(3x10^-4)(5x10^8) in scientific notation

The median, upper and lower quartiles of the data set are:

Lower Quartile = 46

Median = 49

Upper Quartile = 90

The center value or middle value of a data set is the median.

Upper quartile (Q3) is the center or middle data point of the second half of a data set.

Upper quartile (Q3) is the center or middle data point of the second half of a data set.

Order the data set given as:

32, 46, 49, 49, 77, 90, 96

Lower Quartile = 32, (46), 49, 49, 77, 90, 96 = 46

Median = 32, 46, 49, (49,) 77, 90, 96 = 49

Upper Quartile = 32, 46, 49, 49, 77, (90,) 96 = 90

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Answer:

5/6

Step-by-step explanation:

since there already is a common denominator all you have to do is add the numerators

[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$530000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years \end{cases} \\\\\\ A=530000\left(1+\frac{0.04}{4}\right)^{4\cdot t}\implies A=530000(1.01)^{4t} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{after 12 years}}{t=12}\implies A=530000(1.01)^{4(12)}\implies A=530000(1.01)^{48} \\\\\\ A\approx 854479.82~\hfill \underset{\textit{interest in the account}}{\stackrel{854479.82~~ - ~~530000}{\approx 324479.82}}[/tex]

Answer:

s = [tex]\frac{1}{3}[/tex]

Step-by-step explanation:

s = ut + [tex]\frac{1}{2}[/tex] at² ( substitute the given values into the equation )

s = ( 3 × [tex]\frac{1}{3}[/tex] ) + ( [tex]\frac{1}{2}[/tex] × - 12 × ([tex]\frac{1}{3}[/tex] )² )

  = 1 + (- 6 × [tex]\frac{1}{9}[/tex] )

  = 1 + ( - [tex]\frac{2}{3}[/tex] )

  = 1 - [tex]\frac{2}{3}[/tex]

  = [tex]\frac{1}{3}[/tex]

Answer:

[tex] \hookrightarrow \: u = 3 || \: a = - 12 \: || t = \frac{1}{3} \\ \hookrightarrow \: s = ut + \frac{1}{2} a {t}^{2} \\ \hookrightarrow \: s =3 \times \frac{1}{3} + \frac{1}{2} \times - 12 \times (\frac{1}{3} )^{2} \\ \hookrightarrow \: s =1 - \frac{2}{3} \\ \hookrightarrow \: s = \frac{1}{3} [/tex]

Ths solubility curve can be used to obtain the amount of salt dissolved (solubility).

The solubility curve is a plot of the solubility of a substance against the temperature. It serves the purpose of being used to show the solubility of a susbtance at different temperatures. This question is incomplete hence we can not be able to deduce the solubility of the salt at this temperature.

If the solubility curve has been ploted, then we can be able to estimate the solubility of the salt from the graph.

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Answer:

12 cups

Step-by-step explanation:

The ratio he uses is

2 parts strong coffee

3 parts milk

Let's say he makes a recipe exactly like the amounts of the ratio.

2 cups strong coffee

3 cups milk

Total: 2 cups + 3 cups = 5 cups

He wants to make 30 cups, so 5 cups is not enough.

Let's double the amounts of the recipe keeping the same ratio of 2 to 3.

2 × 2 = 4 cups strong coffee

3 × 2 = 6 cups milk

Total: 4 cups + 6 cups = 10 cups

He wants to make 30 cups, so 10 cups is not enough.

We can keep on going up by multiplying the numbers in the ratio by larger numbers, but there is a quicker way.

We need to multiply both numbers in the ratio by a number, let's call it x, so that when both numbers in the ratio are multiplled by x, and the ingredients are added, we end up with 30 cups.

Multiply both numbers in the ratio by x.

2x cups of strong coffee

3x cups of milk

Now add: the total amount will be 5x cups

We want 30 cups, so

5x = 30

Solve for x.

x = 30/5 = 6

x, the multiplier we need is 6.

2x cups strong coffee = 2(6) cups = 12 cups

3x cups milk = 3(6) cups = 18 cups

Answer: 12 cups

Answer:

A rectangle with sides lengths 4cm and 6cm and a rectangle with side lengths 2cm and 12 cm...

