4) Why must the exact same mass of solution (100.0 g) be used in the neutralization reactions?

The balanced NET ionic equation is

Al(OH)3 ----> Al3+(aq) + 3OH(aq) (s)

When AICI and NaOH are combined in an aqueous solution, the following balanced NET ionic equation describes the reaction:

Al(OH)3 -----> Al3+(aq) + 3OH(aq) (s)

An exchange reaction occurs when AICI and NaOH are combined.

Al(OH)3(s) + 3NaCl(aq) -----> AlCl3(aq) + 3NaOH(aq) (1)

In this reaction, the ions Al+3 and Na+ exchange Cl- and OH- ions.

The total ionic equation must first be written in order to create the NET ionic equation:

AI(OH)3(s) + 3Na+(aq) + 3Cl(aq) + Al3+(aq) + 3Cl(aq) + 3Na+(aq) + 3OH (aq) (2)

Since the Al(OH), precipitates, we are unable to describe it as an ion because the aqueous solution does not allow for its dissociation.

The following is the net ionic equation for reaction

Al3+(aq) plus 3OH-(aq) leads to Al(OH)3(s)

The net ionic equation excludes all repeating ions from reactants and products. We eliminated the Na+ and Cl- ions from the net ionic equation because of this

The balanced net ionic equation is as follows:

Al(OH)3 ----> Al3+(aq) + 3OH(aq) (s)

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Answer:

cellular respiration occurs both in plant and animal cells.

Explanation:

Cellular respiration definitely occurs in animals, it is how we break down glucose to get ATP. Plants first use photosynthesis to produce glucose and then need a way to produce ATP, being cellular respiration.

The volume of water that must be added to 15 mL of sodium chloride solution 23.4% to dilute the ​concentration to 0.06 mmol/mL is 999985 mL.

The concentration of 23.4% sodium chloride solution in mol/L is calculated as follows:

23.4% solution = 23.4 g/100 mL solution

23.4 g/100 mL = 234 g/L

molar mass of NaCl = 58.5

Molarity of the NaCl solution = 234 / 58.5

Molarity = 4 mol/L

Using the dilution formula:

C₁V₁ = C₂V₂

where;

C₁ is the initial concentration = 4 mol/L or 4000 mmol/L

V₁ is the initial volume = 15 mL

C₂ is the final concentration = 0.06 mmol/L

V₂ is final volume = ?

V₂ = 4000 * 15 / 0.06

V₂ = 1000000 mL

Hence, the volume of water to be added will be:

1000000 - 15 = 999985 mL

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The volume of 0.180 M KOH that would be needed to completely react with 15.1 mL of 0.190 M [tex]H_2SO_4[/tex] will be  31.88 mL

The equation of the reaction involving KOH and [tex]H_2SO_4[/tex] is as follows:

[tex]2KOH + H_2SO_4 --- > K_2SO_4 + 2H_2O[/tex]

The equation is already balanced and the mole ratio of KOH and  [tex]H_2SO_4[/tex] is 2:1.

But 15.1 mL of 0.190 M  [tex]H_2SO_4[/tex]  is available.

Recall that:

mole = molarity x volume

Mole of 15.1 mL of 0.190 M  [tex]H_2SO_4[/tex] = 0.190 x 15.1/1000

                                                          = 0.002869 mol

From the 2:1 mole ratio, the equivalent mol of KOH would then be:

0.002869 x 2 = 0.005738 mol

Since, mole = molarity x volume. Then, volume = mole/molarity

So, the volume of 0.005738 mol of 0.180 M KOH would be:

volume = 0.005738/0.180

             = 0.03188 liters

Converting 0.03188 liters to mL:

   0.03188 x 1000 = 31.88 mL

Thus, the volume of 0.180 M KOH needed to react completely with 15.1 mL of 0.190 M H2SO4 would be 31.88 mL.

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From the calculations, the new volume of the gas is 30.2 L.

We know that we can be able to obtain the parameters that ahs to do with the gas by use of any of the equations of the laws that relate to an ideal gas.

Given that the;

Initial volume [tex]V_{1}[/tex] = 35.0 L

Initial temperature [tex]T_{1}[/tex] =  268 K

Initial pressure [tex]P_{1}[/tex]  = 5.16 atm

Final temperature [tex]T_{2}[/tex] = 343 K

Final pressure [tex]P_{2}[/tex] =  7.65 atm

Final volume [tex]V_{2}[/tex] = ??

