The magnitude of the force is 12.73N.
What is force?
this can be defined as a push or pull in a particular direction. It is calculated using the formula:
F=m*a
Where,
m=mass of the object
a=acceleration
What is magnitude of force?
This is the quantity or strength of the force. It is calculated using the formular:
Normal Force, N=m*g*Cos θ
From the question given:
m =5.00kg
Cos θ= 30°
g=9.8m/s²
Coefficient of Friction, μ=Frictional force/Normal force
=F/N
coefficient kinetic friction, μ=0.300
Magnitude of Force F= Coefficient of Friction*Normal Force
=μN
=μmg Cos θ
F= 0.300*5.00*9.8*Cos30°
F=0.300*5.00*9.8*0.8660
The magnitude of Force,F=12.73N
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4. Ebo throws the ball again at an initial velocity of 18 m/s but this time at an angle of 53° to the ground. a) Work out the velocity in component vector form. b) Why will the ball spend a longer time in the air than it did before. c) Calculate the range of the ball.
16.52 m/s is the velocity and vcosθ is the velocity in component vector form.
velocity in vector form= vcosθ
vector form= vcosθ
vector form=18cos53
v=16.52 m/s
"The rate at which an item changes its location" is described by a vector number called velocity. Imagine someone walking quickly, one step forward, one step back, and starting each step from the same location. Velocity is a vector quantity. Therefore, velocity is cognizant of direction. The direction must be taken into account when determining an object's velocity. A velocity of 55 miles per hour is not sufficient information. It is necessary to account for the direction in order to accurately describe the object's velocity. Simply put, the direction of the velocity vector represents the motion of the object.
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If your actual mechanical advantage is 70 J, and the theoretical is 100 J, what is your percent efficiency?
Please help! I don't understand how to do this!
A babysitter pushing a stroller starts from rest and accelerates uniformly at a rate of 0.778 m/s^2. What is the velocity of the stroller after it has traveled 5.54 m?
A babysitter pushing a stroller starts from rest and accelerates uniformly at a rate of 0.778 m/s^2. The velocity of the stroller after it has traveled 5.54 m will be 2.94 m/s
acceleration = 0.778 [tex]m/s^{2}[/tex]
distance = 5.54 m
initial velocity = 0
velocity of the stroller after it has traveled 5.54 m = ?
2as = [tex]v^{2} - u^{2}[/tex]
2 * 0.778 * 5.54 = [tex]v^{2}[/tex] - 0
v = 2.94 m/s
The velocity of the stroller after it has traveled 5.54 m will be 2.94 m/s
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Brooke is learning about electronic devices that use electric current to encode information. She learns that when a person speaks into the microphone of a telephone, the sound wave generated by the person’s voice is changed into an electronic signal. This electronic signal is then transmitted to another telephone where it is converted back to a sound wave so the other person can hear the voice. The sound wave is encoded by varying the voltage of the electronic signal. Brooke learns that the voltage can be changed in two ways, resulting in two types of electronic signals: analog and digital. Figure 1 and Figure 2 represent these two types of signals.
Identify the type of signal represented by each figure. Explain your reasoning.
The signals in this problem are classified as follows:
Figure 1: Digital signal.Figure 2: Analog signal.What are analog and digital signals?Analog signals are signals that are continuous in both domain and range, meaning that it can assume decimal values, hence it's graph is represented by a continuous curve.
Digital signals are signals that are discrete in both domain and range, meaning that it assumes only integer values, hence it's graph is composed by pulses.
Hence the classification of the signals for each figure in this problem are given as follows:
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What are the causes of different falls in the air?
A, Highlight drop drop
B, The Wind Blows
C, of object
D, Air resistance
D. air resistance
Hope it helps
A .50 kg mass attached to an ideal spring of spring constant 80N/c oscillate on horizontal frictionless surface , the mechenical energy is .12j , the greatest energy from y to x is
The greatest energy or the greatest extension from its equilibrium positions is equal to 0.12 J.
What is mechanical energy?Mechanical energy is the sum of potential energy and kinetic energy that is used to do work. Mechanical energy defines the energy of a system because of its motion or position.
The total mechanical energy is conserved as we know the energy can neither be created nor destroyed. The mechanical energy of a system can only be changed from one form to another whenever the forces used to do work are conservative in nature.
