As a result, aluminium (Al) and 7.37 litres of hydrochloric acid (HCl) can react to produce 225.46 moles of hydrogen gas (H2).
8.0 moles of Al interacting with HCl can produce how many moles of H2?As a result, when 8 moles of aluminium are entirely consumed during the process of dissolving it in HCl solution, 12 moles of hydrogen gas are created.
The chemical reaction between aluminium (Al) and hydrochloric acid (HCl) has the following balanced chemical equation:
[tex]3 H2 + 2 AlCl3 = 2 HCl + 2 Al[/tex]
According to the equation, 2 moles of HCl result in 3 moles of H2. In order to determine the amount of H2 generated, we must first determine how many moles of HCl are contained in 7.37 litres of acid.
The following formula can be used to determine the quantity of HCl:
Volume in litres times concentration in moles per litre equals moles.
Since the HCl concentration is not specified in the inquiry, we are unable to immediately calculate the moles. However, we may convert the volume in litres to the mass in grams using the density of HCl, and then use the molar mass of HCl to calculate the number of moles.
At standard circumstances (0 °C and 1 abm), HCl has a density of roughly 1.49 g/mL. As a result, 7.37 litres of HCl have the following mass:
Density equals mass, therefore 7.37 L times 1.49 g/mL equals 10.9763 kg.
Since HCl has a molar mass of about 36.46 g/mol, there are the following moles of HCl:
[tex]10.9763 kg / 36.46 g/mol = 300.61 mol is the formula for moles of HCl.[/tex]
Now, we can determine the number of moles of H2 created using the mole ratio from the balanced equation: moles of[tex]H2 = (moles of HCl / 2) x (3/2) = (300.61 mol / 2) x (3/2) = 225.46 mol[/tex]
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CaCO3 + 2HCI =CaCl2 + H₂O + CO2
5. Calcium carbonate (CaCO3) combines with HCl to produce calcium chloride (CaCl₂),
water, and carbon dioxide gas (CO₂). How many grams of HCI are required to react with
6.35 mol CaCO3?
463.5 grams of HCl are required to react with 6.35 moles of CaCO₃.
What is meant by molar mass?Mass of one mole of substance is referred to as the molar mass. The molar mass of a substance can be calculated by adding up the atomic masses of all the atoms in a molecule.
Balanced chemical equation for the reaction between calcium carbonate (CaCO₃) and hydrochloric acid (HCl) is: CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
6.35 mol CaCO₃ * 2 mol HCl / 1 mol CaCO₃ = 12.7 mol HCl
Now, we use the molar mass of HCl (36.46 g/mol) to convert from moles to grams: 12.7 mol HCl * 36.46 g/mol = 463.5 g HCl
Therefore, 463.5 grams of HCl are required to react with 6.35 moles of CaCO₃.
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Given:
2KI → 2K + I2
Calculate the number of moles of iodine produced in the decomposition of 7.0 moles of potassium iodide (KI). Express your answer to the correct number of significant figures.
Since 2 moles of KI produce 1 mole of I2, then 7.0 moles of KI will produce 7.0/2 moles of I2. In other words, 3.5 moles of I2 will be produced
what is the compound formed between two or more non metal element that share electron
A compound formed between two or more non-metal elements that share electrons is called a covalent compound or a molecular compound.
In covalent compounds, the atoms share electrons in order to achieve a full outer shell of electrons and become more stable. Covalent compounds typically have low melting and boiling points, are often gases or liquids at room temperature, and are poor conductors of electricity. Examples of covalent compounds include water (H2O), carbon dioxide (CO2), and methane [CH4].
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Calculate the standard change in Gibbs free energy for the reaction at 25 °C. Refer to the ΔG°f values.
Fe2O3(s)+2Al(s)⟶Al2O3(s)+2Fe(s)
Δ°rxn=
The standard change in Gibbs free energy for the given reaction at 25°C is -757.9 kJ/mol.
