4. Which of these is typically NOT a function of the flywheel?
OA. Power transfer to the transmission
OB. Engage the Starter
OC. Smooth out power pulses
OD. Balance the crankshaft

4. Which Of These Is Typically NOT A Function Of The Flywheel?OA. Power Transfer To The TransmissionOB.

Answers

Answer 1

Answer:D

Explanation:

Answer 2

Option D is correct. Balancing the crankshaft is NOT one of the functions of a flywheel.

A flywheel is part of an automobile. It is a heavy wheel that is attached to a rotating shaft of an automobile. Since there may be the presence of large forces within an automobile structure, the presence of a flywheel helps to balance the force evenly across it.  

Some of the functions of the flywheel are but are not limited to help in transferring power to the transmission, engaging the starter, and smoothing out of power pulses.

Hence based on the explanation above, balancing the crankshaft is NOT one of the function of a flywheel.

Learn more on flywheel here: https://brainly.com/question/14273307

4. Which Of These Is Typically NOT A Function Of The Flywheel?OA. Power Transfer To The TransmissionOB.

Related Questions

technician A says that in any circuit, electrical current takes the path of least resistance. technician B says that while this is true in a series circuit, it's not entirely true in a parallel circuit. who is correct?

Answers

Answer:

  technician A is correct

Explanation:

Technician B has circuit topologies confused. In a series circuit, there is only one path for electrical current to take. In a parallel circuit, the current will divide between paths in proportion to the inverse of their resistance. The least resistance path will have the most current.

Technician A is mostly correct.

PLZ HELP A person hired by a pharmaceutical company to streamline the company’s drug production process would most likely be an electrical engineer? True or False

Answers

Answer:

False

Explanation:

False, though they could do it.

It's most likely and Industrial Engineer, it could also be a Chemical Engineer.

What makes a particular sector of the residential construction market dependent on globalization?
its need for innovation to spur growth
its embrace of renewable and sustainable technology
its commitment to multiculturalism
its requirement of labor or materials from far-flung sources

Answers

Answer:

  its requirement of labor or materials from far-flung sources

Explanation:

"Globalization" generally means having or creating sources of supply in foreign countries, usually those with lower labor or material costs. If some industry sector is dependent upon that, then it's probably because it depends on labor or materials from low-cost sources.

Martha has been running a small business for two years. She now seeks additional investment to finance her business. She has found potential investors who want to check how much Martha's business owns and owes others. Which financial statement should Martha provide to her investors? A. cash flow statement B. balance sheet C. trial balance D. journal

Answers

Answer:

The correct option is B) Balance Sheet

Explanation:

A Balance Sheet offers a description of a company's obligations, assets, and investments as well as net income over a given span of time such as a period of 6 months or 12 months, for instance.

Also known as the Statement of Financial Position, it contains sufficient information for investors and business owners to determine the company's financial performance in that period as well as to compare the performance of that company with industry norms or competition.

Cheers

Mechanic... Mechanical Engineer... What's the difference?
Instructions: Answer the question below with at least TWO complete sentences.

Answers

Answer:

Mechanic: a person who repairs and maintains machinery

Mechanical engineers: design power-producing machines

Explanation:

could you put your sparkplug in the steering wheel and it still works
A. no
B. yes
C. do not care
D. it really doesn't matter

Answers

Answer:

a

Explanation:

Given int variables k and total that have already been declared, use a do...while loop to compute the sum of the squares of the first 50 counting numbers, and store this value in total. Thus your code should put 1*1 + 2*2 + 3*3 +... + 49*49 + 50*50 into total. Use no variables other than k and total.

Answers

Answer:

k-1000

Explanation:

Answer:

k = 1;

total = 0;

do {

total = total + (k*k);

k++;

} while (k <= 50);

Explanation:

answer using Java

what is the IMA of a fixed pulley ​

Answers

Answer:

Not sure

Explanation:

Looking now

In a pulley, the ideal mechanical advantage is equal to the number of rope segments pulling up on the object. ... In the single fixed pulley, only one rope segment pulls up on the load, so the ideal mechanical advantage is 1.

Hope this helps

James is planning on registering for a course in electrical engineering. Which of the following sub-disciplines could he opt for?

Instrumentation engineering
Prosthetics
Plant design
Signal processing

Answers

Answer:

I hope this helps

Explanation:

Instrmentation engineering

Answer:

Instrumentation engineering

Explanation:

What kind of job does mike have? Mike’s job is to study blueprints, evaluate product stability, and to examine the safety of products. Mike’s works as a/n blank engineer with a manufacturing company.

