
<3
The answer to the three questions is as follows:
Out of the 16 possible outcomes, 12 of them have to possess yellow leaves. Out of the 16 possible outcomes, 4 of them have to possess green leaves. Out of the 16 possible outcomes, only one has green leaves and rough seeds. What is a Dihybrid cross?A dihybrid cross may be characterized as a type of cross that significantly takes place between two individuals with two observed traits that are controlled by two distinct genes. It is a breeding experiment between two organisms that are identical hybrids for two traits.
According to the context of this question, the allele Y encodes for yellow color leaves, and y codes for green color leave. Yellow is dominant over the green. Similarly, S encodes for smooth leaves while s codes for rough seeds. Smooth is dominant over rough.
yyss is the only genotype that has a green and rough phenotype. While the possibilities that have yy in their genotypes must possess a green phenotype.
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A group of students were asked to study and record the movement of amoeba to try and determine how they move. The group knew that they must plan this descriptive investigation carefully, including the selection of the appropriate technology needed to observed these single-celled organisms. Which type of microscope would be most appropriate for this investigation? A) Compound Light Microscope B) Scanning Electron Microscope (SEM) Stereo Microscope (Dissecting Scope) D Transmission Electron Microscope (TEM)
Answer:
A. Compound Light Microscope
Explanation:
USA TestPrep
Answer:
coumpound light microscope
Explanation:
A red blood cell has a salt concentration of 0.9%. What will happen if it is placed into
a 0.8% salt solution? The red blood cell will
burst
remain the same
shrink then grow
shrink
Answer:
Shrink
Explanation:
The blood cell would shrink because of osmosis. The molecules move with the concentration gradient so water molecules will move outside of the cell where there is less water than inside of the cell.
Blood cells are the main constituents of the circulatory system and carry the most vital function of oxygen transportation. Blood cells have a specific concentration and osmotic pressure to remain vital.
The correct answer is:
Option D. Shrink.
This can be explained as:
Cells have a tendency to shrink in hypertonic solutions while swells in hypotonic solutions.0.8% of the salt solution will act as a hypertonic solution and the RBC placed in it will shrink.When cells are placed in hypertonic solution it loses their water content to the outside surface and hence shrink.Therefore when the red blood cells are placed in 0.8% salt solution they will shrink.
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Which of the following is an example of a learned response? OA A child figures out how to ride a bicycle. O B. An adult salmon is able to return to the river where it hatched. OC. A plant turns to follow the sun during the day. OD. A man blinks when an object is tossed toward his face.
Answer:
Explanation:
I would say A. Learning to ride a bicycle is a process of getting on and falling off. You have no idea how to do it properly without practice. That's learned.
But look out for D. I'm not sure that that isn't instinctive. Somewhere along the line I think even a baby knows not to let his/her eyes be touched. Is it learned? It's close but A is a much better answer.
The salmon is instinctive. The plant doesn't learn to turn towards the sun. It does so because more food is produced.
Yes, it's A.
A is the only option that is not instinctual. Riding a bicycle is something that has to be taught (and even if you weren't taught to ride a bike, you had to figure it out by trial and error.)
The other options are instinctual and reflexive responses. The salmon returning to the river is a behavior that is pretty much hard-wired into the salmon's brain. The plant turns to follow the sun because it is a source of light and energy.
The other user expressed uncertainty as to option D, but in fact, option D is very much a reflexive, instinctual response as well. To flinch or blink when something abruptly moves towards you is not a choice or something you have to be taught — it's a reflex, something you can't control.
In the laboratory, a genetics student crossed flies with normal, long wings to flies with mutant, dumpy wings, which she believed was a recessive trait. In the F1, all flies had long wings. In the F2, the following results were obtained: 672 long-winged flies 218 dumpy-winged flies The student tested the hypothesis that the dumpy wing is inherited as a recessive trait by performing chi-square analysis of the F2 data.
