3 x 3 x 3 x 3 x 3 x 3 as an exponential notation

The fair share measure would mean that the score of 72 would be the score all 27 students got on the test if they all had the same score.

A fair share measure of the center of the test scores is 72 be the score all 27 students got on the test.

We have given that

a class of 27 students had a mean of 72 on a test,

An equitable or reasonable portion or share of something

The fair share measure would mean that a score of

72 be the score all 27 students got on the test.

If they all had the same score.

Therefore 72 was the score all 27 students got on the test.

To learn more about the fair share visit:

https://brainly.com/question/25957457

Answer:

x= 27

Step-by-step explanation:

Answer:

I would say B

Step-by-step explanation:

Answer:

4(9 – c)

36 – 4c

Step-by-step explanation:

An example of two equivalent expressions includes the general expression and then the one that is factored.

Answer:

so 7*4 is 28 and 7*1/3 is 2 an 1/3 so it would be 30 and 1/3

Step-by-step explanation:

Answer:

50 days

Step-by-step explanation:

5/3 = 50/30

pls brainliest

Answer:

x >_ 1

Step-by-step explanation:

Solving an inequality is a lot like solving an equation. Just pretend the inequality symbol is an equal sign!

(also i wont be using the _ or equal to symbol because I'm too lazy, so you'll get >_ or <_ for those, sorry)

8 + 4x >_ 12

-8             -8

4x >_ 4

/4       /4

x >_ 1

Answer:

When you multiply the number by its reciprocal the numerator of the one becomes the denominator of the other and is equals to 1 .

Answer:

Step-by-step explanation:

Formula:

Solve for t:

Answer:

x = -8

Step-by-step explanation:

-3x -6 = 18

-3x = 24

x = -8

Step-by-step explanation:

✧ [tex] \underline{ \underline{ \large{ \tt{R\: E \: M \: E \: M \: B \: E \: R}}} }: [/tex]

If [tex]( {x}^{a} )^{b} [/tex] is an algebraic term then [tex] {(x}^{a} )^{b} = {x}^{a \times b} [/tex] i.e When an algebraic term in the index form is raised to another index , the base is raised to the product of two indices.

⟶ [tex] \large{ \tt{( {7}^{3} ) ^{3} = {7}^{3 \times 3} = {7}^{9}}} [/tex]

☥ [tex] \boxed{ \boxed{ \large \tt{Our \: Final \: Answer : \underline{ \tt{ {7}^{9}}}}}} [/tex]

Hope I helped ! ♡

⋆ Have a wonderful day / night ! ♪

Let me know if you have any questions regarding my answer! ツ

[tex] \underline{ \underline{ \mathfrak{Carry \: On \: Learning}}}[/tex] !! ✎

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

Answer:

The vertex is at [tex](0, -9)[/tex]

The axis of symmetry [tex]x = 0[/tex]

Step-by-step explanation:

Note: You can answer all the questions looking at the graph

We have the function [tex]f: \mathbb{R} \rightarrow\mathbb{R}[/tex](I am assuming this) such that [tex]f(x) = y = (x-3)(x+3)[/tex]

We note that

[tex](x-3)(x+3) = x^2-9[/tex] once we have a difference of squares

Therefore, we have a quadratic function.

So

[tex]y = x^2-9[/tex]

The vertex [tex](h, k)[/tex] is

[tex]h = \dfrac{-b}{2a} = \dfrac{-0}{2 \cdot 1} = 0[/tex]

[tex]k= h^2 - 9 = 0^2 - 9 =-9[/tex]

Therefore, the vertex is at [tex](0, -9)[/tex]

As we know the vertex, we conclude that the axis of symmetry [tex]x = 0[/tex]

The x-intercepts occur at [tex]y = 0[/tex]

[tex]y = (x-3)(x+3) \implies x = -3, x=3[/tex]

So, the left x-intercept is [tex](-3, 0)[/tex] and the right x-intercept is [tex](3, 0)[/tex]

As I stated in the beginning, the domain is the set of all real numbers. Precisely,

[tex]Dom(f) = \mathbb{R} = (-\infty, \infty)[/tex]  

Once, we know the vertex, we also conclude that the Range is

[tex]Ran(f)= [-9,\infty)[/tex]

Greater than or equal to -9

Answer:

what is this a maths problem

Answer:

The standard deviation of the number of females in the sample is 3.21.

Step-by-step explanation:

For each freshmen, there are only two possible outcomes. Either it is a female, or it is not. Sixty freshmen are randomly selected (without replacement). This means that the hypergeometric distribution is used to solve this question.

Standard deviation of the hypergeometric distribution:

We have that:

N is the population size.

n is the sample size.

s is the number of successes in the sample.

The standard deviation is given by:

[tex]\sigma = \sqrt{n(\frac{s}{N})(1 - \frac{s}{N})(\frac{N - n}{N-1})}[/tex]

A small liberal arts college in the Northeast has 350freshmen.