Describe Gibbs Energy.Gibbs energy, also known as Gibbs free energy, is a thermodynamic quantity used to determine the maximum amount of work that can be obtained from a system at a constant temperature and pressure. It is denoted by the symbol G and is named after the American physicist Josiah Willard Gibbs who introduced the concept in the late 19th century.
Gibbs energy is defined as the difference between the enthalpy of a system and the product of the temperature and the entropy of the system:
G = H - TS
where H is the enthalpy, T is the temperature in Kelvin, and S is the entropy of the system.
The Gibbs energy is related to the equilibrium constant of a reaction through the following equation:
ΔG = -RTlnK
To calculate the standard change in Gibbs free energy for the given reaction at 25°C, we need to use the ΔG°f values (standard Gibbs free energy of formation) for the reactants and products involved in the reaction.
The ΔG°f values for Fe₂O₃(s), Al(s), Al₂O₃(s), and Fe(s) can be found in a table of thermodynamic data and are:
ΔG°f [Fe₂O₃(s)] = -824.2 kJ/mol
ΔG°f [Al(s)] = 0 kJ/mol
ΔG°f [Al₂O₃(s)] = -1582.3 kJ/mol
ΔG°f [Fe(s)] = 0 kJ/mol
The standard change in Gibbs free energy for the reaction can be calculated using the following equation:
Δ°rxn = ΣΔG°f(products) - ΣΔG°f(reactants)
Substituting the values, we get:
Δ°rxn = [ΔG°f(Al₂O₃(s)) + 2ΔG°f(Fe(s))] - [ΔG°f(Fe₂O₃(s)) + 2ΔG°f(Al(s))]
Δ°rxn = [(-1582.3 kJ/mol) + 2(0 kJ/mol)] - [(-824.2 kJ/mol) + 2(0 kJ/mol)]
Δ°rxn = -757.9 kJ/mol
Therefore, the standard change in Gibbs free energy for the given reaction at 25°C is -757.9 kJ/mol.
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Which of the following atoms has the largest atomic radius?
Sr
At
I
Ba
I think it is Ba since the radius increases along the group.but decreases along the period
Answer:
Ba
Explanation:
Ba
what volume of SO3 would be produced by complete reaction of 100cm3 of HO2 with O2?
The volume of [tex]SO_{3}[/tex] would be produced by complete reaction of 100cm3 of [tex]H_{2}O[/tex]with [tex]O_{2}[/tex] is at STP is 60.03L.
Volume22.4 L divided by 2.68 moles per mole yields 60.03 L [tex]SO_{3}[/tex].
describing the elements contributing to the response,
[tex]2SO_{2(g)}+ O_{2} = 2SO_{3}[/tex]
In this instance, [tex]SO_{3}[/tex] and [tex]O_{2}[/tex] have a mole ratio of 2:1. Assume the reaction takes place at STP, where 1 mole of any gas has a volume of 22.4 L. Consequently, 30 [tex]dm^{3}[/tex]of [tex]O_{2}[/tex] (1 dm3 = 1 L) equals 30 L of [tex]O_{2}[/tex] and 30 L/22.4 L times 1 mole equals 1.34 moles of [tex]O_{2}[/tex].
According to stoichiometry, when 1.34 moles of [tex]O_{2}[/tex]are reacted with [tex]SO_{2}[/tex], 2.68 moles of [tex]SO_{3}[/tex] are created, or 2/1 x 1.34 moles of [tex]SO_{3}[/tex].
This means that the amount of [tex]SO_{3}[/tex]produced will be (2.68 moles/1 mole) x 22.4 L = 60.03 L [tex]SO_{3}[/tex].
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The two possible units of molarity are
Answer: The units for molarity are moles/liter.
Similarly, the equation to find molarity is moles divided by liters.
Explanation:
mol / L is a unit of molar concentration. These are the number of moles of dissolved material per liter of solution. 1 mol / L is also called 1M or 1molar. Mol / m3 is also a unit of molar concentration.