Determine:
a. Chi-Square Value.
b. Degrees of freedom.
c. Reject or fail to reject the hypothesis.
Answer:
a. Chi-Square Value = 0.12
b. Degrees of freedom = 1
c. Reject or fail to reject the hypothesis = fail to reject the hypothesis
Explanation:
Available data:
Cross: long wings to flies with mutant, dumpy wingsF1) 100% long-winged fliesF2) 672 long-winged flies 218 dumpy-winged flies Hypothesis: the dumpy wing is inherited as a recessive traitLet us name the allele for Long L and the allele for dumpy l
The number of observed individuals:
Total number: 890 flies (672 + 218) Long-winged = 672 Dump-winged = 218In the F2 generation, if l was a recessive allele and L a dominant allele, exhibiting complete dominance, we would expect a 3:1 phenotypic ratio.
Cross: Ll x Ll
Gametes) L l L l
Punnett square) L l
L LL Ll
l lL ll
F2) 3/4 LL + Ll long-winged individuals
1/4 ll dump-winged individuals
From this ratio and the total number of individuals in the F2 generation, we can get the expected number of individuals:
4 possible genotypes ------- 890 individuals
3 LL + Ll genotype ------------X = 667.5 long-winged individuals
1 ll genotype ---------------------X = 222.5 dump-winged individuals
Chi square = ∑ (O-E)²/E
LL + Ll = (O-E)² /E
LL+ Ll = (672 - 667.5) ² / 667.5
LL + Ll = 0.03
ll= (O-E)²/E
ll= (218 - 222.5)² / 222.5
ll= 0.09
Chi square= ∑ ((O-E)²/E) = 0.03 + 0.09 = 0.12 Freedom Degrees = genotypes - alleles = 3 - 2 = 1 Significance level = 0.05 Table value/Critical value = 3.84
0.12 < 3.84 meaning that there is enough evidence to reject the null hypothesis.
Fail to reject the hypothesis. The genotypes in the population might be in equilibrium H-W. L is the dominant allele, and l is the recessive allele. The dumpy wing is inherited as a recessive trait.
why do we commonly see isotherms on local weather broadcasts?
Explanation:
Isotherms are lines of constant or equal temperature. They are often used on weather maps by meteorologists to give a large scale view of temperatures across the U.S. If you have ever looked at a weather map in a newspaper, the isotherms are used to divide the color-filled temperatures.
Complete the following statement from what you have learned about the motor unit. In some neurodegenerative diseases the lower motor neuron cell bodies die and the remaining lower motor neurons sprout processes that innervate the neuromuscular synapses vacated by the dead lower motor neurons. In these muscles, the size of the motor unit ____________ and the strength of the muscle contraction generated by individually activating each surviving motor neuron _________.
Answer:
The correct answer is - increase, increase.
Explanation:
In some neurodegenerative diseases, some lower motor neuron cells die and the remaining lower motor neurons continuing the process of the vacated dead motor neuron cells to innervate the neuron and muscle synapses.
The size of the motor unit increases and due to the innervations of the new axon
increases the strength of the muscle contraction occurred by individually activating each surviving motor neuron. Here multiple motor units will be controlled by a single neuron.
How many amino acids are there in A peptide, B peptide and C peptide in human insulin???
Answer:
Insulin is composed of an A chain of 21 amino acids and a B chain of 30 amino acids. C-peptide is a peptide composed of 31 amino acids
Explanation:
Insulin is composed of an A chain of 21 amino acids and a B chain of 30 amino acids, the chains being held together by two disulfide bonds. A third disulfide bond is present within the A chain. Human insulin differs from porcine insulin by a single amino acid and from beef insulin by three amino acids.
Explanation:
Dashed circles around either an R or K indicate sites of peptidase cleavage that result in generation of the mature insulin that is comprised by two separate peptides: the A chain with 21 and the B chain with 30 amino acids. A third C peptide with 21 amino acids served as a linker between the A and B chains.