Answers

Answer: a drafting engineer

Explanation:

hi guys can u help me? ​

Answers

Answer:

3. have known

4. wrote

5. not sure

6.have changed, has only

7. answered

8. have missed

9.has never seen

10.never saw

11.became,have changed

12. have changed, have grown

13.was,found

14. was never

am not sure but hope it helps

...........................................................................................................

Answers

……………………………………………………………………………………………………

Compare automation and autonomous

Answers

Answer:

Automation generally means “a process performed without human assistance”, while autonomy implies “satisfactory performance under significant uncertainties in the environment and the ability to compensate for system failures without external intervention [emphasis mine].”

Explanation:

Large wind turbines with blade span diameters of over 100 m are available for electric power generation. Consider a wind turbine with a blade span diameter of 100 m installed at a site subjected to steady winds at 8 m/s. Taking the overall efficiency of the wind turbine to be 32 percent and the air density to be 1.25 kg/m3 , determine the electric power generated by this wind turbine. Also, assuming steady winds of 8 m/s during a 24-hour period, determine the amount of electric energy and the revenue generated per day for a unit price of $0.09/kWh for electricity

Answers

Answer:

The wind turbine generates [tex]19297.222[/tex] kilowatt-hours of electricity daily.

The wind turbine makes a daily revenue of 1736.75 US dollars.

Explanation:

First, we have to determine the stored energy of wind ([tex]E_{wind}[/tex]), measured in Joules, by means of definition of Kinetic Energy:

[tex]E_{wind} = \frac{1}{2}\cdot \dot m_{wind}\cdot \Delta t \cdot v_{wind}^{2}[/tex] (Eq. 1)

Where:

[tex]\dot m_{wind}[/tex] - Mass flow of wind, measured in kilograms per second.

[tex]\Delta t[/tex] - Time in which wind acts in a day, measured in seconds.

[tex]v_{wind}[/tex] - Steady wind speed, measured in meters per second.

By assuming constant mass flow and volume flows and using definitions of mass and volume flows, we expand the expression above:

[tex]E_{wind} = \frac{1}{2}\cdot \rho_{air}\cdot \dot V_{air} \cdot \Delta t \cdot v_{wind}^{2}[/tex] (Eq. 1b)

Where:

[tex]\rho_{air}[/tex] - Density of air, measured in kilograms per cubic meter.

[tex]\dot V_{air}[/tex] - Volume flow of air through wind turbine, measured in cubic meters per second.

[tex]E_{wind} = \frac{1}{2}\cdot \rho_{air}\cdot A_{c}\cdot \Delta t\cdot v_{wind}^{3}[/tex] (Eq. 2)

Where [tex]A_{c}[/tex] is the area of the wind flow crossing the turbine, measured in square meters. This area is determined by the following equation:

[tex]A_{c} = \frac{\pi}{4}\cdot D^{2}[/tex] (Eq. 3)

Where [tex]D[/tex] is the diameter of the wind turbine blade, measured in meters.

If we know that [tex]\rho_{air} = 1.25\,\frac{kg}{m^{3}}[/tex], [tex]D = 100\,m[/tex], [tex]\Delta t = 86400\,s[/tex] and [tex]v_{wind} = 8\,\frac{m}{s}[/tex], the stored energy of the wind in a day is:

[tex]A_{c} = \frac{\pi}{4}\cdot (100\,m)^{2}[/tex]

[tex]A_{c} \approx 7853.982\,m^{2}[/tex]

[tex]E_{wind} = \frac{1}{2}\cdot \left(1.25\,\frac{kg}{m^{3}} \right) \cdot (7853.982\,m^{2})\cdot (86400\,s)\cdot \left(8\,\frac{m}{s} \right)^{3}[/tex]

[tex]E_{wind} = 2.171\times 10^{11}\,J[/tex]

Now, we proceed to determine the quantity of energy from wind being used by the wind turbine in a day ([tex]E_{turbine}[/tex]), measured in joules, with the help of the definition of efficiency:

[tex]E_{turbine} = \eta\cdot E_{wind}[/tex] (Eq. 4)

Where [tex]\eta[/tex] is the overall efficiency of the wind turbine, dimensionless.