The energy is stored in the form of potential energy in a compressed string. If the elastic potential energy is changed into kinetic energy as it is used to accelerate the mass.
The total mechanical energy required to compress the spring is the maximum amount of elastic potential energy stored in the spring. The greatest energy of the spring will be at the maximum displacement. Therefore, the spring will have the greatest potential energy at equilibrium positions equal to 0.12 J.
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Regarding the likelihood of planets orbiting other stars,
I hate to leave you answer less, but there isn't even a question here to answer.
A car increases its velocity from 0m/s to 14 m/s in 2 seconds
answer -
7 m/s^2
Explanation:
it goes 7m/s 14 / 2 = 7
Two wires are 16 m and 24 m long. The wires are to be cut into pieces of equal length. a) Find the maximum length (in m) of each piece. b) What is the total number of such pieces formed from the two wires?
Answer:
A. The maximum is 8cm. B. 5 pieces of wire.
Explanation:
To find each pieces' length we need to find what can divide both wires = 8cm
A. The maximum is 8cm.
The amount of pieces = 16m/8m = 2 pieces and 24m/8m = 3 pieces. 2 pieces + 3 pieces = 5 pieces of wire.
B. 5 pieces of wire.
Jacob and his scooter have a combined mass of 15 kg What is the force it will take to accelerate his scooter at 3 m/s²?
Answer:
45 N
Explanation:
F = m a = 15 * 3 = 45 N
A 10 kg object is on a movable platform. Rank the size of the normal force acting on the object from largest to smallest.
a) The object is at rest and the platform is not moving
b) the object is at rest on the stationary platform and there is a downward force of 10N applied to the top of the object while it remains stationary
c) the object is at rest on the stationary platform and there is an upward force of 10N applied to the top of the object while it remains stationary
d) the platform is accelerating the object upward at 1.5 m/s^2
e) the platform is accelerating the object downward at 0.5 m/s^2
The size of the normal force acting on the object from largest to smallest are;
(b) The object is at rest on the stationary platform and there is a downward force of 10N applied to the top of the object while it remains stationary.
(e) The platform is accelerating the object downward at 0.5 m/s^2.
(a) The object is at rest and the platform is not moving.
(c) The object is at rest on the stationary platform and there is an upward force of 10N applied to the top of the object while it remains stationary
(d) the platform is accelerating the object upward at 1.5 m/s^2.
What is normal force?
The normal force of an object is the upward force exerted on the object by the supporting surface due to weight of the object acting downwards.
The formula for normal force is given as;
Fn = mg
where;
m is mass of the objectg is acceleration due to gravityThe normal force on the 10 kg object when it is at rest and the platform is not moving,
Fn = mg
Fn = 10 x 9.8
Fn = 98 N
When the object is at rest on the stationary platform and there is a downward force of 10N applied to the top of the object while it remains stationary,
Fn = (10 x 9.8) + 10 N
Fn = 108 N
When the object is at rest on the stationary platform and there is a upward force of 10N applied to the top of the object while it remains stationary,
Fn = (10 x 9.8) - 10 N
Fn = 88 N
When the platform is accelerating the object upward at 1.5 m/s^2
Fn = (10 x 9.8) - (1.5 x 10)
Fn = 98 N - 15 N
Fn = 83 N
When the platform is accelerating the object downward at 1.5 m/s^2
Fn = (10 x 9.8) + (10 x 0.5)
Fn = 103 N
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An object with a mass of 33g and a volume of 39cm^3 is placed in a liquid with a density of 1.25 g/cm^3. Find the volume of the part of the object that is NOT submerged in the liquid. Give your answer in cm^3 and with 3 significant figures.
Answer:
V₂ = 12.6 cm³ - volume of the NOT immersed part:
Explanation:
Given:
m = 33 g
V = 39 cm³
ρ = 1.25 g/cm³
____________
V₂ - ?
Gravity:
F = m·g
Strength of Archimedes:
Fa = ρ·g·V₁
V1 - the volume of the submerged
The object is floating, so:
F = Fa
m·g = ρ·g·V₁
m = ρ·V₁
V₁ = m / ρ = 33 / 1.25 ≈ 26,4 cm³
V₂ - volume of the NOT immersed part:
V₂ = V - V₁ = 39 - 26.4 = 12.6 cm³
A 60km is suspended from two cables which makes 30° and 45° angle with the vertical. Determine the tension in each string.
