4. Consider the mailbox shown below. It consists of a square prism for the main pole, a rectangular prism for the main box and half a cylinder for top portion. You are going to provide the dimensions for each of these parts. When you provide the dimensions, they must meet the following criteria:
Use these dimensions to determine the overall volume of the mailbox. This should include both the pole, main box and cylindrical top portion. If necessary, use 3.14 for π and round your answer to the nearest hundredths.

Answer:

Question 13 is 27/2 (decimal form, 13.5, Mixed fraction 13 1/2)

Question 14 = 4

Step-by-step explanation:

hope this helped you:)

Answer:

about 28

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

24 + 12 = ___(8+4)

36 = ___(12)

36/12 = 3

Answer:

The only one that makes sense is A.

Hope this helps.

Step-by-step explanation:

V=LWH

Answer:

A

Step-by-step explanation:

I just took the quiz

Answer:

can you take a better pick

Step-by-step explanation:

Answer:

225,623 miles (363,104 kilometers).

Step-by-step explanation:

Answer:

so least to greatest? 1/4 1/3 1/2

Answer:

1/4, 1/3, 1/2

Step-by-step explanation:

Answer:

y = 5x + 7

Step-by-step explanation:

1. Substitue the numbers into their spots.

7 = 5(2)+b

2. Find b by simplifying

7 = 10 + b

-3 = b

3. Substitute it back in since parallel lines have the same slope.

Answer:

A=2*(t-1)-500

Step-by-step explanation:

I did it on study island.

Function representing the amount of money as per given condition in the account after [tex]t[/tex] months is equals to [tex]A= 2^{t-1} -500[/tex].

" Function is defined as relation between variables is such that for each input value there exist one and only one output."

According to the question,

Given,

Amount in the account

Frist month [tex]= \$1[/tex]

                   [tex]= 2^{1-1}[/tex]

As per given condition,

second month [tex]= \$2[/tex]

                        [tex]= 2^{2-1}[/tex]

Third month  [tex]= \$4[/tex]

                     [tex]= 2^{3-1}[/tex]

.........

Amount in the account in [tex]'t'[/tex] months [tex]= 2^{t-1}[/tex]

Jerry withdraw  [tex]\$500[/tex] to make a down payment on the trip.

[tex]'A'[/tex] represents the total amount left in the account

Required function as per given condition,

[tex]A = 2^{t-1} -500[/tex]

Hence, function representing the amount of money as per given condition in the account after [tex]t[/tex] months is equals to [tex]A= 2^{t-1} -500[/tex].

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Answer: 53.0

Step-by-step explanation:

Then the diameter equals 53.0122774

The diameter of the sphere is 53.01 inch

What is a Sphere?

A sphere is symmetrical, round in shape. It is a three dimensional solid, that has all its surface points at equal distances from the center. It has surface area and volume based on its radius. It does not have any faces, corners or edges.

The Surface Area of a Sphere = 4πr²

The Volume of a Sphere = ( 4/3 ) πr³

where r is the radius of the sphere

Given data ,

Let the diameter of the sphere be = d

The radius of the sphere be = r

The volume of the sphere is V = 78006 inch³

The Volume of a Sphere = ( 4/3 ) πr³

Substituting the values in the equation ,we get

( 4/3 ) πr³ = 78006 inch³

Now , Multiply by ( 3 / 4 ) on both sides , we get

πr³ = ( 78006 x 3 ) / 4

     = 58504.5 inch³

Divide by π on both sides , we get

r³ = 58504.5 / π

   = 18622.56 inch³

Taking cube roots on both sides , we get

r = 26.506 inch

So , the radius of the sphere is r = 26.506 inch

Now , the diameter of the sphere is d = 2 x r

                                                               = 2 x 26.506

                                                               = 53.01 inch

Hence , The diameter of the sphere is 53.01 inch

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Answer:

Step-by-step explanation:

Since there are 2 digits in 29, the very last digit is the "100th" decimal place. So we can just say that . 29 is the same as 29/10

Answer:

