5. 1.250 g of an alloy which is 90.00 % Ag and 10.00 % Cu is reacted with nitric acid producing AgNO3 and Cu(NO3)2 dissolved in solution. To the solution of the nitrate compounds is added a piece of copper wire that reacts only with the AgNO3 in solution to precipitate all of the silver, and produce additional Cu(NO3)2 (aq) . (The equation for this single-replacement reaction is: AgNO3(aq) + Cu(s)  Cu(NO3)2(aq) + 2 Ag(s) ) The resulting solution containing all of the Cu(NO3)2 produced by the above processes is treated with excess zinc to precipitate the entire amount of copper (ll) ion present. ( The equation for this step is Cu(NO3)2(aq) + Zn(s)  Zn(NO3)2(aq) + Cu(s) ) What mass of copper will be precipitated?

Answer:

The acid-base reaction produces glycine reduction, and hence the increase of glycine pH.

Explanation:

The glycine is an amino acid with the following chemical formula:

NH₂CH₂COOH  

The COOH functional group is what gives the acid properties in the molecule.      

Hence, when NaOH is added to glycine an acid-base reaction takes place in which COOH reacts with the NaOH added:

NH₂CH₂COOH + OH⁻ ⇄ NH₂CH₂COO⁻ + H₂O

The glycine concentration starts to shift to its ion form (NH₂CH₂COO⁻) because of the reaction with NaOH, that is why the pH glycine increases when NaOH is added.  

Therefore, the acid-base reaction produces glycine reduction, and hence the increase of glycine pH.  

I hope it helps you!  

Answer:

See explanation

Explanation:

CO2 is often released by the combustion of fossil fuels. Fossil fuels are quite common sources of energy in our world today.

A lot power plants, vehicles, etc rely on energy produced as a result of the combustion of fossil fuels yielding carbon dioxide.

Hence, irrespective of the fact that CO2 leads to global warming but Nigeria is still ranked one of the greatest emitters of CO2.

The menace of rising CO2 leves can only be checked by stakeholders in the energy sector coming together to exploit renewable energy as a regular source of energy.

Answer:

2.57 moles of carbon

Explanation:

1 mole = 6.023x10^23 (this is called avogadro's number)

1/6.023x10^23

1.55x10^24 = 1.55x10^24/6.023x10^23 = 2.57 moles

this means, 1.55x10^24 atom contains 2.57 moles of carbon

Answer:

B- The polarity of the molecules and hydrogen bonding between molecules.

Explanation:

Hope this helps:)

Answer:

1- Se 2-Na 3- I guess Si as well 4-Ar 5-O

Explanation:

Answer:

Yes.....

Explanation:

the decay half-life of a radioactive material can be changed. Radioactive decay happens when an unstable atomic nucleus spontaneously changes to a lower-energy state and spits out a bit of radiation. ... It is impossible to predict when an individual radioactive atom will decay.

Answer:

Ethylene glycol is a syrupy liquid at room temperature whereas polyethylene glycol is a solid material. The main difference between ethylene glycol and polyethylene glycol is that ethylene glycol has a fixed value for molecular weight whereas polyethylene glycol has no fixed value for molecular weight.

Answer:

0.5mol

Explanation:

Please mark as brainliest

Answer: A. 3.28 g of HCl

B. 6.30 g of [tex]HNO_3[/tex]

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} NaOH=\frac{3.65g}{40g/mol}=0.09moles[/tex]

[tex]\text{Moles of} Ca(OH)_2=\frac{3.65g}{74g/mol}=0.05moles[/tex]

a) [tex]HCl(aq)+NaOH(aq)\rightarrow H_2O(l)+NaCl(aq)[/tex]  

According to stoichiometry :

1 mole of [tex]NaOH[/tex] require = 1 mole of [tex]HCl[/tex]

Thus 0.09 moles of [tex]NaOH[/tex] will require=[tex]\frac{1}{1}\times 0.09=0.09moles[/tex]  of [tex]HCl[/tex]

Mass of [tex]HCl=moles\times {\text {Molar mass}}=0.09moles\times 36.5g/mol=3.28g[/tex]

b) [tex]2HNO_3(aq)+Ca(OH)_2(aq)\rightarrow 2H_2O(l)+Ca(NO_3)_2(aq)[/tex]  

According to stoichiometry :

1 mole of [tex]Ca(OH)_2[/tex] require = 2 moles of [tex]HNO_3[/tex]

Thus 0.05 moles of [tex]Ca(OH)_2[/tex] will require=[tex]\frac{2}{1}\times 0.05=0.1moles[/tex]  of [tex]HNO_3[/tex]

Mass of [tex]HNO_3=moles\times {\text {Molar mass}}=0.1moles\times 63g/mol=6.3g[/tex]

Answer:

2M

Explanation:

M=mol/L

1. Find moles of CoCl2

mass of substance/molar mass = 130/129.833 = 1.001 mol

3. Substitute in molarity equation

M=(1.001/0.5)

M= around 2M

The molarity of a solution with 130g of CoCl2 in 1/2 liter is 2M

HOW TO CALCULATE MOLARITY:

Therefore, the molarity of a solution with 130g of CoCl2 in 1/2 liter is 2M.