The tension in each string if a 60 kg is suspended from two cables which makes 30° and 45° angle with the vertical is 429.2 N to the left and 302.25 N to the right.
m = 60 kg
Resolving the tension force of 30° string into its horizontal and vertical components
Tx = T1 sin θ
Tx = T1 sin 30°
Tx = 0.5 T1
Ty = T1 cos θ
Ty = T1 cos 30°
Ty = 0.87 T1
Resolving the tension force of 45° string into its horizontal and vertical components
Tx = T2 sin θ
Tx = T2 sin 45°
Tx = 0.71 T2
Ty = T2 cos θ
Ty = T2 cos 45°
Ty = 0.71 T2
∑Fx = 0
- 0.5 T1 + 0.71 T2 = 0 → ( 1 )
∑Fy = 0
0.87 T1 + 0.71 T2 - m g = 0
0.87 T1 + 0.71 T2 - ( 60 * 9.8 ) = 0
0.87 T1 + 0.71 T2 - 588 = 0 → ( 2 )
( 2 ) - ( 1 ),
1.37 T1 - 588 = 0
T1 = 588 / 1.37
T1 = 429.2 N
Sub T1 in ( 1 ),
( - 0.5 * 429.2 ) + 0.71 T2 = 0
- 214.6 + 0.71 T2 = 0
T2 = 214.6 / 0.71
T2 = 302.25 N
Therefore, the tension in each string is 429.2 N to the left and 302.25 N to the right.
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Planets A and B have the same mass, but planet
is nait the
Which statement correctly explains the
weight you would experience on each
planet?
O A. You would weigh less on planet A because the distance between
you and the planet's center of gravity would be smaller.
•
B. You would weigh the same on both planets because the masses
of the planets are the same.
• C.
You would weigh more on planet A because the distance between
you and the planet's of center of gravity would be smaller.
both planets because your mass
D. You would weigh the same on
would be the same on both.
b
Statement is accurate C. You would weight more on planet A because the distance between you and the planet's of center of gravity would be smaller.
What is the proper statement's justification?You would weigh less on planet A due to a closer proximity to the planet's center of gravity, which is the statement that best represents your weight on each planet.
According to Newton's rule of universal gravitation, "the force of gravity between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distances between them,"
Given that weight is a function of both mass and gravity, objects on planets with stronger gravitational pull will have heavier masses.
The weight will be lighter since there is less space between the individual and the planet's center.
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Which of the following are projectiles (using the definition of a projectile)? (KEEP IN MIND, these are under normal circumstances unless otherwise stated) human walking meteor in Earth's atmosphere car driving airplane landing asteroid basketball being shot by Steph Curry ball on a rope , swinging around a pole (tetherball football thrown bird flying tennis ball served at 140 mph
The example of projectile is a basketball being shot by Steph Curry.
What is projectile?Projectile is any object propelled through space by the application of a force.
Projectile is used to describe any object that is cast, fired, flung, heaved, hurled, tossed, or thrown. For example, when a ball is thrown straight upward, or kicked.
In projectile motion, gravity is the only force acting on the object. This doesn’t necessarily mean that other forces do not act on it, just that their effect is minimal compared to gravity. The path followed by a projectile is known as a trajectory.
Other examples of projectile is as follows:
Firing a canonJavelin throwArcheryGun fireGolf ballTherefore, it can be said that a basketball being shot by a renowned basket baller into the air is an example of projectile.
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Nabil wants to work out the density of a pebble. He has a displacement can and a beaker. What other piece of equipment will he need?
In order to determine the density of the pebble, Nabil requires a balance to measure the mass of the pebble.
What is the density of a substance?The density of a substance is the measure of how tightly-packed the particles in the substance are.
Density is the ratio of the mass and volume of the substance.
Density = mass/volumeTo determine the density of a substance, the mass of the substance is measured with a balance and the volume of the substance if it is solid is measured using a displacement can and a beaker.
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please help
help having issues with the problem
Answer:
2 m/s²
Explanation:
You want the acceleration produced by a force on 14 kg if that same force produces an acceleration of 7 m/s² when acting on a mass of 4 kg.
Inverse proportionFor the same force, the acceleration is inversely proportional to the mass. In this problem, the mass increases from 4 kg to 14 kg, a factor of 14/4 = 7/2.