Then we have to use the general gas equation;

[tex]P_{1}[/tex] [tex]V_{1}[/tex]/ [tex]T_{1}[/tex]=  [tex]P_{2}[/tex] [tex]V_{2}[/tex]/ [tex]T_{2}[/tex]

[tex]V_{2}[/tex] =  5.16 * 35.0 *  343/7.65 * 268

[tex]V_{2}[/tex] = 61945.8/2050.2

[tex]V_{2}[/tex] = 30.2 L

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The statement " Inertia and distance combine to keep Earth in orbit around the Sun and the Moon in orbit around Earth " is false.

According to Sir Isaac Newton, he proposed and concluded in his investigation that the earth is being kept in its orbit around the Sun and the Moon in orbit around Earth by means of gravity and inertia. This is not done through inertia and distance.

In conclusion, it can be deduced from the explanation given above that inertia and gravity combine to keep the earth in orbit around the Sun and the Moon in orbit around Earth.

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The reaction is not at equilibrium and it is in the forward direction.

a.

Given,

[N₂] = 0.910 mol / L

[H₂] = 0.3 mol / L

[NH₃] = 0.0081 mol / L

K = 9.83 x 10⁻²

The balanced chemical equation for the given reaction is,

N₂(g) + 3H₂(g) ⇄ 2NH₃(g)

The formula of equilibrium constant is given by,

K = [NH₃]² / [N₂] [H₂]²

9.83 x 10⁻² = [(0.0081)² ]/ [0.910 × (0.3)²]

⇒9.83 x 10⁻² = (0.00006561) / (0.0819)

⇒9.83 x 10⁻² = 0.0008010989

⇒0.00983 = 0.0008010989

LHS ≠ RHS

Hence, the reaction is not at equilibrium.

b.

The reaction is in forward direction.

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77.094*[tex]10^{23}[/tex]  molecules are in 12.80 moles of strontium bydroxide.

The chemical strontium hydroxide has a molecular weight of 121.6324 g/mol and the molecular formula Sr(OH)2. It appears in the form of an anhydrate with prismatic, colorless crystals that are liquescent.

The building By counting the number of components (and their corresponding quantities) listed in the chemical formula, one can easily determine that each molecule of the compound NaOH contains three atoms.

By mole concept-

1moleof strontium bydroxide =6.023*[tex]10^{23}[/tex] molecules of strontium bydroxide.

so,

12.80 moles of strontium bydroxide =12.80*6.023*[tex]10^{23}[/tex]

No of molecule =77.094*[tex]10^{23}[/tex] molecule

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The compound with the chemical formula PbBr₄ is called lead(IV) bromide.

Lead(IV) bromide is an inorganic compound composed of the elements lead (Pb) and bromine (Br). The compound is named based on the oxidation state of lead, which is +4 in this case.

In naming compounds, the Roman numeral in parentheses after the element name indicates the oxidation state of the metal. In the case of lead(IV) bromide, the Roman numeral IV indicates that lead is in the +4 oxidation state. This means that lead has lost four electrons to achieve a stable configuration.

The name "lead(IV) bromide" accurately represents the composition and oxidation state of the compound. It is worth noting that lead(IV) bromide is a relatively unstable compound and is not commonly encountered in practical applications.

Hence, the name of the compound is lead(IV) bromide.

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1) We could use the bromine water test to tell the difference between the alkane and the alkene

2) We can use a detergent to wash a cloth that is contaminated by oil.

The term alkane has to do with a hydrocarbon that is composed of only a straight chain compound there are no multiple bonds in the alkane molecule and this is the difference between the alkane and the alkene. The alkene is composed of double bonds. The alkene compounds are able to decolorize bromine water while the alkanes can not.

If you have a contaminated cloth, you can be able to wash it by the use of a detergent because it is able to lift off the grease or oil by the use of the hydrophobic tail of the detergent.

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NADP, nicotinamide adenine dinucleotide phosphate forms NADPH by combining with the H+ ion and two electrons. Thus, option C is correct.

NADP, nicotinamide adenine dinucleotide phosphate is a reducing agent in electron transport chains of metabolic processes in living things. NADPH is the reduced form of NADP.

In biochemical reactions such as glycolysis, photosynthesis etc, NADP plays a significant role as a reducing agent. NADP and NADPH together are called the redox couple and they maintain cellular redox homeostasis.

Hydrogenation of molecules is called reduction and thus the NADP+ reduces to its NADPH by combining with a two electrons and H+. Hence option C is correct.

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Answer:

Explanation:

I forgot

Volume should you dilute 35 mL of a 12 M stock HCl solution to obtain a 0.500 M is 840 mL,

Given that :

Molarity of the solution M1 = 12 M

volume of the solution V1 = 35 mL

Molarity of the solution after the dilution M2 = 0.500 M

volume of the solution after the dilution V2 = ?

the dilution law states that :

M1 V1 = M2 V2

12 × 35 = 0.500 × V2

V2 = 840 mL

Thus, Volume should you dilute 35 mL of a 12 M stock HCl solution to obtain a 0.500 M is 840 mL.