0.29 = 29/100

Explanation:

its c because i already did that and got it right

Answer:

[tex]f(x) = \frac{6}{x^2} -8[/tex] or [tex]f(x) = -\frac{6}{x^2} + 4[/tex]

Step-by-step explanation:

Given

[tex](x,y) = (1,-2)[/tex] --- Point

[tex]\int\limits^6_2 {(1 + 144x^{-6})} \, dx[/tex]

The arc length of a function on interval [a,b]:  [tex]\int\limits^b_a {(1 + f'(x^2))} \, dx[/tex]

By comparison:

[tex]f'(x)^2 = 144x^{-6}[/tex]

[tex]f'(x)^2 = \frac{144}{x^6}[/tex]

Take square root of both sides

[tex]f'(x) =\± \sqrt{\frac{144}{x^6}}[/tex]

[tex]f'(x) = \±\frac{12}{x^3}[/tex]

Split:

[tex]f'(x) = \frac{12}{x^3}[/tex] or [tex]f'(x) = -\frac{12}{x^3}[/tex]

To solve fo f(x), we make use of:

[tex]f(x) = \int {f'(x) } \, dx[/tex]

For: [tex]f'(x) = \frac{12}{x^3}[/tex]

[tex]f(x) = \int {\frac{12}{x^3} } \, dx[/tex]

Integrate:

[tex]f(x) = \frac{12}{2x^2} + c[/tex]

[tex]f(x) = \frac{6}{x^2} + c[/tex]

We understand that it passes through [tex](x,y) = (1,-2)[/tex].

So, we have:

[tex]-2 = \frac{6}{1^2} + c[/tex]

[tex]-2 = \frac{6}{1} + c[/tex]

[tex]-2 = 6 + c[/tex]

Make c the subject

[tex]c = -2-6[/tex]

[tex]c = -8[/tex]

[tex]f(x) = \frac{6}{x^2} + c[/tex] becomes

[tex]f(x) = \frac{6}{x^2} -8[/tex]

For: [tex]f'(x) = -\frac{12}{x^3}[/tex]

[tex]f(x) = \int {-\frac{12}{x^3} } \, dx[/tex]

Integrate:

[tex]f(x) = -\frac{12}{2x^2} + c[/tex]

[tex]f(x) = -\frac{6}{x^2} + c[/tex]

We understand that it passes through [tex](x,y) = (1,-2)[/tex].

So, we have:

[tex]-2 = -\frac{6}{1^2} + c[/tex]

[tex]-2 = -\frac{6}{1} + c[/tex]

[tex]-2 = -6 + c[/tex]

Make c the subject

[tex]c = -2+6[/tex]

[tex]c = 4[/tex]

[tex]f(x) = -\frac{6}{x^2} + c[/tex] becomes

[tex]f(x) = -\frac{6}{x^2} + 4[/tex]

You can use the formula for finding the arc length on specified interval on x axis.
The curves whose arc length on the given interval is described are

[tex]f(x) = 6x^{-2} -8[/tex]

and

[tex]f(x) = -6x^{-2} + 4[/tex]

If the function is differentiable in the given interval, then we have:

[tex]s = \int_a^b\sqrt{(1 + (f'(x))^2)}\:dx[/tex]

where s denotes the length of the arc of the given function from x = a to x = b

Using the above formula, as we're already given the arc length, thus,

[tex]\int_a^b\sqrt{(1 + (f'(x))^2)}\:dx = \int_2^6\sqrt{(1 +144x^{-6})}\:dx[/tex]

This gives us

[tex]f'(x) = \pm \sqrt{144x^{-6}} = \pm 12x^{-3}[/tex]

Integrating both sides with respect to x, we get:

[tex]f(x) = \pm \int 12x^{-3}\\\\f(x) = \pm 6x^{-2} + c[/tex]

where c is constant of integration.

