42. A triangle has an area of 14 square inches. The height of the triangle is three inches more than the
base. What are the base and height of the triangle?
43. Jill has a small treasure box that is 6 inches long. It can hold a volume of 72 inches cubed, and the
width of the box is 5 inches less than twice the height of the box. What are the dimensions of the box?
44. Jessie is mowing her back yard that is in the shape of a right triangle. The shortest side is 7 meters
shorter than the second side, and the hypotenuse is 13 meters long. What are the lengths of the two
sides?

Area = length x height:

Area = 7 x 11 = 77 square feet.

divide area of wall by area per can:

77/20 = 3.85 cans

they will need to buy 4 cans

Answer: area of the circle is [tex]3.14ft^{2}[/tex]

Step-by-step explanation:

1. the equation to find the area of a circle is [tex]\pi r^{2}[/tex]

2. the diameter is equal to 2r, meaning to get the radius, divide the diameter by 2.     [tex]\frac{2}{2} =1[/tex]

3. plug in the the radius into the equation. [tex]3.14*1^{2} =3.14ft^{2}[/tex]

hope this helped! ♡

Answer:

220

Step-by-step explanation:

first u gotta bla bla bla

Answer:

137°

Step-by-step explanation:

a straight line is 180°

x = 180 - (22 + 21)

x = 180 - 43

x = 137

Answer:

C

Step-by-step explanation:

[tex]24a-22 = -4(1-6a)\\\\\implies 24a-22 = -4+24a\\\\\implies -22 = -4\\\\\text{Which is not true, so no solutions exist.}[/tex]

Answer:

Angle A=87°

Step-by-step explanation:

(5x-3)°+(4x+21)°=180°

9x°+18°=180°

9x°+18°-18°=180°-18°

9x°=162°

9x°/9°=162°/9°

x=18°

Angle A=(5x18-3)°

(90-3)°

Angle A=87°

The possible value of the third length is an illustration of Triangle inequality theorem

The possible third lengths are 4 units and 6 units

To determine the third length, we make use of the following Triangle inequality theorem.

a + b > c

Let the third side be x.

So, we have:

x + 6 > 3

x + 3 > 6

3 + 6 > x

Solve the inequalities

x > -3

x > 3

x < 9

Remove the negative inequality value.

So, we have:

x > 3 or x < 9

Rewrite as:

3 < x or x < 9

Combine the inequality

3 < x < 9

This means that the possible value of the third length is between 3 and 9 (exclusive)

Hence, the possible third lengths are 4 units and 6 units

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Answer:

2 2/3 foot

Step-by-step explanation:

3x=8

x=8÷3

=2 2/3 foot

Answer:

the 852 is the perfect fit q3

Step-by-step explanation:

The five-number summary of this data set are minimum is 515, maximum value is 986, Q₁ is 686, Q₂ is 852 and Q₃ is 966.

Median of a data set is the element in the middle if the data are arranged in increasing or decreasing order. It is also called second quartile.

Given data set is,

{852, 687, 515, 986, 907, 784, 967, 685, 965}

Arrange this in ascending order first.

{515, 685, 687, 784, 852, 907, 965, 967, 986}

Minimum value = 515

Maximum value = 986

First we have to find the median or the second quartile.

Second quartile, Q₂ = Middle element of the set

Q₂ = 5th element = 852

First quartile = 1/4 (n + 1)th element = 1/4 (9 + 1) = 2.5 th element

Q₁ = (685 + 687) / 2 = 686

Third quartile = 3/4(n + 1)th element = 3/4 (9 + 1) = 7.5th element

Q₃ = (965 + 967) / 2 = 966

Hence the five-number summary of this data set are found.

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Step-by-step explanation:

can you tell me what you don't understand about this ?

because it is really simple, once you understand the transformations of equations.

remember, whatever we do to one side. we have to do also to the other side, so that the information in general stays the same.

