4.(03.01)
Is the following relation a function? (1 point)


A: Yes
B: No

5.2 inches 13.12 cm

50m

42.195 kilometers

Step-by-step explanation:

This graph shows linear

y = f(x) and y = g(x).

Find the solution to the equation f(x) - g(x) = 0

Answer:

I Meant y =  -13

Step-by-step explanation:

Answer:

y= -13

Step-by-step explanation:

-13 plus 20 is 7

plug the -13 in where the y is and do the equation

-13+20=7

Answer: future the time or a period of time following the moment of speaking or writing; time regarded as still to come.

Step-by-step explanation:

Step-by-step explanation:

b=1 the person above or below me has the explanation

Answer:

101.5m left to use after the big top goes up.

Step-by-step explanation:

18*10=180  [tex]\pi[/tex]r[tex]x^{2}[/tex]= 3.14*5^{2}=3.14*25=78.5

180-78.5= 101.5m

Answer:

I think the answer is y=2x-2

Hope it is correct! The x is positive because the angle is pointing to the right, and the -2 came from the position of the line.

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Complete Question

In a sample of 80 light bulbs, the mean lifetime was 1217 hours with a standard deviation of 52 hours. a. Find the 95% confidence interval for the mean lifetime of this type of bulb. Justify the reason you chose the distribution used to construct the confidence interval. b. How many light bulbs must be sampled so that a 95% confidence interval will specify the mean lifetime to within [tex]\pm 8 \ hours[/tex]?

Answer:

a

    [tex]1206 <  \mu <  1228 [/tex]

The reason why a normal distribution was chosen is because the sample size is large enough that is  [tex]n > 30[/tex]  

b

   [tex]n =162 [/tex]

Step-by-step explanation:

From the question we are told that

    The sample size is  n  =  80  

    The sample mean is  [tex]\= x = 1217[/tex]

     The standard deviation is  [tex]\sigma = 52[/tex]

From the question we are told the confidence level is  95% , hence the level of significance is    

      [tex]\alpha = (100 - 95 ) \%[/tex]

=>   [tex]\alpha = 0.05[/tex]

Generally from the normal distribution table the critical value  of   is  

   [tex]Z_{\frac{\alpha }{2} } =  1.96[/tex]

Generally the margin of error is mathematically represented as  

      [tex]E = Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }[/tex]

=>    [tex]E = 1.96  *  \frac{ 52}{\sqrt{80} }[/tex]

=>    [tex]E = 11.395 [/tex]

Generally 95% confidence interval is mathematically represented as  

      [tex]\= x -E <  \mu <  \=x  +E[/tex]

=>   [tex]1217  -11.395 <  \mu <  1217  + 11.395[/tex]

=>   [tex]1206 <  \mu <  1228 [/tex]

Generally the sample size is mathematically represented as  

   [tex]n = [\frac{Z_{\frac{\alpha }{2} } *  \sigma }{E} ] ^2[/tex]

Here  E =  8

=>   [tex]n = [\frac{1.96  * 52 }{8} ] ^2[/tex]

=>   [tex]n =162 [/tex]

Answer:

50

I've attached the drawing of my number line to show my thinking.  Download to turn it in if you need to.

Have a beautiful day, and stay safe.

Answer:

Students use linear, quadratic, and exponential functions to model data from tables and choose the regression

most appropriate to a given context. They use the correlation coefficient to determine the accuracy of a

regression model and then interpret the function in context. They then make predictions based on their model

and use an appropriate level of precision for reporting results and solutions.  

Lesson 7 focuses on data sets that cannot be modeled accurately, and students are asked

to articulate why. Students use skills learned in Lesson 14 of Module 2 (where they used

calculators to write linear regressions) and apply similar techniques for data sets that are

better suited to modeling with quadratic or exponential regressions. Students use that

same technique to find linear regressions and use their graphing calculators to examine

the correlation coefficient and to find quadratic and exponential regressions. They

compare correlation coefficients to determine which model is best for the data.

Ultimately, students choose the regression model (linear, quadratic, or exponential) most

appropriate to a given data set and then write, verify, and interpret these models in

context. Students need a graphing calculator to complete this lesson. Graphing calculator

instructions are provided, but steps may vary slightly depending on the model of the

graphing calculator.

Refer to the following full modeling cycle during this lesson (Found on page 61 of the CCLS

and page 72 of the CCSSM).

Scaffolding:

 Students are more

engaged when working

with relevant and real data

that interests them.