0.3 kilogram golf ball moving at 45 meters/second equals
Answer:
F = 13.5 N
Explanation:
I NEED HELP!!!! What 4 minerals most commonly found in rocks?
•calcite
•feldspar
•fluorite
•halite
•hematite
•magnetite
•mica
•quartz
About 200 minerals make up the rocks.
What are Rocks?The chemical composition and atomic structure of minerals are distinctive. Numerous physical characteristics of minerals, including as hardness, lustre, streak, and cleavage, can be used to quickly identify them. For instance, the mineral quartz is quite hard and not as readily scratched as the mineral talc, which is quite soft and easily scratched.
One of the most effective ways to categorize and differentiate between various minerals is by careful examination of crystal forms.
A crystalline solid is composed of constituent atoms, molecules, or ions arranged in an orderly repeating pattern that extends across all three spatial dimensions.
Therefore, About 200 minerals make up the rocks.
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help l m a o ........
Answer:
D
Explanation:
LKM iF i AM CORRECT
Consider a plant with the following characteristics. Round leaves (R) are dominant to pointed leaves (r). White flowers (W) are dominant to pink flowers (w). Plants heterozygous for both traits are crossed. What is the probability of obtaining a plant with pointed leaves and pink flowers
Answer:
.0625 or 6.25%
Explanation:
Find the probability for the plant to have pointed leaves. If the two parent plants are heterzygous, then the likelihood the plant has a recessive characteristic is 25%, 1/4, or .25 for our calculations.Find the probability for the plant to be pink. If the two parent plants are heterzygous, the likelihood the plant has another recessive characterisitc is again 25%, 1/4, or .25 for our calculations.Multiply them together. (1/4)*(1/4)=(1/16) or .0625, or 6.25%Answer for 10 points!
Answer:
I think the answer is D
Explanation:
Hope that helps!
One of the following is not a function of proteins:
Select one:
a. Catalysis as Enzymes
b. Transport of proteins
c. Protection as antibodies
d. Regulation of hormones
the main sugar that is used as a reactant in cellular respiration is called ____?
Answer:
glucose
Explanation:
Write a scientific explanation to explain how natural selection and adaptation increase or decreases the chances of survival for the mice if they entered one another’s environment.
Answer:
Natural selection is a factor of biological evolution, by means of which individuals who possess a certain characteristic tend to prevail over those who lack such characteristic. Thus, by reproducing, individuals with favorable characteristics end up imposing their own set of characteristics, taking control of the environment in which they develop and relegating other individuals or condemning them to their extinction or displacement.
Thus, in the case, if some mice entered the environment of others, most likely they would not be able to adapt to the conditions to which the original group of that environment had previously adapted. In this way, natural selection itself would make the new mice end up disappearing from it, in favor of the mice that already lived there and that, therefore, had adapted their characteristics to those of the environment.
The kingdom Eubacteria is so called as they have a "True" nucleus.
True
False
Yeast is a: rhizobium, legume, bacteria or fungi?
Answer:
legume mark me brainy plz!
Explanation:
Answer:
I think its a legume?
Explanation:
Distinguish between herbaceous and woody stems
Answer: herbaceous plants are plants with very flexible stems. Their leaves and stems die down to soil level at the end of every growing season amd woody plants are plants with very strong and not easily bendable stems such as trees. Woody plants produce wood as a structural tissue
what is a selectable marker?????
Ask a question about your assignment Explain what are shared characteristics of transcription to translation and what are their differences. Explain what their function is in each cell and their importance to the body.
Explanation:
perform the following the rhythm patterns using the given legend use any kind of membranophones pearl shoes us
helppppppppppp meeeeeeee
Which of the following best explains the difference between autotrophs and
heterotrophs?
A Heterotrophs are organisms that can produce their own food and autotrophs are organisms that
must consume or break down other organisms for food.
B Autotrophs are consumers and heterotrophs are producers.
