Answer:
0.0806 mm
735.588 MPa
Explanation:
Given data:
Esteel = 200 GPa
vsteel = 0.3,
EAI = 70 GPa, vAI = 1/3
diameter of steel ball = 20-mm
Applied force = 1 kN force
density of steel ( ρ ) = 8050 kg/m^3
weight of steel = ρvg = 0.33 N
Calculate the size of
i) contact patch
size of contact patch = [tex]\sqrt[3]{\frac{3FR}{4E} }[/tex] ----------- ( 1 )
where: F = 1000 + 0.33 = 1000.33 N , r = 0.01 m,
E = 57.26 * 10^9 ( calculated value )
Input values into equation 1
size of contact patch ( a ) = 0.0806 mm
ii) maximum contact pressure
P = 3F / 2πa^2
= ( 3 * 1000.33 ) / 2π(0.0806)^2
= 735.588 MPa
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This is a test. Please ignore
Explanation:
Test
Assume we have one road section which has 3 lanes in both directions. If the Sf for both direction is 75 mph, and Dj for both direction is 200 veh/mi/ln. Estimate the S0, D0 (veh/mi/ln) and maximum Vm (veh/hr) for either direction.
Answer:
i) 3750 veh/hr/ln
ii) 100 veh/mi/In
iii) 37.5 mph
Explanation:
number of lanes = 3
sf for both directions = 75 mph ( free mean speed )
Dj for both directions = 200 veh/mi/In
Calculate the value of S0, D0 (veh/mi/ln) and maximum Vm (veh/hr)
For either direction we will consider the total volume = 3 lanes
value of Dj = 3 lanes * 200 = 600 veh/mi/
i) value of SO
= ( Dj * sf ) / 4 = ( 600 * 75 ) / 4 = 11250 veh/hr = 3750 veh/hr/lane
ii) Value of DO
DO = Dj / 2 = 200 /2 = 100 veh/mi/In
iii) Value of Vm
= sf /2 = 75 / 2 = 37.5 mph
Hot combustion gases, modeled as air behaving as an ideal gas, enter a steady-state turbine at 145 psi, 2700oR, and exit at 29 psi and 1974oR. The power output is 74.26 hp, and heat transfer from the turbine to the surroundings occurs at a rate of 14 BTU/s.
Required:
Determine the power output of the turbine, in hp.
Hot combustion gases, modeled as air behaving as an ideal gas, enter a steady-state turbine at 145 psi, 2700oR, and exit at 29 psi and 1974oR. The power output is 74.26 hp, and heat transfer from the turbine to the surroundings occurs at a rate of 14 BTU/s.
Required:
a)Determine the power output of the turbine, in hp.
b) The Flow rate
Answer:
a) [tex]w=74.26hp[/tex]
b) [tex]m=0.22[/tex]
Explanation:
From the question we are told that:
Initial Pressure [tex]p_1= 145 psi[/tex]
Initial Temperature [tex]T_1 =2700oR=>2240.33^oF[/tex]
Final Pressure [tex]p_2= 29 psi[/tex]
Final Temperature [tex]t_2=1974oR=>1514.33^oF[/tex]
Output Power [tex]w=74.26hp[/tex]
Heat transfer Rate [tex]Q=14BTU/s[/tex]
Generally the equation for Steady flow energy is mathematically given by
[tex]Q-w=m(h_2-h_1)[/tex]
Where
[tex]m=Flow\ rate[/tex]
From Steam table
[tex]h_1=704btu/ib (at\ p_1= 145\ psi,\ T_1 =2700oR=>2240.33^oF )[/tex]
[tex]h_2=401btu/ib (at\ p_2= 29psi\ t_2=1974oR=>1514.33^oF )[/tex]
Therefore
[tex]-14-74.26=m(401-704)[/tex]
[tex]m=\frac{-14-74.26}{(401-704)}[/tex]
[tex]m=0.22[/tex]
Consider the same piping system. this time, the same pipe is buried underground. assuming that there is a constant heat flux of 100w/m^2 from the outer surfance of the pipe to the soil determine the exit temperature of the water.