This means that [tex]N = 350[/tex]

One hundred five of the freshmen are female.

This means that [tex]s = 105[/tex]

Suppose sixty freshmen are randomly selected

This means that [tex]n = 60[/tex]

Find the standard deviation of the number of females in the sample.

[tex]\sigma = \sqrt{60(\frac{105}{350})(1 - \frac{105}{350})(\frac{350 - 60}{350 -1})} = 3.21[/tex]

The standard deviation of the number of females in the sample is 3.21.

Answer:

FD = 25.94

Step-by-step explanation:

13x - 16 = 4x + 11 (Tangents drawn from an external point are equal)

13x - 4x = 11 + 16

9x = 27

x = 3

substituting x in 4x + 11,

4(3) + 11

12 + 11

23

ΔFED is a right triangle,

FD² = FE² + DE²

FD² = 12² + 23²

FD² = 144 + 529

FD² = 673

FD = 25.94

Answer:

FD= +-25.94

Step-by-step explanation:

EF=CF=r(radius)=12

we know,

FD^2=EF^2+ED^2 ......(1)

and

FD^2=CF^2+CD^2 ......(2)

We Know,

area of triangle, a= 1/2xbasexHeight

a=1/2xEFxED .......(3)

and

a=1/2xCFxCD .....(4)

from equation 3 and 4

1/2xEFxED=1/2xCFxCD

=> 1/2x12xED=1/2x12xCD

=>ED=CD

=>13x-16=4x+11

13x-4x=16+11

9x=27

x=3

so

FD^2=EF^2+(ED)^2

FD^2=(12)^2+(4x3+11)^2

=>FD^2=144+529

=>FD^2=673

FD=+-25.94

Answer:

3

Step-by-step explanation:

If you count the units its three units away from each other.

Answer:

Perimeter: 18u^2

Area: 18u^2

Step-by-step explanation:

perimeter is just adding all the sides together so 6+3+6+3

area is multiplying length by width so 6•3

both give us 18

hope this helps chu <3

9514 1404 393

Answer:

  -5/y

Step-by-step explanation:

The wording "the quotient of A and B" is used to signify A/B.

Here, we want the quotient of -5 and y:

  -5/y

A=2(1+[tex]\sqrt{2}[/tex])a^2=2·(1+[tex]\sqrt{2}[/tex])·20^2≈1931.37085cm²

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

[tex]P = (\frac{1}{2}, \frac{\sqrt 3}{2})[/tex]

Answer:

[tex]Rate = 0.935042^\circ /cm[/tex]

Step-by-step explanation:

Given

[tex]P = (\frac{1}{2}, \frac{\sqrt 3}{2})[/tex]

[tex]T(x,y) =x\sin2y[/tex]

[tex]r = 1m[/tex]

[tex]v = 2m/s[/tex]

Express the given point P as a unit tangent vector:

[tex]P = (\frac{1}{2}, \frac{\sqrt 3}{2})[/tex]

[tex]u = \frac{\sqrt 3}{2}i - \frac{1}{2}j[/tex]

Next, find the gradient of P and T using: [tex]\triangle T = \nabla T * u[/tex]

Where

[tex]\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})} = (sin \sqrt 3)i + (cos \sqrt 3)j[/tex]

So: the gradient becomes:

[tex]\triangle T = \nabla T * u[/tex]

[tex]\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j][/tex]

By vector multiplication, we have:

[tex]\triangle T = (sin \sqrt 3)* \frac{\sqrt 3}{2} - (cos \sqrt 3) \frac{1}{2}[/tex]

[tex]\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)[/tex]

[tex]\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5[/tex]

[tex]\triangle T = 0.935042[/tex]

Hence, the rate is:

[tex]Rate = \triangle T = 0.935042^\circ /cm[/tex]

Answer:

nine z plus nine z.

lol tell me.if.its wrong

Answer:

there is no picture?

Step-by-step explanation:

Answer:

x>-1

Step-by-step explanation:

[tex] \frac{17}{17}x > - \frac{17}{17} \\x > - 1 [/tex]

Answer:

x= 49.1

Step-by-step explanation:

Please see the attached picture for the full solution.

Answer:

the answer is B hope it helps

Answer:

answer is B

Step-by-step explanation:

Answer:

Step-by-step explanation:

1. 2

2. 3

3. 6

4. 2

5. 4

Answer:

x=-2

Step-by-step explanation:

[tex]\sqrt{x+3}+4=5[/tex]

subtract 4 from each side

[tex]\sqrt{x+3} +4-4=5-4[/tex]

square both sides

[tex]\sqrt{x+3}^2=1^2[/tex]

so we have

[tex]x+3=1[/tex]

subtract 3 from each side

[tex]x+3-3=1-3[/tex]

so our answer is [tex]x=-2[/tex]