The acceleration will change by a factor that is the inverse of this: 2/7.
acceleration of 14 kg = (7 m/s²) × (2/7) = 2 m/s²
The decibel rules of thumb can be combined. (a) If a sound has intensity xdB, how many dB does a sound 100 times more intense have? (b) If another sound has intensity ydB, how many dB does a sound 4 times less intense have? (c) Combine what you know about (a) and (b): If a sound has intensity zdB, how many dB does a sound 25 times more intense have?
If one of the cars starts and ends at the same point in the race (making a loop around the track), what is the car's displacement?
A 0
B 1
C 2
D 7.5
PLEASE
Answer:
A.0
Explanation:
What are the rock forming minerals and its meaning.
Answer:
There are almost 5000 known mineral species, yet the vast majority of rocks are formed from combinations of a few common minerals, referred to as “rock-forming minerals”.
ASTRONOMY QUESTION
Over what range of distances from the Sun would you expect to find solid, rocky material collecting together to form a terrestrial planet?
Group of answer choices
A) 5 - 50 AU
B) beyond 50 AU
C) 0.2 - 5 AU
D) 0 - 0.2 AU
The range of distances from the Sun that you would expect to find solid, rocky material collecting together to form a terrestrial planet is option (C) 0.2 - 5 AU.
What is formation of a terrestrial planet about?Jovian planets can be found at distances of 2 AU to 50 AU or more. This is the area where the early Solar System's temperature was below 273 K, water's freezing point.
Therefore, While rocky and metallic materials (Terrestrial planets) might have condensed over the whole range of distances from the Sun, only the rocky material could have accumulated over the range from 2 AU and inwards. H and He may have also been captured by the planet if it had been further from the Sun than 2 AU, which would have made it a Jovian or gas giant planet.
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It takes 5.91 J of work to stretch a Hooke’s-law spring 4.78 cm from its unstressed length.
How much the extra work is required to stretch it an additional 9.95 cm?
Answer in units of J.
The extra work is required to stretch the spring to an additional 9.95 cm is 25.61 J.
What is the spring constant of spring?
The spring constant of the spring is determined by applying the formula for elastic potential energy of a spring as shown below.
E = ¹/₂kx²
where;
k is the spring constantx is the extension of the springkx²= 2E
k = 2E/x²
k = (2 x 5.91)/(0.0478²)
k = 5,173.2 N/m
The work done to stretch the string to 9.95 cm is calculated as;
E = ¹/₂kx²
E = ¹/₂(5173.2)(0.0995)²
E = 25.61 J
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In Graph C above, which line(s) shows an object that has a constant
velocity?
Answer:
it's D that has a constant velocity
how long (in seconds) would it take a Narwhal to accelerate from rest down a 30 meter long ravine with an acceleration of 2.2 m/s^2
The time (in seconds) it will take the Narwhal to accelerate from rest down a 30 meter long ravine is 5.2 s
How do I determine the time?We know from equations of motion that distance, acceleration and time are related according to the following formula:
s = ut + ½at²
Where
s is the distanceu is the initial velocitya is the accelerationt is the timeWith the above formula, we can obtain the time as follow:
Initial velocity (u) = 0 m/sDistance (s) = 30 mAcceleration(a) = 2.2 m/s²Time (t) = ?s = ut + 1/2at²
30 = (0 × t) + (½ × 2.2 × t²)
30 = 0 + (1.1 × t²)
30 = 1.1 × t²
Divide both side by 1.1
t² = 30 / 1.1
Take the square root of both side
t = √(30 / 1.1)
t = 5.2 s
Thus, the time taken is 5.2 s
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A tennis ball with a mass of 0.2 kg is thrown upwards from the ground at a velocity of 30 m/s. What
is the height of the ball when it has a velocity of 20 m/s?
The height of the ball when it has a velocity of 20 m/s is 45m.
What is mass?
It is the most fundamental feature of matter and one of the fundamental quantities in Physics. Mass can be defined as the amount of matter in a body. Kilogram is the SI unit of mass (kg).
It should be noted that a body's mass does not alter with time. Only in severe instances where a massive amount of energy is provided or removed from the body. In a nuclear reaction, for example, a tiny bit of matter is turned into a massive amount of energy, reducing the mass of the substance.
Given Initial velocity of ball, u=30 m/s
Let the maximum height reached and time taken to reach that height be H and t respectively.