Websites that provide

data sets are a good

resource for classroom

investigations.

 This lesson might need to

be divided into two days if

students need more time

to master the technology.

Step-by-step explanation:

Answer:

y = 50x + 26.50

Step-by-step explanation:

we put the x after 50 be cause we don't know how many hours he worked

then add 26.50 the cost of the parts.

Hoped this helped.

Answer:

C: y=50x+26.50

Step-by-step explanation:

I just took the test and i got it right!!! 100%

do i get brainlest

Answer:

160 in.

Step-by-step explanation:

10 *  16 = 160

Answer:

1/6

Step-by-step explanation:

2/3*1/4

=2/12

=1/6

PLS GIVE BRAINLIEST

Answer:

Step-by-step explanation:

Givens

a = 2187

r = 1/3

L = 1/9

what is n

Formula

L = a*r^(n-1)

1/9 = 2187 * (1/3)^(n-1)

1/(9 * 2187) = (1/3)^(n - 1)

1/19683 = (1/3)^(n - 1)

=================

You need to break 19683 down into its prime factors.

19683 = 3* 729

19683 = 3 * 3 * 243

19683 = 3 * 3 * 3 * 81

81 = 3^4 so there are 4 more threes in the breakdown.

19683 = 3 * 3 * 3 * 3 * 3 * 3 * 3

1/19683 = 1/(3)^(7-1)

1/9 is the 6th term in the series.

Answer:

[tex]w=\frac{y+1}{a-2} (a\neq 2)[/tex]

Step-by-step explanation:

[tex]y - aw=2w-1\\y-aw-2w=-1\\-aw-2w=-1-y\\-w(a-2)=-(y+1)\\w(a-2)=y+1\\w=\frac{y+1}{a-2} (a\neq 2)[/tex]

Hope this helps!

Answer: percent is 0.53%

The ratio is 7 to 13 so you just divide 7/13

Step-by-step explanation:

Answer:

The correct option is  a

Step-by-step explanation:

Generally the null hypothesis is  rejected (that the result is significant ) when the p-value is less that the the level of significance

Now from the question when the the level of significance was 5% the p-value was less than the level of significance so also when the level of significance is   10% the p-value will be less than the level of significance hence null hypothesis will also be rejected at this level(that is the result will also  be significant at the level of significance )  

Answer:

I think it's B

Step-by-step explanation:

I believe the answer is C

Answer:

It's positive.

Step-by-step explanation:

There are many reasons.... but one of the obvious ones is that it would've shown negative, correct?

Answer:

11

Step-by-step explanation:

Answer:

June is correct.

Step-by-step explanation:

June is correct because Common Multiples are what we get after multiplying the number while common factors are what we can multiply to get the number.

The scale factor will create a similar triangle and thus there will be no change in angles so angles will still be 30° 60° and 90°.

You must specify the extent of the shape's enlargement when describing one.

The scale factor is the ratio of two dimensions such that one figure is large and another is small.

The scale factor is done due to the unpractical measurement of any figure.

Scale factor gives either a small or big similar image of a triangle, for example, if we have a triangle with vertices 2,4,6 and it is scaled by 1/2 then the resultant dimension will 1,2,3 but angles still remain the same.

Hence "The scale factor will create a similar triangle and thus there will be no change in angles so angles will still be 30° 60° and 90°".

To learn more about scale factors,

brainly.com/question/22312172

#SPJ1

Answer:

a. Only the x-value is given.

Step-by-step explanation:

Taking a look at the graph of both equations, both equations are graphed correctly, because the slope (m) and y-intercept (b) values corresponds of each equation corresponds with what we have on the graph representing each equation.

The solution of two linear equations ought to be in a coordinate pair, (x, y). This means the x-value and it's correaponding y-value of the solution needs to be stated, not just the x-value.

Thus, the correct solution. Of the two linear equations are x = 4, when y = 3.

Solution in coordinate pair form is (4, 3).

Therefore, the statement that describes the error is:

a. Only the x-value is given.

Answer:

Option C: 0.7734

Step-by-step explanation:

From z-distribution table attached,

P(Z ≤ -0.75) = 0.2266

However, we are looking for proportion of observations from a standard Normal distribution that take values larger than -0.75.

Thus;

P(Z > -0.75) = P(Z ≤ 0.75) = 1 - 0.2266

P(Z > -0.75) = 0.7734

Option C is the correct answer.