Learn more at: https://brainly.com/question/15948514?referrer=searchResults

Answer:

mass

Explanation:

Answer:

C Mass

Explanation:

mass wont change when a force is put upon it.

Answer:

1072 torr

Explanation:

To answer this problem we can use Gay-Lussac's law, which states:

Now we convert the given temperatures into K:

We input the data:

And solve for P₂:

Answer:

i think 15

Explanation:

Answer: About Barium Acetate

All metallic acetates are inorganic salts containing a metal cation and the acetate anion, a univalent (-1 charge) polyatomic ion composed of two carbon atoms ionically bound to three hydrogen and two oxygen atoms (Symbol: CH3COO) for a total formula weight of 59.05. Hopefully i helped

Explanation:

Answer:

Pubic hair smells bad

Explanation:

Answer:

[tex]0.060molH_2O[/tex]

Explanation:

Hello there!

In this case, since the chemical reaction between ethanol and oxygen to water and acetic acid is:

[tex]CH_3CH_2OH+O_2\rightarrow CH_3COOH+H_2O[/tex]

Thus, since there is a 1:1 mole ratio between oxygen and water, the produced moles of water are calculated down below:

[tex]0.060molO_2*\frac{1molH_2O}{1molO_2}=0.060molH_2O[/tex]

Best regards!

Answer:  [tex][Ni(NH_3)_3Br]Cl[/tex] and [tex][Ni(NH_3)_3Cl]Br[/tex] are ionization isomers.

[tex][Pt(Cl)_2(SCN)_4]^{4-}[/tex] and [tex][Pt(Cl)_2(NCS)_4]^{4-}[/tex] are linkage isomers.

Explanation:

Ionization isomerism occur when a ligand that is bound to the metal center exchanges places with an anion or neutral molecule that was originally outside the coordination complex

Thus [tex][Ni(NH_3)_3Br]Cl[/tex] and [tex][Ni(NH_3)_3Cl]Br[/tex] are ionization isomers.

Linkage isomerism is the existence of coordination compounds that have the same composition differing with the connectivity of the metal to a ligand.

Thus [tex][Pt(Cl)_2(SCN)_4]^{4-}[/tex] and [tex][Pt(Cl)_2(NCS)_4]^{4-}[/tex] are linkage isomers.

Answer:

D. Increase the pressure.

Explanation:

Okay, lets break this down.

So first, lets imagine what decreasing the volume looks like. I like to think of it as squishing a balloon or water bottle. You condense what's inside it. So, with this in mind, lets look at the question.

A. Decrease temperature:

Does this happen when you squeeze something? It gets colder? No, that's not true. So we can eliminate that one.

B. Increase the liters:

Does this happen when you squeeze something? It gets larger? It takes up more space? No, that's not true. So we can eliminate that one.

C. Decrease in moles:

Okay, so moles is just a fancy way of saying "stuff." So does the amount of "stuff" decrease when you squeeze something? No, it just gets closer together. It's denser. So we can eliminate that one.

D. Increase the pressure:

Now we're getting somewhere!! When you squeeze a balloon, the pressure DOES increase because you are condensing the gas inside it. That's why balloons will pop if you squeeze too hard, the pressure is too great and has to escape. So yes, this is your answer.

Answer: D. Increase the pressure

Answer:

if you did it would probably make it bigger...

Explanation:

:)

Answer:

48 g/mol

Explanation:

Step 1: Calculate the mass of the gas (m)

According to the law of conservation of mass, the mass of the solid before the decomposition must be equal to the sum of the masses of the solid residue and the gas

mSolid = mResidue + mGas

mGas = mSolid - mResidue = 4.73 g - 4.10 g = 0.63 g

Step 2: Convert 320 cm³ to L

We will use the conversion factor 1 L = 1000 cm³.

320 cm³ × 1 L/1000 cm³ = 0.320 L

Step 3: Calculate the moles of gas (n)

The gas is at room temperature (298.15 K) and room pressure (1 atm). We can calculate the moles of gas using the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 1 atm × 0.320 L/(0.0821 atm.L/mol.K) × 298.15 K = 0.0131 mol

Step 4: Calculate the molecular mass of the gas (M)

We will use the following expression.

M = m/n = 0.63 g/0.0131 mol = 48 g/mol

Hello,

During telophase, the cell, each pole of which inherits the same number of single  chromosomes, begins to divide into 2: this is  cytodieresis.

Answer:

C.

Explanation:

Chemical structure

Answer:

B. summer

Explanation:

The northern hemisphere experiences summer during the months of June, July, and August because it is tilted toward the sun and receives the most direct sunlight.

Answer:

Option C. 11.2 L

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T₁) = 25.0 °C

Initial volume (V₁) = 8.66 L

Final temperature (T₂) = 112 °C

Pressure = constant

Final volume (V₂) =?