Molarity is expressed in units of moles per liter (mol / L). This is a very common unit, so it has its own symbol, which is the uppercase M. A solution with a concentration of 5 mmol / l is called a 5 M solution or has a concentration value of 5 mol.
The molar concentration of the solution is equal to the number of moles of the solute divided by the mass of the solvent (kilogram), and the molar concentration of the solution is equal to the number of moles of the solute divided by the volume of the solution (liter). increase.
Question 4 of 10
Based on information from the periodic table, what does this image
represent?
= 9 Protons
= 10 Neutrons
= 10 Electrons
A.Neutral fluorine
B. A positively charged fluoride ion
C. A negatively charged fluoride ion
D. A neutral neon atom
48 grams of MgCl2 is dissolved in 500g of water, DENSITY OF
WATER = 1 kg/1L. What is the MOLALITY of this solution? Please
show your steps.
mol
kg
m =
or
m = mol = kg
Step1: given information:
solute=
(UNIT=
Solvent =
(UNIT =
)
)
The molality of the solution is 1.080 mol/kg of a 48 grams of MgCl2 is dissolved in 500g of water, density of water = 1 kg/1L.
How to calculate molality?Taking the moles of solute and dividing it by the kilograms of solvent yields the molality of a solution.
Molality is calculated as follows: kg of solvent/kg of solute
500 g, or 0.500 kg, is the mass of the solvent.
MgCl2 molecular weight divided by its mass gives the amount of moles.
48 g / 95.2 g m o l 1 equals the quantity of moles of magnesium chloride.
0.504 moles of MgCl2 are present in one mole.
Molality is calculated as 0.504moles per kilogram.
Molality is equal to 1.080 mol k g 1.
As stated in the definition, molality is the "total moles of a solute contained in a kilogram of a solvent." The terms "molality" and "molal concentration" are synonymous. It is a measurement of a solvent.
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The speed of sound in diamond, 12,000 meters/sec, is roughly four times the
speed in air. What is the speed of sound in diamond in feet per hour (ft/hr)?
Answer:
The speed of sound in diamond is about **12,000 metres per second (39,000 ft/s)** which is about **35 times** its speed in air³. To convert this to feet per hour (ft/hr), we can use the following conversion factors:
1 meter = 3.28084 feet
1 second = 3600 hours
Therefore, the speed of sound in diamond in feet per hour (ft/hr) is:
12,000 m/s x 3.28084 ft/m x 3600 s/hr = 141,732,480 ft/hr
the rate constant for a specific reaction has been determined at the following temps. 82 C, k= 3.97x10^-3 M^-1 x s^-1 , 125 C, k= 2.07x10^-2 ,M^-1 x s^-1. a) calculate the activation energy for the reaction
b) If data points were plotted in Arrhenius plot, what would the slope of the line be?
c) at what temp will the rate constant have k=1.00x10^-3 M^-1 x s^-1
A) the activation energy is = 66.5 kJ/mol
B) the slope of the line in this case would be -8000 K^-1
C) the temperature at which the rate constant is 1.00x10^-3 M^-1 x s^-1 is 408 K (135°C).
The activation energy, slope and temperaturea) To calculate the activation energy, we can use the Arrhenius equation:
k = Ae^(-Ea/RT)
where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant (8.314 J/mol x K), and T is the temperature in Kelvin.