If we get that [tex]E_{wind} = 2.171\times 10^{11}\,J[/tex] and [tex]\eta = 0.32[/tex], then the energy is:

[tex]E_{turbine} = 0.32\cdot (2.171\times 10^{11}\,J)[/tex]

[tex]E_{turbine} = 6.947\times 10^{10}\,J[/tex]

The wind turbine generates [tex]6.947\times 10^{10}[/tex] joules of electricity daily.

A kilowatt-hours equals 3.6 million joules. We calculate the equivalent amount of energy generated by wind turbine in kilowatt-hours:

[tex]E_{turbine} = 6.947\times 10^{10}\,J\times\frac{1\,kWh}{3.6\times 10^{6}\,J}[/tex]

[tex]E_{turbine} = 19297.222\,kWh[/tex]

The wind turbine generates [tex]19297.222[/tex] kilowatt-hours of electricity daily.

Lastly, the revenue generated per day can be found by employing the following:

[tex]C_{rev} = c\cdot E_{turbine}[/tex] (Eq. 5)

Where:

[tex]c[/tex] - Unit price, measured in US dollars per kilowatt-hour.

[tex]C_{rev}[/tex] - Revenue generated by the wind turbine in a day, measured in US dollars.

If we know that [tex]c = 0.09\,\frac{USD}{kWh}[/tex] and [tex]E_{turbine} = 19297.222\,kWh[/tex], then the revenue is:

[tex]C_{rev} = \left(0.09\,\frac{USD}{kWh} \right)\cdot (19297.222\,kWh)[/tex]

[tex]C_{rev} = 1736.75\,USD[/tex]

The wind turbine makes a daily revenue of 1736.75 US dollars.

Do you consider the letter of Andres Bonifacio an eyewitness account of a firsthand account of the Philippine Revolution?

Answers

Lazaro Makapagal, no relation to Speaker Gloria Macapagal Arroyo, would be a forgotten footnote in Philippine history, except that he led the pack that executed Andres Bonifacio, on orders of the Council of War that imposed the death sentence on the brothers Andres and Procopio Bonifacio. The brothers were found guilty of treason against the newly formed Revolutionary Government that had replaced the Katipunan.

So much has been written about the execution of Bonifacio; some say he was shot, others say he was hacked to death.

On the other hand, in the emotional and contentious matter of Emilio Aguinaldo’s hand in the death of his rival Bonifacio, one believes what one wants to believe despite Makapagal’s two public statements—first to the Philippines Free Press in 1928; second in a detailed letter to historian Jose P. Santos dated June 27, 1929. Biased or inaccurate, Makapagal may be in making these declarations three decades after the fact, but he remains the only eyewitness to Bonifacio’s last moments. Other sources, like Generals Santiago Alvarez and Artemio Ricarte, are not eyewitnesses. Their information was lifted from Makapagal, with Ricarte identifying, wrongly, that the executioners were Colonels Agapito Bonson and Jose Ignacio Paua. A certain Guillermo Masangkay, who concocted and propagated the hacked-to-death story, claimed firsthand information about the May 10, 1897, death of Bonifacio. In a 1967 news article, Masangkay was billed as: “He witnessed Andres Bonifacio’s court martial and murder.” However, archival records consulted by the late historian Isagani Medina state that Masangkay had been imprisoned in Bilibid from Sept. 26, 1896, to at least May 29, 1897.



Makapagal’s controversial handwritten document, previously available to historians in pictures or photocopies, has finally surfaced and will be on the block next weekend, together with Emilio Aguinaldo’s handwritten account of the death of Bonifacio dated March 22, 1948—his 79th birthday! Is it a coincidence that these documents, highlighted by auction house hype as “extremely important and exceedingly rare,” have come to light on the 150th anniversary of Aguinaldo’s birth?

Auction house PR Lisa Guerrero Nakpil waxes poetic in an article on the coming auction, describing the historical documents as revelations of “pure hearts.” She insinuates “shocking secrets,” though they are not so, because all the documents have been previously reproduced in various books. I am relieved that she has stopped using “explosive” to describe these documents because, in my opinion, that adjective is best deployed to portray a bad case of diarrhea.

Using Makapagal’s two accounts of the execution when I drove to Maragondon two decades ago, I had some difficulty finding the place where the group stopped to rest: “It had a small mountain, somewhat round, near the bamboos [Cawayanan]; the other riverbank, facing north, we could see the town of Maragondon with the sunrise on our right, behind us was Mount Buntis.” While seated at the foot of the small round mountain, near the water and the bamboo, Andres said: “Since we are nearing Mt. Tala [our destination], why don’t you open the envelope so we will know where you will leave us.”