Since the curve passes through (1,-2), thus, putting f(x) = -2, x = 1, we get:

[tex]f(x) = \pm 6x^{-2} + c\\-2 = \pm 6 + c\\c = -2 \mp 6 = -8, or ,4[/tex]

c = -8 when we have [tex]f(x) = 6x^{-2} + c[/tex]

c = + 4 when we have [tex]f(x) = -6x^{-2} + c[/tex]

The curves whose arc length on the given interval is described are

[tex]f(x) = 6x^{-2} -8[/tex]

and

[tex]f(x) = -6x^{-2} + 4[/tex]

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Answer:

(-6, -3) (-3,-3) (-3,-6)

Step-by-step explanation:

Multiple all of the vertices by 1.5.

(-6, -3) (-3,-3) (-3,-6)

Hope I helped!

[enlargment will still be a triangle]

Answer:

26.5

Step-by-step explanation:

dont worry I'm actually the salesperson at the  jewlery store

Step-by-step explanation:

it is not confrmed answer

commission:106%

Answer:

128

Step-by-step explanation:

16 x 8 = 128

Answer:

128

Step-by-step explanation:

you multiply 16 and 8 because each team has 16 and there are 8 teams so, 16×8=128

Answers:

Here you go, hope this helps

Step-by-step explanation:

6+2x

Answer:

his speed is 2 meters per second

Answer:

his speed is 2 meters per second

Step-by-step explanation: none

Answer:

x=13 y=25

Step-by-step explanation:

Answer:

Step-by-step explanation:

ΔABC has AB = 2BC, hypotenuse is twice the leg

ΔBCD is isosceles right triangle

ΔMPN is isosceles right triangle (∠M = 45°)

ΔMKP is isosceles right triangle (∠M = 45°)

Hello!

[tex]\large\boxed{\frac{2\pi}{3} \text{ and } \frac{4\pi}{3}}[/tex]

2cosФ + 1 = 0

Begin by isolating for cosФ. Subtract both sides by -1:

2cosФ = -1

Divide both sides by 2:

cosФ = -1/2

Using the unit circle, we know that from [0, 2π), values that have a cosine of -1/2 are 2π/3 and 4π/3.

Therefore, the solutions of this equation are:

Ф = 2π/3 and 4π/3

Answer:

C

Step-by-step explanation:

A is impossible. You cannot have both a right triangle and in the same triangle have an angle in it that is over 90 (that's the meaning of scalene)

B is sort of true, but only sort of. All scalene triangles have an angle over 90 and 2 acute angles.

C this is the answer to the question. It has 1 right angle and 2 equal sides. The two equal sides make it isosceles and the right angle is given.

D an acute triangle has three angles under 90 that add to 180. Not the right description.

A triangle with one right angle and two congruent sides is described as a "right isosceles triangle." (Option C)

Let's break down the terms:

1. Right Angle: A right angle is an angle that measures exactly 90 degrees.

2. Isosceles Triangle: An isosceles triangle is a triangle with at least two sides of equal length (congruent sides).

3. Right Isosceles Triangle: A right isosceles triangle is a special type of isosceles triangle where one of the angles is a right angle (90 degrees) and the other two angles are equal, each measuring 45 degrees.

In a right isosceles triangle, the two congruent sides are the legs of the right triangle, and the third side (opposite the right angle) is called the hypotenuse.

So, among the given options, the best description for a triangle with one right angle and two congruent sides is a "right isosceles triangle" (Option C).

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Answer:

The zero of a function is any replacement for the variable that will produce an answer of zero. Graphically, the real zero of a function is where the graph of the function crosses the x‐axis; that is, the real zero of a function is the x‐intercept(s) of the graph of the function.

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

We know that when x=0 y=5

B and D are the only ones that meet this criteria

we know that when x=2 y= 13 or so

D no longer works

it has to be B

Answer:

128°

Step-by-step explanation:

180-52=128

Answer:

A  , B, and C

Step-by-step explanation:

i just did it

Answer:

Step-by-step explanation:

[tex]\tan22=h_1/200,\ \tan29=h_2/200

h_2+h_1=200(\tan29+\tan22)

H\approx 191.667ft

H\approx 191’ 8”