Taking the natural logarithm of both sides of the equation, we get:
ln(k) = ln(A) - (Ea/RT)
We can use the two sets of data to set up two equations:
ln(k1) = ln(A) - (Ea/RT1)
ln(k2) = ln(A) - (Ea/RT2)
Solving for Ea by taking the difference between the two equations:
ln(k2/k1) = (Ea/R) [(1/T1) - (1/T2)]
Ea = -R ln(k2/k1) / [(1/T1) - (1/T2)]
Plugging in the values:
Ea = -8.314 J/mol x K x ln(2.07x10^-2 / 3.97x10^-3) / [(1/398 K) - (1/398 K)]
Ea = 66.5 kJ/mol
b) In an Arrhenius plot, ln(k) is plotted against 1/T, and the slope of the line is equal to -Ea/R. Therefore, the slope of the line in this case would be:
slope = -Ea/R = -(66.5 x 10^3 J/mol) / (8.314 J/mol x K) = -8000 K^-1
c) To solve for the temperature at which the rate constant is 1.00x10^-3 M^-1 x s^-1, we can rearrange the Arrhenius equation:
k = Ae^(-Ea/RT)
ln(k) = ln(A) - (Ea/RT)
1/T = (ln(k) - ln(A)) / (-Ea/R)
T = -R / (Ea ln(k) - ln(A))
Plugging in the values:
T = -8.314 J/mol x K / [(66.5 x 10^3 J/mol) ln(1.00x10^-3) - ln(3.97x10^-3)]
T = 408 K
Therefore, the temperature at which the rate constant is 1.00x10^-3 M^-1 x s^-1 is 408 K (135°C).
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15.0 moles of gas are in a 6.00 L tank at 20.3 ∘C . Calculate the difference in pressure between methane and an ideal gas under these conditions. The van der Waals constants for methane are a=2.300L2⋅atm/mol2 and b=0.0430 L/mol.
Under the given circumstances, the pressure difference between methane and an ideal gas is 58.5 atm.
What is an ideal gas?An ideal gas is a theoretical gas composed of a large number of small particles that have zero volume, do not interact with each other, and are in constant random motion. The behavior of an ideal gas is described by the ideal gas law, which relates the pressure, volume, temperature, and number of moles of the gas.
The van der Waals equation can be used to figure out the pressure difference between methane and an ideal gas under these circumstances:
(P + a n² / V²)(V - n b) = n R T
where P is the pressure, n is the number of moles, V is the volume, T is the temperature in Kelvin, R is the ideal gas constant (0.08206 L·atm/K·mol), a and b are the van der Waals constants for methane.
First, we can calculate the pressure of an ideal gas under these conditions using the ideal gas law:
P = n R T / V
P = (15.0 mol) (0.08206 L·atm/K·mol) (293.45 K) / (6.00 L)
P = 299.8 atm
Next, we can use the van der Waals equation to calculate the pressure of methane under these conditions:
(P + a n² / V²)(V - n b) = n R T
(P + (2.300 L²·atm/mol²) (15.0 mol)² / (6.00 L)²) ((6.00 L) - (15.0 mol) (0.0430 L/mol)) = (15.0 mol) (0.08206 L·atm/K·mol) (293.45 K)
Simplifying the equation gives:
P + 1.319 atm = 359.6 atm
P = 358.3 atm
As a result, under these circumstances, the pressure difference between methane and an ideal gas is:
ΔP = P (methane) - P (ideal gas) = 358.3 atm - 299.8 atm = 58.5 atm.
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Which reactions have a positive Δrxn?
o A(g)+B(g)⟶C(g)
o A(g)+B(g)⟶3C(g)
o A(s)+B(s)⟶C(g)
o 2A(g)+B(g)⟶C(g)
The reactions with a positive Δrxn are:
A(g) + B(g) ⟶ 3C(g)
A(s) + B(s) ⟶ C(g)
What is (Δrxn) of a reaction?The entropy change (Δrxn) of a reaction indicates the change in the degree of randomness or disorder of the system during the reaction. If the number of product molecules is greater than the number of reactant molecules, the disorder of the system usually increases, resulting in a positive Δrxn. Therefore, we can determine the answer by analyzing the stoichiometry of each reaction:
A(g) + B(g) ⟶ C(g)
In this reaction, the number of product molecules is less than the number of reactant molecules, so the disorder of the system decreases. Therefore, this reaction has a negative Δrxn.
A(g) + B(g) ⟶ 3C(g)
In this reaction, the number of product molecules is greater than the number of reactant molecules, so the disorder of the system increases. Therefore, this reaction has a positive Δrxn.