(7 - 3x)/2 = 8 multiply both sides by 2

7 - 3x = 16 subtract 7 from both sides

-3x = 9 divide both sides by 3

-x = 3 multiply both sides by -1

x = -3

and that's the whole "secret" about solving an equation.

Answer:

Step-by-step explanation:

In the question we are given with an equation that is ( 7 - 3x ) / 2 = 8 . And we have asked to find the value of x .

Solution : -

[tex] \longrightarrow \qquad \: \dfrac{7 - 3x}{2} = 8[/tex]

Step 1 : Multiplying both sides by 2 :

[tex] \longrightarrow \qquad \: \dfrac{7 - 3x}{ \cancel{2} }\times \cancel{2 }= 8 \times 2 [/tex]

On further calculations, We get :

[tex] \longrightarrow \qquad \: 7 - 3x = 16[/tex]

Step 2 : Subtracting with 7 on both sides :

[tex] \longrightarrow \qquad \: \cancel{ 7 }- 3x - \cancel{ 7 }= 16 - 7[/tex]

On calculating further, We get :

[tex] \longrightarrow \qquad \: - 3x = 9[/tex]

Step 3 : Dividing with -3 on both sides :

[tex] \longrightarrow \qquad \: \dfrac{ \cancel{ - 3}x}{ \cancel{-3}} = \cancel{\dfrac{9}{ - 3} }[/tex]

On calculating further, We get :

[tex] \longrightarrow \qquad \: \red{\underline{\boxed{\frak{x = - 3}}}}[/tex]

Verifying : -

Now , we are verifying our answer by substituting value of x in given equation . So ,

Therefore , our answer is valid .

Answer:

  f(x) = 5/4x

Step-by-step explanation:

The equation of the line can be found using the 2-point form of the equation of a line:

  y -y1 = (y2 -y1)/(x2 -x1)(x -x1)

This can be rearranged to the desired funtional form.

__

Using the given points (x1, y1) = (8, 10) and (x2, y2) = (4, 5), we have ...

  y -10 = (5 -10)/(4 -8)(x -8)

  y = (-5/-4)(x -8) +10 = (5/4)x . . . . . add 10 and simplify

The equation can be written ...

  f(x) = 5/4x

Answer:

(a) 0 (b) 1^2

Step-by-step explanation:

photo number 1 is answer for question 2(a)

photo number 2 is answer for question 2(b)

[tex](8-15i) +(11+24i) = 19+9i\\\\(8-15i)-(11+24i)=-3-39i=-3(1+13i)[/tex]

Answer:

None

Step-by-step explanation:

Answer is isn't there

the gcf = 2

the LCM = 20

Answer:

1.4.5m/s^2

2.6.25m/s^2

3.15m/s^2

4.0.05m/s^2

Step-by-step explanation:

a=v-u

----

t

27-0

------ = 27/6

6

=4.5m/s^2

u=4.5m/s

v=24.5m/s

t=3.2s

(24.5-4.5)÷3.2

=20/3.2

=6.25m/s^2

v=80m/s

u=50m/s

t=2s

(80-50)÷2

15m/s^2

v=0.80m/s

u=0.50m/s

t=6s

(0.80-0.50)÷6

=0.05m/s^2

Answer:

b. is the equation and 18 is the answer.

Step-by-step explanation:

the 9 plus b has to equal the 27

18 is the value of b.

Answer:

1

Step-by-step explanation:

when x is 1 g(1) is 0

so

(f(g(1)) is f(0)

f(0) is 3√0 + 1 which is

1

sorry it looks like its not one of the answer choices

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The composition of functions f ( g ( 1 ) ) = 1

Evaluation of a function at the value of another function is known as Composition of function. A function composition is a process in which two functions, f and g, form a new function, h, in such a way that h(x) = g(f(x)). This signifies that function g is being applied to the function x. So, in essence, a function is applied to the output of another function.