C Autotrophs are organisms that can produce their own food and heterotrophs are organisms that
must consume or break down other organisms for food.
D Heterotrophs live in terrestrial ecosystems only and autotrophs can live in terrestrial or aquatic
ecosystems.
Answer:
C. Autotrophs (plants) are organisms that can produce their own food and heterotrophs (animals) are organisms that must consume or break down other organisms for food.
Please help with questions 4 to 11 for 75 points!!!
Thank you :D
Answer:
1 .Atom goes to C
2.Proton goes to A
3. Neutron goes to b
Question 4:Protons are a type of subatomic particle with a positive charge. ... Protons and neutrons have approximately the same mass, but they are both much more massive than electrons (approximately 2,000 times as massive as an electron). The positive charge on a proton is equal in magnitude to the negative charge on an electron
Question 5:Atoms are the basic building blocks of ordinary matter. Atoms can join together to form molecules, which in turn form most of the objects around you. ... The protons and neutrons cluster together in the central part of the atom, called the nucleus, and the electrons 'orbit' the nucleus.
Question6:Thomson's model of the atom in 1897 shows that the atom was a sphere of matter, wherein the electrons are mixed inside it. This model does not show the protons and the neurons. On the contrary, the current model that was proposed by Niels Bohr gives us a clearer representation of the structure of an atom.
Question 7:its mass number A is 23.
Question 8: 1 i found the number because hydrogen only has 1 atom so yuh..
I will answer the rest in the comennts:)
Explanation:
Consider a cross between a plant with two flower colors, yellow and red. Yellow (Y) exhibits complete dominance over red (y). It also has either single blossoms or double blossoms, single blossoms (S) exhibit complete dominance over double blossoms (s). A dihybrid yellow, single blossomed flower is crossed with a red flowered and double blossomed plant. You observe the following phenotype frequencies among the 1545 offspring plants:
500 yellow flowers and single blossom plants
515 red flowers and double blossom plants
260 yellow flowers and double blossom plants 270 red flower and single blossom plants.
What is the recombination frequency between these two genes?
a. (260+270) 1545
b. 270/1545
c. 1545/ (260+270)
d. 260/1545
e. (500+515)/1545
f. 1545/260
g. 1545/270
From these results one can conclude that:_______.
a. the two genes are linked
b. the two genes are not linked
c. if the genes are linked, they are separated far enough apart to appear to assort independently
Answer:
1) option a is correct. (260+270)/1545
(Note about this option: In the statement, it is written as (260+270) 1545. Lacks the division symbol, / )
2) From these results one can conclude that the two genes are linked (option a)
Explanation:
To know if two genes are linked, we must observe the progeny distribution. If heterozygous individuals, whose genes assort independently, are test crossed, they produce a progeny with equal phenotypic frequencies 1:1:1:1. If we observe a different distribution, phenotypes appearing in different proportions, we can assume linked genes in the double heterozygote parent.
We might verify which are the recombinant gametes produced by the di-hybrid, and we will be able to recognize them by looking at the phenotypes with lower frequencies in the progeny. Phenotypes with the highest frequencies represent the parental gametes.
To calculate the recombination frequency, we will use the following formula: P = Recombinant number / Total of individuals.
In the present example:
Parental) YySs x yyss
Gametes) YS parental type ys, ys, ys, ys
ys parental type
Ys recombinant type
yS recombinante type
The total number of individuals in the offspring: 1545
Phenotypic class Number of offspring
500 Y-S- (parental)515 yyss (parental)260 Y-ss (recombinant)270 yyS- (recombinant)According to this information, the phenotypic frequencies of the progeny differ from the phenotypic ratio 1:1:1:1. We can assume then, that these genes are linked.
The recombination frequency is:
P = Recombinant number / Total of individuals
P = 260 + 270 / 1545
P = 530/1545
P = 0.343
The genetic distance between genes is 0.343 x 100= 34.4 MU.