A(s) + B(s) ⟶ C(g)
In this reaction, the solid reactants are combining to form a gaseous product. The disorder of the system is expected to increase, resulting in a positive Δrxn.
2A(g) + B(g) ⟶ C(g)
In this reaction, the number of product molecules is less than the number of reactant molecules, so the disorder of the system decreases. Therefore, this reaction has a negative Δ rxn.
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what is a type of atom that can be bonded with water and hydrogen
Answer: Oxygen (??)
Explanation: Im not sure but smth like H2O (my brain is not braining T-T)
Using the thermodynamic information in the ALEKS Data tab, calculate the standard reaction free energy of the following chemical reaction 2NH3 =N2H4 +H2
The reaction [tex]2NH_3=N_2H_4+H_2[/tex] has a standard reaction free energy of -62.4 kJ/mol.
What is energy?Energy is the capacity to carry out tasks or affect change. It comes in a variety of shapes and sizes, including kinetic energy (energy of motion), potential energy (stored energy of position), thermal energy (heat), electrical, chemical, and nuclear energy. Energy is required for the survival and growth of all living things. Additionally, it is necessary for the operation of industries and equipment.
Equation can be used to get a reaction's standard reaction free energy.
ΔG°rxn = ΣΔG°f (products) - ΣΔG°f (reactants).
For the reaction [tex]2NH_3=N_2H_4+H_2[/tex], the ΔG°f values are as follows:
ΔG°f ([tex]2NH_3[/tex]) = -46.2 kJ/mol
ΔG°f ([tex]N_2H_4[/tex]) = -20.8 kJ/mol
ΔG°f ([tex]H_2[/tex]) = 0 kJ/mo
The equation yields the average reaction free energy (ΔG°rxn) of the reaction is:
ΔG°rxn = (2 x -20.8) - (-46.2)
= -62.4 kJ/mol
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A 1.5 L sample of a 0.44 M H Br solution is mixed with 2.2 L of a 0.080 M HCIO4 solution. What is the pH of the mixture?
If you are given one mole of NH2 and have an excess of H2, how many moles of NH3 can you produce?
You can only get 1 mole of ammonia (NH3) since NH2 is the limiting reactant
Lattice energy is an estimate of the bond
Answer:
strength in ionic compounds.
Explanation:
:)
Lattice energy is an estimate of the bond of strength. It denotes the amount of energy required to break down one mole of a solid ionic compound into its constituent gaseous ions.
What does the lattice energy represent?The strength of an ionic compound's ionic bonds is measured by lattice energy. It explains several properties of ionic solids, including their volatility, solubility, and hardness. An ionic solid's lattice energy cannot be measured directly.
How does lattice energy influence ionic compound solubility in water?The higher an ionic compound's lattice energy, the more difficult it is to disassemble the crystal lattice structure and dissolve it in water. As a result, compounds with high lattice energies are less soluble in water than those with low lattice energies.
What factors influence lattice energy?The value of lattice energy is determined by the charges on the two ions as well as the distance between them. The distance between the ions is directly proportional to their size.
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Complete question:
Lattice energy is an estimated bond of the bond:
A. conductivity
B. group
C. length
D. strength
Choose the correct option.
If the salt created from the reaction of a strong acid and a weak base is added to a solution, what will happen to the solution? A. The pH will decrease. B. The pH will increase. C. The pH will stay the same. D. More OH- ions will form. E. The H3O+ ions will decrease.
HELP ASAP
A 2.6 mol sample of N2 is held in a 4191 mL balloon at 89.9 atm. What temperature (in Celcius) is the gas at? Answer to one decimal place.
Answer: the temperature of the gas is approximately 16.1°C.
Explanation: PV=nRT Rearranging the equation gives us T = PV/(nR), with all variables defined as before. Convert mL to L: V = 4191 mL = 4.191 L. Use equation: T = (89.9 atm) x (4.191 L) / (2.6 mol x 0.08206 L atm/(mol K)). Simplify to get T = 289.2 K. Convert Kelvin to Celsius: T = 289.2 K - 273.15 = 16.1°C.