Given data ,

Let the first function be represented as f ( x )

Now , the value of f ( x ) is

f ( x ) = 3√x + 1

Let the second function be represented as g ( x )

Now , the value of g ( x ) is

g ( 1 ) = 0

g ( 2 ) = 1

g ( 3 ) = 4

g ( 4 ) = 9

Now , the composition of function is given by f ( g ( 1 )

The value of g ( 1 ) = 0

And , f ( x ) = 3√x + 1

when x = 0

So , the value of f ( 0 ) = 3√0 + 1

The function is f ( 0 ) = 1

Hence , the value of the function f ( g ( 1 ) = 1

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Answer:

just remove the bracket and write normally so it's 23x+4-5b

Step-by-step explanation:

if you meant something else then let me know

Answer:

B. (-3, 10)

Step-by-step explanation:

     I am going to graph the given equation. I then will see which of the points given are within the required area.

-> See attached.

-> I have explained in the image more in-depth as well.

Answer:

Volume

Step-by-step explanation:

Length times width times height, is volume and the formula of finding what is inside something.

Volume :- it's the amount of the mass a body can hold

Answer: 1)3.26.3

2)326.15

3)325.39

4)326.48

Step-by-step explanation: you want to start from the lowest number to get your answer

Step-by-step explanation:

each pack 15 pencil

n* 15= 15n

Answer:

6 = 6/10

Step-by-step explanation:

.6 = 6/10 , by definition. = 3/5 (reduced -- divide numerator and denominator by 2.

Answer:

[tex]\dfrac{60}{100}[/tex]

Step-by-step explanation:

Six tenths:

[tex]\dfrac{6}{10}[/tex]

where 6 is the numerator and 10 is the denominator

We want the denominator to be 100, so how do we convert 10 into 100?

We multiply by 10, since 10 x 10 = 100

When working out equivalent fractions, we must remember to do the same operation to both the numerator and denominator.  Therefore, we should multiply both by 10:

[tex]\dfrac{6 \times 10}{10 \times 10}=\dfrac{60}{100}[/tex]

Therefore, the fraction that is equivalent to six tenths and has a denominator of 100 is:

[tex]\dfrac{60}{100}[/tex]

(sixty hundredths)

Answer:

Step-by-step explanation:

The rate of change can be found by using the difference quotient formula and in this case it would be -0.5

┍━━━━━»•» «•«━━━━━━»•» «•«━┑

[tex]f (x)= x^{2},(2, 3) -2[/tex]

The gneral rate of change can be found by using the difference quitieont formula. To find the average rate of change over an interval, enter a function with an interval: f (x)= x^{2},(2, 3) -2

┍━━━━━»•» «•«━━━━━━»•» «•«━┑

HOPE THIS HELPS

The maximum probability that both event A and event B will occur is 18%.

From the information, Event A has a 90% chance of occurring. Event B has a 20% chance of occurring. Therefore, the maximum probability will be:

= 90% × 20%

= 18%

The minimum probability that both event A and event B will occur will be:

= (90% + 20%) - 1

= 1.10 - 1

= 10%

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let's recall that d = rt, distance = rate * time.

a = speed of the airplane in still air.

w = speed of the wind

the distance travelled with the wind is 960 miles, so the return trip is pretty much just that, 960 miles.

when the airplane is going with with wind, the airplane is really not going as fast as "a" mph, is really going faster due to the wind, so the speed of the plane is "a + w", because the wind is adding its speed to it.

when the airplane is going against the wind is not really going "a" mph fast either, is really going slower at "a - w" mph, because the wind is subtracting speed from it, so

[tex]\begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ \textit{with the wind}&960&a+w&5\\ \textit{against the wind}&960&a-w&6 \end{array}~\hfill \begin{cases} 960=(a+w)(5)\\\\ 960=(a-w)(6) \end{cases} \\\\\\ \stackrel{\textit{using the 1st equation}}{960=(a+w)(5)}\implies \cfrac{960}{5}= a + w\implies 192=a+w\implies \boxed{192-w=a}[/tex]