The document was read, and at the words “shoot the brothers,” Procopio jumped and exclaimed, “Naku kuyang!”

“Andres fell to his knees and was to embrace me, shouting ‘Kapatid, patawarin mo ako,’” wrote Makapagal.

A single phase, 50-KVA, 2400-240-volt, 60 Hz distribution transformer has the following parameters: •
Resistance of the 2400-volt winding Ri=0.75 ohm
Resistance of the 240-volt winding R=0.0075 ohm
Leakage reactance of the 2400-volt winding X:=1 ohm
Leakage reactance of the 240-volt winding X2=0.01 ohm
Core loss resistance on the 2400 side Rc=733.5 ohms
Magnetizing reactance on the 2400 side X=4890 ohms
a. Draw the equivalent circuit referred to the high voltage side and referred to the low- voltage side. Label the impedances numerically.
b. The transformer is used as a step-down transformer at the load end of a feeder having impedance of (0.5+j2.0) ohms. Determine the voltage V. at the ending end of the feeder when the transformer delivers rated load at rated secondary voltage and 0.8 laggin power factor. Neglect the "exciting current" l. of the transformer (this is the current into the parallel Rc/jXm combination), which is another way of saying that you should use what we called in class the "approximate circuit #2).

Answers

Answer:

B) voltage at the sending end of the feeder = 2483.66 v

Explanation:

attached below is the the equivalent circuits and the remaining solution  for option A

B) voltage = 2400 v

   I  = [tex]\frac{50*10^3}{2400}[/tex]  =  20.83 A

calculate voltage at sending end ( Vs )

Vs = 2400 +  20.83 ∠ -cos^-1 (0.8) ( 0.75*2 + 0.5 + j 2 + j2 )

hence Vs = 2483.66 ∠ 0.961

therefore voltage at the sending end = 2483.66 v

Create an array of 10 size and assign 10 random numbers. Now find the sum of the array using for and while loop.

Answers

Answer:

10

Explanation:

The site earthwork in Phase III of Four Hills Landfill project included a 3.0 ft deep cut across an entire 2.5-acre site. Soil was excavated from within the proposed Phase III footprint. The average unit weight of this soil is 118 lb/ft3, and the average moisture content is 9.6%. It also has a maximum dry unit weight of 122 lb/ft3 and an optimum moisture content of 11.1%, based on the modified Proctor test. The excavated soil will be placed on a nearby site and compacted to an average relative compaction of 93%. Compute the volume of fill that will be produced and express your answer in cubic yards.

Answers

Answer: 11470.4 cubic yards

Explanation:

first we calculate the volume of the site;

V1 = Area × depth

V1 = 2.5 acre ×  (43560 ft² / 1 acre )×3ft

V1 = 326700 ft

next we is the relative compaction

RC = [γd(field) / γdmax(laboratory)] × 100

so we substitute

93 =  [γd(field) / 122 lb/ft³)] × 100

γd(field) = 113.46 lb/ft³

then the dry unit weight of the site

γday1 = γavg / ( 1 + w)

= 118 lb/ft³ / ( 1 + (9.6/100))

= 118 lb/ft³ /1.096

= 107.664 lb/ft³

finally we find the fill volume of the site

V2/V1 = γd / γd(field)

we substitute

V2/326700 = 107.664 / 113.46

V2 = 310010.83 ft³

we convert to cubic yards

= 310010.83 ft³ × (0.037 cubic yard / 1 ft³)

= 11470.4 cubic yards

Complete the sentence using the correct term.
are made without yeast and are often savory or sweet.

Answers

Answer:

Quick Breads

Explanation:

I think this is correct. I am not for sure i just looked it up and it says word for word that this is the answer.

Answer:

Quick Breads

Explanation:

I got it right on my Plato test

which one of these reduce fraction?

Answers

How is I’m supposed to answer the question

Estimate the chronic daily intake of toluene from exposure to a city water supply that contains a toluene concentration equal to the drinking water standard of 1 mg · L−1. Assume the exposed individual is an adult female who consumes water at the adult rate for 70 years, that she abhors swimming, and that she takes a long (20 minute) bath every day. Assume that the average air concentration of toluene during the bath is 1 µg · m−3. Assume the dermal uptake from water (PC) is 9.0 × 10−6 m · h−1 and that direct dermal absorption during bathing is no more than 80% of the available toluene because she is not completely submerged. Use the EPA lifetime exposure of 75 years.