A flask filled to the 25.0 ml mark contain 29.97 g of a concentrated salt water solution. What is the density of the solution?
A concentrated saltwater solution weighing 29.97 g and fitting into a flask to the mark of 25.0 ml has a density of about 1199.2 g/L.
How is the density of the solution determined?By dividing the solution's mass by its volume, we may get its density: density = mass/volume
We need to know the density of water at the solution's temperature as well as the capacity of the flask up to the 25.0 ml level in order to calculate the volume of the solution.
Since 1 mL = 0.001 L, volume is equal to 25.0 mL, or 0.0250 L.
Now, we may determine the solution's density as follows:
1199.2 g/L or 29.97 g/0.0250 L is what is referred to as density.
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The ΔHvap of a certain compound is 32.77 kJ·mol−1 and its ΔSvap is 94.72 J·mol−1·K−1. What is the boiling point of this compound?
The compound's boiling point is around 73.65 °C.
Which spontaneous responses are positive?Unexpected Responses. Favorable reactions are those that cause the system's enthalpy to drop while its entropy rises. The reaction happens naturally when both of these conditions are true. Both endothermic and exothermic reactions, which absorb heat and release it, can occur spontaneously.
We can use the Gibbs-Helmholtz equation to solve for the boiling point:
ΔG = ΔH - TΔS
At boiling point, ΔG = 0, so we can solve for T:
T = ΔH/ΔS
Substituting the given values:
T = (32.77 kJ·mol−1) / (94.72 J·mol−1·K−1)
T = 346.8 K
Converting to Celsius:
Boiling point = 346.8 K - 273.15 = 73.65 °C
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If you started with 20.0 g of a radioisotope and waited for 3 half-lives to pass, then how much would remain? 2.50 g 5.00 g 10.0 g 15.0 g
The amount that would remain, given that 3 half-lives has pass when you started with 20.0 g is 2.50 grams (1st option)
How do i determine the amount that would remain?The following data were obtained from the question:
Original amount of radioisotope (N₀) = 20.0 gramsNumber of half-lives that has passed (n) = 3Amount remaining after 3 half-lives (N) = ?The amount remaining can be obtained as shown below:
N = N₀ / 2ⁿ
N = 20 / 2³
N = 20 / 8
N = 2.50 grams
Thus, we can conclude from the above calculation that the amount that would remain after 3 half-lives to pass is 2.50 grams (1st option)
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Answer:
2.50g
Explanation:
What are two basic aspects of science?
The Two Aspects of Science: Control over nature and understanding of nature must both be held in equal honor.
In order to estimate the population size of the woodlice in her garden, Jessica used the mark-recapture method: she trapped, marked and released 20 woodlice. Three days later, she trapped 15 woodlice and observed that 10 had marks. Use the following formula to estimate the woodlice population size: population size = 1st sample × 2nd sample ÷ 2nd sample that had been marked.
NEED HELP ASAP!!!!!!
To determine the size of the entire population: In the equation N = M, replace the variables of M solutions, R (number all marked recaptured), with T (total recaptured during second visit). T R = frac M T R N = RMT.
What is the mark-recapture method's formula?In order for the mark-recapture method to function, it must be assumed that the proportion the marked organisms that are recaptured inside the second sample corresponds to that of the original marked in the entire population. This equation R(recaptured)/C(captured in second sample)=M(marked initially)/N) illustrates this (total number in population).
Why do people employ the capture-recapture technique?It has been suggested that capture-recapture techniques be used to gauge a register's degree of completeness. These techniques were initially created to determine how big a confined animal colony was. The process aims to capture, tag, and release as many animals is possible in a given region all at once. This is known as the "capture" stage.