a. 129.1
b. 111.1
c. 82.1
d. 68.1
Complete Question
Complete Question is attached below
Answer:
Option A
Explanation:
From the question we are told that:
inner Diameter of pipe [tex]d_i=100^c[/tex]
Thickness [tex]t=50mm[/tex]
Outer diameter of pipe [tex]d_o=1.1m[/tex]
Length [tex]l=5m[/tex]
Temperature [tex]T_i=130^oC[/tex]
Generally the equation for Heat Balance is mathematically given by
[tex]q*\pi d_oL=mC_p(T_i-T_o)[/tex]
Therefore
[tex]T_o=T_i+\frac{q*\pi d_oL}{mC_p}[/tex]
[tex]T_o=130+\frac{100*3.142 *1.1*5}{0.5*4000}[/tex]
[tex]T_o=129.136^oC[/tex]
Therefore the exit temperature of the water.is [tex]T_o=129.136^oC[/tex]
Option A
7. The binary addition 1 + 1 + 1 gives
11 [2-bit]
011 [3-bit]
0011 [4-bit]
________
1 + 1 + 1 = 3
________
3 = 2 + 1
2¹ 2⁰
3 = (.. × 0) + (2¹ × 1) + (2⁰ × 1)
3 = ..011
Since 2³, 2⁴, 2⁵, .. are not used, they are represented as 0.
[ 2⁷ 2⁶ 2⁵ 2⁴ 2³ 2² 2¹ 2⁰ ]
[ 128 64 32 16 8 4 2 1 ]
A wastewater treatment plant treats 20 MGD of wastewater containing 950 mg/L of suspended solids in a primary clarifier that has a 20% suspended solids removal efficiency. The rate of sludge collection, the flow rate out the bottom of the clarifier, is 0.08 MGD.
a) What is the solids concentration (in mg/L) in the sludge leaving the clarifier?
b) What mass of solids (in kg/y) is removed annually by the primary clarifier?
Answer:
a) 47500 mg/L
b) 5250366.444 kg/year
Explanation:
Given data:
suspended solids removal efficiency = 20%
Flowrate in the primary clarifier ( Q ) = 20 MGD ( change to Liters/day
Q = 20* 10^6 * 3.785412 Liters /day
settled concentration ( St ) = 950mg/L * 0.2 = 190 mg/L
amount of settled solid = Q * St
= ( 20* 10^6 * 3.785412 ) * 190 = 14384.5656 kg/day
∴ Amount going into sludge with a flowrate of 0.08 MGD = 14384.5656 kg/day
a) concentration of solid in sludge ( leaving the clarifier )
= amount of settled solid / flow rate out of the clarifier in liters/day
= 14384.5656 / ( 0.08 * 10^6 * 3.785412 )
= 0.0475 kg/L
= 47500 mg/L
b) Determine mass of solids that is removed annually
= 14384.5656 kg/day * 365 days
= 5250366.444 kg/year
Find at the terminals of the circuit
đạo hàm hàm boole là gì
Answer:
đạo hàm hàm boole là gì
Explanation:
Định nghĩa: Ký hiệu B = {0, 1} và Bn = {(x1, x2, …, xn) | xiB, 1≤ i ≤ n}, ở đây
B và Bn là các đại số Boole (xem 2) và 3) của Thí dụ 1). Biến x được gọi là một biến Boole nếu nó nhận các giá trị chỉ từ B. Một hàm từ Bn vào B được gọi là một hàm Boole (hay hàm đại số lôgic) bậc n.
Các hàm Boole cũng có thể được biểu diễn bằng cách dùng các biểu thức được
tạo bởi các biến và các phép toán Boole (xem Bảng 1 trong Thí dụ 1). Các biểu thức
Boole với các biến x1, x2, …, xn được định nghĩa bằng đệ quy như sau:
- 0, 1, x1, x2, …, xn là các biểu thức Boole.
- Nếu P và Q là các biểu thức Boole thì P, PQ và P+Q cũng là các biểu thức Boole.
Mỗi một biểu thức Boole biểu diễn một hàm Boole. Các giá trị của hàm này nhận
được bằng cách thay 0 và 1 cho các biến trong biểu thức đó.
Hai hàm n biến F và G được gọi là bằng nhau nếu F(a1, a2, …, an)=G(a1, a2, …,an)
với mọi a1, a2, …, anB. Hai biểu thức Boole khác nhau biểu diễn cùng một hàm Boole
được gọi là tương đương. Phần bù của hàm Boole F là hàm F với F (x1, x2, …, xn) =
),...,,( 1 2 nxxxF . Giả sử F và G là các hàm Boole bậc n. Tổng Boole F+G và tích Boole
FG được định nghĩa bởi:
(F+G)(x1, x2, …, xn) = F(x1, x2, …, xn)+G(x1, x2, …, xn),
(FG)(x1, x2, …, xn) = F(x1, x2, …, xn)G(x1, x2, …, xn).