Answers

Answer: the total chronic daily intake is  0.03296 mg/ kg.d  

Explanation:

First of  we have to determine the CDI due to ingestion of drinking water

so

CDI = (C x IR x EF x ED) / (BW x AT)     let leave this as equation 1

where C is the concentration of the life time risk of drinking water(1.0mg/L)

ED is the risk dying per year((70),

EF is the number of days per year(365 day/year)

BW is the weight of body(65.4)kg

AT is the average tenure time of life(75years)

IR = 2.3 L/days

so we substitute

CDI₁ = (1(mg/L) x 2.3(L/day) x 365 x 70) / (65.4 x 365 x 75)

= 3.29 x 10⁻² mg/kg.d  

next we determine the CDI due to dermal contact with water.  

find the ingestion rate which is equal to the exposure time in hour/day.

IR = ET

(20 min/day) /  (60 min/hour)

= 0.333 h/day

now lets substitute for CD1₂

1.0 mg/L for C , 0.333 h/day for m , 365 day/year for EF, 70 year for ED, 65.4 kg for Bw , and 75 year for AT

0.8 for submergence and 1.69m² for area of skin of adult female in our equation 1

CDI₂ = [(1 mg/1) × (1.69 m²) × (9.0 x 10⁻⁶(m/h)) × 0.333(h/day) x 365 x 70)) / (65.4 x 365 x 75)]  × ( 0.8 x 10³ L/m³)

CDI₂ = 5.41 x 10⁻⁵ mg/kg.d  

now we find the CDI due to inhalation during bath

we substitute 1.0 mg/L for C, 11.3m³/day for IR , 365 day/year for EF , 70 year for ED. 65.4 kg for BW , and 75 year for AT in our equation 1

CDI₃ = [( 1ug/m³ × 1mg/10³ug) x (11.3m³/day x 1day/24 hr) x 365 x 70)] / (65.4 kg x 365 x 75 )

= 6.71 x 10⁻⁶ mg/kg.d

finally we Calculate the total chronic daily intake value

CDI_total = CDI₁ + CDI₂ + CDI₃  

we substitute

CDI_total = 3.29 x 10⁻² + 5.41 x 10⁻⁵ + 6.71 x 10⁻⁶

= 0.03296 mg/kg.d  

so the total chronic daily intake is  0.03296 mg/ kg.d  

Type your response in the box. Most novels include at least one important symbol. Identify at least one symbol in the novel you just finished. In 125 to 150 words, identify the symbol. State the type of symbol it is (universal or contextual), and describe its meaning. Be sure to include specific details from the story to support your answer.

Answers

Answer:

Symbols in The Secret Garden:

The secret garden: The garden seems to be a symbol for Mary’s transformation. She changes from a sickly child to a healthy one. It is a contextual symbol.  

The robin: The robin symbolizes the kindness and compassion of nature. The robin is a contextual symbol.

Spring: The spring season is a symbol for change and new life. It represents these ideas in each of the characters at the end of the story. It is a universal symbol.

Symbols in The Hunger Games:

Katniss’s mockingjay pin: It might stand for rebellion and resistance against the Capitol. It is a contextual symbol.

The mockingjay: The bird itself is a symbol for resistance against the Capitol. It is a contextual symbol.

Bread: It is a symbol for the connection between Katniss and Peeta. It is a contextual symbol.

Symbols in Hatchet:

The hatchet: The hatchet symbolizes survival and self-reliance. The hatchet is a contextual symbol.

The moose and the tornado: Both symbolize confusion and the power nature has over people. They are contextual symbols. However, a tornado can also be a universal symbol for destruction.

The plane: The plane symbolizes the changes in Brian’s life. It represents how Brian moves from one stage of his life to another. It is a contextual symbol.

Symbols in The Red Badge of Courage:

The dead soldier: The dead soldier symbolizes how all things will eventually end. It expresses the idea that accomplishments may mean very little. It is a universal symbol for an end.

Henry’s wound: For Henry, a wound symbolizes a soldier’s bravery at war. It is a contextual symbol.

Flag: A flag symbolizes the values and identity of a state or nation. It also represents the reason why two opposing sides of a war are fighting. A flag is a universal symbol.

Explanation:

These are the answers for Plato,  these are the answers from each novel.

I hope this helps you!