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Answer:

Cu(NO3)2 (aq) + K2CO3 (aq) => CuCO3 (s) + 2KNO3 (aq)

Explanation:

I interpret your question is how to balance the above reaction, right?

Cu(NO3)2 (aq) + K2CO3 (aq) => CuCO3 (s) + 2KNO3 (aq)

Cu: 2

NO3: 2

K: 2

CO3: 2

Density=mass/volume

d=6.2/4.4

d=1.40 grams/cm³

Answer:

option d rain evoporates

Answer:

D. Rain Evaporates

Explanation:

Heat causes liquid and frozen water to evaporate into water vapor gas, which rises high in the sky to form clouds. Clouds move over the globe and drop rain and snow.

The concentration in mmol/L of the chemist's mercury(I) chloride solution. is 2.03 × 10^-8 M

We are given;

Number of moles of mercury (i) chloride as 0.000406 μmol

Volume is 200 mL

We are required to calculate the concentration of the solution.

We need to know that;

Concentration is also known as molarity is given by;

Molarity = Number of moles ÷ Volume

Number of moles = 4.06 × 10^-10 Moles

Volume = 0.02 L

Therefore;

Concentration = 4.06 × 10^-10 Moles ÷ 0.02L

                      = 2.03 × 10^-8 M

Thus, the molarity of the solution is 2.03× 10^-8 M.

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Have two sides that mirror each other along one plane through the central axis called as symmetrical

The line of centroids or central axis is defined as the line that passes through the centroids along the beam and the cross section are then defined as the beam section which are perpendicular to the central axis and that two side are mirror images of each other and place a mirror on the fold then image of one side of the picture will fall exactly on the other side of the picture and that are called as symmetrical means same

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Answer:

0.0833 M NaOH

Explanation:

To calculate the molarity, you need to

(1) convert grams NaOH to moles (using the molar mass)

(2) convert mL to liters

(3) calculate the molarity

It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs like the given value with the smallest amount of sig figs (0.499 = 3 sig figs).

 0.499 g NaOH              1 mole
--------------------------  x  ------------------  =  0.0125 moles NaOH
                                       40.00 g

 150.00 mL H₂O                  1 L
---------------------------  x  ------------------  =  0.15000 L H₂O
                                        1,000 mL

Molarity = moles / volume

Molarity = 0.0125 moles NaOH / 0.15000 L H₂O

Molarity = 0.0833 M

The mass of 45.0 L of Cl₂ at 87.0° C and 950 mm Hg is 134.7214 g.

Volume = 45.0 L

Temperature =  = (87.0 + 273) K = 360 K

Pressure = 950 mm Hg (1 mm Hg = 0.00131579 atm) = 1.25 atm

The formula used to calculate moles is as follows.

∴PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into the above formula as follows:

 ∴ PV = nRT

=> 1.25 atm × 45.0 L = n × 0.0821 L atm/mol K × 360K

=> n = 1.25 atm × 45.0 L / n × 0.0821 L atm/mol K × 360K

=> n = 56.25 / 29.556 mol

=> n = 1.90 mol

Moles is the mass of a substance divided by its molar mass. So, the mass of Cl₂ (molar mass = 70.906 g/mol) is calculated as follows:

∴  Moles = mass / molar mass

=> 1.90 mol = mass /  70.906 g/mol

=> mass = 134.7214 g

Thus, we can conclude that the mass of 45.0 L of Cl₂ at 87.0° C and 950 mm Hg is 134.7214 g.

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Answer:

Don't follow this!

Explanation:

Your chemistry teacher knows that you are cheating and using this as your own work.

-From said teacher!

To determine if the piece of plastic has a density greater or less than 1 g/cm³, the piece of plastic is placed in water, if it sinks, it has a greater density, but if it floats, it has a lesser density.

The density of a substance measure how compact the substance is.

For fluids such as water, objects that are denser than water will sink in water. However, if the density is less than that of water, it will float in water.

The density of water is 1 g/cm³.

Hence, objects that have densities greater than 1 g/cm³ will sink in water, whereas objects that have densities less than 1 g/cm³ will float in water.

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The full burning of 6.70x10-3 g of methane results in the production of 2.95872 mass of carbon dioxide.

Burning is sometimes referred to as combustion. A fuel is heated and interacts with oxygen in a combustion reaction. The three elements of fuel, heat, and oxygen required for combustion are summarized by the fire triangle.

Chemical processes that occur during combustion are frequently quite exothermic. The energy of chemical molecules generated during this reactive process is used by combustion systems to power vehicles, produce electricity, or heat a variety of uses.