Assumption: g=9.8 m/s2
holds true (maximum height reached is small compared to the radius of earth)
30/g=30/9.8=3 seconds
as the time taken to reach max height.
h(3)=-4.9(3²)+30(3)
=90–45
=45m
The height of the ball when it has a velocity of 20 m/s is 45m.
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Help on solving this single logarithm
log 8 + log 16 - log 2 = log64, In order to get another number, a number should be raised to a certain power, which is known as a logarithm.
The correct answer is A
Describe a logarithm.A number must be increased to a specific power, or logarithm, in order to obtain another number. For additional information on exponents, visit Figure 3.3 of this Math Review. As an example, the base 10 logarithm of the number ten raised to the power of two two is two, or log 100, which equals two.
What does a number's log mean?Exponentiation is a mathematical operation, and the logarithm, simply log, is its inverse. In other words, the log of a number is the value that a fixed base must be increased to in order to produce the value. Although technically any base can be used, the term "log" often suggests that base 10 is being used.
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A wave on a rope is shown in the diagram. In the diagram, d = 3 m.
(a) What is the wavelength of this wave?
(b) If the frequency is 5 Hz, what is the speed of the wave?
The wavelength of the wave is 3m and the speed of the wave is 15 m/s
What is a wave?We define a wave as a disturbance that occurs along a medium and leads to the transference of energy from one point to another. As we can see the energy in this case is transferred along the length of the string. We know that the wavelength is the distance between the two successive crests or troughs.
Now we know that the distance between the two successive crests as we can see is the wavelength of the wave and this is shown the length that have been designated as d and we thus have the wavelength as 3m.
Again we have;
v = λf
v = speed of the wave
f = frequency of the wave
λ = wavelength of the wave
Then;
v = 3 m * 5 Hz
= 15 m/s
Thus the wave speed is obtained as 15 m/s.
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Two small plastic spheres having positive electrical charges are given. When they are 60.00cm apart, the repulsive force between them has the magnitude 0.250N.calculate the charge on each sphere
Answer:
3.16 × 10‐⁶
Explanation:
through coulomb's law
the force of attraction or repulsion of charges is given by the relation
F = k.q1.q2/r²
where your k = 9 × 10⁹
Answer:
Charge 3.16 mkC microcoulomb
Explanation:
Given:
q₁ = q₂ = q - Electrical charges
r = 60.00 sm = 0.60 m - Distance between charges
F = 0.250 N - Repulsive force between charges
___________________
q - ?
F = k·q₁·q₂ / r² = k·q·q / r² = k·q² / r²
Charge:
q = √ (F·r² / k )
q = r·√ (F / k )
q = 0.60· √ (0.250 / 9·10⁹) ≈ 3.16·10⁻⁶ C or:
q = 3.16 mkC (microcoulomb)
A 40 N force is applied to a 10 kg block, but the object only accelerates at 2 m/s?. Explain why this happens using a free-body diagram.
Using a free body diagram to explain the situation, the acceleration of the block decreased because of force of friction acting in opposite direction reducing the net force on the block and consequently the acceleration of the block.
What is net force on an object?
The net force on an object is the sum of all the forces acting on an object.
According to Newton's second law of motion, the net force on an object is directly proportional to the product of mass and acceleration of the object.
F(net) = ma
F - Ff = ma
where;
F is the applied force on the objectFf is the force of friction on the objectm is the mass of the objecta is the acceleration of the objectIn the absence of friction force, the maximum acceleration of the block is calculated as;
a = F/m
a = 40 N / 10 kg
a = 4 m/s²
In the presence of friction force, the net force will decrease and the acceleration of the block will decrease as well.
In free body diagram (FBD) this can be represented as;
F → Ф ← Ff
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A 975-kg car accelerates from rest to 26.7 m/s in a distance of 120 m. What is the magnitude of the average net force acting on the car?
The force that is applied to the car is 2896 N.
What is the acceleration?We know that the acceleration is the often gotten by the use of the kinematic equations. We can write;
v^2 = u^2 + 2as
Given that;
v = final velocity
u = initial velocity
a = acceleration
s = distance
Then we know that u = o m/s since it started from rest
v^2 = 2as
a = v^2/2s
a = (26.7)^2/ 2 * 120
a = 2.97 m/s^2
We know that;
Force = mass * acceleration
Force = 975-kg * 2.97 m/s^2
Force = 2896 N
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