A 2*8 inches wood member has a length =11 ft it's density is =30 Lb/ft^3 find the actual weight of this member in Lb
Answer:
359.046 Ib
Explanation:
density = m / v ---- ( 1 )
m = mass
v = volume = l * b * h
Given data :
density = 30 Ib / ft^3
l = 2 inches = 0.1667 ft
b = 8 inches = 0.6667 ft
h = 11 ft
v ( volume ) = 0.1667 * 0.6667 * 11 = 1.22 ft^3
back to equation 1
m = 30 * 1.22 = 36.6 Ib
Actual weight ( F ) = m * g
= 36.6 * 9.81 = 359.046 Ib.
Explain the advantages of using register indirect addressing mode over direct addressing mode with an 8051 assembly code. Also provide an example where it is inefficient to code using register indirect addressing mode.
When you double the velocity, you _____ the kinetic energy.
Answer:
you quadruple the kinetic energy
vertical gate in an irrigation canal holds back 12.2 m of water. Find the average force on the gate if its width is 3.60 m. Report your answer with proper units and 3 sig figs.
Answer:
The right solution is "2625 kN".
Explanation:
According to the question,
The average pressure will be:
= [tex]density\times g\times \frac{h}{2}[/tex]
By putting values, we get
= [tex]1000\times 9.8\times \frac{12.2}{2}[/tex]
= [tex]1000\times 9.8\times 6.1[/tex]
= [tex]59780[/tex]
hence,
The average force will be:
= [tex]Pressure\times Area[/tex]
= [tex]59780\times 3.6\times 12.2[/tex]
= [tex]2625537 \ N[/tex]
Or,
= [tex]2625 \ kN[/tex]
Consider a single crystal of nickel oriented such that a tensile stress is applied along a [001] direction. If slip occurs on a (111) plane and in a [101]direction and is initiated at an applied tensile stress of 13.9 MPa (2020 psi), compute the critical resolved shear stress
Answer:
[tex]\mathbf{\tau_c =5.675 \ MPa}[/tex]
Explanation:
Given that:
The direction of the applied tensile stress =[001]
direction of the slip plane = [[tex]\bar 1[/tex]01]
normal to the slip plane = [111]
Now, the first thing to do is to calculate the angle between the tensile stress and the slip by using the formula:
[tex]cos \lambda = \Big [\dfrac{d_1d_2+e_1e_2+f_1f_2}{\sqrt{(d_1^2+e_1^2+f_1^2)+(d_2^2+e_2^2+f_2^2) }} \Big][/tex]
where;
[tex][d_1\ e_1 \ f_1][/tex] = directional indices for tensile stress
[tex][d_2 \ e_2 \ f_2][/tex] = slip direction
replacing their values;
i.e [tex]d_1[/tex] = 0 ,[tex]e_1[/tex] = 0 [tex]f_1[/tex] = 1 & [tex]d_2[/tex] = -1 , [tex]e_2[/tex] = 0 , [tex]f_2[/tex] = 1
[tex]cos \lambda = \Big [\dfrac{(0\times -1)+(0\times 0) + (1\times 1) }{\sqrt{(0^2+0^2+1^2)+((-1)^2+0^2+1^2) }} \Big][/tex]
[tex]cos \ \lambda = \dfrac{1}{\sqrt{2}}[/tex]
Also, to find the angle [tex]\phi[/tex] between the stress [001] & normal slip plane [111]
Then;
[tex]cos \ \phi = \Big [\dfrac{d_1d_3+e_1e_3+f_1f_3}{\sqrt{(d_1^2+e_1^2+f_1^2)+(d_3^2+e_3^2+f_3^2) }} \Big][/tex]
replacing their values;
i.e [tex]d_1[/tex] = 0 ,[tex]e_1[/tex] = 0 [tex]f_1[/tex] = 1 & [tex]d_3[/tex] = 1 , [tex]e_3[/tex] = 1 , [tex]f_3[/tex] = 1
[tex]cos \ \phi= \Big [ \dfrac{ (0 \times 1)+(0 \times 1)+(1 \times 1)} {\sqrt {(0^2+0^2+1^2)+(1^2+1^2 +1^2)} } \Big][/tex]
[tex]cos \phi= \dfrac{1} {\sqrt{3} }[/tex]
However, the critical resolved SS(shear stress) [tex]\mathbf{\tau_c}[/tex] can be computed using the formula:
[tex]\tau_c = (\sigma )(cos \phi )(cos \lambda)[/tex]
where;
applied tensile stress [tex]\sigma =[/tex] 13.9 MPa
∴
[tex]\tau_c =13.9\times ( \dfrac{1}{\sqrt{2}} )( \dfrac{1}{\sqrt{3}})[/tex]
[tex]\mathbf{\tau_c =5.675 \ MPa}[/tex]
For a metal that has a yield strength of 690 MPa and a plane strain fracture toughness (KIc) of 32 MPa-m1/2, compute the minimum component thickness for which the condition of plane strain is valid.