Answer:

15% interest

Step-by-step explanation:

because it's 15 out of 100 so that would be 15%

Answer:

  sh.299,449.72

Step-by-step explanation:

The future value of an ordinary annuity with annual payments P earning interest rate r compounded annually for t years is ...

  FV = P((1+r)^t -1)/r

For the given numbers, the future value is ...

  FV = sh.25000(1.07^9 -1)/0.07 ≈ sh.299,449.72

The town should be located 13.4 units from each other

The formula for calculating the distance between two points is expressed as:
√(x2-x1)²+(y2-y1)²

The midpoint of two coordinates is expressed as:
[tex]m(x, y)=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2} )[/tex]

Substitute the given coordinate

[tex]m(x, y)=(\frac{3+15}{2}, \frac{1+7}{2} )\\m(x,y)=(9,4)[/tex]

Hence the town should be located at coordinate (9, 4)

Calculate the distance

D =  √(15-3)²+(7-1)²

D =  √(12)²+(6)²

D = 13.4units

Hene the town should be located 13.4 units from each other

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Answer:

15

Step-by-step explanation:

hope this helps

Answer:

  7.2 meters

Step-by-step explanation:

Similar triangles have linear dimensions that are proportional. The ratio of heights will be the same as the ratio of permeters:

  h/(12 m) = 3/5 . . . . . . . small/large

  h = (3/5)(12 m) = 7.2 m . . . . . . multiply by 12 m

The height of the smaller triangle is 7.2 meters.

The surface area of the right prism with an isosceles triangle base is 720 inches squared.

surface area = bh + l(x + y + z)

where

Therefore,

b = 24 inches

h = 5 inches

x = 13 inches

y = 13 inches

z = 24 inches

l = 12 inches

Surface area = 24 × 5 + 12(13 + 13 + 24)

Surface area = 120 + 12(50)

Surface area = 120 + 600

Surface area = 720 inches²

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Answer:

get a book from shop and draw with ruler and write the numbers too

The twenty units of potatoes illustrates the measure of central tendency  and probability

Start by sorting the dataset:

0.19; 0.28; 0.55;

0.62; 0.68; 0.77;

0.88; 0.89; 0.98;

0.99; 1.11; 1.22;

1.22; 1.22; 1.33;

1.44; 1.48; 1.68;

1.77; 1.99

The highest occuring element is 1.22 with a frequency of 3

The two middle elements are 0.99 and 1.11.

The mean of these two middle elements is: 0.5 * (0.99 + 1.11) = 1.05

The mean of the whole dataset is:

Mean = (0.19+ 0.28+ 0.55+ 0.62+ 0.68+ 0.77+ 0.88+ 0.89+ 0.98+ 0.99+ 1.11+ 1.22+1.22+ 1.22+ 1.33+ 1.44+ 1.48+ 1.68+1.77+1.99)/20

Mean = 1.06

Hence, the modal weight is 1.22, the mean is 1.06, and the median is 1.05

(a) at least 1.1 kg

There are 10 potatoes that weigh at least 1.1 kg.

So, the probability is:

P = 10/20

P = 0.5

(b) more than 3.5kg

There are 0 potatoes that weigh more than 3.5 kg.

So, the probability is:

P = 0/20

P = 0

(c) below 0.50kg

There are 2 potatoes that weigh below 0.50 kg.

So, the probability is:

P = 2/20

P = 0.1

The Variance of the weight.

This is calculated as:

Var = [tex]\sum[/tex](x - mean)^2/n

This gives

Var = [(0.19 - 1.06)^2 + (0.28 - 1.06)^2 + (0.55 - 1.06)^2 + (0.62 - 1.06)^2 + (0.68 - 1.06)^2 + (0.77 - 1.06)^2 + (0.88 - 1.06)^2 + (0.89 - 1.06)^2 + (0.98 - 1.06)^2 + (0.99 - 1.06)^2 + (1.11 - 1.06)^2 + (1.22 - 1.06)^2 + (1.22 - 1.06)^2 + (1.22 - 1.06)^2 + (1.33 - 1.06)^2 + (1.44 - 1.06)^2 + (1.48 - 1.06)^2 + (1.68 - 1.06)^2 + (1.77 - 1.06)^2 + (1.99 - 1.06)^2]/20

Evaluate

Var = 0.22

This means that:

The expectation of the squared deviation of the random variable from the mean is 0.22 kg

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Answer:

0.22 kg

Step-by-step explanation:

The frequency count that should be recorded for the soup category is 6.