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The final solution has a strength of 2%.

Let the initial volume of solution = x unit^3

The solution is initially by 20%

Amount of solute = x*20/100

                             = x/5 unit^3

Now,  

We first diluted by 1:5

1 part of initial solution is diluted with 4 parts of diluent

For 'x' unit^3 solution,

Diluent added = 4x unit^3

Total volume of solution becomes = x+4x

                                                          = 5x unit^3

Now,

We diluted by 1:2

1 part of solution is diluted with 1 part of diluent

5x unit^3 of solution is diluted with 5x unit^3 of diluent

Final solution = 5x + 5x = 10x unit^3

Final strength = (Amount of Solute/Final solution)*100%

                       = (x/5/10x)*100%

                       = x/50x*100%

                       = 2%  

The final strength of final solution is 2%

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1.6987 grams the silver nitrate crystals is weighed, 100 mL of water is measured, and the weighed silver nitrate is dissolved in the measured amount of water.

We are to prepare a 0.1 M silver nitrate solution given the following:

First, we need to make some calculations to make the amount of silver nitrate and water that will be used.

0.1 M means 0.1 mol silver nitrate crystal in 1 L of water. However, we only have a 100 mL volumetric flask. We need to know the mol amount that will be equivalent to 100 mL of water.

0.1 mol = 1000 mL

100 mL = 100 x 0.1/1000

            = 0.01 mol

Mole = mass/molar mass

Molar mass of silver nitrate = 169.87 g/mol

0.01 mol silver nitrate = 0.01 x 169.87

                                    = 1.6987 grams

Thus, 1.6987 grams of silver nitrate would be weighed.

The following steps would be taken to prepare the solution:

What you will have is 100 mL of 0.1 M silver nitrate solution.

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An object is placed in 20 mL of water. This water rose to a level of 26 mL. The object has a mass of 18 g. the density of the object is 3 g/mL.

given the data as follows :

mass of object  =  18 g

volume of object = final volume - initial volume

volume of object = 26 mL - 20 mL

                             = 6 mL

the density expression is given as:

Density = mass / volume

Density = 18 g / 6 mL

Density = 3 g/mL

Thus, An object is placed in 20 mL of water. This water rose to a level of 26 mL. The object has a mass of 18 g. the density of the object is 3 g/mL

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The empirical formula of compound is C₃H₇O₃. The molecular formula is 1, 2, 3, tri hydroxyl propane.

What is molecular formula ?

The molecular formula is an equation that specifies how many atoms of each element there are in a single compound's molecule. It displays the precise amount of atoms present in a molecule.

Propane, for instance, has the chemical formula C4H10. The given compound has a formula of 4 carbon atoms and 10 hydrogen atoms.

The empirical  formula of compound is C₃H₇O₃.

Then, ( 12 × 3 ) + ( 1 × 7 ) + ( 16 × 3 )

= 36 + 7 + 48

= 91

( 39.6 ) + ( 7.75 ) = 47.35

91 - 47.35

= 43.65

Thus, molecular formula of given compound is 1, 2, 3, tri hydroxyl propane.

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The correct summary of the properties is; Metals are generally very shiny, good conductors, high in density, and melt at high temperatures. Nonmetals are generally dull, poor conductors, low in density, and melt at low temperatures. Metalloids exhibit properties of both metals and nonmetals, make fair conductors, and can appear as shiny or dull.

Materials are of course composed of matter and mater is composed of atoms of elements. There are three main classes of the elements that we have in the periodic table. The classes of the elements are known as;

1) Metals

2) Non metals

3) Metalloids

Metals do conduct electricity while the non metals just do not conduct electricity. The metalloids would acts as conductors of electricity under certain circumstances.

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The concentration terms are molality, normality and mole fraction. Molarity can be used to find out the ionic strength of any solution. Therefore, the mass of CH[tex]_2[/tex]O is 4.80g.

Molarity can be calculated by dividing number of moles of solute by volume of solution in liter. Molarity is affected by temperature. Its unit is mole/liter. It measure the concentration of any solute in a solution.

Mathematically,

Molarity= number of moles of solute÷ Volume of solution in liter

number of moles of solute =given mass÷ Molar mass of solute

number of moles of solute =mass÷30.03 g/mol

Molarity=0.314 M

Volume of solution=0.505 liters

Substituting all the given values, we get

0.314 M= {mass÷30.03 g/mol}÷ 0.505 liters

mass÷30.03 g/mol=0.15

mass =4.80g

Therefore, the mass of CH[tex]_2[/tex]O is 4.80g.

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Answer:

b

Explanation:

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