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How can you evaluate how well a transportation system meets the needs of a community?
four score and seven years ago (our father) brought this continent, a new nation,
answer our fathersif only 11.00g SnF2 were produced calculate percent yield
A. The mass (in grams) of SnF₂ that can be produced theoretically from the reaction is 13.20 g
B. The percentage yield of the reaction is 83.3%
A. How do i determine the mass produced theoretically?The mass of SnF₂ produced theorethically, can be obtained as shown below:
Sn + 2HF -> SnF₂ + H₂
Molar mass of Sn = 118.71 g/molMass of Sn from the balanced equation = 1 × 118.71 = 118.71 g Molar mass of SnF₂ = 156.71 g/molMass of SnF₂ from the balanced equation = 1 × 156.71 = 156.71 gFrom the balanced equation above,
118.71 g of Sn reacted to produce 156.71 g of SnF₂
Therefore,
10 g of Sn will react to produce = (10 × 156.71) / 118.71 = 13.20 g of SnF₂
Thus, the mass of SnF₂ produced is 13.20 g
B. How do i determine the percentage yield?The percentage yield for the reaction can be obtained as follow:
Actual yield of SnF₂ = 11 gTheoretical yield of SnF₂ = 13.20 gPercentage yield of SnF₂ =?Percentage yield = (Actual /Theoretical) × 100
Percentage yield of SnF₂ = (11 / 13.20) × 100
Percentage yield of SnF₂ = 83.3%
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Complete question:
See attached photo
The combustion of ethane (C2H6) produces CO2 and H2O:
2C2H6 (g) + 7O2 (g) → 4CO2 (g) + 6H2O (g)
How many moles of O2 are needed to react with 15.5 g of ethane?
When 3 g of a petroleum are burned with more oxygen than is required, 8.8 g of Atmospheric carbon dioxide plus 5.4 g liquid [tex]H_{2}O[/tex] are produced.
What happens when ethane gas ([tex]C_{2}H_6}[/tex]) and oxygen gas ([tex]O_{2}[/tex]) burn together?
Oxygen gas and ethane ([tex]C_{2}H_6}[/tex]) react to create water as well as carbon dioxide. Find the total quantity of carbon dioxide created when the reaction yield is 60% when 5 mol of methane is burned and 16 mol of oxygen initially. 2[tex]C_{2}H_4}[/tex]+7[tex]O_{2}[/tex] →4[tex]CO_{2}[/tex]+6[tex]H_{2}O.[/tex]
How many tumours of CO2 are created when 2.2 blackheads of [tex]C_{2}H_4}[/tex]are burned?
As a result, 2 m of carbon dioxide is generated from mole of a substance of [tex]C_{2}H_4} .[/tex] Thus, multiply 2.2 over 2 by 1 pot to get 2.2 moles for c into h or just a cross. It consists of 4.4 moles of carbon.
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Which of these pairs of atoms would experience a polar covalent bond?
Cl and Cl
K and Br
P and S
C and O
C and O since their electronegativity differs by quite a lot
The equation below represents the dissociation of vinegar which is a weak acid. How can you tell that it is an acid and it is weak? Just from looking at the equation.
Because it is not very effective at transferring [tex]H^{+}[/tex] ions to water, vinegar is a weak acid. Less than 0.4% of the [tex]CH_{3}CO_{2}H[/tex]molecules in a 1 M solution interact with water to create [tex]H_{3}O^{+}[/tex]and [tex]CH_{3}CO_{2}^{-}[/tex] ions. More than 99.6% of the acetic acid molecules are still whole.
Weak acidsAcids that partially dissociate in solution are referred to as weak acids. To put it another way, a weak acid is any acid that is not a strong acid. A weak acid's strength is influenced by how much it dissociates; the more it dissociates, the stronger the acid.In comparison to weak acids, strong acids have a lower pH. 2) Strong acids dissociate more, resulting in a lower pH (greater concentration of [tex]H^{+}[/tex] ions in solution). 3) This can be verified by usingFor more information on weak acid kindly visit to
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