Subtraction is the process of taking one number away from another number. The sign used to represent subtraction is -.

The frequency count on the table should be equal to the number of students. Thus, in order to determine the frequency count for the soup category, subtract 22 from the total frequency count.

The frequency count for the soup category = 22 - (5 + 8 + 2 + 1 ) = 6

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Answer:

Soln:

Step-by-step explanation:

Here,

Base(b) =9

Opposite/Perpendicular (p)= x

Hypotenus (h) = 24

We know,

(p)^2 = (h)^2 - (b)^2

(x)^2 = (24)^2 - (9)^2

x^2 = 576 - 81

x^2 = 495

x = root under 495

Answer:

1- 22.2486  2- No

Step-by-step explanation:
1:

[tex]b = \sqrt{ c^{2}- a^{2}[/tex]

C is the hypotenuse, or longest side of the triangle (24).

A is the one length we have besides the hypotenuse(9).

[tex]b = \sqrt{ 24^{2}- 9^{2}[/tex]

b = 22.2486

2:
No, because if it was a Pythagorean triple, it would follow the equation [tex]a^{2} +b^{2} =c^{2}[/tex].

[tex]9^{2} + 22.2485^{2} \neq 24^{2}[/tex].

Answer:

  yes; 2 m = 200 cm

Step-by-step explanation:

The SI prefix "centi-" signifies 1/100. That is 300 cm = 300/100 m = 3 m.

If the ceiling is 3 meters high, a sculpture that is 2 meters tall will have no difficulty fitting into the room.

The areas of the square pyramid are the amount of space on it

The given parameters are:

Base (b) = 12 cm

Slant height (l) = 12.8 cm

The lateral surface area is calculated using:

L = 2bl

So, we have:

L = 2 * 12 * 12.8

Evaluate the product

L = 307.2

This is calculated using:

T = L + b^2

So, we have:

T = 307.2 + 12^2

Evaluate

T = 451.2

Hence, the total surface area is 451.2 square cm

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Answer: TThere is no picture

Step-by-step explanation:

Answer:

$600

Step-by-step explanation:

This can be modeled as an exponential equation.

General form of an exponential function: [tex]y=ab^x[/tex]

where:

Therefore:

[tex]\implies 75=a(0.5)^3[/tex]

[tex]\implies 75=0.125a[/tex]

[tex]\implies a=\dfrac{75}{0.125}[/tex]

[tex]\implies a=600[/tex]

Therefore, the computer initially cost $600.

Answer:

hopefully this helps :] 16th line down I think

Answer:

The distance is 20 units

Step-by-step explanation:

Answer:

D.  1  1/2 feet

Step-by-step explanation:

Multiply the numbers to find the length of wire used.

Correct choice is D

Answer:

3.6 m/h

Step-by-step explanation:

Distance (d) = 9 Km

Time (t) = 2.5 hour

Speed ( s )

Speed = Distance / Time

s = d / t

s = 9 / 2.5

s = 90 / 25

s = 18 / 5

s = 3.6 Km/h

Answer: About 800 thousand

The more accurate value is 807,528 but this is also an approximation.

=======================================================

Work Shown:

[tex]t = \text{number of years since the year 2000}[/tex]

[tex]P_0 = \text{population (in millions) in the year 2000}[/tex]

[tex]P = P_0(1.2)^t\\\\5 = P_0(1.2)^{10}\\\\5 \approx P_0*6.1917364224\\\\P_0 \approx \frac{5}{6.1917364224}\\\\P_0 \approx 0.80752791444922\\\\P_0 \approx 0.807528\\\\[/tex]

That's the rough population of wild pigs (in millions) for the year 2000.

Multiply by [tex]10^6[/tex] to get it in terms of units instead.

[tex]0.807528\times10^6 = 807,528[/tex]

There were roughly 800 thousand wild pigs in the year 2000.

Answer:

1. 3/20    

2. 76/4

3. 16

4. 1/8

5. 11/1

6. 2.5/1

7. 13/1

8. 255/1

9. 20, 140, 240

10. 3.5, 17.5, 31.5

11. 12

12. 2