Answer:
the minimum component thickness for which the condition of plane strain is valid is 0.005377 m or 5.38 mm
Explanation:
Given the data in the question;
yield strength σ[tex]_y[/tex] = 690 Mpa
plane strain fracture toughness K[tex]_{Ic[/tex] = 32 MPa-[tex]m^{1/2[/tex]
minimum component thickness for which the condition of plane strain is valid = ?
Now, for plane strain conditions, the minimum thickness required is expressed as;
t ≥ 2.5( K[tex]_{Ic[/tex] / σ[tex]_y[/tex] )²
so we substitute our values into the formula
t ≥ 2.5( 32 / 690 )²
t ≥ 2.5( 0.0463768 )²
t ≥ 2.5 × 0.0021508
t ≥ 0.005377 m or 5.38 mm
Therefore, the minimum component thickness for which the condition of plane strain is valid is 0.005377 m or 5.38 mm
Ratio equivalent to 12 red beans to 5 total beans
Hello!
The answer to this question as a percentage is 240%
Answer:
n
Explanation:
Sally made a diagram to show one way that Earth’s systems interact near a volcano.
Some General Motors flex fuel vehicles do not use a fuel sensor to measure the percentage of ethanol in the fuel. These vehicles use ________ as a base fuel to calculate the percentage using oxygen sensor readings.
La fuerza necesaria para girar los birlos de una llanta es de 40 N, si se tiene una cruceta de 0.5m. ¿Cuál es el torque del birlo?
To Find :
The torque of the stud.
Solution :
We know, torque can be calculated by force and distance between the center and force applied.
So,
[tex]\tau = F\times R\\\\\tau = 40 \times 0.5 \ N .\ m\\\\\tau = 20 \ N .\ m[/tex]
Therefore, the torque on the stud is 20 N m .
Greek engineers had the unenviable task of moving largecolumns from the quarries to the city.One engineer,Chersiphron, tried several different techniques to do this. Onemethodwas to cut pivot holes into the ends of the stone andthen use oxen to pull the column. The 5-ft diameter columnweighs 14,000 lbs, andthe team of oxen generates a constantpull force of 2,000 lbs on the center of the cylinder,G. Knowingthat the column starts from rest and rolls without slipping,determine:(a) the velocity of its center,G,after it has moved7ft,and (b) the minimum static coefficient of friction that will keepit from slipping.
Answer:
yea
Explanation:
okkudjeheud email and delete the electronic version of this communication
A steel plate of width 120mm and thickness of 20mm is bent into a circular arc radius of 10. You are required to calculate the maximum stress induced and the bending moment which will give the maximum stress. You are given that E=2*10^5
Answer:
Hence the magnitude of the pure moment m will be [tex]2\times 10^5.[/tex]
Explanation:
Width of steel fleet = 120 mm The thickness of steel fleet = 10 mm Let the circle of radius = 10 mNow,
We know that,
[tex]\frac{M}{I} = \frac{E}{R}[/tex]
Thus, [tex]M =\frac{EI}{R}[/tex]
Here
R = 10000 mm
[tex]I=\frac{1}{12}\times 120\times 10^{3}\\= 10^{4} mm^{4}[/tex]
[tex]E=2\times 10^{5}n/mm^{2}\\\\E=2\times 10^{5}n/mm^{2}\\\\M={(2\times 10^{5}\times 10^{4})/{10000}}\\\\M=2\times 10^{5}[/tex]
Hence, the magnitude of the pure moment m will be [tex]2\times 10^5.[/tex]
A spring having a stiffness k is compressed a distance δ. The stored energy in the spring is used to drive a machine which requires power P. Determine how long the spring can supply energy at the required rate.
Units Used: kN = 103 N
Given: k = 5 kN/m; δ = 400 mm; P = 90 W
Answer:
30w
Explanation:
Is it permissible to install recessed fixture directly against wood ceiling joists? Explain why or why not.