Will give correct answer brainliest!!
Fill in the blank.
_________ are engineers who help to develop products and projects by creating technical drawings

Answers

Answer:

Design engineer

Explanation:

Inventors ? I’m not sure but that’s my educated guess

6. Question
Which statements are true about routers? Check all that apply.
A router can only send data to another computer that's on the same network.
A router is a set of components that makes up computer networking.
A router connects devices together and helps direct network traffic.
A router utilizes network protocols to help determine where to send data packets.
7.
Question

Answers

Answer:

Check  the 2nd, 3rd and 4th statements.

Explanation:

The router provides two basic functions traffic management between these networks through the transmission of data packets to the designated IP address, and the use of the same Internet connection by many devices.

A networking device is a router that transmits data packets between computer nets. Traffic control functions are executed on the internet via routers. Data sent via the internet are in data packets, for example, a web page or email.A router is a device connecting two or more packets or subnetworks. It is used to sets the components from the networking of your computer.

Therefore, the final answer is "the second choice".

Learn more:

brainly.com/question/2162586

Design a U-tube manometer that can measure gage pressures up to 69 kPa of air. You will want to choose a manometer fluid with good static sensitivity but will not result in an unreasonably tall manometer. Further, the manometer fluid should be mostly immiscible with the air. The two design parameters you should consider are manometer fluid (impacts manometer fluid density) as well as the manometer height.

Required:
Compute the static sensitivity, K, in mmHg/Pa

Answers

Answer:

The answer "K = 0.0075"

Explanation:

If we try to measure up to 69 kPa of air, find mercury or fluid for gauge.  

While mercury was its largest liquid with a density of 13600 kg / m3 at normal room temperature.  

Let's all measure for 69 kPa that height of the  mercury liquid column.

[tex]\to P = 69 \ kPa[/tex]

       [tex]= 69000 Pa \\\\[/tex]

[tex]\to \rho = 13600 \ \ \frac{kg}{m^3} \\\\\\to g = 9.81 \ \ \frac{m}{s^2} \\\\[/tex]

Formula:

[tex]\to P=\rho \ gh[/tex]

[tex]\to 69000 = 13600\times9.81 \times h\\\\\to h= \frac{69000}{13600\times9.81} \\\\\to h= \frac{69000}{133416} \\\\\to h= 0.517179349 \\\\ \to h= 517 \ mm \\\\[/tex]

The right choice for pressure measurements up to 69 kPa is mercury.  

Atmospheric Mercury up to 69 kPa Air 517 mm  

The relationship of Hg to Pa is = 134.22 Pa 1 mm Hg  

Static sensitivity to Pa of mm hg = change of mercury height to Pa:

[tex]= \frac{\Delta Hg }{ \Delta P }\\\\= \frac{1 }{ 133.3 }\\\\= 0.0075[/tex]

Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m^2 at 500°C. Assume a diffusion coefficient of 1.0 x 10^8 m^2 /s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained.

Answers

Answer:

The answer is "[tex]\bold{ 259.2 \times 10^{11} }[/tex]".

Explanation:

The amount of kilograms, which travel in a thick sheet of hydrogen:

[tex]M= -DAt \frac{\Delta C}{ \Delta x} \\\\[/tex]

[tex]D =1.0 \times 10^{8} \ \ \ \frac{m^2}{s} \\\\ A = 0.20 \ m^2\\\\t = 1\ \ h = 3600 \ \ sec \\\\[/tex]

calculating the value of [tex]\Delta C:[/tex]

[tex]\Delta C =C_A -C_B[/tex]

  [tex]= 2.4 - 0.6 \\\\ = 1.8 \ \ \frac{kg}{m^3}[/tex]

calculating the value of [tex]\Delta X:[/tex]

[tex]\Delta x = x_{A} -x_{B}[/tex]

     [tex]= 0 - (5\ mm) \\\\ = - 5 \ \ mm\\\\= - 5 \times 10^{-3} \ m[/tex]

[tex]M = -(1.0 \times 10^{8} \times 0.20 \times 3600 \times (\frac{1.8}{-5 \times 10^{-3}})) \\\\[/tex]

    [tex]= -(1.0 \times 10^{8} \times 720 \times (\frac{1.8}{-5 \times 10^{-3}})) \\\\= -(1.0 \times 10^{8} \times \frac{ 1296}{-5 \times 10^{-3}})) \\\\= (1.0 \times 10^{8} \times 259.2 \times 10^3)) \\\\= 259.2 \times 10^{11} \\\\[/tex]

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