[tex]\stackrel{\textit{substituting on the 2nd equation}}{960=(\underline{192-w}~~ - ~~w)(6)}\implies \cfrac{960}{6}=192-w-w\implies 160=192-2w \\\\\\ 2w+160=192\implies 2w=32\implies w=\cfrac{32}{2}\implies \blacktriangleright w=16 \blacktriangleleft ~\hfill \blacktriangleright \stackrel{192 - 16}{176=a} \blacktriangleleft[/tex]

Answer:145

Step-by-step explanation:

if h=33 and g=5 the expression would look like 33-4x5 frist 33-4=29 so now we imes by 5, 29x5=145 so 145 is your answer

Answer:

The angle B = 70°

Step-by-step explanation:

The sum of angles of a triangle is 180°

=> 40°+(2x-30)°+(x+20)° = 180°

=> 40°+2x°-30°+x°+20° = 180°

=> 30°+3x= 180°

=> 3x = 180°-30°

=> 3x = 150°

=> x = 150/3

=> x = 50°

So,the value of x = 50°

now , angle B = (2x-30) = (2×50 -30 ) = (100-30) = 70°

Let's recall that, the potential difference between any two points X(x,y,z) and Y(a,b,c) is given by ;

So, here ;

[tex]{:\implies \quad \sf \overrightarrow{E}=3x\hat{i}-2y\hat{j}+5z\hat{k}}[/tex]

So, now our second component of the Integrand will just be ;

[tex]{:\implies \quad \sf \overrightarrow{dr}=dx\hat{i}+dy\hat{j}+dz\hat{k}}[/tex]

So, now the whole integrand will just be ;

[tex]{:\implies \quad \sf \overrightarrow{E}\cdot \overrightarrow{dr}=(3x\hat{i}-2y\hat{j}+5z\hat{k})(dx\hat{i}+dy\hat{j}+dz\hat{k})}[/tex]

[tex]{:\implies \quad \sf \overrightarrow{E}\cdot \overrightarrow{dr}=3xdx-2ydy+5zdz}[/tex]

Now, Let's move to the final answer ;

[tex]{:\implies \quad \displaystyle \sf V_{Y}-V_{X}=-\int_{X}^{Y}3xdx-2ydy+5zdz}[/tex]

As,X is the point (1,3,5) and Y being (3,2,7) , so seperate the integral into three integrals with limits as follows respectively;

[tex]{:\implies \quad \displaystyle \sf V_{Y}-V_{X}=-\bigg(\int_{1}^{3}3xdx-\int_{3}^{2}ydy+\int_{5}^{7}zdz\bigg)}[/tex]

[tex]{:\implies \quad \displaystyle \sf V_{Y}-V_{X}=-\bigg(3\int_{1}^{3}xdx-2\int_{3}^{2}ydy+5\int_{5}^{7}zdz\bigg)}[/tex]

[tex]{:\implies \quad \displaystyle \sf V_{Y}-V_{X}=-\bigg\{3\bigg(\dfrac{x^2}{2}\bigg)\bigg|_{1}^{3}-2\bigg(\dfrac{y^2}{2}\bigg)\bigg|_{3}^{2}+5\bigg(\dfrac{z^2}{2}\bigg)\bigg|_{5}^{7}\bigg\}}[/tex]

[tex]{:\implies \quad \displaystyle \sf V_{Y}-V_{X}=-\bigg\{2\bigg(\dfrac{9}{2}-\dfrac12\bigg)-2\bigg(\dfrac{4}{2}-\dfrac92\bigg)+5\bigg(\dfrac{49}{2}-\dfrac{25}{2}\bigg)\bigg\}}[/tex]

[tex]{:\implies \quad \displaystyle \sf V_{Y}-V_{X}=-\{3(4)-(-5)+5(12)\}}[/tex]

[tex]{:\implies \quad \displaystyle \sf V_{Y}-V_{X}=-\{12+5+60\}}[/tex]

[tex]{:\implies \quad \displaystyle \boxed{\bf{V_{Y}-V_{X}=-77\:\: Volt}}}[/tex]

Hence, this is the required answer