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 25 °C

Initial temperature (T₁) = 25 °C +273

Initial temperature (T₁) = 298 K

Final temperature (T₂) = 112 °C

Final temperature (T₂) = 112 °C + 273

Final temperature (T₂) = 385 K

Finally, we shall determine final volume of the gas. This can be obtained as follow:

Initial temperature (T₁) = 298 K

Initial volume (V₁) = 8.66 L

Final temperature (T₂) = 385 K

Pressure = constant

Final volume (V₂) =?

V₁/T₁ = V₂/T₂

8.66/298 = V₂/385

Cross multiply

298 × V₂ = 8.66 × 385

298 × V₂ = 3334.1

Divide both side by 298

V₂ = 3334.1 / 298

V₂ = 11.2 L

Thus, the final (i.e new) volume of the gas is 11.2 L

Answer:

A

Explanation:

Both students are Pushing/Pulling towards the same direction meaning if enough force is applied the object will move into that direction

Answer:

22

Explanation:

5.5 mol C3H8 • (4 mol H2O / 1 mol C3H8 ) = 22 mol H2O

Answer:

2 NH3(g) + 3 O2(g) + 2 CH4(g) = 2 HCN(aq) + 6 H2O(l)

Explanation:

Reaction stoichiometry Limiting reagent

Compound Coefficient Molar Mass Moles Weight

NH3(g) 2 17.03052  

O2(g) 3 31.9988  

CH4(g) 2 16.04246  

HCN(aq) 2 27.02534  

H2O(l) 6 18.01528

Instructions on balancing chemical equations:

Enter an equation of a chemical reaction and click 'Balance'. The answer will appear below

Always use the upper case for the first character in the element name and the lower case for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.     Compare: Co - cobalt and CO - carbon monoxide

To enter an electron into a chemical equation use {-} or e

To enter an ion specify charge after the compound in curly brackets: {+3} or {3+} or {3}.

Example: Fe{3+} + I{-} = Fe{2+} + I2

Substitute immutable groups in chemical compounds to avoid ambiguity.

For instance equation C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced,

but PhC2H5 + O2 = PhOH + CO2 + H2O will

Compound states [like (s) (aq) or (g)] are not required.

If you do not know what products are enter reagents only and click 'Balance'. In many cases a complete equation will be suggested.

Reaction stoichiometry could be computed for a balanced equation. Enter either the number of moles or weight for one of the compounds to compute the rest.

Limiting reagent can be computed for a balanced equation by entering the number of moles or weight for all reagents.

The given chemical equation is already balanced and does not require any further balancing.

The chemical equation NH₃(g) + O₂(g) + CH₄(g) → HCN(aq) + H₂O(l) is already balanced because the number of atoms of each element is the same on both sides of the equation.

On the left side of the equation, there is 1 nitrogen (N) atom in NH₃ and 1 nitrogen (N) atom in HCN.

On the right side of the equation, there are 3 hydrogen (H) atoms in NH₃, 2 hydrogen (H) atoms in HCN, and 2 hydrogen (H) atoms in H₂O.

There are 3 oxygen (O) atoms in O₂ on the left side of the equation and 1 oxygen (O) atom in H₂O on the right side of the equation.

Finally, there is 1 carbon (C) atom in CH₄ on the left side of the equation.

Since the number of atoms of each element is balanced on both sides of the equation, we can conclude that the given equation is already balanced and does not require any further adjustments or coefficients.

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The complete question is:

How can I balance NH₃(g) + O₂ (g) + CH₄ (g) -> HCN (aq) + H₂O (l)?

Answer:

Answer is explained in the explanation section below.

Explanation:

Penetration refers to the proximity of electrons in an orbital to the nucleus.

Deeper-penetrating electrons have less shielding and therefore a higher Effective nuclear charge (Zeff), but they better shield other electrons.

To illustrate penetration, we may use the idea of Zeff, or effective nuclear charge. It's actually the difference between the number of charged protons and the number of shielded electrons. To put it another way, how effective the nucleus is at attracting electrons. Since they do not shield themselves, the core electrons penetrate the most and are exposed to the most strong nuclear charge.

The electron probability density is highest in the orbital's centre or nucleus for 28-orbitals.

In a multi-electron unit, the electron density near the nucleus of an atom for each shell and subshell of an electron is used to measure the nucleus penetration by an electron.

Since it has a higher electron density near the nucleus, the 2s electron penetrates the nucleus of the atom more than the 2p electron.

A 2s electron is less well shielded by the core electrons than a 2p electron because it can spend more time near the nucleus as a result of the penetration.

Mathematical Expression:

v = [tex]\frac{-Zeff * e^{z} }{r^{2} }[/tex]

Answer:

the generation of electricity and other energy jointly, especially the utilization of the steam left over from electricity generation to produce heat.

I hope it helps!! Have a nice day

Answer:

Cogeneration r is the use of a heat engine or power station to generate electricity and useful heat at the same time.