Answer:
No
Explanation:
It is not permissible to install recessed fixture directly against wood ceiling joists when the label on the fixture does not indicate that it can be used for Insulation in contact with the recessed fixture .
Because The trim finishing and points of support of openings in finished surfaces are not allowed to be in contact with the combustible materials
4 points
Para transportar una Unidad
Evaporadora Horizontal que mide 5
pies de largo, 3 pies de ancho y 4
pies de alto se necesita un volumen
de: *
23 pies cúbicos
12 pies cúbicos
60 pies cúbicos
O
63 pies cúbicos
Planos de construcción
Answer:
4 points
Para transportar una Unidad
Evaporadora Horizontal que mide 5
pies de largo, 3 pies de ancho y 4
pies de alto se necesita un volumen
de: *
23 pies cúbicos
12 pies cúbicos
60 pies cúbicos
O
63 pies cúbicos
Planos de construcciónExplanation:
The answer to the question mark the park in a
The current flowing into the collector lead of a certain bipolar junction transistor (BJT) is measured to be 1 nA. If no charge was transferred in or out of the collector lead prior to t = 0, and the current flows for 1 min. calculate the total charge which crosses into the collector.
Answer:
the total charge which crosses into the collector is 60 nC
Explanation:
Given the data in the question;
current flowing into the collector lead of the bipolar junction transistor (BJT); i = 1 nA = 10⁻⁹ A
no charge was transferred in or out of the collector lead prior to t = 0
the current flow time t = 1 min = 60 sec
Now we write the relation between current, charge, and time;
i = dq / dt
where i is current, q is charge and t is time. { d refers to change }
Now,
[tex]q=\int\limits^t_{t=0} {i(t)} \, dt[/tex]
[tex]q=\int\limits^{t=60}_{t=0} { (10^{-9}) } \, dt[/tex]
[tex]q = ( 10^{-9}) (t)_0^{60[/tex]
[tex]q = ( 10^{-9}) ( 60 - 0 )[/tex]
q = 60 × 10⁻⁹ C
q = 60 nC
Therefore, the total charge which crosses into the collector is 60 nC
What competitive strategy was used by Regal Marine?
Answer:
Regal Marine uses a strategy of product differentiation, which constantly introduces new products with new innovations and new styling to stay competitive in the luxury performance boat market.
3. Which of these instruments is used to measure wind speed? A. anemometer C. wind sock B. thermometer D. wind vane It is an instrument that can show both the wind speed and direction. A. Anemometer C. Wind sock B. thermometer D. wind vane 4. 5. At what time does air temperature changes? A. from time to time C. in the evening only B. in the afternoon only D. in the morning only
Answer:
wind vane if it can be used to show wind speed and the other is a
Explanation:
please mark 5 star if im right and brainly when ya can
what would the current through the Load curve look like when the alternating current source S has the following shape Draw the shape of the current vs time curve and assume that the diodes are perfect so that current goes in one direction exclusively without delay or loss
Answer:
Following are the response to the given question:
Explanation:
In the given question, A curve one would be to "reject" them. Within this way, people are directly non-confrontationally off from their amorous interests or advances. The curve looks much like a current through the unidirectional load, and it has only a good maximum value. It seems like the total rating of the complete wave rectifier that is illustrated below, the present vas temporal curve please find it.
HELP PLEASE!!!!
The question is up and the answer is down but i don't know what should i write mr want the answer as a paragraph HELPPOP
Answer:
DESCULPA MAS EU NÃO ENTENDI
After adding refrigerant to a nonpressurized container used with a system-dependent recovery
device, the pressure of the container will:
Select one:
A. Increase to the saturation point.
B. Remain at 0 psig.
C. Increase in proportion to the amount of refrigerant added.
D. Decrease in proportion to the refrigerant added.
There are different aspect to system-dependent recovery equipment. The pressure of the container will Increase to the saturation point.
System-dependent is known to be a passive recovery system. It is known as the recovery of refrigerant from a system by using the refrigeration system's internal pressure and/or compressor so as to simulate the recovery process.
System-dependent equipment is not used used with appliances that has more than 15 pounds of refrigerant.
When refrigerant pressure increases, saturation temperature is known to also increases and as pressure decreases, the saturation temperature will also decrease. Saturation is known to have a pressure-temperature relationships for all refrigerants.
Learn more about saturation from
https://brainly.com/question/4529762